Why will Wolfram CountryData not give population data after 2014 (e.g. for the US)?












11












$begingroup$


CountryData[ "UnitedStates", {"Population", 2014} ]



322 422 965 people




CountryData[ "UnitedStates", {"Population", 2015} ]



Missing[ "NotAvailable" ]




How can I update it?
I am new to Mathematica.










share|improve this question









New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$








  • 1




    $begingroup$
    Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
    $endgroup$
    – user64494
    2 days ago








  • 1




    $begingroup$
    Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
    $endgroup$
    – gwr
    2 days ago










  • $begingroup$
    @gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
    $endgroup$
    – gwr
    2 days ago
















11












$begingroup$


CountryData[ "UnitedStates", {"Population", 2014} ]



322 422 965 people




CountryData[ "UnitedStates", {"Population", 2015} ]



Missing[ "NotAvailable" ]




How can I update it?
I am new to Mathematica.










share|improve this question









New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
    $endgroup$
    – user64494
    2 days ago








  • 1




    $begingroup$
    Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
    $endgroup$
    – gwr
    2 days ago










  • $begingroup$
    @gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
    $endgroup$
    – gwr
    2 days ago














11












11








11


4



$begingroup$


CountryData[ "UnitedStates", {"Population", 2014} ]



322 422 965 people




CountryData[ "UnitedStates", {"Population", 2015} ]



Missing[ "NotAvailable" ]




How can I update it?
I am new to Mathematica.










share|improve this question









New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




CountryData[ "UnitedStates", {"Population", 2014} ]



322 422 965 people




CountryData[ "UnitedStates", {"Population", 2015} ]



Missing[ "NotAvailable" ]




How can I update it?
I am new to Mathematica.







curated-data






share|improve this question









New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 2 days ago









gwr

7,88322659




7,88322659






New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 2 days ago









user10311334user10311334

564




564




New contributor




user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






user10311334 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    $begingroup$
    Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
    $endgroup$
    – user64494
    2 days ago








  • 1




    $begingroup$
    Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
    $endgroup$
    – gwr
    2 days ago










  • $begingroup$
    @gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
    $endgroup$
    – gwr
    2 days ago














  • 1




    $begingroup$
    Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
    $endgroup$
    – user64494
    2 days ago








  • 1




    $begingroup$
    Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
    $endgroup$
    – gwr
    2 days ago










  • $begingroup$
    @gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
    $endgroup$
    – user64494
    2 days ago










  • $begingroup$
    @user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
    $endgroup$
    – gwr
    2 days ago








1




1




$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
2 days ago






$begingroup$
Both statistics and its implementation in Mathematica are slow. Lags usually equal few years. WolframAlpha in my Mma through ==Population of United States in 2015 answers 320 million people (2015 estimate).
$endgroup$
– user64494
2 days ago






1




1




$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 days ago




$begingroup$
Also WA in my Mma answers 327 million people (world rank: 3^(rd)) (2018 estimate)
$endgroup$
– user64494
2 days ago












$begingroup$
@user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
$endgroup$
– gwr
2 days ago




$begingroup$
@user64494 That is interesting, WolframAlpha[ "Population of the United States"] for me returns 324 million people (2017 estimate). Seems like there are different data bases queried?
$endgroup$
– gwr
2 days ago












$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 days ago




$begingroup$
@gwr: Your question should be addressed to Wolfram developers, not to me. Try WolframAlpha["Population of the United States in 2018"]. Good luck!
$endgroup$
– user64494
2 days ago












$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 days ago




$begingroup$
@user64494 But you indeed have given the answer! Specifically asking for the population in 2018 will give the value you have given. It simply will not appear just asking for population for some reason. :)
$endgroup$
– gwr
2 days ago










2 Answers
2






active

oldest

votes


















14












$begingroup$

CountryData does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue] to see that this is true.



But CountryData has not been updated to work this way. So we can call EntityValue directly for the data. To find out what the right syntax would be I will use Ctrl=:



enter image description here



becomes



enter image description here



which is a formatted form of



Entity["Country", "UnitedStates"][
EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
]


I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018" returns this input expression:



Entity["Country", "UnitedStates"][
EntityProperty["Country",
"Population",
{"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
]
]


which returns a TimeSeries object suitable for further computation or visualization.






share|improve this answer









$endgroup$





















    9












    $begingroup$

    You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.



