How to store variable value into an array inside a for loop in java
I need to calculate distance between 2 (points) latitudes and longitudes, one point is in an array and other is sent as parameter. The calculated distance should store in another array so that I can calculate minimum distance in an array. The problem is am not able to store that calculated distance into an array so plzz do help me out.
@Override
public MinimumDistanceModel getMinimumDistance(double latitude, double longitude) throws Exception {
try {
double lon1 = longitude;
double lat1 = latitude;
List<MinimumDistanceDomain> minDistDomain = minimumDistanceDAO.getFranchiseDetails();
for(MinimumDistanceDomain minimumDistanceDomain : minDistDomain) {
double lat2 = minimumDistanceDomain.getLatitude();
double lon2 = minimumDistanceDomain.getLongitude();
MinimumDistanceModel minimumDistanceModel = new MinimumDistanceModel();
minimumDistanceModel.setDistance1(CommonUtils.distance(lat1, lat2, lon1, lon2));
System.out.println(minimumDistanceModel.getDistance1());
Double distance = minimumDistanceModel.getDistance1();
}
} catch (Exception e) {
logger.info("Exception getMinimumDistance in DistanceServiceImpl" + e.getMessage());
}
return null;
}
`
Result of above code: It's just printing the distances between those 2 points, how do I return those distances in an array
java arrays
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
add a comment |
I need to calculate distance between 2 (points) latitudes and longitudes, one point is in an array and other is sent as parameter. The calculated distance should store in another array so that I can calculate minimum distance in an array. The problem is am not able to store that calculated distance into an array so plzz do help me out.
@Override
public MinimumDistanceModel getMinimumDistance(double latitude, double longitude) throws Exception {
try {
double lon1 = longitude;
double lat1 = latitude;
List<MinimumDistanceDomain> minDistDomain = minimumDistanceDAO.getFranchiseDetails();
for(MinimumDistanceDomain minimumDistanceDomain : minDistDomain) {
double lat2 = minimumDistanceDomain.getLatitude();
double lon2 = minimumDistanceDomain.getLongitude();
MinimumDistanceModel minimumDistanceModel = new MinimumDistanceModel();
minimumDistanceModel.setDistance1(CommonUtils.distance(lat1, lat2, lon1, lon2));
System.out.println(minimumDistanceModel.getDistance1());
Double distance = minimumDistanceModel.getDistance1();
}
} catch (Exception e) {
logger.info("Exception getMinimumDistance in DistanceServiceImpl" + e.getMessage());
}
return null;
}
`
Result of above code: It's just printing the distances between those 2 points, how do I return those distances in an array
java arrays
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
1
Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
3
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07
add a comment |
I need to calculate distance between 2 (points) latitudes and longitudes, one point is in an array and other is sent as parameter. The calculated distance should store in another array so that I can calculate minimum distance in an array. The problem is am not able to store that calculated distance into an array so plzz do help me out.
@Override
public MinimumDistanceModel getMinimumDistance(double latitude, double longitude) throws Exception {
try {
double lon1 = longitude;
double lat1 = latitude;
List<MinimumDistanceDomain> minDistDomain = minimumDistanceDAO.getFranchiseDetails();
for(MinimumDistanceDomain minimumDistanceDomain : minDistDomain) {
double lat2 = minimumDistanceDomain.getLatitude();
double lon2 = minimumDistanceDomain.getLongitude();
MinimumDistanceModel minimumDistanceModel = new MinimumDistanceModel();
minimumDistanceModel.setDistance1(CommonUtils.distance(lat1, lat2, lon1, lon2));
System.out.println(minimumDistanceModel.getDistance1());
Double distance = minimumDistanceModel.getDistance1();
}
} catch (Exception e) {
logger.info("Exception getMinimumDistance in DistanceServiceImpl" + e.getMessage());
}
return null;
}
`
Result of above code: It's just printing the distances between those 2 points, how do I return those distances in an array
java arrays
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
I need to calculate distance between 2 (points) latitudes and longitudes, one point is in an array and other is sent as parameter. The calculated distance should store in another array so that I can calculate minimum distance in an array. The problem is am not able to store that calculated distance into an array so plzz do help me out.
