How to create a cover page like this?
I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.
How could I create a cover page in my own classnotes like that?
tikz-pgf covers bookcover
add a comment |
I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.
How could I create a cover page in my own classnotes like that?
tikz-pgf covers bookcover
4
What have you tried so far?
– manooooh
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago
add a comment |
I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.
How could I create a cover page in my own classnotes like that?
tikz-pgf covers bookcover
I saw my Chinese classmate reading a book whose cover page is really fancy, though I don’t know the Chinese characters on it.
How could I create a cover page in my own classnotes like that?
tikz-pgf covers bookcover
tikz-pgf covers bookcover
asked 4 hours ago
user450201user450201
7213
7213
4
What have you tried so far?
– manooooh
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago
add a comment |
4
What have you tried so far?
– manooooh
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago
4
4
What have you tried so far?
– manooooh
4 hours ago
What have you tried so far?
– manooooh
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago
add a comment |
1 Answer
1
active
oldest
votes
Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of usingdisplaystyle
you could usedfrac
fromamsmath
.
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
@HenriMenke I believe that the cover is correct.rho
is the sixth root of unity, i.e.rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parametertau
withrho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)
– marmot
2 hours ago
|
show 2 more comments
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1 Answer
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1 Answer
1
active
oldest
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Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of usingdisplaystyle
you could usedfrac
fromamsmath
.
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
@HenriMenke I believe that the cover is correct.rho
is the sixth root of unity, i.e.rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parametertau
withrho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)
– marmot
2 hours ago
|
show 2 more comments
Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of usingdisplaystyle
you could usedfrac
fromamsmath
.
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
@HenriMenke I believe that the cover is correct.rho
is the sixth root of unity, i.e.rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parametertau
withrho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)
– marmot
2 hours ago
|
show 2 more comments
Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}
Can one do something like this? Yes. Most likely the curves in the upper right part are are some sort of Apollonius (Golden Ratio?) circles but I was too lazy to look them up.
documentclass{article}
usepackage{tikz}
usetikzlibrary{intersections,decorations.text}
definecolor{c1}{RGB}{62, 97, 127}
definecolor{c2}{RGB}{104, 182, 182}
definecolor{c3}{RGB}{107, 190, 190}
definecolor{c4}{RGB}{100, 172, 174}
begin{document}
thispagestyle{empty}
begin{tikzpicture}[overlay,remember picture,font=sffamilybfseries]
draw[very thick,c4,name path=big arc] ([xshift=-2mm]current page.north) arc(150:285:11)
coordinate[pos=0.225] (x0);
begin{scope}
clip ([xshift=-2mm]current page.north) arc(150:285:11) --(current page.north
east);
fill[c4!50,opacity=0.25] ([xshift=4.55cm]x0) circle (4.55);
fill[c4!50,opacity=0.25] ([xshift=3.4cm]x0) circle (3.4);
fill[c4!50,opacity=0.25] ([xshift=2.25cm]x0) circle (2.25);
draw[very thick,c4!50] (x0) arc(-90:30:6.5);
draw[very thick,c4] (x0) arc(90:-30:8.75);
draw[very thick,c4!50,name path=arc1] (x0) arc(90:-90:4.675);
draw[very thick,c4!50] (x0) arc(90:-90:2.875);
path[name intersections={of=big arc and arc1,by=x1}];
draw[very thick,c4,name path=arc2] (x1) arc(135:-20:4.75);
draw[very thick,c4!50] (x1) arc(135:-20:8.75);
path[name intersections={of=big arc and arc2,by={aux,x2}}];
draw[very thick,c4!50] (x2) arc(180:50:2.25);
end{scope}
path[decoration={text along path,text color=c4,
raise = -2.8ex,
text along path,
text = {|sffamilybfseries|02/18/2019},
text align = center,
},
decorate
] ([xshift=-2mm]current page.north) arc(150:245:11);
%
begin{scope}
path[clip,postaction={fill=c3}]
([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (4.2,7.7);
fill[c2] ([xshift=0.5cm,yshift=-8cm]current page.center)
([xshift=0.5cm,yshift=-8cm]current page.center) arc(180:60:2)
|- ++ (-3,6) --cycle;
draw[very thick,c4] ([xshift=-1.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=0.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=2.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
draw[very thick,c4] ([xshift=4.5cm,yshift=-8cm]current page.center)
arc(180:0:2);
fill[red] ([xshift=2.5cm,yshift=-8cm]current page.center) +(60:2) circle(1.5mm)
node[above right=2mm]{$displaystylerho=frac{1+sqrt{-3}}{2}$};
end{scope}
%
fill[c1] ([xshift=2cm,yshift=-8cm]current page.center) rectangle ++ (-12.7,7.7);
node[text=white,anchor=west,scale=5,inner sep=0pt] at
([xshift=-8cm,yshift=-3.25cm]current page.center) {Some text};
node[text=white,anchor=west,scale=2.5,inner sep=0pt] at
([xshift=-8cm,yshift=-6cm]current page.center) {Some text};
%
draw[gray,line width=5mm]
([xshift=2mm,yshift=-1mm]current page.south west) rectangle ([xshift=-2mm,yshift=1mm]current
page.north east);
end{tikzpicture}
end{document}
edited 2 hours ago
answered 3 hours ago
marmotmarmot
101k4118227
101k4118227
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of usingdisplaystyle
you could usedfrac
fromamsmath
.
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
@HenriMenke I believe that the cover is correct.rho
is the sixth root of unity, i.e.rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parametertau
withrho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)
– marmot
2 hours ago
|
show 2 more comments
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of usingdisplaystyle
you could usedfrac
fromamsmath
.
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
@HenriMenke I believe that the cover is correct.rho
is the sixth root of unity, i.e.rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parametertau
withrho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)
– marmot
2 hours ago
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
You’re so great!! Thanks a lot!!!
– user450201
3 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
Such a nice answer...great...
– MadyYuvi
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle
you could use dfrac
from amsmath
.– Henri Menke
2 hours ago
sqrt{-3}
I have the feeling that there is a typo on the original cover. Also, instead of using displaystyle
you could use dfrac
from amsmath
.– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
I don't think it's Apollonian circles, because they don't intersect: en.wikipedia.org/wiki/Apollonian_gasket
– Henri Menke
2 hours ago
1
1
@HenriMenke I believe that the cover is correct.
rho
is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau
with rho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)– marmot
2 hours ago
@HenriMenke I believe that the cover is correct.
rho
is the sixth root of unity, i.e. rho=(1+sqrt{-3})/2=(1+mathrm{i}sqrt{3})/2=exp(2pimathrm{i}/6)
. I agree that these are not the standard Apollonius circles, which is why I wrote "some sort of Apollonius circles". While I believe to understand the inlay figure (which is the fundamental domain of the torus parameter tau
with rho
being the nontrivial selfdual point, I do not remember what the circles are even though I should.)– marmot
2 hours ago
|
show 2 more comments
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4
What have you tried so far?
– manooooh
4 hours ago
There is a rather straightforward part, the graphics, which can be done with TikZ (for instance) and a part which requires familiarity with the Chinese characters. It seems to me that anyone trying to answer this will have to know TikZ and these characters.
– marmot
4 hours ago
@marmot I think these characters is book name, these characters are not important.
– user450201
4 hours ago
Thank you for a really good question. I'm going to be up all night, trying to recreate what @marmot has done.
– GermanShepherd
2 hours ago