2D array size specified by the user
So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:
Enter a number between 1 and 12:
3
The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
using namespace std;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;
void displayOverview ();
void playOrQuit();
void promptNumber();
void fillUserArray(char grid);
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}
void fillUserGrid (char grid){
for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}
void outputUserGrid(char grid){
for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}
c++ arrays multidimensional-array
add a comment |
So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:
Enter a number between 1 and 12:
3
The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
using namespace std;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;
void displayOverview ();
void playOrQuit();
void promptNumber();
void fillUserArray(char grid);
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}
void fillUserGrid (char grid){
for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}
void outputUserGrid(char grid){
for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}
c++ arrays multidimensional-array
1
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
@KenY-N I don't agree because OP didn't explicitly ask fornew
.
– Swordfish
Nov 21 '18 at 4:59
1
If you want an array-like thingy that you can resize, please usestd::vector<char> grid;
, set its size torows * columns
and access it usinggrid[y * columns + x];
. Thanks.
– Swordfish
Nov 21 '18 at 5:01
@Swordfish and neither did they ask for a 1Dstd::vector
- they havegrid[row][col]
(although that function's parameter is wrong...).
– Ken Y-N
Nov 21 '18 at 5:03
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18
add a comment |
So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:
Enter a number between 1 and 12:
3
The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
using namespace std;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;
void displayOverview ();
void playOrQuit();
void promptNumber();
void fillUserArray(char grid);
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}
void fillUserGrid (char grid){
for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}
void outputUserGrid(char grid){
for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}
c++ arrays multidimensional-array
So, I have a code when I prompt the user to enter a number, I want the size of the 2D array to be changed according to what the user entered, for example:
Enter a number between 1 and 12:
3
The 2D array then will change according to that size to become a 3x3 2D array, I hope I am as clear as I could be, I would really appreciate it if someone can please guide me to a solution, Thank you everyone !!
#include <iostream>
#include <cstdio>
#include <cmath>
#include <cstdlib>
using namespace std;
double Atemp = 0;
double Utemp = 0;
double Working = 0;
double Total = 0;
char Answer = 'x';
int Umain;
void displayOverview ();
void playOrQuit();
void promptNumber();
void fillUserArray(char grid);
int main(){
displayOverview();
playOrQuit();
promptNumber();
return 0;
}
void displayOverview(){
}
void playOrQuit(){
string playOrNot;
cout << "If you want to play please press 'p' for play, and 'q' if you wish to quitn";
cin >> playOrNot;
if(playOrNot == "p"){
cout << "Awesome, lets start playing !!! n";
}if(playOrNot == "q"){
cout << "Alright then, see you soon !!n";
exit(0);
}if(playOrNot != "p" && playOrNot != "q"){
cout << "Invalid entry !!n";
exit(0);
}
}
void promptNumber(){
do{
cout << "Please Enter numbers between 1 and 12: ";
cin >> Umain;
if(Umain <= 12){
for (Utemp = Umain; Utemp > 0; Utemp--){
cout << "Please enter a number: ";
cin >> Atemp;
}
}else{
cout << "Not within limit :(n";
}
}while (Answer == 'y');
}
void fillUserGrid (char grid){
for( int row = 0; row < Umain; row++ ) {
for(int col = 0; col < Umain; col++){
grid[row][col] = userInput.at( row * Umain + col );
}
}
}
void outputUserGrid(char grid){
for (int row = 0; row < Umain; row++){
for(int col = 0; col < Umain; col++){
cout << grid[row][col]<<" ";
}
cout << endl;
}
}
c++ arrays multidimensional-array
c++ arrays multidimensional-array
edited Nov 21 '18 at 4:49
DanielAA9
asked Nov 21 '18 at 4:40
DanielAA9DanielAA9
375
375
1
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
@KenY-N I don't agree because OP didn't explicitly ask fornew
.
– Swordfish
Nov 21 '18 at 4:59
1
If you want an array-like thingy that you can resize, please usestd::vector<char> grid;
, set its size torows * columns
and access it usinggrid[y * columns + x];
. Thanks.
– Swordfish
Nov 21 '18 at 5:01
@Swordfish and neither did they ask for a 1Dstd::vector
- they havegrid[row][col]
(although that function's parameter is wrong...).
– Ken Y-N
Nov 21 '18 at 5:03
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18
add a comment |
1
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
@KenY-N I don't agree because OP didn't explicitly ask fornew
.
– Swordfish
Nov 21 '18 at 4:59
1
If you want an array-like thingy that you can resize, please usestd::vector<char> grid;
, set its size torows * columns
and access it usinggrid[y * columns + x];
. Thanks.
– Swordfish
Nov 21 '18 at 5:01
@Swordfish and neither did they ask for a 1Dstd::vector
- they havegrid[row][col]
(although that function's parameter is wrong...).
– Ken Y-N
Nov 21 '18 at 5:03
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18
1
1
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
@KenY-N I don't agree because OP didn't explicitly ask for
new
.– Swordfish
Nov 21 '18 at 4:59
@KenY-N I don't agree because OP didn't explicitly ask for
new
.– Swordfish
Nov 21 '18 at 4:59
1
1
If you want an array-like thingy that you can resize, please use
std::vector<char> grid;
, set its size to rows * columns
and access it using grid[y * columns + x];
. Thanks.– Swordfish
Nov 21 '18 at 5:01
If you want an array-like thingy that you can resize, please use
std::vector<char> grid;
, set its size to rows * columns
and access it using grid[y * columns + x];
. Thanks.– Swordfish
Nov 21 '18 at 5:01
@Swordfish and neither did they ask for a 1D
std::vector
- they have grid[row][col]
(although that function's parameter is wrong...).– Ken Y-N
Nov 21 '18 at 5:03
@Swordfish and neither did they ask for a 1D
std::vector
- they have grid[row][col]
(although that function's parameter is wrong...).– Ken Y-N
Nov 21 '18 at 5:03
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18
add a comment |
1 Answer
1
active
oldest
votes
It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.
The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
add a comment |
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1 Answer
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oldest
votes
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oldest
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active
oldest
votes
It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.
The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
add a comment |
It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.
The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
add a comment |
It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.
The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.
It's quite legitimate to just use a 12x12 array for your game. When the user wants to play on a smaller grid, you can just use part of it.
The only times this might be an issue are if you're running into L1/L2 cache issues for performance-critical programs, or if you're storing lots of these grids and need to reduce memory use. I would be surprised if either of these scenarios applies to you.
answered Nov 21 '18 at 5:08
paddypaddy
42.7k53176
42.7k53176
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
add a comment |
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
I see, thank you for helping me out
– DanielAA9
Nov 21 '18 at 5:17
add a comment |
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1
Possible duplicate of How do I declare a 2d array in C++ using new?
– Ken Y-N
Nov 21 '18 at 4:47
@KenY-N I don't agree because OP didn't explicitly ask for
new
.– Swordfish
Nov 21 '18 at 4:59
1
If you want an array-like thingy that you can resize, please use
std::vector<char> grid;
, set its size torows * columns
and access it usinggrid[y * columns + x];
. Thanks.– Swordfish
Nov 21 '18 at 5:01
@Swordfish and neither did they ask for a 1D
std::vector
- they havegrid[row][col]
(although that function's parameter is wrong...).– Ken Y-N
Nov 21 '18 at 5:03
This feels like XY Problem. I've answered accordingly. If it turns out you absolutely need a data structure that is the exact size you need, then the duplicate question mentioned earlier provides solutions... But scroll down to some of the lesser-voted answers to find the good solutions.
– paddy
Nov 21 '18 at 5:18