mod() in PL/SQL returns an unexpected value











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In PL/SQL, the MOD() returns some unexpected values. MOD(23,2) which is expected to return 1 actually returns 0.



MOD(29,2) also returns 0, I think the problem is that it uses the float values.



Is there any alternative to MOD()?










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  • mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
    – William Robertson
    Nov 20 at 0:07












  • @Adarsh, please accept my answer, if it's helpful for your.Thanks.
    – Georgy
    2 days ago















up vote
-1
down vote

favorite












In PL/SQL, the MOD() returns some unexpected values. MOD(23,2) which is expected to return 1 actually returns 0.



MOD(29,2) also returns 0, I think the problem is that it uses the float values.



Is there any alternative to MOD()?










share|improve this question
























  • mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
    – William Robertson
    Nov 20 at 0:07












  • @Adarsh, please accept my answer, if it's helpful for your.Thanks.
    – Georgy
    2 days ago













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











In PL/SQL, the MOD() returns some unexpected values. MOD(23,2) which is expected to return 1 actually returns 0.



MOD(29,2) also returns 0, I think the problem is that it uses the float values.



Is there any alternative to MOD()?










share|improve this question















In PL/SQL, the MOD() returns some unexpected values. MOD(23,2) which is expected to return 1 actually returns 0.



MOD(29,2) also returns 0, I think the problem is that it uses the float values.



Is there any alternative to MOD()?







database plsql oracle11g oracle-sqldeveloper plsqldeveloper






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edited Nov 19 at 17:55









Federico Grandi

2,53021026




2,53021026










asked Nov 19 at 16:12









Adarsh

21




21












  • mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
    – William Robertson
    Nov 20 at 0:07












  • @Adarsh, please accept my answer, if it's helpful for your.Thanks.
    – Georgy
    2 days ago


















  • mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
    – William Robertson
    Nov 20 at 0:07












  • @Adarsh, please accept my answer, if it's helpful for your.Thanks.
    – Georgy
    2 days ago
















mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
– William Robertson
Nov 20 at 0:07






mod(23,2) returns 1 for me in both Oracle SQL and PL/SQL. Is this specific to one of the desktop applications you tagged? A reproducible test case would help a lot.
– William Robertson
Nov 20 at 0:07














@Adarsh, please accept my answer, if it's helpful for your.Thanks.
– Georgy
2 days ago




@Adarsh, please accept my answer, if it's helpful for your.Thanks.
– Georgy
2 days ago












1 Answer
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0
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Alternative ?



Mod is:



x - y * floor(x/y)


Good to know:




The function to 'round up' is CEIL, but it generates an integer.



The function to 'round down' is FLOOR, but it too generates an integer.



The function to 'round nearest' is ROUND, and it allows you to specify a number of decimal places (dp).



Note that CEIL rounds to an integer; to round to 2 dp, you'd have to multiply by 100, use CEIL, and divide by 100.







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    1 Answer
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    1 Answer
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    active

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    up vote
    0
    down vote













    Alternative ?



    Mod is:



    x - y * floor(x/y)


    Good to know:




    The function to 'round up' is CEIL, but it generates an integer.



    The function to 'round down' is FLOOR, but it too generates an integer.



    The function to 'round nearest' is ROUND, and it allows you to specify a number of decimal places (dp).



    Note that CEIL rounds to an integer; to round to 2 dp, you'd have to multiply by 100, use CEIL, and divide by 100.







    share|improve this answer

























      up vote
      0
      down vote













      Alternative ?



      Mod is:



      x - y * floor(x/y)


      Good to know:




      The function to 'round up' is CEIL, but it generates an integer.



      The function to 'round down' is FLOOR, but it too generates an integer.



      The function to 'round nearest' is ROUND, and it allows you to specify a number of decimal places (dp).



      Note that CEIL rounds to an integer; to round to 2 dp, you'd have to multiply by 100, use CEIL, and divide by 100.







      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        Alternative ?



        Mod is:



        x - y * floor(x/y)


        Good to know:




        The function to 'round up' is CEIL, but it generates an integer.



        The function to 'round down' is FLOOR, but it too generates an integer.



        The function to 'round nearest' is ROUND, and it allows you to specify a number of decimal places (dp).



        Note that CEIL rounds to an integer; to round to 2 dp, you'd have to multiply by 100, use CEIL, and divide by 100.







        share|improve this answer












        Alternative ?



        Mod is:



        x - y * floor(x/y)


        Good to know:




        The function to 'round up' is CEIL, but it generates an integer.



        The function to 'round down' is FLOOR, but it too generates an integer.



        The function to 'round nearest' is ROUND, and it allows you to specify a number of decimal places (dp).



        Note that CEIL rounds to an integer; to round to 2 dp, you'd have to multiply by 100, use CEIL, and divide by 100.








        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 1:00









        Georgy

        647




        647






























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