Trying to create an array. Keep getting TypeError

I'm trying to get a better grasp on the data structures.
I've been trying to add an array as an element of another array, but i keep getting the TypeError: Array item must be unicode character, when I try to create an array. I'm following videos/everything I read to a T from what i can tell.

from array import array



Swords = array('u',['Steel Sword', 'Bronze Sword', 'Iron Sword'])

Axes = ['Steel Axe', 'Bronze Axe', 'Iron Axe']

Maces = ['Steel Mace','Bronze Mace','Iron Mace']

Bows = ['Wood Bow', 'Bone Bow', 'Obsidian Bow']

Daggers = ['Steel Dagger', 'Bronze Dagger', 'Obsidian Dagger']



Weapons = array('u',([Swords])



for i in Weapons:



    print(i)

Any idea what is going on?

asked Nov 20 '18 at 23:39

Adag89

708

The 'u' type code corresponds to Python’s obsolete unicode character. Why exactly are you trying to use the array datatype instead of a normal list?

– jk622
Nov 21 '18 at 1:13

@jk622 I was just trying to get comfortable working with arrays. Is there any difference between an array, and a list in python, or should I just use a list when I need an array?

– Adag89
Nov 21 '18 at 1:48

In general, you should be using a list. Unless you are trying to use a particular function available to the array class, all you'd be doing is adding a constraint to the datatype of the objects inside it.

– jk622
Nov 21 '18 at 1:56

Ok, I did some additional reading, and makes sense when to use which. Why the type error for trying to place a list inside of an array though? This is what every tutorial I have watched has shown.

– Adag89
Nov 21 '18 at 1:59

add a comment |

from array import array



Swords = array('u',['Steel Sword', 'Bronze Sword', 'Iron Sword'])

Axes = ['Steel Axe', 'Bronze Axe', 'Iron Axe']

Maces = ['Steel Mace','Bronze Mace','Iron Mace']

Bows = ['Wood Bow', 'Bone Bow', 'Obsidian Bow']

Daggers = ['Steel Dagger', 'Bronze Dagger', 'Obsidian Dagger']



Weapons = array('u',([Swords])



for i in Weapons:



    print(i)

Any idea what is going on?

asked Nov 20 '18 at 23:39

Adag89

708

The 'u' type code corresponds to Python’s obsolete unicode character. Why exactly are you trying to use the array datatype instead of a normal list?

– jk622
Nov 21 '18 at 1:13

@jk622 I was just trying to get comfortable working with arrays. Is there any difference between an array, and a list in python, or should I just use a list when I need an array?

– Adag89
Nov 21 '18 at 1:48

In general, you should be using a list. Unless you are trying to use a particular function available to the array class, all you'd be doing is adding a constraint to the datatype of the objects inside it.

– jk622
Nov 21 '18 at 1:56

Ok, I did some additional reading, and makes sense when to use which. Why the type error for trying to place a list inside of an array though? This is what every tutorial I have watched has shown.

– Adag89
Nov 21 '18 at 1:59

add a comment |

from array import array



Swords = array('u',['Steel Sword', 'Bronze Sword', 'Iron Sword'])

Axes = ['Steel Axe', 'Bronze Axe', 'Iron Axe']

Maces = ['Steel Mace','Bronze Mace','Iron Mace']

Bows = ['Wood Bow', 'Bone Bow', 'Obsidian Bow']

Daggers = ['Steel Dagger', 'Bronze Dagger', 'Obsidian Dagger']



Weapons = array('u',([Swords])



for i in Weapons:



    print(i)

Any idea what is going on?

asked Nov 20 '18 at 23:39

Adag89

708

from array import array



Swords = array('u',['Steel Sword', 'Bronze Sword', 'Iron Sword'])

Axes = ['Steel Axe', 'Bronze Axe', 'Iron Axe']

Maces = ['Steel Mace','Bronze Mace','Iron Mace']

Bows = ['Wood Bow', 'Bone Bow', 'Obsidian Bow']

Daggers = ['Steel Dagger', 'Bronze Dagger', 'Obsidian Dagger']



Weapons = array('u',([Swords])



for i in Weapons:



    print(i)

Any idea what is going on?

arrays python-3.x typeerror

asked Nov 20 '18 at 23:39

Adag89

708

asked Nov 20 '18 at 23:39

Adag89

708

asked Nov 20 '18 at 23:39

Adag89

708

asked Nov 20 '18 at 23:39

Adag89

708

asked Nov 20 '18 at 23:39

Adag89

708

The 'u' type code corresponds to Python’s obsolete unicode character. Why exactly are you trying to use the array datatype instead of a normal list?

– jk622
Nov 21 '18 at 1:13

@jk622 I was just trying to get comfortable working with arrays. Is there any difference between an array, and a list in python, or should I just use a list when I need an array?

– Adag89
Nov 21 '18 at 1:48

In general, you should be using a list. Unless you are trying to use a particular function available to the array class, all you'd be doing is adding a constraint to the datatype of the objects inside it.

– jk622
Nov 21 '18 at 1:56

Ok, I did some additional reading, and makes sense when to use which. Why the type error for trying to place a list inside of an array though? This is what every tutorial I have watched has shown.

– Adag89
Nov 21 '18 at 1:59

add a comment |

The 'u' type code corresponds to Python’s obsolete unicode character. Why exactly are you trying to use the array datatype instead of a normal list?

– jk622
Nov 21 '18 at 1:13

@jk622 I was just trying to get comfortable working with arrays. Is there any difference between an array, and a list in python, or should I just use a list when I need an array?

– Adag89
Nov 21 '18 at 1:48

In general, you should be using a list. Unless you are trying to use a particular function available to the array class, all you'd be doing is adding a constraint to the datatype of the objects inside it.

