How to count the files and directories by excluding dot folders in command prompt?












-2















I am using dir /s to view all the files and directives in my folder. But this also displaying . directories. I am almost having more than 100 top level and inside folders. When I execute above command the result is not accurate.



How to get the exact files and directories count using window command prompt?










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  • So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

    – LotPings
    Dec 25 '18 at 21:09
















-2















I am using dir /s to view all the files and directives in my folder. But this also displaying . directories. I am almost having more than 100 top level and inside folders. When I execute above command the result is not accurate.



How to get the exact files and directories count using window command prompt?










share|improve this question























  • So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

    – LotPings
    Dec 25 '18 at 21:09














-2












-2








-2








I am using dir /s to view all the files and directives in my folder. But this also displaying . directories. I am almost having more than 100 top level and inside folders. When I execute above command the result is not accurate.



How to get the exact files and directories count using window command prompt?










share|improve this question














I am using dir /s to view all the files and directives in my folder. But this also displaying . directories. I am almost having more than 100 top level and inside folders. When I execute above command the result is not accurate.



How to get the exact files and directories count using window command prompt?







windows command-line






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Dec 25 '18 at 20:26









MihirMihir

972




972













  • So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

    – LotPings
    Dec 25 '18 at 21:09



















  • So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

    – LotPings
    Dec 25 '18 at 21:09

















So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

– LotPings
Dec 25 '18 at 21:09





So just because YOU want some directories not counted the result is not accurate? You will have to set up a batch/script to count the way you want. There are examples for that here Super User or on Stack Overflow.

– LotPings
Dec 25 '18 at 21:09










1 Answer
1






active

oldest

votes


















1














Count files recursively:



set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount


Count directories recursively:



set dirsCount=0 & (for /D /R %f in (*) do @(set /a dirsCount+=1 > nul)) & set dirscount


Resource: FOR loop commands.



Edit: if you care about hidden files, compare the following results:



d:bat> set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-h-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /ah-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=10

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3105


Apply to directories (mutatis mutandis) using dir switches /aD, /aHD and /a-HD sequentially.






share|improve this answer


























  • This will exclude hidden files and directories also?

    – Mihir
    Dec 28 '18 at 10:35











  • @Mihir answer updated.

    – JosefZ
    Dec 28 '18 at 11:09











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














Count files recursively:



set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount


Count directories recursively:



set dirsCount=0 & (for /D /R %f in (*) do @(set /a dirsCount+=1 > nul)) & set dirscount


Resource: FOR loop commands.



Edit: if you care about hidden files, compare the following results:



d:bat> set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-h-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /ah-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=10

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3105


Apply to directories (mutatis mutandis) using dir switches /aD, /aHD and /a-HD sequentially.






share|improve this answer


























  • This will exclude hidden files and directories also?

    – Mihir
    Dec 28 '18 at 10:35











  • @Mihir answer updated.

    – JosefZ
    Dec 28 '18 at 11:09
















1














Count files recursively:



set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount


Count directories recursively:



set dirsCount=0 & (for /D /R %f in (*) do @(set /a dirsCount+=1 > nul)) & set dirscount


Resource: FOR loop commands.



Edit: if you care about hidden files, compare the following results:



d:bat> set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-h-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /ah-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=10

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3105


Apply to directories (mutatis mutandis) using dir switches /aD, /aHD and /a-HD sequentially.






share|improve this answer


























  • This will exclude hidden files and directories also?

    – Mihir
    Dec 28 '18 at 10:35











  • @Mihir answer updated.

    – JosefZ
    Dec 28 '18 at 11:09














1












1








1







Count files recursively:



set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount


Count directories recursively:



set dirsCount=0 & (for /D /R %f in (*) do @(set /a dirsCount+=1 > nul)) & set dirscount


Resource: FOR loop commands.



Edit: if you care about hidden files, compare the following results:



d:bat> set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-h-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /ah-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=10

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3105


Apply to directories (mutatis mutandis) using dir switches /aD, /aHD and /a-HD sequentially.






share|improve this answer















Count files recursively:



set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount


Count directories recursively:



set dirsCount=0 & (for /D /R %f in (*) do @(set /a dirsCount+=1 > nul)) & set dirscount


Resource: FOR loop commands.



Edit: if you care about hidden files, compare the following results:



d:bat> set filesCount=0 & (for /R %f in (*) do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-h-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3095

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /ah-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=10

d:bat> set filesCount=0 & (for /F "delims=" %f in ('dir /b /s /a-d') do @(set /a filesCount+=1 > nul)) & set filescount
filesCount=3105


Apply to directories (mutatis mutandis) using dir switches /aD, /aHD and /a-HD sequentially.







share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 28 '18 at 11:09

























answered Dec 25 '18 at 22:16









JosefZJosefZ

7,25041544




7,25041544













  • This will exclude hidden files and directories also?

    – Mihir
    Dec 28 '18 at 10:35











  • @Mihir answer updated.

    – JosefZ
    Dec 28 '18 at 11:09



















  • This will exclude hidden files and directories also?

    – Mihir
    Dec 28 '18 at 10:35











  • @Mihir answer updated.

    – JosefZ
    Dec 28 '18 at 11:09

















This will exclude hidden files and directories also?

– Mihir
Dec 28 '18 at 10:35





This will exclude hidden files and directories also?

– Mihir
Dec 28 '18 at 10:35













@Mihir answer updated.

– JosefZ
Dec 28 '18 at 11:09





@Mihir answer updated.

– JosefZ
Dec 28 '18 at 11:09


















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