Why are we using “Euler's Number” constantly? [duplicate]
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This question already has an answer here:
Why is the number $e$ so important in mathematics?
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I am a student at technical university.We are currently studying Calculus and I am really curious about why we are using Euler's Number.
functions trigonometry logarithms exponential-function exponentiation
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marked as duplicate by Lord Shark the Unknown, amWhy, Mark S., egreg, Matthew Towers 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
up vote
2
down vote
favorite
This question already has an answer here:
Why is the number $e$ so important in mathematics?
9 answers
I am a student at technical university.We are currently studying Calculus and I am really curious about why we are using Euler's Number.
functions trigonometry logarithms exponential-function exponentiation
New contributor
marked as duplicate by Lord Shark the Unknown, amWhy, Mark S., egreg, Matthew Towers 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
6
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
This question already has an answer here:
Why is the number $e$ so important in mathematics?
9 answers
I am a student at technical university.We are currently studying Calculus and I am really curious about why we are using Euler's Number.
functions trigonometry logarithms exponential-function exponentiation
New contributor
This question already has an answer here:
Why is the number $e$ so important in mathematics?
9 answers
I am a student at technical university.We are currently studying Calculus and I am really curious about why we are using Euler's Number.
This question already has an answer here:
Why is the number $e$ so important in mathematics?
9 answers
functions trigonometry logarithms exponential-function exponentiation
functions trigonometry logarithms exponential-function exponentiation
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New contributor
New contributor
asked 2 days ago
SeptemberSKY
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133
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New contributor
marked as duplicate by Lord Shark the Unknown, amWhy, Mark S., egreg, Matthew Towers 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by Lord Shark the Unknown, amWhy, Mark S., egreg, Matthew Towers 2 days ago
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
6
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago
add a comment |
6
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago
6
6
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago
add a comment |
2 Answers
2
active
oldest
votes
up vote
4
down vote
accepted
Below is one of my favourite examples of compound interest, we will illustrate that the maximum amount of interest we can receive over interest has an upper bound in a way. Note that this answer is just a peak at the wonderful world of maths and not meant to scare away any readers, it is by no means rigorous, it is supposed to be a light read.
Suppose we have a euro and over some amount of time we receive 100% interest over this euro:
$$ 1+frac{1}{1}=2$$
Nice, can we get more money if we ask the bank folks to just give us 50% interest, but over half the time (interest over interest?)
$$ (1+frac{1}{2})^2=1.5^2=2.25$$
Nice, more money!
Does this go on forever $dots$ ?
$$ (1+frac{1}{100})^{100}=1.5^2=2.7048dots$$
Hmm, it seems like this number has a ceiling, in fact:
$$ (1+frac{1}{n})^{n} rightarrow e$$
If you would like to know why, read up on some real analysis, it's a truly marvellous subject.
Another great illustration is the polynomial that is its own derivative, let's define the polynomial by a funny name:
$$ exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 + frac{1}{24}x^4dots $$
Notice that if we derive term by term we get:
$$ frac{d}{dx} exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 dots $$
How peculiar, what would $exp(1)$ be?
$$exp(1) approx 1+ 1 + frac{1}{2} + frac{1}{6} + frac{1}{24}=2.708 dots$$
Truly, this number has such an interesting property in nature, if it would be the base of an exponent it would correspond to one of the most natural things to define, maybe we could even define some sort of logarithm for it, wouldn't that be the natural thing to do?
Also see:
http://math.wikia.com/wiki/Euler%27s_number
https://www.quora.com/What-are-the-most-fascinating-facts-about-Eulers-number-e
Actually Jacob Bernoulli was possibly the first to discover $e$, not Euler, who was a student of Jacob Bernoulli: https://en.wikipedia.org/wiki/Jacob_Bernoulli
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
add a comment |
up vote
3
down vote
Because it is a special number, indeed it is the only base for the exponential function $f(x)=a^x$ such that the derivative is equal to the function itself, that is
$$f'(x)=f(x)$$
Refer also to
- Applications - Calculus (Wiki)
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
Below is one of my favourite examples of compound interest, we will illustrate that the maximum amount of interest we can receive over interest has an upper bound in a way. Note that this answer is just a peak at the wonderful world of maths and not meant to scare away any readers, it is by no means rigorous, it is supposed to be a light read.
