Function for SortBy
2
Let's say I have the following list
list = {{-1, 0, 0, 1}, {-1, 0, 1, 0}, {-1, 1, 0, 0}, {0, -1, 0, 1},
{0, -1, 1, 0}, {0, 0, -1, 1}, {0, 0, 1, -1}, {0, 1, -1, 0},
{0, 1, 0, -1}, {1, -1, 0, 0}, {1, 0, -1, 0}, {1, 0, 0, -1}}
What sort function (sfunc) used in SortBy [list, sfunc] can give me slist?
slist = {{0, 0, 1, -1}, {0, 0, -1, 1}, {0, -1, 0, 1}, {-1, 0, 0, 1},
{0, 1, 0, -1}, {0, 1, -1, 0}, {0, -1, 1, 0}, {-1, 0, 1, 0},
{1, 0, 0, -1}, {1, 0, -1, 0}, {1, -1, 0, 0}, {-1, 1, 0, 0}}
Few examples of sorted data
slist1 = {{0, 0, 1, -2}, {0, 0, -2, 1}, {0, -2, 0, 1}, {-2, 0, 0, 1}, {0, 1, 0, -2}, {0, 1, -2, 0}, {0, -2, 1, 0}, {-2, 0, 1, 0}, {1, 0, 0, -2}, {1, 0, -2, 0}, {1, -2, 0, 0}, {-2, 1, 0, 0}, {0, 1, -1, -1}, {0, -1, 1, -1}, {0, -1, -1, 1}, {-1, 0, 1, -1}, {-1, 0, -1, 1},{-1, -1, 0, 1}, {1, 0, -1, -1}, {1, -1, 0, -1}, {1, -1, -1, 0}, {-1, 1, 0, -1}, {-1, 1, -1, 0}, {-1, -1, 1, 0}}
slist2 = {{0, 0, 2, -2}, {0, 0, -2, 2}, {0, -2, 0, 2}, {-2, 0, 0, 2}, {0, 1, 1, -2}, {0, 1, -2, 1}, {0, -2, 1, 1}, {-2, 0, 1, 1}, {0, 2, 0, -2}, {0, 2, -2, 0}, {0, -2, 2, 0}, {-2, 0, 2, 0}, {1, 0, 1, -2}, {1, 0, -2, 1}, {1, -2, 0, 1}, {-2, 1, 0, 1}, {1, 1, 0, -2}, {1, 1, -2, 0}, {1, -2, 1, 0}, {-2, 1, 1, 0}, {2, 0, 0, -2}, {2, 0, -2, 0}, {2, -2, 0, 0}, {-2, 2, 0, 0}, {0, 2, -1, -1}, {0, -1, 2, -1}, {0, -1, -1, 2}, {-1, 0, 2, -1}, {-1, 0, -1, 2}, {-1, -1, 0, 2}, {1, 1, -1, -1}, {1, -1, 1, -1}, {1, -1, -1, 1}, {-1, 1, 1, -1}, {-1, 1, -1, 1}, {-1, -1, 1, 1}, {2, 0, -1, -1}, {2, -1, 0, -1}, {2, -1, -1, 0}, {-1, 2, 0, -1}, {-1, 2, -1, 0}, {-1, -1, 2, 0}}
list-manipulation sorting
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
add a comment |
2
Let's say I have the following list
list = {{-1, 0, 0, 1}, {-1, 0, 1, 0}, {-1, 1, 0, 0}, {0, -1, 0, 1},
{0, -1, 1, 0}, {0, 0, -1, 1}, {0, 0, 1, -1}, {0, 1, -1, 0},
{0, 1, 0, -1}, {1, -1, 0, 0}, {1, 0, -1, 0}, {1, 0, 0, -1}}
What sort function (sfunc) used in SortBy [list, sfunc] can give me slist?
