How to apply `Length` in all elements












2












$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: {1,{2,3},{4,5,6}}



How to apply Length in each element of this list?



Length[{1}]

Length[{2,3}]

Length[{4,5,6}]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[{1, {2, 3}, {4, 5, 6}}]]



Out[235]= 3


The result that I want is some like:



1

2

3


Which is the number of elements in each element.






functions function-construction







share|improve this question









$endgroup$








  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
    $endgroup$
    – Carl Lange
    2 days ago
















2












$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: {1,{2,3},{4,5,6}}



How to apply Length in each element of this list?



Length[{1}]

Length[{2,3}]

Length[{4,5,6}]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[{1, {2, 3}, {4, 5, 6}}]]



Out[235]= 3


The result that I want is some like:



1

2

3


Which is the number of elements in each element.






functions function-construction







share|improve this question









$endgroup$








  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
    $endgroup$
    – Carl Lange
    2 days ago














2












2








2


1



$begingroup$


I want to apply Length in each element from a list.
For example:



My list is: {1,{2,3},{4,5,6}}



How to apply Length in each element of this list?



Length[{1}]

Length[{2,3}]

Length[{4,5,6}]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[{1, {2, 3}, {4, 5, 6}}]]



Out[235]= 3


The result that I want is some like:



1

2

3


Which is the number of elements in each element.






functions function-construction







share|improve this question









$endgroup$




I want to apply Length in each element from a list.
For example:



My list is: {1,{2,3},{4,5,6}}



How to apply Length in each element of this list?



Length[{1}]

Length[{2,3}]

Length[{4,5,6}]


I have tried to use Thread, but doesn't works:



In[235]:= Thread[Length[{1, {2, 3}, {4, 5, 6}}]]



Out[235]= 3


The result that I want is some like:



1

2

3


Which is the number of elements in each element.






functions function-construction




functions function-construction






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 2 days ago









MateusMateus

48616




48616








  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
    $endgroup$
    – Carl Lange
    2 days ago














  • 2




    $begingroup$
    What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
    $endgroup$
    – Carl Lange
    2 days ago








2




2




$begingroup$
What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
$endgroup$
– Carl Lange
2 days ago




$begingroup$
What in your opinion is the Length of 1? You can use Map: Map[Length, {1, {2, 3}, {4, 5, 6}}].
$endgroup$
– Carl Lange
2 days ago










3 Answers
3






active

oldest

votes


















7












$begingroup$

If[AtomQ @ #, 1, Length @ #] & /@ {1, {2, 3}, {4, 5, 6}}



{1, 2, 3}




If the input list does not contain {} (thanks: @corey979), you can also use:



Length /@ {1, {2, 3}, {4, 5, 6}} /. 0 -> 1

(* or Map[Length]@{1, {2, 3}, {4, 5, 6}} /. 0 -> 1 *)



{1, 2, 3}







share|improve this answer











$endgroup$













  • $begingroup$
    Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
    $endgroup$
    – corey979
    2 days ago










  • $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    2 days ago



















5












$begingroup$

Introduce Charting`padList to make a list for your element..



Length@*Charting`padList /@ {1, {2, 3}, {4, 5, 6}}



{1, 2, 3}







share|improve this answer











$endgroup$









  • 1




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    2 days ago



















0












$begingroup$

A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



Length@Flatten@List@#&/@{1, {2, 3}, {4, 5, 6}}





share|improve this answer








New contributor




Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$













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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7












    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}




    If the input list does not contain {} (thanks: @corey979), you can also use:



    Length /@ {1, {2, 3}, {4, 5, 6}} /. 0 -> 1
    
(* or Map[Length]@{1, {2, 3}, {4, 5, 6}} /. 0 -> 1 *)



    {1, 2, 3}







    share|improve this answer











    $endgroup$













    • $begingroup$
      Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
      $endgroup$
      – corey979
      2 days ago