Suppose we have a euro and over some amount of time we receive 100% interest over this euro:
$$ 1+frac{1}{1}=2$$
Nice, can we get more money if we ask the bank folks to just give us 50% interest, but over half the time (interest over interest?)
$$ (1+frac{1}{2})^2=1.5^2=2.25$$
Nice, more money!
Does this go on forever $dots$ ?
$$ (1+frac{1}{100})^{100}=1.5^2=2.7048dots$$
Hmm, it seems like this number has a ceiling, in fact:
$$ (1+frac{1}{n})^{n} rightarrow e$$
If you would like to know why, read up on some real analysis, it's a truly marvellous subject.
Another great illustration is the polynomial that is its own derivative, let's define the polynomial by a funny name:
$$ exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 + frac{1}{24}x^4dots $$
Notice that if we derive term by term we get:
$$ frac{d}{dx} exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 dots $$
How peculiar, what would $exp(1)$ be?
$$exp(1) approx 1+ 1 + frac{1}{2} + frac{1}{6} + frac{1}{24}=2.708 dots$$
Truly, this number has such an interesting property in nature, if it would be the base of an exponent it would correspond to one of the most natural things to define, maybe we could even define some sort of logarithm for it, wouldn't that be the natural thing to do?
Also see:
http://math.wikia.com/wiki/Euler%27s_number
https://www.quora.com/What-are-the-most-fascinating-facts-about-Eulers-number-e
Actually Jacob Bernoulli was possibly the first to discover $e$, not Euler, who was a student of Jacob Bernoulli: https://en.wikipedia.org/wiki/Jacob_Bernoulli
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
add a comment |
up vote
4
down vote
accepted
Below is one of my favourite examples of compound interest, we will illustrate that the maximum amount of interest we can receive over interest has an upper bound in a way. Note that this answer is just a peak at the wonderful world of maths and not meant to scare away any readers, it is by no means rigorous, it is supposed to be a light read.
Suppose we have a euro and over some amount of time we receive 100% interest over this euro:
$$ 1+frac{1}{1}=2$$
Nice, can we get more money if we ask the bank folks to just give us 50% interest, but over half the time (interest over interest?)
$$ (1+frac{1}{2})^2=1.5^2=2.25$$
Nice, more money!
Does this go on forever $dots$ ?
$$ (1+frac{1}{100})^{100}=1.5^2=2.7048dots$$
Hmm, it seems like this number has a ceiling, in fact:
$$ (1+frac{1}{n})^{n} rightarrow e$$
If you would like to know why, read up on some real analysis, it's a truly marvellous subject.
Another great illustration is the polynomial that is its own derivative, let's define the polynomial by a funny name:
$$ exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 + frac{1}{24}x^4dots $$
Notice that if we derive term by term we get:
$$ frac{d}{dx} exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 dots $$
How peculiar, what would $exp(1)$ be?
$$exp(1) approx 1+ 1 + frac{1}{2} + frac{1}{6} + frac{1}{24}=2.708 dots$$
Truly, this number has such an interesting property in nature, if it would be the base of an exponent it would correspond to one of the most natural things to define, maybe we could even define some sort of logarithm for it, wouldn't that be the natural thing to do?
Also see:
http://math.wikia.com/wiki/Euler%27s_number
https://www.quora.com/What-are-the-most-fascinating-facts-about-Eulers-number-e
Actually Jacob Bernoulli was possibly the first to discover $e$, not Euler, who was a student of Jacob Bernoulli: https://en.wikipedia.org/wiki/Jacob_Bernoulli
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
Below is one of my favourite examples of compound interest, we will illustrate that the maximum amount of interest we can receive over interest has an upper bound in a way. Note that this answer is just a peak at the wonderful world of maths and not meant to scare away any readers, it is by no means rigorous, it is supposed to be a light read.
Suppose we have a euro and over some amount of time we receive 100% interest over this euro:
$$ 1+frac{1}{1}=2$$
Nice, can we get more money if we ask the bank folks to just give us 50% interest, but over half the time (interest over interest?)
$$ (1+frac{1}{2})^2=1.5^2=2.25$$
Nice, more money!
Does this go on forever $dots$ ?
$$ (1+frac{1}{100})^{100}=1.5^2=2.7048dots$$
Hmm, it seems like this number has a ceiling, in fact:
$$ (1+frac{1}{n})^{n} rightarrow e$$
If you would like to know why, read up on some real analysis, it's a truly marvellous subject.
