Milky Way Density











up vote
2
down vote

favorite












It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?



I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?



Thank you very much in advance!










share|cite|improve this question






















  • You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
    – Run like hell
    2 days ago












  • Someone asked about the density profile a while ago, but it's been left unanswered :(
    – Kyle Kanos
    2 days ago















up vote
2
down vote

favorite












It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?



I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?



Thank you very much in advance!










share|cite|improve this question






















  • You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
    – Run like hell
    2 days ago












  • Someone asked about the density profile a while ago, but it's been left unanswered :(
    – Kyle Kanos
    2 days ago













up vote
2
down vote

favorite









up vote
2
down vote

favorite











It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?



I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?



Thank you very much in advance!










share|cite|improve this question













It seems to be a simple question, but I wasn't really able to find an appropriate answer: How dense is the Milky Way? I am certain that there are reliable statistic, maybe even new ones from the GAIA catalogue?



I am very aware of the fact that the tremendously varies between the core, the bulge, the spiral arms and the inter-arm regions, but I'd like to have a single number for the whole galaxy, something like "a solar system per pc$^3$". Is there anything around?



Thank you very much in advance!







cosmology astrophysics astronomy density milky-way






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked 2 days ago









kalle

11611




11611












  • You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
    – Run like hell
    2 days ago












  • Someone asked about the density profile a while ago, but it's been left unanswered :(
    – Kyle Kanos
    2 days ago


















  • You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
    – Run like hell
    2 days ago












  • Someone asked about the density profile a while ago, but it's been left unanswered :(
    – Kyle Kanos
    2 days ago
















You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
2 days ago






You want an average density? Just take the mass over volume ratio. Mass of stars is, if I remember correctly $10^11$ solar masses and volume I don't know but you can easily calculate it using the radius and the height of the disk. If you want to consider dark matter too you have to add the extra volume of the dark matter halo Which you can consider a sphere in first approximation
– Run like hell
2 days ago














Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
2 days ago




Someone asked about the density profile a while ago, but it's been left unanswered :(
– Kyle Kanos
2 days ago










1 Answer
1






active

oldest

votes

















up vote
3
down vote



accepted










It's possible to give a rough estimate with the data on Wikipedia:





  • Diameter: 46–61 kpc

  • Thickness of thin stellar disk: 0.6 kpc

  • Number of stars: 1–4 × 1011




If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.



(Also, not every star has its own solar system.)






share|cite|improve this answer








New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
    – kalle
    2 days ago











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "151"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f443377%2fmilky-way-density%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










It's possible to give a rough estimate with the data on Wikipedia:





  • Diameter: 46–61 kpc

  • Thickness of thin stellar disk: 0.6 kpc

  • Number of stars: 1–4 × 1011




If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.



(Also, not every star has its own solar system.)






share|cite|improve this answer








New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
    – kalle
    2 days ago















up vote
3
down vote



accepted










It's possible to give a rough estimate with the data on Wikipedia:





  • Diameter: 46–61 kpc

  • Thickness of thin stellar disk: 0.6 kpc

  • Number of stars: 1–4 × 1011




If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.



(Also, not every star has its own solar system.)






share|cite|improve this answer








New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.


















  • Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
    – kalle
    2 days ago













up vote
3
down vote



accepted







up vote
3
down vote



accepted






It's possible to give a rough estimate with the data on Wikipedia:





  • Diameter: 46–61 kpc

  • Thickness of thin stellar disk: 0.6 kpc

  • Number of stars: 1–4 × 1011




If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.



(Also, not every star has its own solar system.)






share|cite|improve this answer








New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









It's possible to give a rough estimate with the data on Wikipedia:





  • Diameter: 46–61 kpc

  • Thickness of thin stellar disk: 0.6 kpc

  • Number of stars: 1–4 × 1011




If we take the average of the range, the volume of the disc is $0.6 times frac{pi}4 53.5^2=1348.8 ,text{kpc}^3$ (the volume of the core is negligible, given the inaccuracy of the number of stars). So the average number of stars per $text{pc}^3$ is $frac{2.5 cdot 10^{11}}{1348.8 cdot 10^9} ≈ 0.2$, but given the inaccuracies in the estimates it could be three times higher or lower.



(Also, not every star has its own solar system.)







share|cite|improve this answer








New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this answer



share|cite|improve this answer






New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 2 days ago









Glorfindel

2401310




2401310




New contributor




Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Glorfindel is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
    – kalle
    2 days ago


















  • Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
    – kalle
    2 days ago
















Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
2 days ago




Thanks a lot. I took the same numbers and came to a range of 0.029 and 0.201 stars per pc$^3$.
– kalle
2 days ago


















 

draft saved


draft discarded



















































 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f443377%2fmilky-way-density%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

"Incorrect syntax near the keyword 'ON'. (on update cascade, on delete cascade,)

Alcedinidae

RAC Tourist Trophy