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      2 days ago
















    7












    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}




    If the input list does not contain {} (thanks: @corey979), you can also use:



    Length /@ {1, {2, 3}, {4, 5, 6}} /. 0 -> 1
    
(* or Map[Length]@{1, {2, 3}, {4, 5, 6}} /. 0 -> 1 *)



    {1, 2, 3}







    share|improve this answer











    $endgroup$













    • $begingroup$
      Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
      $endgroup$
      – corey979
      2 days ago










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      2 days ago














    7












    7








    7





    $begingroup$

    If[AtomQ @ #, 1, Length @ #] & /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}




    If the input list does not contain {} (thanks: @corey979), you can also use:



    Length /@ {1, {2, 3}, {4, 5, 6}} /. 0 -> 1
    
(* or Map[Length]@{1, {2, 3}, {4, 5, 6}} /. 0 -> 1 *)



    {1, 2, 3}







    share|improve this answer











    $endgroup$



    If[AtomQ @ #, 1, Length @ #] & /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}




    If the input list does not contain {} (thanks: @corey979), you can also use:



    Length /@ {1, {2, 3}, {4, 5, 6}} /. 0 -> 1
    
(* or Map[Length]@{1, {2, 3}, {4, 5, 6}} /. 0 -> 1 *)



    {1, 2, 3}








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago

























    answered 2 days ago









    kglrkglr

    180k9200413




    180k9200413












    • $begingroup$
      Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
      $endgroup$
      – corey979
      2 days ago










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      2 days ago


















    • $begingroup$
      Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
      $endgroup$
      – corey979
      2 days ago










    • $begingroup$
      @corey979, very good point.
      $endgroup$
      – kglr
      2 days ago
















    $begingroup$
    Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
    $endgroup$
    – corey979
    2 days ago




    $begingroup$
    Note that the first approach fails on {1, {2, 3}, {}, {4, 5, 6}}. The second, however, works well.
    $endgroup$
    – corey979
    2 days ago












    $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    2 days ago




    $begingroup$
    @corey979, very good point.
    $endgroup$
    – kglr
    2 days ago











    5












    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}







    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      2 days ago
















    5












    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}







    share|improve this answer











    $endgroup$









    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      2 days ago














    5












    5








    5





    $begingroup$

    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}







    share|improve this answer











    $endgroup$



    Introduce Charting`padList to make a list for your element..



    Length@*Charting`padList /@ {1, {2, 3}, {4, 5, 6}}



    {1, 2, 3}








    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 2 days ago

























    answered 2 days ago









    yodeyode

    10.2k234100




    10.2k234100








    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      2 days ago














    • 1




      $begingroup$
      Brilliant. Care to elaborate more on Charting`padList?
      $endgroup$
      – corey979
      2 days ago








    1




    1




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    2 days ago




    $begingroup$
    Brilliant. Care to elaborate more on Charting`padList?
    $endgroup$
    – corey979
    2 days ago











    0












    $begingroup$

    A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



    Length@Flatten@List@#&/@{1, {2, 3}, {4, 5, 6}}





    share|improve this answer








    New contributor




    Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$


















      0












      $begingroup$

      A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



      Length@Flatten@List@#&/@{1, {2, 3}, {4, 5, 6}}





      share|improve this answer








      New contributor




      Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$
















        0












        0








        0





        $begingroup$

        A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



        Length@Flatten@List@#&/@{1, {2, 3}, {4, 5, 6}}





        share|improve this answer








        New contributor




        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        $endgroup$



        A mildly adjusted version of the nice Charting answer by yode is to apply a list to each element and flatten:



        Length@Flatten@List@#&/@{1, {2, 3}, {4, 5, 6}}






        share|improve this answer








        New contributor




        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer






        New contributor




        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered yesterday









        Jordan MoxonJordan Moxon

        1




        1




        New contributor




        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        Jordan Moxon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






























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