ugettext_lazy not working in model choices when using format functions
I am trying to translate choices from my models.py
from django.utils.translation import ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = _('Level %s') % str(r)
GRID_LEVEL.append((str(r), text))
I have tried brackets and %(var)s syntax but still no luck. Any help would be appreciated
django localization
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I am trying to translate choices from my models.py
from django.utils.translation import ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = _('Level %s') % str(r)
GRID_LEVEL.append((str(r), text))
I have tried brackets and %(var)s syntax but still no luck. Any help would be appreciated
django localization
add a comment |
I am trying to translate choices from my models.py
from django.utils.translation import ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = _('Level %s') % str(r)
GRID_LEVEL.append((str(r), text))
I have tried brackets and %(var)s syntax but still no luck. Any help would be appreciated
django localization
I am trying to translate choices from my models.py
from django.utils.translation import ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = _('Level %s') % str(r)
GRID_LEVEL.append((str(r), text))
I have tried brackets and %(var)s syntax but still no luck. Any help would be appreciated
django localization
django localization
asked Nov 22 '18 at 22:06
AUBGAUBG
434
434
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1 Answer
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Found the solution to this. Concatenation, formatting etc. doesn't work on lazy objects. I instead used string_concat
for Django 1.10 which returns a lazy object.
from django.utils.translation import string_concat, ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = string_concat(_('Level '), str(r))
GRID_LEVEL.append((str(r), text))
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Found the solution to this. Concatenation, formatting etc. doesn't work on lazy objects. I instead used string_concat
for Django 1.10 which returns a lazy object.
from django.utils.translation import string_concat, ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = string_concat(_('Level '), str(r))
GRID_LEVEL.append((str(r), text))
add a comment |
Found the solution to this. Concatenation, formatting etc. doesn't work on lazy objects. I instead used string_concat
for Django 1.10 which returns a lazy object.
from django.utils.translation import string_concat, ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = string_concat(_('Level '), str(r))
GRID_LEVEL.append((str(r), text))
add a comment |
Found the solution to this. Concatenation, formatting etc. doesn't work on lazy objects. I instead used string_concat
for Django 1.10 which returns a lazy object.
from django.utils.translation import string_concat, ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = string_concat(_('Level '), str(r))
GRID_LEVEL.append((str(r), text))
Found the solution to this. Concatenation, formatting etc. doesn't work on lazy objects. I instead used string_concat
for Django 1.10 which returns a lazy object.
from django.utils.translation import string_concat, ugettext_lazy as _
GRID_LEVEL = [(None, 'null')]
for r in range(-15, 15):
text = string_concat(_('Level '), str(r))
GRID_LEVEL.append((str(r), text))
answered Nov 23 '18 at 16:38
AUBGAUBG
434
434
add a comment |
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