    First you can get a list of qualifier values of an EntityProperty by



    EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]



    {Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
    CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
    Date->{},
    Gender->{Female,Male},
    HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
    MarginOfError->{MarginOfError,StandardError},
    Percent->{Main},
    Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
    TwoOrMore->{ThreeOrMore,TwoIncludingOther},
    UrbanRural->{Rural,Urban}}



    "Date" is a qualifier. This post gives details on how to specify a "Date" qualifier (156014); an area where the docs can improve.



    EntityValue[
    Entity["Country", "UnitedStates"],
    EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
    ]



    319,929,162 people



    However, you do have a bit more flexibility with this syntax.



    EntityValue[
    Entity["Country", "UnitedStates"],
    EntityProperty["Country",
    "Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
    ]



    Mathematica graphics




    and



    EntityValue[
    Entity["Country", "UnitedStates"],
    EntityProperty["Country", "Population", {"Date" -> All}]
    ]



    Mathematica graphics




    Hope this helps.






    share|improve this answer











    $endgroup$













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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      14












      $begingroup$

      CountryData does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue] to see that this is true.



      But CountryData has not been updated to work this way. So we can call EntityValue directly for the data. To find out what the right syntax would be I will use Ctrl=:



      enter image description here



      becomes



      enter image description here



      which is a formatted form of



      Entity["Country", "UnitedStates"][
      EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
      ]


      I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018" returns this input expression:



      Entity["Country", "UnitedStates"][
      EntityProperty["Country",
      "Population",
      {"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
      ]
      ]


      which returns a TimeSeries object suitable for further computation or visualization.






      share|improve this answer









      $endgroup$


















        14












        $begingroup$

        CountryData does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue] to see that this is true.



        But CountryData has not been updated to work this way. So we can call EntityValue directly for the data. To find out what the right syntax would be I will use Ctrl=:



        enter image description here



        becomes



        enter image description here



        which is a formatted form of



        Entity["Country", "UnitedStates"][
        EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
        ]


        I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018" returns this input expression:



        Entity["Country", "UnitedStates"][
        EntityProperty["Country",
        "Population",
        {"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
        ]
        ]


        which returns a TimeSeries object suitable for further computation or visualization.






        share|improve this answer









        $endgroup$
















          14












          14








          14





          $begingroup$

          CountryData does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue] to see that this is true.



          But CountryData has not been updated to work this way. So we can call EntityValue directly for the data. To find out what the right syntax would be I will use Ctrl=:



          enter image description here



          becomes



          enter image description here



          which is a formatted form of



          Entity["Country", "UnitedStates"][
          EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
          ]


          I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018" returns this input expression:



          Entity["Country", "UnitedStates"][
          EntityProperty["Country",
          "Population",
          {"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
          ]
          ]


          which returns a TimeSeries object suitable for further computation or visualization.






          share|improve this answer









          $endgroup$



          CountryData does appear to be out of date, and that is a shame. Many of the XXXData functions now act as wrappers to call EntityValue. Run TracePrint[PlanetData["Venus", "AngularDiameterFromEarth"],_EntityValue] to see that this is true.



          But CountryData has not been updated to work this way. So we can call EntityValue directly for the data. To find out what the right syntax would be I will use Ctrl=:



          enter image description here



          becomes



          enter image description here



          which is a formatted form of



          Entity["Country", "UnitedStates"][
          EntityProperty["Country", "Population", {"Date" -> DateObject[{1978}]}]
          ]


          I can query for a date range as well. Using Ctrl= on "US population 2000 through 2018" returns this input expression:



          Entity["Country", "UnitedStates"][
          EntityProperty["Country",
          "Population",
          {"Date" -> Interval[{DateObject[{2000}], DateObject @ {2018}}]}
          ]
          ]


          which returns a TimeSeries object suitable for further computation or visualization.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 2 days ago









          Jason B.Jason B.

          48.1k388189




          48.1k388189























              9












              $begingroup$

              You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.



              First you can get a list of qualifier values of an EntityProperty by



              EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]



              {Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
              CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
              Date->{},
              Gender->{Female,Male},
              HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
              MarginOfError->{MarginOfError,StandardError},
              Percent->{Main},
              Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
              TwoOrMore->{ThreeOrMore,TwoIncludingOther},
              UrbanRural->{Rural,Urban}}



              "Date" is a qualifier. This post gives details on how to specify a "Date" qualifier (156014); an area where the docs can improve.



              EntityValue[
              Entity["Country", "UnitedStates"],
              EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
              ]



              319,929,162 people



              However, you do have a bit more flexibility with this syntax.



