I want to compare two column which has different date format












0














I want to compare two column which has different date format.



REQ_END_TIME = 03-APR-18 06.15.30.000000000 AM
SENDDATE = 4/3/2018



Both have same dates , so i just want to validate date part is same or not by skipping timestamp.
SENDDATE format is M/D/YYYY



How can I change any of it to make it similar to validate with query.



Database - Oracle










share|improve this question




















  • 5




    Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
    – HoneyBadger
    Nov 20 '18 at 14:28






  • 3




    Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
    – JNevill
    Nov 20 '18 at 14:30












  • How to convert a column to date format?
    – Avinash Singh
    Nov 20 '18 at 14:39






  • 2




    I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
    – mathguy
    Nov 20 '18 at 14:51






  • 1




    @mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
    – Wernfried Domscheit
    Nov 20 '18 at 14:55
















0














I want to compare two column which has different date format.



REQ_END_TIME = 03-APR-18 06.15.30.000000000 AM
SENDDATE = 4/3/2018



Both have same dates , so i just want to validate date part is same or not by skipping timestamp.
SENDDATE format is M/D/YYYY



How can I change any of it to make it similar to validate with query.



Database - Oracle










share|improve this question




















  • 5




    Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
    – HoneyBadger
    Nov 20 '18 at 14:28






  • 3




    Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
    – JNevill
    Nov 20 '18 at 14:30












  • How to convert a column to date format?
    – Avinash Singh
    Nov 20 '18 at 14:39






  • 2




    I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
    – mathguy
    Nov 20 '18 at 14:51






  • 1




    @mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
    – Wernfried Domscheit
    Nov 20 '18 at 14:55














0












0








0


0





I want to compare two column which has different date format.



REQ_END_TIME = 03-APR-18 06.15.30.000000000 AM
SENDDATE = 4/3/2018



Both have same dates , so i just want to validate date part is same or not by skipping timestamp.
SENDDATE format is M/D/YYYY



How can I change any of it to make it similar to validate with query.



Database - Oracle










share|improve this question















I want to compare two column which has different date format.



REQ_END_TIME = 03-APR-18 06.15.30.000000000 AM
SENDDATE = 4/3/2018



Both have same dates , so i just want to validate date part is same or not by skipping timestamp.
SENDDATE format is M/D/YYYY



How can I change any of it to make it similar to validate with query.



Database - Oracle







sql database oracle






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 14:30









JNevill

31.4k31544




31.4k31544










asked Nov 20 '18 at 14:27









Avinash SinghAvinash Singh

45




45








  • 5




    Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
    – HoneyBadger
    Nov 20 '18 at 14:28






  • 3




    Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
    – JNevill
    Nov 20 '18 at 14:30












  • How to convert a column to date format?
    – Avinash Singh
    Nov 20 '18 at 14:39






  • 2




    I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
    – mathguy
    Nov 20 '18 at 14:51






  • 1




    @mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
    – Wernfried Domscheit
    Nov 20 '18 at 14:55














  • 5




    Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
    – HoneyBadger
    Nov 20 '18 at 14:28






  • 3




    Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
    – JNevill
    Nov 20 '18 at 14:30












  • How to convert a column to date format?
    – Avinash Singh
    Nov 20 '18 at 14:39






  • 2




    I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
    – mathguy
    Nov 20 '18 at 14:51






  • 1




    @mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
    – Wernfried Domscheit
    Nov 20 '18 at 14:55








5




5




Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
– HoneyBadger
Nov 20 '18 at 14:28




Convert both to date. If you are storing them with format, you are using a varchar/char, don't do that: always use the appropriate datatype.
– HoneyBadger
Nov 20 '18 at 14:28




3




3




Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
– JNevill
Nov 20 '18 at 14:30






Don't store dates and time as varchar. Ever. And this will never be a problem you need to solve ever again. It's best that you spend your time now learning how to convert these to store them properly as dates instead of figuring out how to convert them or compare the string representation of the datetimes on the fly.
– JNevill
Nov 20 '18 at 14:30














How to convert a column to date format?
– Avinash Singh
Nov 20 '18 at 14:39




How to convert a column to date format?
– Avinash Singh
Nov 20 '18 at 14:39




2




2




I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
– mathguy
Nov 20 '18 at 14:51




I don't know how the earlier responders know the data type of your columns. It is not clear from your post. Is SENDDATE a string, or is it actually a DATE in the database? You can find out easily with the DESCRIBE command - DESCRIBE TABLE_NAME will show the names and the data types of each column in a table called TABLE_NAME. Please check the data type of the two columns and add your findings to your post.
– mathguy
Nov 20 '18 at 14:51




1




1




@mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
– Wernfried Domscheit
Nov 20 '18 at 14:55




@mathguy, indeed perhaps REQ_END_TIME is a TIMESTAMP and SENDDATE is a DATE value. Default NLS_DATE_FORMAT and NLS_TIMESTAMP_FORMAT can be completely different.
– Wernfried Domscheit
Nov 20 '18 at 14:55