slist = {{0, 0, 1, -1}, {0, 0, -1, 1}, {0, -1, 0, 1}, {-1, 0, 0, 1},
{0, 1, 0, -1}, {0, 1, -1, 0}, {0, -1, 1, 0}, {-1, 0, 1, 0},
{1, 0, 0, -1}, {1, 0, -1, 0}, {1, -1, 0, 0}, {-1, 1, 0, 0}}
Few examples of sorted data
slist1 = {{0, 0, 1, -2}, {0, 0, -2, 1}, {0, -2, 0, 1}, {-2, 0, 0, 1}, {0, 1, 0, -2}, {0, 1, -2, 0}, {0, -2, 1, 0}, {-2, 0, 1, 0}, {1, 0, 0, -2}, {1, 0, -2, 0}, {1, -2, 0, 0}, {-2, 1, 0, 0}, {0, 1, -1, -1}, {0, -1, 1, -1}, {0, -1, -1, 1}, {-1, 0, 1, -1}, {-1, 0, -1, 1},{-1, -1, 0, 1}, {1, 0, -1, -1}, {1, -1, 0, -1}, {1, -1, -1, 0}, {-1, 1, 0, -1}, {-1, 1, -1, 0}, {-1, -1, 1, 0}}
slist2 = {{0, 0, 2, -2}, {0, 0, -2, 2}, {0, -2, 0, 2}, {-2, 0, 0, 2}, {0, 1, 1, -2}, {0, 1, -2, 1}, {0, -2, 1, 1}, {-2, 0, 1, 1}, {0, 2, 0, -2}, {0, 2, -2, 0}, {0, -2, 2, 0}, {-2, 0, 2, 0}, {1, 0, 1, -2}, {1, 0, -2, 1}, {1, -2, 0, 1}, {-2, 1, 0, 1}, {1, 1, 0, -2}, {1, 1, -2, 0}, {1, -2, 1, 0}, {-2, 1, 1, 0}, {2, 0, 0, -2}, {2, 0, -2, 0}, {2, -2, 0, 0}, {-2, 2, 0, 0}, {0, 2, -1, -1}, {0, -1, 2, -1}, {0, -1, -1, 2}, {-1, 0, 2, -1}, {-1, 0, -1, 2}, {-1, -1, 0, 2}, {1, 1, -1, -1}, {1, -1, 1, -1}, {1, -1, -1, 1}, {-1, 1, 1, -1}, {-1, 1, -1, 1}, {-1, -1, 1, 1}, {2, 0, -1, -1}, {2, -1, 0, -1}, {2, -1, -1, 0}, {-1, 2, 0, -1}, {-1, 2, -1, 0}, {-1, -1, 2, 0}}
list-manipulation sorting
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
4
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
2
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
1
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago
add a comment |
2
2
2
Let's say I have the following list
list = {{-1, 0, 0, 1}, {-1, 0, 1, 0}, {-1, 1, 0, 0}, {0, -1, 0, 1},
{0, -1, 1, 0}, {0, 0, -1, 1}, {0, 0, 1, -1}, {0, 1, -1, 0},
{0, 1, 0, -1}, {1, -1, 0, 0}, {1, 0, -1, 0}, {1, 0, 0, -1}}
What sort function (sfunc) used in SortBy [list, sfunc] can give me slist?
