how to solve XQ=0 type matrix in Matlab?
I have 2 matrices, Q and X such that XQ=0. X is 1x16 matrix with unknown values i.e. X=[x1, x2, x3, x4, ...x16]. Q is 16x16 real valued matrix. How can I find values of X in Matlab? code please...
matlab math matrix linear-algebra
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
add a comment |
I have 2 matrices, Q and X such that XQ=0. X is 1x16 matrix with unknown values i.e. X=[x1, x2, x3, x4, ...x16]. Q is 16x16 real valued matrix. How can I find values of X in Matlab? code please...
matlab math matrix linear-algebra
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24
add a comment |
I have 2 matrices, Q and X such that XQ=0. X is 1x16 matrix with unknown values i.e. X=[x1, x2, x3, x4, ...x16]. Q is 16x16 real valued matrix. How can I find values of X in Matlab? code please...
matlab math matrix linear-algebra
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
I have 2 matrices, Q and X such that XQ=0. X is 1x16 matrix with unknown values i.e. X=[x1, x2, x3, x4, ...x16]. Q is 16x16 real valued matrix. How can I find values of X in Matlab? code please...
matlab math matrix linear-algebra
matlab math matrix linear-algebra
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
asked Nov 23 '18 at 5:49
Abdullah1Abdullah1
134
134
uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24
add a comment |
uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24
uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24
uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24
add a comment |
2 Answers
2
active
oldest
votes
Look into the null function. https://www.mathworks.com/help/matlab/ref/null.html
It provides the solution to the problem
A*x=0
The solutions to
Q'*X' = 0
are the same as
X*Q = 0
So
X = null(Q')'
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
add a comment |
If det(Q)~=0, then unique solution is x=zeros(1,16).
If det(Q)==0, the set of solutions form a vector space of dimension r=16-rank(Q). In fact, the solutions are the kernel of Q, so you can use the function eig to find the corresponding eigenvectors, which form a basis of your solutions.
answered Nov 23 '18 at 13:39
SergioSergio
613
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
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active
oldest
votes
Look into the null function. https://www.mathworks.com/help/matlab/ref/null.html
It provides the solution to the problem
A*x=0
The solutions to
Q'*X' = 0
are the same as
X*Q = 0
So
X = null(Q')'
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
add a comment |
Look into the null function. https://www.mathworks.com/help/matlab/ref/null.html
It provides the solution to the problem
A*x=0
The solutions to
Q'*X' = 0
are the same as
X*Q = 0
So
X = null(Q')'
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
add a comment |
Look into the null function. https://www.mathworks.com/help/matlab/ref/null.html
It provides the solution to the problem
A*x=0
The solutions to
Q'*X' = 0
are the same as
X*Q = 0
So
X = null(Q')'
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
Look into the null function. https://www.mathworks.com/help/matlab/ref/null.html
It provides the solution to the problem
A*x=0
The solutions to
Q'*X' = 0
are the same as
X*Q = 0
So
X = null(Q')'
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
answered Nov 23 '18 at 15:20
Jonathan ChiangJonathan Chiang
936
936
add a comment |
add a comment |
If det(Q)~=0, then unique solution is x=zeros(1,16).
If det(Q)==0, the set of solutions form a vector space of dimension r=16-rank(Q). In fact, the solutions are the kernel of Q, so you can use the function eig to find the corresponding eigenvectors, which form a basis of your solutions.
answered Nov 23 '18 at 13:39
SergioSergio
613
add a comment |
If det(Q)~=0, then unique solution is x=zeros(1,16).
If det(Q)==0, the set of solutions form a vector space of dimension r=16-rank(Q). In fact, the solutions are the kernel of Q, so you can use the function eig to find the corresponding eigenvectors, which form a basis of your solutions.
answered Nov 23 '18 at 13:39
SergioSergio
613
add a comment |
If det(Q)~=0, then unique solution is x=zeros(1,16).
If det(Q)==0, the set of solutions form a vector space of dimension r=16-rank(Q). In fact, the solutions are the kernel of Q, so you can use the function eig to find the corresponding eigenvectors, which form a basis of your solutions.
answered Nov 23 '18 at 13:39
SergioSergio
613
If det(Q)~=0, then unique solution is x=zeros(1,16).
If det(Q)==0, the set of solutions form a vector space of dimension r=16-rank(Q). In fact, the solutions are the kernel of Q, so you can use the function eig to find the corresponding eigenvectors, which form a basis of your solutions.
answered Nov 23 '18 at 13:39
SergioSergio
613
answered Nov 23 '18 at 13:39
SergioSergio
613
answered Nov 23 '18 at 13:39
SergioSergio
613
answered Nov 23 '18 at 13:39
SergioSergio
613
613
add a comment |
add a comment |
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uk.mathworks.com/help/matlab/ref/mrdivide.html Matrix division.
– Ander Biguri
Nov 23 '18 at 11:24