3 Answers
3






active

oldest

votes


















0














You would convert both to dates or to strings:



where to_date(substr(req_end_time, 9), 'DD-MON-YYYY') = to_date(send_date, 'MM/DD/YYYY')





share|improve this answer























  • to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
    – Wernfried Domscheit
    Nov 20 '18 at 15:05





















0














You can use CAST and to_date (with the format mask)



select * from mytable
where to_date(CAST(REQ_END_TIME as char(10)), 'DD/MM/YYYY') =
to_date(SENDDATE, 'MM/DD/YYYY')


It'll return:



03.04.18   =   03.04.18


Compiled query






share|improve this answer





























    0














    Assuming SENDDATE is already in date format



    select (to_date(REQ_END_TIME,'M/D/YYYY') - SENDDATE ) COMPARE
    from mytable





    share|improve this answer























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0














      You would convert both to dates or to strings:



      where to_date(substr(req_end_time, 9), 'DD-MON-YYYY') = to_date(send_date, 'MM/DD/YYYY')





      share|improve this answer























      • to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
        – Wernfried Domscheit
        Nov 20 '18 at 15:05


















      0














      You would convert both to dates or to strings:



      where to_date(substr(req_end_time, 9), 'DD-MON-YYYY') = to_date(send_date, 'MM/DD/YYYY')





      share|improve this answer























      • to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
        – Wernfried Domscheit
        Nov 20 '18 at 15:05
















      0












      0








      0






      You would convert both to dates or to strings:



      where to_date(substr(req_end_time, 9), 'DD-MON-YYYY') = to_date(send_date, 'MM/DD/YYYY')





      share|improve this answer














      You would convert both to dates or to strings:



      where to_date(substr(req_end_time, 9), 'DD-MON-YYYY') = to_date(send_date, 'MM/DD/YYYY')






      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited Nov 20 '18 at 18:41

























      answered Nov 20 '18 at 14:56









      Gordon LinoffGordon Linoff

      761k35294399




      761k35294399












      • to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
        – Wernfried Domscheit
        Nov 20 '18 at 15:05




















      • to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
        – Wernfried Domscheit
        Nov 20 '18 at 15:05


















      to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
      – Wernfried Domscheit
      Nov 20 '18 at 15:05






      to_date('03-APR-18 06.15.30.000000000 AM', 'DD-MON-YYYY') will not work. Better use TO_timestamp('03-APR-18 06.15.30.000000000 AM', 'DD-MON-RR hh.mi.ssxff am') provided they are varchar2
      – Wernfried Domscheit
      Nov 20 '18 at 15:05















      0














      You can use CAST and to_date (with the format mask)



      select * from mytable
      where to_date(CAST(REQ_END_TIME as char(10)), 'DD/MM/YYYY') =
      to_date(SENDDATE, 'MM/DD/YYYY')


      It'll return:



      03.04.18   =   03.04.18


      Compiled query






      share|improve this answer


























        0














        You can use CAST and to_date (with the format mask)



        select * from mytable
        where to_date(CAST(REQ_END_TIME as char(10)), 'DD/MM/YYYY') =
        to_date(SENDDATE, 'MM/DD/YYYY')


        It'll return:



        03.04.18   =   03.04.18


        Compiled query






        share|improve this answer
























          0












          0








          0






          You can use CAST and to_date (with the format mask)



          select * from mytable
          where to_date(CAST(REQ_END_TIME as char(10)), 'DD/MM/YYYY') =
          to_date(SENDDATE, 'MM/DD/YYYY')


          It'll return:



          03.04.18   =   03.04.18


          Compiled query






          share|improve this answer












          You can use CAST and to_date (with the format mask)



          select * from mytable
          where to_date(CAST(REQ_END_TIME as char(10)), 'DD/MM/YYYY') =
          to_date(SENDDATE, 'MM/DD/YYYY')


          It'll return:



          03.04.18   =   03.04.18


          Compiled query







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 20 '18 at 20:54









          GeorgyGeorgy

          788




          788























              0














              Assuming SENDDATE is already in date format



              select (to_date(REQ_END_TIME,'M/D/YYYY') - SENDDATE ) COMPARE
              from mytable





              share|improve this answer




























                0














                Assuming SENDDATE is already in date format



                select (to_date(REQ_END_TIME,'M/D/YYYY') - SENDDATE ) COMPARE
                from mytable





                share|improve this answer


























                  0












                  0








                  0






                  Assuming SENDDATE is already in date format



                  select (to_date(REQ_END_TIME,'M/D/YYYY') - SENDDATE ) COMPARE
                  from mytable





                  share|improve this answer














                  Assuming SENDDATE is already in date format



                  select (to_date(REQ_END_TIME,'M/D/YYYY') - SENDDATE ) COMPARE
                  from mytable






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 21 '18 at 2:59









                  Pang

                  6,8711563101




                  6,8711563101










                  answered Nov 21 '18 at 2:51









                  user3439907user3439907

                  112




                  112






























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