slist = {{0, 0, 1, -1}, {0, 0, -1, 1}, {0, -1, 0, 1}, {-1, 0, 0, 1},
{0, 1, 0, -1}, {0, 1, -1, 0}, {0, -1, 1, 0}, {-1, 0, 1, 0},
{1, 0, 0, -1}, {1, 0, -1, 0}, {1, -1, 0, 0}, {-1, 1, 0, 0}}
Few examples of sorted data
slist1 = {{0, 0, 1, -2}, {0, 0, -2, 1}, {0, -2, 0, 1}, {-2, 0, 0, 1}, {0, 1, 0, -2}, {0, 1, -2, 0}, {0, -2, 1, 0}, {-2, 0, 1, 0}, {1, 0, 0, -2}, {1, 0, -2, 0}, {1, -2, 0, 0}, {-2, 1, 0, 0}, {0, 1, -1, -1}, {0, -1, 1, -1}, {0, -1, -1, 1}, {-1, 0, 1, -1}, {-1, 0, -1, 1},{-1, -1, 0, 1}, {1, 0, -1, -1}, {1, -1, 0, -1}, {1, -1, -1, 0}, {-1, 1, 0, -1}, {-1, 1, -1, 0}, {-1, -1, 1, 0}}
slist2 = {{0, 0, 2, -2}, {0, 0, -2, 2}, {0, -2, 0, 2}, {-2, 0, 0, 2}, {0, 1, 1, -2}, {0, 1, -2, 1}, {0, -2, 1, 1}, {-2, 0, 1, 1}, {0, 2, 0, -2}, {0, 2, -2, 0}, {0, -2, 2, 0}, {-2, 0, 2, 0}, {1, 0, 1, -2}, {1, 0, -2, 1}, {1, -2, 0, 1}, {-2, 1, 0, 1}, {1, 1, 0, -2}, {1, 1, -2, 0}, {1, -2, 1, 0}, {-2, 1, 1, 0}, {2, 0, 0, -2}, {2, 0, -2, 0}, {2, -2, 0, 0}, {-2, 2, 0, 0}, {0, 2, -1, -1}, {0, -1, 2, -1}, {0, -1, -1, 2}, {-1, 0, 2, -1}, {-1, 0, -1, 2}, {-1, -1, 0, 2}, {1, 1, -1, -1}, {1, -1, 1, -1}, {1, -1, -1, 1}, {-1, 1, 1, -1}, {-1, 1, -1, 1}, {-1, -1, 1, 1}, {2, 0, -1, -1}, {2, -1, 0, -1}, {2, -1, -1, 0}, {-1, 2, 0, -1}, {-1, 2, -1, 0}, {-1, -1, 2, 0}}
list-manipulation sorting
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
Let's say I have the following list
list = {{-1, 0, 0, 1}, {-1, 0, 1, 0}, {-1, 1, 0, 0}, {0, -1, 0, 1},
{0, -1, 1, 0}, {0, 0, -1, 1}, {0, 0, 1, -1}, {0, 1, -1, 0},
{0, 1, 0, -1}, {1, -1, 0, 0}, {1, 0, -1, 0}, {1, 0, 0, -1}}
What sort function (sfunc) used in SortBy [list, sfunc] can give me slist?
slist = {{0, 0, 1, -1}, {0, 0, -1, 1}, {0, -1, 0, 1}, {-1, 0, 0, 1},
{0, 1, 0, -1}, {0, 1, -1, 0}, {0, -1, 1, 0}, {-1, 0, 1, 0},
{1, 0, 0, -1}, {1, 0, -1, 0}, {1, -1, 0, 0}, {-1, 1, 0, 0}}
Few examples of sorted data
slist1 = {{0, 0, 1, -2}, {0, 0, -2, 1}, {0, -2, 0, 1}, {-2, 0, 0, 1}, {0, 1, 0, -2}, {0, 1, -2, 0}, {0, -2, 1, 0}, {-2, 0, 1, 0}, {1, 0, 0, -2}, {1, 0, -2, 0}, {1, -2, 0, 0}, {-2, 1, 0, 0}, {0, 1, -1, -1}, {0, -1, 1, -1}, {0, -1, -1, 1}, {-1, 0, 1, -1}, {-1, 0, -1, 1},{-1, -1, 0, 1}, {1, 0, -1, -1}, {1, -1, 0, -1}, {1, -1, -1, 0}, {-1, 1, 0, -1}, {-1, 1, -1, 0}, {-1, -1, 1, 0}}
slist2 = {{0, 0, 2, -2}, {0, 0, -2, 2}, {0, -2, 0, 2}, {-2, 0, 0, 2}, {0, 1, 1, -2}, {0, 1, -2, 1}, {0, -2, 1, 1}, {-2, 0, 1, 1}, {0, 2, 0, -2}, {0, 2, -2, 0}, {0, -2, 2, 0}, {-2, 0, 2, 0}, {1, 0, 1, -2}, {1, 0, -2, 1}, {1, -2, 0, 1}, {-2, 1, 0, 1}, {1, 1, 0, -2}, {1, 1, -2, 0}, {1, -2, 1, 0}, {-2, 1, 1, 0}, {2, 0, 0, -2}, {2, 0, -2, 0}, {2, -2, 0, 0}, {-2, 2, 0, 0}, {0, 2, -1, -1}, {0, -1, 2, -1}, {0, -1, -1, 2}, {-1, 0, 2, -1}, {-1, 0, -1, 2}, {-1, -1, 0, 2}, {1, 1, -1, -1}, {1, -1, 1, -1}, {1, -1, -1, 1}, {-1, 1, 1, -1}, {-1, 1, -1, 1}, {-1, -1, 1, 1}, {2, 0, -1, -1}, {2, -1, 0, -1}, {2, -1, -1, 0}, {-1, 2, 0, -1}, {-1, 2, -1, 0}, {-1, -1, 2, 0}}
list-manipulation sorting
list-manipulation sorting
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
edited Jan 4 at 20:06
Hubble07
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
asked Jan 4 at 18:59
Hubble07Hubble07
2,916721
2,916721
4
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
2
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
1
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago
add a comment |
4
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
2
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
1