– jk622
Nov 21 '18 at 1:56

Ok, I did some additional reading, and makes sense when to use which. Why the type error for trying to place a list inside of an array though? This is what every tutorial I have watched has shown.

– Adag89
Nov 21 '18 at 1:59

The 'u' type code corresponds to Python’s obsolete unicode character. Why exactly are you trying to use the array datatype instead of a normal list?

– jk622
Nov 21 '18 at 1:13

@jk622 I was just trying to get comfortable working with arrays. Is there any difference between an array, and a list in python, or should I just use a list when I need an array?

– Adag89
Nov 21 '18 at 1:48

In general, you should be using a list. Unless you are trying to use a particular function available to the array class, all you'd be doing is adding a constraint to the datatype of the objects inside it.

– jk622
Nov 21 '18 at 1:56

Ok, I did some additional reading, and makes sense when to use which. Why the type error for trying to place a list inside of an array though? This is what every tutorial I have watched has shown.

– Adag89
Nov 21 '18 at 1:59

add a comment |

1 Answer
1

active

oldest

votes

The 'u' type code corresponds to Python’s obsolete unicode character. This means it will work with unicode characters. You can test this

test_one = array("u", ["u2641","u2642","u2643"])

for i in test_one:

    print(i)

You can also see it with this

test_two = array("u", ["T","e","s","t"])

for i in test_two:

    print(i)

Notice, in both cases it is a single character. Not entire strings. In order to do the string, you would have to convert each string to a list of characters.

test_three = array("u", [ch for ch in "Test"])

for i in test_three:

    print(i)

Lastly, if you want to break down the individual characters from a list of strings you can do a list comprehension similar to test_three or you can use a generator.

def character_generator(word_list):

    for word in word_list:

        for ch in word:

            yield ch



test_four = array("u", character_generator(["Test","One","Two"]))

for i in test_four:

    print(i)

At the end of the day though, the u typecode is for individual characters. Not strings.

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

The 'u' type code corresponds to Python’s obsolete unicode character. This means it will work with unicode characters. You can test this

test_one = array("u", ["u2641","u2642","u2643"])

for i in test_one:

    print(i)

You can also see it with this

test_two = array("u", ["T","e","s","t"])

for i in test_two:

    print(i)

Notice, in both cases it is a single character. Not entire strings. In order to do the string, you would have to convert each string to a list of characters.

test_three = array("u", [ch for ch in "Test"])

for i in test_three:

    print(i)

Lastly, if you want to break down the individual characters from a list of strings you can do a list comprehension similar to test_three or you can use a generator.

def character_generator(word_list):

    for word in word_list:

        for ch in word:

            yield ch



test_four = array("u", character_generator(["Test","One","Two"]))

for i in test_four:

    print(i)

At the end of the day though, the u typecode is for individual characters. Not strings.

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

add a comment |

The 'u' type code corresponds to Python’s obsolete unicode character. This means it will work with unicode characters. You can test this

test_one = array("u", ["u2641","u2642","u2643"])

for i in test_one:

    print(i)

You can also see it with this

test_two = array("u", ["T","e","s","t"])

for i in test_two:

    print(i)

Notice, in both cases it is a single character. Not entire strings. In order to do the string, you would have to convert each string to a list of characters.

test_three = array("u", [ch for ch in "Test"])

for i in test_three:

    print(i)

Lastly, if you want to break down the individual characters from a list of strings you can do a list comprehension similar to test_three or you can use a generator.

def character_generator(word_list):

    for word in word_list:

        for ch in word:

            yield ch



test_four = array("u", character_generator(["Test","One","Two"]))

for i in test_four:

    print(i)

At the end of the day though, the u typecode is for individual characters. Not strings.

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

add a comment |

The 'u' type code corresponds to Python’s obsolete unicode character. This means it will work with unicode characters. You can test this

test_one = array("u", ["u2641","u2642","u2643"])

for i in test_one:

    print(i)

You can also see it with this

test_two = array("u", ["T","e","s","t"])

for i in test_two:

    print(i)

Notice, in both cases it is a single character. Not entire strings. In order to do the string, you would have to convert each string to a list of characters.

test_three = array("u", [ch for ch in "Test"])

for i in test_three:

    print(i)

Lastly, if you want to break down the individual characters from a list of strings you can do a list comprehension similar to test_three or you can use a generator.

def character_generator(word_list):

    for word in word_list:

        for ch in word:

            yield ch



test_four = array("u", character_generator(["Test","One","Two"]))

for i in test_four:

    print(i)

At the end of the day though, the u typecode is for individual characters. Not strings.

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

The 'u' type code corresponds to Python’s obsolete unicode character. This means it will work with unicode characters. You can test this

test_one = array("u", ["u2641","u2642","u2643"])

for i in test_one:

    print(i)

You can also see it with this

test_two = array("u", ["T","e","s","t"])

for i in test_two:

    print(i)

Notice, in both cases it is a single character. Not entire strings. In order to do the string, you would have to convert each string to a list of characters.

test_three = array("u", [ch for ch in "Test"])

for i in test_three:

    print(i)

Lastly, if you want to break down the individual characters from a list of strings you can do a list comprehension similar to test_three or you can use a generator.

def character_generator(word_list):

    for word in word_list:

        for ch in word:

            yield ch



test_four = array("u", character_generator(["Test","One","Two"]))

for i in test_four:

    print(i)

At the end of the day though, the u typecode is for individual characters. Not strings.

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

edited Nov 21 '18 at 3:15

answered Nov 21 '18 at 2:20

jk622

3211312

answered Nov 21 '18 at 2:20

jk622

3211312

answered Nov 21 '18 at 2:20

jk622

3211312

add a comment |

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