findall returning only the last attribute
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
0
i have searched for similar questions but didn't find what i need.
I am searching a web for two attributes in this case red and green in span
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.findAll("span",{"class":"red","class":"green"})
print(nameList)
However i am only getting the green attribute,i tried using
nameList,nameList2=soup.findAll("span",{"class":"red","class":"green"})
but i get the error ValueError: too many values to unpack (expected 2)
is there a way to print both and store each attribute in a namelist (without using multiple findAll)
python web-scraping findall
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
add a comment |
0
i have searched for similar questions but didn't find what i need.
I am searching a web for two attributes in this case red and green in span
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.findAll("span",{"class":"red","class":"green"})
print(nameList)
However i am only getting the green attribute,i tried using
nameList,nameList2=soup.findAll("span",{"class":"red","class":"green"})
but i get the error ValueError: too many values to unpack (expected 2)
is there a way to print both and store each attribute in a namelist (without using multiple findAll)
python web-scraping findall
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
add a comment |
0
0
0
i have searched for similar questions but didn't find what i need.
I am searching a web for two attributes in this case red and green in span
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.findAll("span",{"class":"red","class":"green"})
print(nameList)
However i am only getting the green attribute,i tried using
nameList,nameList2=soup.findAll("span",{"class":"red","class":"green"})
but i get the error ValueError: too many values to unpack (expected 2)
is there a way to print both and store each attribute in a namelist (without using multiple findAll)
python web-scraping findall
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
i have searched for similar questions but didn't find what i need.
I am searching a web for two attributes in this case red and green in span
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.findAll("span",{"class":"red","class":"green"})
print(nameList)
However i am only getting the green attribute,i tried using
nameList,nameList2=soup.findAll("span",{"class":"red","class":"green"})
but i get the error ValueError: too many values to unpack (expected 2)
is there a way to print both and store each attribute in a namelist (without using multiple findAll)
python web-scraping findall
python web-scraping findall
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
asked Nov 23 '18 at 13:26
wishmasterwishmaster
35210
35210
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
You can try to use CSS selector to match span with both class names as below:
nameList = soup.select("span.red, span.green")
If you still want to use findAll, try
nameList = soup.findAll("span",{"class":["red", "green"]})
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,soup.select("span.red, span.green")select both,soup.select("span.green")select green only,soup.select("span.red")select red only
– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why isfindAllnot storing both attributes?
– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:soup.findAll("span",{"class":["red","green"]})
– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
|
show 3 more comments
0
As your red and green are the only class attributes you can just check for span with class attribute
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.select("span[class]")
print(nameList)
To have separate lists you can use 2 selects by class name:
reds = soup.select('span.red')
greens = soup.select('span.green')
print(reds,greens)
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You can try to use CSS selector to match span with both class names as below:
nameList = soup.select("span.red, span.green")
If you still want to use findAll, try
nameList = soup.findAll("span",{"class":["red", "green"]})
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,soup.select("span.red, span.green")select both,soup.select("span.green")select green only,soup.select("span.red")select red only
– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why isfindAllnot storing both attributes?
– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:soup.findAll("span",{"class":["red","green"]})
– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
|
show 3 more comments
0
You can try to use CSS selector to match span with both class names as below:
nameList = soup.select("span.red, span.green")
If you still want to use findAll, try
nameList = soup.findAll("span",{"class":["red", "green"]})
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,soup.select("span.red, span.green")select both,soup.select("span.green")select green only,soup.select("span.red")select red only
– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why isfindAllnot storing both attributes?
– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:soup.findAll("span",{"class":["red","green"]})
– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
|
show 3 more comments
0
0
0
You can try to use CSS selector to match span with both class names as below:
nameList = soup.select("span.red, span.green")
If you still want to use findAll, try
nameList = soup.findAll("span",{"class":["red", "green"]})
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
You can try to use CSS selector to match span with both class names as below:
nameList = soup.select("span.red, span.green")
If you still want to use findAll, try
nameList = soup.findAll("span",{"class":["red", "green"]})
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
edited Nov 23 '18 at 14:04
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
answered Nov 23 '18 at 13:30
AnderssonAndersson
39.1k113669
39.1k113669
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,soup.select("span.red, span.green")select both,soup.select("span.green")select green only,soup.select("span.red")select red only
– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why isfindAllnot storing both attributes?
– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:soup.findAll("span",{"class":["red","green"]})
– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
|
show 3 more comments
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,soup.select("span.red, span.green")select both,soup.select("span.green")select green only,soup.select("span.red")select red only
– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why isfindAllnot storing both attributes?
– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:soup.findAll("span",{"class":["red","green"]})
– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
it works, is there a way to store red alone and green alone?
– wishmaster
Nov 23 '18 at 13:44
@timmy ,
soup.select("span.red, span.green") select both, soup.select("span.green") select green only, soup.select("span.red") select red only– Andersson
Nov 23 '18 at 13:56
@timmy ,
soup.select("span.red, span.green") select both, soup.select("span.green") select green only, soup.select("span.red") select red only– Andersson
Nov 23 '18 at 13:56
@Andersson i understand,this a fine method. However why is
findAll not storing both attributes?– wishmaster
Nov 23 '18 at 14:01
@Andersson i understand,this a fine method. However why is
findAll not storing both attributes?– wishmaster
Nov 23 '18 at 14:01
@timmy , because you should pass class names as list:
soup.findAll("span",{"class":["red","green"]})– Andersson
Nov 23 '18 at 14:04
@timmy , because you should pass class names as list:
soup.findAll("span",{"class":["red","green"]})– Andersson
Nov 23 '18 at 14:04
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
this method works,but leaves no way for storing each alone right ?
– wishmaster
Nov 23 '18 at 14:16
|
show 3 more comments
0
As your red and green are the only class attributes you can just check for span with class attribute
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.select("span[class]")
print(nameList)
To have separate lists you can use 2 selects by class name:
reds = soup.select('span.red')
greens = soup.select('span.green')
print(reds,greens)
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
add a comment |
0
As your red and green are the only class attributes you can just check for span with class attribute
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.select("span[class]")
print(nameList)
To have separate lists you can use 2 selects by class name:
reds = soup.select('span.red')
greens = soup.select('span.green')
print(reds,greens)
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
add a comment |
0
0
0
As your red and green are the only class attributes you can just check for span with class attribute
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.select("span[class]")
print(nameList)
To have separate lists you can use 2 selects by class name:
reds = soup.select('span.red')
greens = soup.select('span.green')
print(reds,greens)
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
As your red and green are the only class attributes you can just check for span with class attribute
from urllib.request import urlopen
from bs4 import BeautifulSoup
html=urlopen('http://www.pythonscraping.com/pages/warandpeace.html')
soup=BeautifulSoup(html,'html.parser')
nameList=soup.select("span[class]")
print(nameList)
To have separate lists you can use 2 selects by class name:
reds = soup.select('span.red')
greens = soup.select('span.green')
print(reds,greens)
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
edited Nov 23 '18 at 13:52
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
answered Nov 23 '18 at 13:42
QHarrQHarr
37.7k82245
37.7k82245
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
add a comment |
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
how can i store red alone and green alone without using multiple select?
– wishmaster
Nov 23 '18 at 13:48
add a comment |
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