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago
4
4
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
2
2
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
1
1
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago
add a comment |
1 Answer
1
active
oldest
votes
8
EDITED TO ADD A SORT CRITERION
For the data sets, you are sorting on
- the number of negative numbers first, then
- the subset of just the nonnegative elements (using canonical ordering for lists), then
- the set gained when you replace negative terms with a '1' and nonnegative with '0'
The subset of just the negative elements (using canonical ordering)
funkySort[list_]:= SortBy[list,{
Count[#, _?Negative] &,
Select[#, NonNegative] &,
Negative,
Select[#, Negative] &
}]
slist == funkySort[slist[[RandomPermutation[Length[slist]]]]]
slist1 == funkySort[slist1[[RandomPermutation[Length[slist1]]]]]
slist2 == funkySort[slist2[[RandomPermutation[Length[slist2]]]]]
True
True
True
edited yesterday
J. M. is computer-less♦
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
Butslist != funkySort[list]. Are you sure this works. It doesn't seem to work on my system. Do you get really getslist1andslist2when your function is applied to any random ordering of those lists.
– Hubble07
2 days ago
Oops, copied over the wrongfunkySort[ ]from my notebook. Fixed it...
– MikeY
2 days ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
8
EDITED TO ADD A SORT CRITERION
For the data sets, you are sorting on
- the number of negative numbers first, then
- the subset of just the nonnegative elements (using canonical ordering for lists), then
- the set gained when you replace negative terms with a '1' and nonnegative with '0'
The subset of just the negative elements (using canonical ordering)
funkySort[list_]:= SortBy[list,{
Count[#, _?Negative] &,
Select[#, NonNegative] &,
Negative,
Select[#, Negative] &
}]
slist == funkySort[slist[[RandomPermutation[Length[slist]]]]]
slist1 == funkySort[slist1[[RandomPermutation[Length[slist1]]]]]
slist2 == funkySort[slist2[[RandomPermutation[Length[slist2]]]]]
True
True
True
edited yesterday
J. M. is computer-less♦
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
Butslist != funkySort[list]. Are you sure this works. It doesn't seem to work on my system. Do you get really getslist1andslist2when your function is applied to any random ordering of those lists.
– Hubble07
2 days ago
Oops, copied over the wrongfunkySort[ ]from my notebook. Fixed it...
– MikeY
2 days ago
add a comment |
8
EDITED TO ADD A SORT CRITERION
For the data sets, you are sorting on
- the number of negative numbers first, then
- the subset of just the nonnegative elements (using canonical ordering for lists), then
- the set gained when you replace negative terms with a '1' and nonnegative with '0'
The subset of just the negative elements (using canonical ordering)
funkySort[list_]:= SortBy[list,{
Count[#, _?Negative] &,
Select[#, NonNegative] &,
Negative,
Select[#, Negative] &
}]
slist == funkySort[slist[[RandomPermutation[Length[slist]]]]]
slist1 == funkySort[slist1[[RandomPermutation[Length[slist1]]]]]
slist2 == funkySort[slist2[[RandomPermutation[Length[slist2]]]]]
True
True
True
edited yesterday
J. M. is computer-less♦
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
Butslist != funkySort[list]. Are you sure this works. It doesn't seem to work on my system. Do you get really getslist1andslist2when your function is applied to any random ordering of those lists.
