Removing extra whitespace between words using for loop Python

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-2

I need to remove all excess white space and leave one space, between my words while only using if and while statements. and then state the amount of characters that have been removed and the new sentence
edit, it must also work for punctuation included within the sentence.
This is what I have come up with however it leaves me with only the first letter of the sentence i choose as both the number, and the final sentence. can anyone Help.

def cleanupstring(S):



    lasti = ""

    result = ""

    for i in S:

        if lasti == " " and i == " ":

            i = ""

        else:

            lasti = i    

        result += i    



    return result



sentence = input("Enter a string: ")



outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

3

Possible duplicate of Cleaning up a string without split/strip/built-in functions

– Adam
Nov 23 '18 at 18:55

1

One easy: print("The new string is:", outputList).

– Austin
Nov 23 '18 at 18:56

You only print the first item if the string

– Tobias Wilfert
Nov 23 '18 at 18:57

Also outputList[1] is not the amount of characters that have been removed

– Tobias Wilfert
Nov 23 '18 at 18:58

add a comment |

-2

def cleanupstring(S):



    lasti = ""

    result = ""

    for i in S:

        if lasti == " " and i == " ":

            i = ""

        else:

            lasti = i    

        result += i    



    return result



sentence = input("Enter a string: ")



outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

3

Possible duplicate of Cleaning up a string without split/strip/built-in functions

– Adam
Nov 23 '18 at 18:55

1

One easy: print("The new string is:", outputList).

– Austin
Nov 23 '18 at 18:56

You only print the first item if the string

– Tobias Wilfert
Nov 23 '18 at 18:57

Also outputList[1] is not the amount of characters that have been removed

– Tobias Wilfert
Nov 23 '18 at 18:58

add a comment |

-2

def cleanupstring(S):



    lasti = ""

    result = ""

    for i in S:

        if lasti == " " and i == " ":

            i = ""

        else:

            lasti = i    

        result += i    



    return result



sentence = input("Enter a string: ")



outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

def cleanupstring(S):



    lasti = ""

    result = ""

    for i in S:

        if lasti == " " and i == " ":

            i = ""

        else:

            lasti = i    

        result += i    



    return result



sentence = input("Enter a string: ")



outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

python

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

edited Nov 23 '18 at 19:17

asked Nov 23 '18 at 18:52

Funnacho

asked Nov 23 '18 at 18:52

Funnacho

asked Nov 23 '18 at 18:52

Funnacho

3

Possible duplicate of Cleaning up a string without split/strip/built-in functions

– Adam
Nov 23 '18 at 18:55

1

One easy: print("The new string is:", outputList).

– Austin
Nov 23 '18 at 18:56

You only print the first item if the string

– Tobias Wilfert
Nov 23 '18 at 18:57

Also outputList[1] is not the amount of characters that have been removed

– Tobias Wilfert
Nov 23 '18 at 18:58

add a comment |

3

Possible duplicate of Cleaning up a string without split/strip/built-in functions

– Adam
Nov 23 '18 at 18:55

1

One easy: print("The new string is:", outputList).

– Austin
Nov 23 '18 at 18:56

You only print the first item if the string

– Tobias Wilfert
Nov 23 '18 at 18:57

Also outputList[1] is not the amount of characters that have been removed

– Tobias Wilfert
Nov 23 '18 at 18:58

Possible duplicate of Cleaning up a string without split/strip/built-in functions

– Adam
Nov 23 '18 at 18:55

One easy: print("The new string is:", outputList).

– Austin
Nov 23 '18 at 18:56

You only print the first item if the string

– Tobias Wilfert
Nov 23 '18 at 18:57

Also outputList[1] is not the amount of characters that have been removed

– Tobias Wilfert
Nov 23 '18 at 18:58

add a comment |

1 Answer
1

active

oldest

votes

Your code should be something like this:

def cleanupstring(S):

counter = 0

lasti = ""

result = ""

for i in S:

    if lasti == " " and i == " ":

        i = ""

        counter += 1

    else:

        lasti = i

        result += i

return result, counter



sentence = input("Enter a string: ")

outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

The counter keeps track of how often you remove a character and your [0] and [1] work now the way you want them to.

This is because outputList is now a tuple, the first value at index 0 is now the result and the second value at index 1 is the counter.

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

|
show 2 more comments

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

Your code should be something like this:

def cleanupstring(S):

counter = 0

lasti = ""

result = ""

for i in S:

    if lasti == " " and i == " ":

        i = ""

        counter += 1

    else:

        lasti = i

        result += i

return result, counter



sentence = input("Enter a string: ")

outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

|
show 2 more comments

Your code should be something like this:

def cleanupstring(S):

counter = 0

lasti = ""

result = ""

for i in S:

    if lasti == " " and i == " ":

        i = ""

        counter += 1

    else:

        lasti = i

        result += i

return result, counter



sentence = input("Enter a string: ")

outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

|
show 2 more comments

Your code should be something like this:

def cleanupstring(S):

counter = 0

lasti = ""

result = ""

for i in S:

    if lasti == " " and i == " ":

        i = ""

        counter += 1

    else:

        lasti = i

        result += i

return result, counter



sentence = input("Enter a string: ")

outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

Your code should be something like this:

def cleanupstring(S):

counter = 0

lasti = ""

result = ""

for i in S:

    if lasti == " " and i == " ":

        i = ""

        counter += 1

    else:

        lasti = i

        result += i

return result, counter



sentence = input("Enter a string: ")

outputList = cleanupstring(sentence)



print("A total of", outputList[1], "characters have been removed from your string.")

print("The new string is:", outputList[0])

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

answered Nov 23 '18 at 19:02

Tobias Wilfert

84531022

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

|
show 2 more comments

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

thank you that works! I forgot to mention it also must work with sentences containing punctuation like commas and periods. a space after is okay. where can i build in that condition? thanks again

– Funnacho
Nov 23 '18 at 19:16

It doesn't remove any spaces behind a comma is just leaves the one before so 'hello , world' would not be changed.

– Tobias Wilfert
Nov 23 '18 at 19:28

this is because the first space between them is not considered "extra" when it is checking the string?

– Funnacho
Nov 23 '18 at 19:38

@Funnacho yes, the program doesn't check if the spaces are on the correct position it just removes one if there are 2 behind each other.

– Tobias Wilfert
Nov 23 '18 at 19:40

thanks for all the clarification and help, would you be able to send me in the right direction to fix this issue?

– Funnacho
Nov 23 '18 at 19:46

|
show 2 more comments

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