For loop within GeoGraphics











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2
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I'm trying to plot a map with a list of destinations as Disks.



I first input the cities into a list such as:



destinations = {GeoPosition[New York City],
GeoPosition[Mumbai],
...}


where "New York City" is input using the Ctrl+= method to access interpreter and specify it as a city.



Then I have something summarizing to:



GeoGraphics[{
Black,
Disk[For[i=1, i<Length[destinations]+1,i++,destinations[[i]],1],
...
Disk[city,1],
},
...
]


This outputs a map with my desired projection settings such as background, range, and the single disk that I specified separately like:



Disk[city,1],


I have also tried to put the Disk function inside a for loop like:



For[i=1, i<Length[destinations]+1,i++,Disk[destinations[[i]],1]],


It's not an incorrect indexing of the destinations list either, because



For[i=1, i<Length[destinations]+1,i++,Print[destinations[[i]]]]


outputs the correct amount of cities, whereas



For[i=0, i<Length[destinations],i++,Print[destinations[[i]]]]


outputs a first item of "List" and doesn't print the last city.



Is it possible to use for loops within a GeoGraphics function, or would I be required to add a Disk function line for each item I would like to plot instead of iterating through a list?



Thanks in advance for the help!










share|improve this question




























    up vote
    2
    down vote

    favorite












    I'm trying to plot a map with a list of destinations as Disks.



    I first input the cities into a list such as:



    destinations = {GeoPosition[New York City],
    GeoPosition[Mumbai],
    ...}


    where "New York City" is input using the Ctrl+= method to access interpreter and specify it as a city.



    Then I have something summarizing to:



    GeoGraphics[{
    Black,
    Disk[For[i=1, i<Length[destinations]+1,i++,destinations[[i]],1],
    ...
    Disk[city,1],
    },
    ...
    ]


    This outputs a map with my desired projection settings such as background, range, and the single disk that I specified separately like:



    Disk[city,1],


    I have also tried to put the Disk function inside a for loop like:



    For[i=1, i<Length[destinations]+1,i++,Disk[destinations[[i]],1]],


    It's not an incorrect indexing of the destinations list either, because



    For[i=1, i<Length[destinations]+1,i++,Print[destinations[[i]]]]


    outputs the correct amount of cities, whereas



    For[i=0, i<Length[destinations],i++,Print[destinations[[i]]]]


    outputs a first item of "List" and doesn't print the last city.



    Is it possible to use for loops within a GeoGraphics function, or would I be required to add a Disk function line for each item I would like to plot instead of iterating through a list?



    Thanks in advance for the help!










    share|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I'm trying to plot a map with a list of destinations as Disks.



      I first input the cities into a list such as:



      destinations = {GeoPosition[New York City],
      GeoPosition[Mumbai],
      ...}


      where "New York City" is input using the Ctrl+= method to access interpreter and specify it as a city.



      Then I have something summarizing to:



      GeoGraphics[{
      Black,
      Disk[For[i=1, i<Length[destinations]+1,i++,destinations[[i]],1],
      ...
      Disk[city,1],
      },
      ...
      ]


      This outputs a map with my desired projection settings such as background, range, and the single disk that I specified separately like:



      Disk[city,1],


      I have also tried to put the Disk function inside a for loop like:



      For[i=1, i<Length[destinations]+1,i++,Disk[destinations[[i]],1]],


      It's not an incorrect indexing of the destinations list either, because



      For[i=1, i<Length[destinations]+1,i++,Print[destinations[[i]]]]


      outputs the correct amount of cities, whereas



      For[i=0, i<Length[destinations],i++,Print[destinations[[i]]]]


      outputs a first item of "List" and doesn't print the last city.



      Is it possible to use for loops within a GeoGraphics function, or would I be required to add a Disk function line for each item I would like to plot instead of iterating through a list?



      Thanks in advance for the help!










      share|improve this question















      I'm trying to plot a map with a list of destinations as Disks.



      I first input the cities into a list such as:



      destinations = {GeoPosition[New York City],
      GeoPosition[Mumbai],
      ...}


      where "New York City" is input using the Ctrl+= method to access interpreter and specify it as a city.



