Is it possible to have “pseudo route” in Angular 4+
I'm trying to understand how to create multiple routes that all points towards the same component, but that it adjust some filter accordingly to the active route.
For example I have multiple routes here:
const routes: Route = [
{
path: '',
component: HelloComponent
},
{
path: 'Test',
component: HelloComponent
},
{
path: 'Truth',
component:HelloComponent
}
];
And this one component (just pasting the reaction of this component) :
constructor(private activeRoute: ActivatedRoute) {
activeRoute.url.subscribe(x => {
let paths: string = x.map(y => y.path);
let concated = paths.join() || "";
if(concated == "Test")
this.value = "This is a test"
else if(concated == "Truth")
this.value = "This is not a lie";
else
this.value = "Base value. Nothing to see here";
});
}
Why I'm doing this is for easier navigation in my component. This removes some click that the user have to do to get where he wants to get.
My questions is: Is there another way to acheive the same functionnality?
The link to the stackblitz reproduction: https://stackblitz.com/edit/angular-so-53400902
angular navigation angular-router
asked Nov 20 '18 at 20:18
ChaxChax
510727
add a comment |
I'm trying to understand how to create multiple routes that all points towards the same component, but that it adjust some filter accordingly to the active route.
For example I have multiple routes here:
const routes: Route = [
{
path: '',
component: HelloComponent
},
{
path: 'Test',
component: HelloComponent
},
{
path: 'Truth',
component:HelloComponent
}
];
And this one component (just pasting the reaction of this component) :
constructor(private activeRoute: ActivatedRoute) {
activeRoute.url.subscribe(x => {
let paths: string = x.map(y => y.path);
let concated = paths.join() || "";
if(concated == "Test")
this.value = "This is a test"
else if(concated == "Truth")
this.value = "This is not a lie";
else
this.value = "Base value. Nothing to see here";
});
}
Why I'm doing this is for easier navigation in my component. This removes some click that the user have to do to get where he wants to get.
My questions is: Is there another way to acheive the same functionnality?
The link to the stackblitz reproduction: https://stackblitz.com/edit/angular-so-53400902
angular navigation angular-router
asked Nov 20 '18 at 20:18
ChaxChax
510727
add a comment |
I'm trying to understand how to create multiple routes that all points towards the same component, but that it adjust some filter accordingly to the active route.
For example I have multiple routes here:
const routes: Route = [
{
path: '',
component: HelloComponent
},
{
path: 'Test',
component: HelloComponent
},
{
path: 'Truth',
component:HelloComponent
}
];
And this one component (just pasting the reaction of this component) :
constructor(private activeRoute: ActivatedRoute) {
activeRoute.url.subscribe(x => {
let paths: string = x.map(y => y.path);
let concated = paths.join() || "";
if(concated == "Test")
this.value = "This is a test"
else if(concated == "Truth")
this.value = "This is not a lie";
else
this.value = "Base value. Nothing to see here";
});
}
Why I'm doing this is for easier navigation in my component. This removes some click that the user have to do to get where he wants to get.
My questions is: Is there another way to acheive the same functionnality?
The link to the stackblitz reproduction: https://stackblitz.com/edit/angular-so-53400902
angular navigation angular-router
asked Nov 20 '18 at 20:18
ChaxChax
510727
I'm trying to understand how to create multiple routes that all points towards the same component, but that it adjust some filter accordingly to the active route.
For example I have multiple routes here:
const routes: Route = [
{
path: '',
component: HelloComponent
},
{
path: 'Test',
component: HelloComponent
},
{
path: 'Truth',
component:HelloComponent
}
];
And this one component (just pasting the reaction of this component) :
constructor(private activeRoute: ActivatedRoute) {
activeRoute.url.subscribe(x => {
let paths: string = x.map(y => y.path);
let concated = paths.join() || "";
if(concated == "Test")
this.value = "This is a test"
else if(concated == "Truth")
this.value = "This is not a lie";
else
this.value = "Base value. Nothing to see here";
});
}
Why I'm doing this is for easier navigation in my component. This removes some click that the user have to do to get where he wants to get.
My questions is: Is there another way to acheive the same functionnality?
The link to the stackblitz reproduction: https://stackblitz.com/edit/angular-so-53400902
angular navigation angular-router
angular navigation angular-router
asked Nov 20 '18 at 20:18
ChaxChax
510727
asked Nov 20 '18 at 20:18
ChaxChax
510727
edited Dec 5 '18 at 20:29
Chax
asked Nov 20 '18 at 20:18
ChaxChax
510727
asked Nov 20 '18 at 20:18
ChaxChax
510727
asked Nov 20 '18 at 20:18
ChaxChax
510727
510727
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53400902%2fis-it-possible-to-have-pseudo-route-in-angular-4%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53400902%2fis-it-possible-to-have-pseudo-route-in-angular-4%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