              EntityValue[
              Entity["Country", "UnitedStates"],
              EntityProperty["Country",
              "Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
              ]



              Mathematica graphics




              and



              EntityValue[
              Entity["Country", "UnitedStates"],
              EntityProperty["Country", "Population", {"Date" -> All}]
              ]



              Mathematica graphics




              Hope this helps.






              share|improve this answer











              $endgroup$


















                9












                $begingroup$

                You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.



                First you can get a list of qualifier values of an EntityProperty by



                EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]



                {Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
                CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
                Date->{},
                Gender->{Female,Male},
                HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
                MarginOfError->{MarginOfError,StandardError},
                Percent->{Main},
                Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
                TwoOrMore->{ThreeOrMore,TwoIncludingOther},
                UrbanRural->{Rural,Urban}}



                "Date" is a qualifier. This post gives details on how to specify a "Date" qualifier (156014); an area where the docs can improve.



                EntityValue[
                Entity["Country", "UnitedStates"],
                EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
                ]



                319,929,162 people



                However, you do have a bit more flexibility with this syntax.



                EntityValue[
                Entity["Country", "UnitedStates"],
                EntityProperty["Country",
                "Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
                ]



                Mathematica graphics




                and



                EntityValue[
                Entity["Country", "UnitedStates"],
                EntityProperty["Country", "Population", {"Date" -> All}]
                ]



                Mathematica graphics




                Hope this helps.






                share|improve this answer











                $endgroup$
















                  9












                  9








                  9





                  $begingroup$

                  You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.



                  First you can get a list of qualifier values of an EntityProperty by



                  EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]



                  {Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
                  CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
                  Date->{},
                  Gender->{Female,Male},
                  HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
                  MarginOfError->{MarginOfError,StandardError},
                  Percent->{Main},
                  Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
                  TwoOrMore->{ThreeOrMore,TwoIncludingOther},
                  UrbanRural->{Rural,Urban}}



                  "Date" is a qualifier. This post gives details on how to specify a "Date" qualifier (156014); an area where the docs can improve.



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
                  ]



                  319,929,162 people



                  However, you do have a bit more flexibility with this syntax.



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country",
                  "Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
                  ]



                  Mathematica graphics




                  and



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country", "Population", {"Date" -> All}]
                  ]



                  Mathematica graphics




                  Hope this helps.






                  share|improve this answer











                  $endgroup$



                  You should report to WRI. As a workaround you may use the entity functions instead; it is a bit verbose.



                  First you can get a list of qualifier values of an EntityProperty by



                  EntityValue[EntityProperty["Country", "Population"], "QualifierValues"]



                  {Age->{Adult,MiddleAge,PreSchool,SchoolAge,Senior,Young,YoungAdult},
                  CitizenshipStatus->{BornInPuertoRico,BornInUS,BornToAmericanParents,NaturalizedCitizen,NotCitizen,TotalCitizens},
                  Date->{},
                  Gender->{Female,Male},
                  HispanicOrigin->{Argentinean,Bolivian,CentralAmerican,Chilean,Colombian,CostaRican,Cuban,Dominican,Ecuadorian,Guatemalan,Hispanic,HispanicOrLatinoAllOther,Honduran,Mexican,Nicaraguan,NotHispanic,OtherCentralAmerican,OtherHispanicOrLatino,OtherSouthAmerican,Panamanian,Paraguayan,Peruvian,PuertoRican,Salvadoran,SouthAmerican,Spaniard,Spanish,SpanishAmerican,Uruguayan,Venezuelan},
                  MarginOfError->{MarginOfError,StandardError},
                  Percent->{Main},
                  Race->{AmericanIndian,Asian,Black,NativeHawaiian,Other,TwoOrMore,White,{All,Hispanic}},
                  TwoOrMore->{ThreeOrMore,TwoIncludingOther},
                  UrbanRural->{Rural,Urban}}



                  "Date" is a qualifier. This post gives details on how to specify a "Date" qualifier (156014); an area where the docs can improve.



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country", "Population", {"Date" -> DateObject[{2015}]}]
                  ]



                  319,929,162 people



                  However, you do have a bit more flexibility with this syntax.



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country",
                  "Population", {"Date" -> Interval[{DateObject[{2015}], DateObject[{2019}]}]}]
                  ]



                  Mathematica graphics




                  and



                  EntityValue[
                  Entity["Country", "UnitedStates"],
                  EntityProperty["Country", "Population", {"Date" -> All}]
                  ]



                  Mathematica graphics




                  Hope this helps.







                  share|improve this answer














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                  edited 2 days ago

























                  answered 2 days ago









                  EdmundEdmund

                  26.3k330100




                  26.3k330100






















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