Another great illustration is the polynomial that is its own derivative, let's define the polynomial by a funny name:
$$ exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 + frac{1}{24}x^4dots $$
Notice that if we derive term by term we get:
$$ frac{d}{dx} exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 dots $$
How peculiar, what would $exp(1)$ be?
$$exp(1) approx 1+ 1 + frac{1}{2} + frac{1}{6} + frac{1}{24}=2.708 dots$$
Truly, this number has such an interesting property in nature, if it would be the base of an exponent it would correspond to one of the most natural things to define, maybe we could even define some sort of logarithm for it, wouldn't that be the natural thing to do?
Also see:
http://math.wikia.com/wiki/Euler%27s_number
https://www.quora.com/What-are-the-most-fascinating-facts-about-Eulers-number-e
Actually Jacob Bernoulli was possibly the first to discover $e$, not Euler, who was a student of Jacob Bernoulli: https://en.wikipedia.org/wiki/Jacob_Bernoulli
Below is one of my favourite examples of compound interest, we will illustrate that the maximum amount of interest we can receive over interest has an upper bound in a way. Note that this answer is just a peak at the wonderful world of maths and not meant to scare away any readers, it is by no means rigorous, it is supposed to be a light read.
Suppose we have a euro and over some amount of time we receive 100% interest over this euro:
$$ 1+frac{1}{1}=2$$
Nice, can we get more money if we ask the bank folks to just give us 50% interest, but over half the time (interest over interest?)
$$ (1+frac{1}{2})^2=1.5^2=2.25$$
Nice, more money!
Does this go on forever $dots$ ?
$$ (1+frac{1}{100})^{100}=1.5^2=2.7048dots$$
Hmm, it seems like this number has a ceiling, in fact:
$$ (1+frac{1}{n})^{n} rightarrow e$$
If you would like to know why, read up on some real analysis, it's a truly marvellous subject.
Another great illustration is the polynomial that is its own derivative, let's define the polynomial by a funny name:
$$ exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 + frac{1}{24}x^4dots $$
Notice that if we derive term by term we get:
$$ frac{d}{dx} exp(x)= 1+ x+ frac{1}{2}x^2 + frac{1}{6}x^3 dots $$
How peculiar, what would $exp(1)$ be?
$$exp(1) approx 1+ 1 + frac{1}{2} + frac{1}{6} + frac{1}{24}=2.708 dots$$
Truly, this number has such an interesting property in nature, if it would be the base of an exponent it would correspond to one of the most natural things to define, maybe we could even define some sort of logarithm for it, wouldn't that be the natural thing to do?
Also see:
http://math.wikia.com/wiki/Euler%27s_number
https://www.quora.com/What-are-the-most-fascinating-facts-about-Eulers-number-e
Actually Jacob Bernoulli was possibly the first to discover $e$, not Euler, who was a student of Jacob Bernoulli: https://en.wikipedia.org/wiki/Jacob_Bernoulli
edited 2 days ago
answered 2 days ago
WesleyGroupshaveFeelingsToo
1,002321
1,002321
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
add a comment |
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
1
1
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
Isn't that polynomial called the Taylor Expansion?
– iBug
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
what is a Taylor polynomial, the Taylor polynomial of which function ;D
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
Yes, it is actually.
– WesleyGroupshaveFeelingsToo
2 days ago
add a comment |
up vote
3
down vote
Because it is a special number, indeed it is the only base for the exponential function $f(x)=a^x$ such that the derivative is equal to the function itself, that is
$$f'(x)=f(x)$$
Refer also to
- Applications - Calculus (Wiki)
add a comment |
up vote
3
down vote
Because it is a special number, indeed it is the only base for the exponential function $f(x)=a^x$ such that the derivative is equal to the function itself, that is
$$f'(x)=f(x)$$
Refer also to
- Applications - Calculus (Wiki)
add a comment |
up vote
3
down vote
up vote
3
down vote
Because it is a special number, indeed it is the only base for the exponential function $f(x)=a^x$ such that the derivative is equal to the function itself, that is
$$f'(x)=f(x)$$
Refer also to
- Applications - Calculus (Wiki)
Because it is a special number, indeed it is the only base for the exponential function $f(x)=a^x$ such that the derivative is equal to the function itself, that is
$$f'(x)=f(x)$$
Refer also to
- Applications - Calculus (Wiki)
answered 2 days ago
gimusi
87.4k74393
87.4k74393
add a comment |
add a comment |
6
I'm sure it's because you are studying calculus.
– Lord Shark the Unknown
2 days ago