– Hubble07
2 days ago
Oops, copied over the wrongfunkySort[ ]from my notebook. Fixed it...
– MikeY
2 days ago
add a comment |
8
8
8
EDITED TO ADD A SORT CRITERION
For the data sets, you are sorting on
- the number of negative numbers first, then
- the subset of just the nonnegative elements (using canonical ordering for lists), then
- the set gained when you replace negative terms with a '1' and nonnegative with '0'
The subset of just the negative elements (using canonical ordering)
funkySort[list_]:= SortBy[list,{
Count[#, _?Negative] &,
Select[#, NonNegative] &,
Negative,
Select[#, Negative] &
}]
slist == funkySort[slist[[RandomPermutation[Length[slist]]]]]
slist1 == funkySort[slist1[[RandomPermutation[Length[slist1]]]]]
slist2 == funkySort[slist2[[RandomPermutation[Length[slist2]]]]]
True
True
True
edited yesterday
J. M. is computer-less♦
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
EDITED TO ADD A SORT CRITERION
For the data sets, you are sorting on
- the number of negative numbers first, then
- the subset of just the nonnegative elements (using canonical ordering for lists), then
- the set gained when you replace negative terms with a '1' and nonnegative with '0'
The subset of just the negative elements (using canonical ordering)
funkySort[list_]:= SortBy[list,{
Count[#, _?Negative] &,
Select[#, NonNegative] &,
Negative,
Select[#, Negative] &
}]
slist == funkySort[slist[[RandomPermutation[Length[slist]]]]]
slist1 == funkySort[slist1[[RandomPermutation[Length[slist1]]]]]
slist2 == funkySort[slist2[[RandomPermutation[Length[slist2]]]]]
True
True
True
edited yesterday
J. M. is computer-less♦
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
edited yesterday
J. M. is computer-less♦
96.2k10300460
edited yesterday
J. M. is computer-less♦
96.2k10300460
edited yesterday
J. M. is computer-less♦
96.2k10300460
96.2k10300460
answered Jan 4 at 19:52
MikeYMikeY
2,317411
answered Jan 4 at 19:52
MikeYMikeY
2,317411
answered Jan 4 at 19:52
MikeYMikeY
2,317411
2,317411
Butslist != funkySort[list]. Are you sure this works. It doesn't seem to work on my system. Do you get really getslist1andslist2when your function is applied to any random ordering of those lists.
– Hubble07
2 days ago
Oops, copied over the wrongfunkySort[ ]from my notebook. Fixed it...
– MikeY
2 days ago
add a comment |
Butslist != funkySort[list]. Are you sure this works. It doesn't seem to work on my system. Do you get really getslist1andslist2when your function is applied to any random ordering of those lists.
– Hubble07
2 days ago
Oops, copied over the wrongfunkySort[ ]from my notebook. Fixed it...
– MikeY
2 days ago
But
slist != funkySort[list] . Are you sure this works. It doesn't seem to work on my system. Do you get really get slist1 and slist2 when your function is applied to any random ordering of those lists.– Hubble07
2 days ago
But
slist != funkySort[list] . Are you sure this works. It doesn't seem to work on my system. Do you get really get slist1 and slist2 when your function is applied to any random ordering of those lists.– Hubble07
2 days ago
Oops, copied over the wrong
funkySort[ ] from my notebook. Fixed it...– MikeY
2 days ago
Oops, copied over the wrong
funkySort[ ] from my notebook. Fixed it...– MikeY
2 days ago
add a comment |
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4
Explain the core idea behind your sorted list. It certainly isn't clear what you're seeking.
– David G. Stork
Jan 4 at 19:01
2
Can you give some examples with more complicated data?
– MikeY
Jan 4 at 19:33
1
@MikeY I have added 2 more sorted sets.
– Hubble07
Jan 4 at 20:10
So if you sort your data like this, it can probably be counted and therefore indexed in closed form.
– MikeY
2 days ago
@MikeY Yes I have decided to use this sorting. I have edited by bounty question. If you have time then you could answer that, then I can gladly give you the bounty.
– Hubble07
2 days ago