How to access observedAttributes on Web Components
So in Web Components you can use the attributeChangedCallback once ou have specified attributes to observe using static get observedAttributes() { return ['myAttribute']; }.
How can I list/access the observed attributes from within my sub class?
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.observedAttributes); // <= undefined
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
Is this somehow possible? Is there a getter for the observed attributes?
I think the difficulty here lies in getting the observed attributes of the parent class. Because if it was on the same class, you could just Foo.observedAttributes as @javimovi mentioned.
I added a jsbin to play with: https://jsbin.com/sonekedavo/edit?js,console
Thank you!
javascript html ecmascript-6 web-component es6-class
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
add a comment |
So in Web Components you can use the attributeChangedCallback once ou have specified attributes to observe using static get observedAttributes() { return ['myAttribute']; }.
How can I list/access the observed attributes from within my sub class?
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.observedAttributes); // <= undefined
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
Is this somehow possible? Is there a getter for the observed attributes?
I think the difficulty here lies in getting the observed attributes of the parent class. Because if it was on the same class, you could just Foo.observedAttributes as @javimovi mentioned.
I added a jsbin to play with: https://jsbin.com/sonekedavo/edit?js,console
Thank you!
javascript html ecmascript-6 web-component es6-class
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
1
Tryconsole.log(Foo.observedAttributes);
– javimovi
Nov 21 '18 at 8:58
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
1
This works ?console.log(Bar.observedAttributes);
– javimovi
Nov 21 '18 at 9:28
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44
add a comment |
So in Web Components you can use the attributeChangedCallback once ou have specified attributes to observe using static get observedAttributes() { return ['myAttribute']; }.
How can I list/access the observed attributes from within my sub class?
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.observedAttributes); // <= undefined
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
Is this somehow possible? Is there a getter for the observed attributes?
I think the difficulty here lies in getting the observed attributes of the parent class. Because if it was on the same class, you could just Foo.observedAttributes as @javimovi mentioned.
I added a jsbin to play with: https://jsbin.com/sonekedavo/edit?js,console
Thank you!
javascript html ecmascript-6 web-component es6-class
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
So in Web Components you can use the attributeChangedCallback once ou have specified attributes to observe using static get observedAttributes() { return ['myAttribute']; }.
How can I list/access the observed attributes from within my sub class?
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.observedAttributes); // <= undefined
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
Is this somehow possible? Is there a getter for the observed attributes?
I think the difficulty here lies in getting the observed attributes of the parent class. Because if it was on the same class, you could just Foo.observedAttributes as @javimovi mentioned.
I added a jsbin to play with: https://jsbin.com/sonekedavo/edit?js,console
Thank you!
javascript html ecmascript-6 web-component es6-class
javascript html ecmascript-6 web-component es6-class
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
edited Nov 21 '18 at 10:22
chitzui
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
asked Nov 21 '18 at 8:55
chitzuichitzui
698819
698819
1
Tryconsole.log(Foo.observedAttributes);
– javimovi
Nov 21 '18 at 8:58
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
1
This works ?console.log(Bar.observedAttributes);
– javimovi
Nov 21 '18 at 9:28
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44
add a comment |
1
Tryconsole.log(Foo.observedAttributes);
– javimovi
Nov 21 '18 at 8:58
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
1
This works ?console.log(Bar.observedAttributes);
– javimovi
Nov 21 '18 at 9:28
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44
1
1
Try
console.log(Foo.observedAttributes);– javimovi
Nov 21 '18 at 8:58
Try
console.log(Foo.observedAttributes);– javimovi
Nov 21 '18 at 8:58
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
1
1
This works ?
console.log(Bar.observedAttributes);– javimovi
Nov 21 '18 at 9:28
This works ?
console.log(Bar.observedAttributes);– javimovi
Nov 21 '18 at 9:28
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44
add a comment |
1 Answer
1
active
oldest
votes
Found it!:
The constructor can be used:
Returns a reference to the Object constructor function that created the instance object
Using the example mentioned before.
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.constructor.observedAttributes); // <= ['bar']
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
Found it!:
The constructor can be used:
Returns a reference to the Object constructor function that created the instance object
Using the example mentioned before.
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.constructor.observedAttributes); // <= ['bar']
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
add a comment |
Found it!:
The constructor can be used:
Returns a reference to the Object constructor function that created the instance object
Using the example mentioned before.
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.constructor.observedAttributes); // <= ['bar']
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
add a comment |
Found it!:
The constructor can be used:
Returns a reference to the Object constructor function that created the instance object
Using the example mentioned before.
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.constructor.observedAttributes); // <= ['bar']
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
Found it!:
The constructor can be used:
Returns a reference to the Object constructor function that created the instance object
Using the example mentioned before.
class Foo extends HTMLElement {
connectedCallback() {
console.log(this.constructor.observedAttributes); // <= ['bar']
}
}
class Bar extends Foo {
static get observedAttributes() {
return ['bar'];
}
}
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
answered Nov 21 '18 at 11:44
chitzuichitzui
698819
698819
add a comment |
add a comment |
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1
Try
console.log(Foo.observedAttributes);– javimovi
Nov 21 '18 at 8:58
Yes, that works! Thank you! However, I have a different setup actually. How to get the attributes from a parent class if it extends that one. I’ve edited the question to match that case, please have a look
– chitzui
Nov 21 '18 at 9:17
1
This works ?
console.log(Bar.observedAttributes);– javimovi
Nov 21 '18 at 9:28
Yes, that would work. But the problem is, I never know what the mixin class is called. It can be Bar, it can be Baz or C or MyClass or whatever
– chitzui
Nov 21 '18 at 10:23
Found the solution thanks to your help!
– chitzui
Nov 21 '18 at 11:44