      Then I have something summarizing to:



      GeoGraphics[{
      Black,
      Disk[For[i=1, i<Length[destinations]+1,i++,destinations[[i]],1],
      ...
      Disk[city,1],
      },
      ...
      ]


      This outputs a map with my desired projection settings such as background, range, and the single disk that I specified separately like:



      Disk[city,1],


      I have also tried to put the Disk function inside a for loop like:



      For[i=1, i<Length[destinations]+1,i++,Disk[destinations[[i]],1]],


      It's not an incorrect indexing of the destinations list either, because



      For[i=1, i<Length[destinations]+1,i++,Print[destinations[[i]]]]


      outputs the correct amount of cities, whereas



      For[i=0, i<Length[destinations],i++,Print[destinations[[i]]]]


      outputs a first item of "List" and doesn't print the last city.



      Is it possible to use for loops within a GeoGraphics function, or would I be required to add a Disk function line for each item I would like to plot instead of iterating through a list?



      Thanks in advance for the help!







      list-manipulation geographics






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      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 29 at 21:08









      kglr

      175k9197402




      175k9197402










      asked Nov 29 at 20:02









      Reedinationer

      415




      415






















          1 Answer
          1






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          up vote
          5
          down vote













          You don't need For loops.



          Instead you can Map Disk on destinations; that is, use Disk /@ destionations (Disk[#, 5]& /@ destionations if you want a radius of 5 instead of the default radius 1).



          cities = {Entity["City", {"NewYork", "NewYork", "UnitedStates"}], 
          Entity["City", {"London", "GreaterLondon", "UnitedKingdom"}],
          Entity["City", {"Bombay", "Maharashtra", "India"}],
          Entity["City", {"Delhi", "Delhi", "India"}]};
          destinations = GeoPosition /@ cities;

          GeoGraphics[{Black, Disk /@ destinations}]


          enter image description here



          Notes: If you have to use a For loop you can do:



          disks = {}; 
          For[i = 1, i <= Length[destinations], i++, AppendTo[disks, Disk[destinations[[i]]]]];
          GeoGraphics[{Black, disks}]



          same picture




          Alternatively, you can use Table:



          Table[Disk[i], {i, destinations}] == disks



          True




          and if you have to use a For loop inside GeoGraphics



          GeoGraphics[{Black, disks = {}; 
          For[i = 1, i <= Length[destinations], i++,
          AppendTo[disks, Disk[destinations[[i]]]]]; disks}]



          same picture







          share|improve this answer























          • Yes, this works perfectly thank you!
            – Reedinationer
            Nov 29 at 22:07











          Your Answer





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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          5
          down vote













          You don't need For loops.



          Instead you can Map Disk on destinations; that is, use Disk /@ destionations (Disk[#, 5]& /@ destionations if you want a radius of 5 instead of the default radius 1).



          cities = {Entity["City", {"NewYork", "NewYork", "UnitedStates"}], 
          Entity["City", {"London", "GreaterLondon", "UnitedKingdom"}],
          Entity["City", {"Bombay", "Maharashtra", "India"}],
          Entity["City", {"Delhi", "Delhi", "India"}]};
          destinations = GeoPosition /@ cities;

          GeoGraphics[{Black, Disk /@ destinations}]


          enter image description here



          Notes: If you have to use a For loop you can do:



          disks = {}; 
          For[i = 1, i <= Length[destinations], i++, AppendTo[disks, Disk[destinations[[i]]]]];
          GeoGraphics[{Black, disks}]



          same picture




          Alternatively, you can use Table:



          Table[Disk[i], {i, destinations}] == disks



          True




          and if you have to use a For loop inside GeoGraphics



          GeoGraphics[{Black, disks = {}; 
          For[i = 1, i <= Length[destinations], i++,
          AppendTo[disks, Disk[destinations[[i]]]]]; disks}]



          same picture







          share|improve this answer























          • Yes, this works perfectly thank you!
            – Reedinationer
            Nov 29 at 22:07















          up vote
          5
          down vote













          You don't need For loops.