@Override
public MinimumDistanceModel getMinimumDistance(double latitude, double longitude) throws Exception {
try {
double lon1 = longitude;
double lat1 = latitude;
List<MinimumDistanceDomain> minDistDomain = minimumDistanceDAO.getFranchiseDetails();
for(MinimumDistanceDomain minimumDistanceDomain : minDistDomain) {
double lat2 = minimumDistanceDomain.getLatitude();
double lon2 = minimumDistanceDomain.getLongitude();
MinimumDistanceModel minimumDistanceModel = new MinimumDistanceModel();
minimumDistanceModel.setDistance1(CommonUtils.distance(lat1, lat2, lon1, lon2));
System.out.println(minimumDistanceModel.getDistance1());
Double distance = minimumDistanceModel.getDistance1();
}
} catch (Exception e) {
logger.info("Exception getMinimumDistance in DistanceServiceImpl" + e.getMessage());
}
return null;
}
`
Result of above code: It's just printing the distances between those 2 points, how do I return those distances in an array
java arrays
java arrays
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
edited Nov 22 '18 at 7:59
Bhavyashree N L
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
asked Nov 22 '18 at 7:50
Bhavyashree N LBhavyashree N L
11
11
1
Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
3
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07
add a comment |
1
Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
3
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07
1
1
Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
3
3
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07
add a comment |
1 Answer
1
active
oldest
votes
The below code will assign a value for each iteration, basically what I am saying is since you have the lat and long you can do a calc within each iteration to get the distance instead of using common utils . Key line here is this one testArray[i]=i;
var lat ;
var long;
var distance;
int testDistanceArray = new int[50];
for (int i = 0; i < testDistanceArray.length; i++) {
testDistanceArray[i]= lat -long ;
distance = testDistanceArray[i]
// that will give you the distance for each iteration
}
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
add a comment |
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1 Answer
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oldest
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oldest
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oldest
votes
The below code will assign a value for each iteration, basically what I am saying is since you have the lat and long you can do a calc within each iteration to get the distance instead of using common utils . Key line here is this one testArray[i]=i;
var lat ;
var long;
var distance;
int testDistanceArray = new int[50];
for (int i = 0; i < testDistanceArray.length; i++) {
testDistanceArray[i]= lat -long ;
distance = testDistanceArray[i]
// that will give you the distance for each iteration
}
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
add a comment |
The below code will assign a value for each iteration, basically what I am saying is since you have the lat and long you can do a calc within each iteration to get the distance instead of using common utils . Key line here is this one testArray[i]=i;
var lat ;
var long;
var distance;
int testDistanceArray = new int[50];
for (int i = 0; i < testDistanceArray.length; i++) {
testDistanceArray[i]= lat -long ;
distance = testDistanceArray[i]
// that will give you the distance for each iteration
}
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
add a comment |
The below code will assign a value for each iteration, basically what I am saying is since you have the lat and long you can do a calc within each iteration to get the distance instead of using common utils . Key line here is this one testArray[i]=i;
var lat ;
var long;
var distance;
int testDistanceArray = new int[50];
for (int i = 0; i < testDistanceArray.length; i++) {
testDistanceArray[i]= lat -long ;
distance = testDistanceArray[i]
// that will give you the distance for each iteration
}
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
The below code will assign a value for each iteration, basically what I am saying is since you have the lat and long you can do a calc within each iteration to get the distance instead of using common utils . Key line here is this one testArray[i]=i;
var lat ;
var long;
var distance;
int testDistanceArray = new int[50];
for (int i = 0; i < testDistanceArray.length; i++) {
testDistanceArray[i]= lat -long ;
distance = testDistanceArray[i]
// that will give you the distance for each iteration
}
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
edited Nov 22 '18 at 8:24
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
answered Nov 22 '18 at 8:13
ZidaneZidane
4442721
4442721
add a comment |
add a comment |
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Questions seeking debugging help ("why isn't this code working?") must include the desired behavior, a specific problem or error and the shortest code necessary to reproduce it in the question itself. Questions without a clear problem statement are not useful to other readers. See: How to create a Minimal, Complete, and Verifiable example.
– Joe C
Nov 22 '18 at 7:52
3
Why do you need to store things in an array to calculate the minimum? Just keep the minimum you have seen so far in a variable.
– Andy Turner
Nov 22 '18 at 7:52
@JoeC i have updated question with current behaviour
– Bhavyashree N L
Nov 22 '18 at 8:01
@AndyTurner How to keep the minimum without storing it into an array
– Bhavyashree N L
Nov 22 '18 at 8:02
Like Andy mentioned you store it in a variable, the same way you store values in lon1 and lat1
– Joakim Danielson
Nov 22 '18 at 8:07