          Instead you can Map Disk on destinations; that is, use Disk /@ destionations (Disk[#, 5]& /@ destionations if you want a radius of 5 instead of the default radius 1).



          cities = {Entity["City", {"NewYork", "NewYork", "UnitedStates"}], 
          Entity["City", {"London", "GreaterLondon", "UnitedKingdom"}],
          Entity["City", {"Bombay", "Maharashtra", "India"}],
          Entity["City", {"Delhi", "Delhi", "India"}]};
          destinations = GeoPosition /@ cities;

          GeoGraphics[{Black, Disk /@ destinations}]


          enter image description here



          Notes: If you have to use a For loop you can do:



          disks = {}; 
          For[i = 1, i <= Length[destinations], i++, AppendTo[disks, Disk[destinations[[i]]]]];
          GeoGraphics[{Black, disks}]



          same picture




          Alternatively, you can use Table:



          Table[Disk[i], {i, destinations}] == disks



          True




          and if you have to use a For loop inside GeoGraphics



          GeoGraphics[{Black, disks = {}; 
          For[i = 1, i <= Length[destinations], i++,
          AppendTo[disks, Disk[destinations[[i]]]]]; disks}]



          same picture







          share|improve this answer























          • Yes, this works perfectly thank you!
            – Reedinationer
            Nov 29 at 22:07













          up vote
          5
          down vote










          up vote
          5
          down vote









          You don't need For loops.



          Instead you can Map Disk on destinations; that is, use Disk /@ destionations (Disk[#, 5]& /@ destionations if you want a radius of 5 instead of the default radius 1).



          cities = {Entity["City", {"NewYork", "NewYork", "UnitedStates"}], 
          Entity["City", {"London", "GreaterLondon", "UnitedKingdom"}],
          Entity["City", {"Bombay", "Maharashtra", "India"}],
          Entity["City", {"Delhi", "Delhi", "India"}]};
          destinations = GeoPosition /@ cities;

          GeoGraphics[{Black, Disk /@ destinations}]


          enter image description here



          Notes: If you have to use a For loop you can do:



          disks = {}; 
          For[i = 1, i <= Length[destinations], i++, AppendTo[disks, Disk[destinations[[i]]]]];
          GeoGraphics[{Black, disks}]



          same picture




          Alternatively, you can use Table:



          Table[Disk[i], {i, destinations}] == disks



          True




          and if you have to use a For loop inside GeoGraphics



          GeoGraphics[{Black, disks = {}; 
          For[i = 1, i <= Length[destinations], i++,
          AppendTo[disks, Disk[destinations[[i]]]]]; disks}]



          same picture







          share|improve this answer














          You don't need For loops.



          Instead you can Map Disk on destinations; that is, use Disk /@ destionations (Disk[#, 5]& /@ destionations if you want a radius of 5 instead of the default radius 1).



          cities = {Entity["City", {"NewYork", "NewYork", "UnitedStates"}], 
          Entity["City", {"London", "GreaterLondon", "UnitedKingdom"}],
          Entity["City", {"Bombay", "Maharashtra", "India"}],
          Entity["City", {"Delhi", "Delhi", "India"}]};
          destinations = GeoPosition /@ cities;

          GeoGraphics[{Black, Disk /@ destinations}]


          enter image description here



          Notes: If you have to use a For loop you can do:



          disks = {}; 
          For[i = 1, i <= Length[destinations], i++, AppendTo[disks, Disk[destinations[[i]]]]];
          GeoGraphics[{Black, disks}]



          same picture




          Alternatively, you can use Table:



          Table[Disk[i], {i, destinations}] == disks



          True




          and if you have to use a For loop inside GeoGraphics



          GeoGraphics[{Black, disks = {}; 
          For[i = 1, i <= Length[destinations], i++,
          AppendTo[disks, Disk[destinations[[i]]]]]; disks}]



          same picture








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 29 at 21:05

























          answered Nov 29 at 20:44









          kglr

          175k9197402




          175k9197402












          • Yes, this works perfectly thank you!
            – Reedinationer
            Nov 29 at 22:07


















          • Yes, this works perfectly thank you!
            – Reedinationer
            Nov 29 at 22:07
















          Yes, this works perfectly thank you!
          – Reedinationer
          Nov 29 at 22:07




          Yes, this works perfectly thank you!
          – Reedinationer
          Nov 29 at 22:07


















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