Z and T score to probability in python3
I'm developing a basic calculator that will take some data and return the Z and T scores, now, I need to check this values against the T and Z tables, however, the only idea i get, is to use 2D array, and recreate the same lists that any person would use to calculate them, but that would mean loading a big table into the memory, is there any function i could use?
python-3.x probability
add a comment |
I'm developing a basic calculator that will take some data and return the Z and T scores, now, I need to check this values against the T and Z tables, however, the only idea i get, is to use 2D array, and recreate the same lists that any person would use to calculate them, but that would mean loading a big table into the memory, is there any function i could use?
python-3.x probability
add a comment |
I'm developing a basic calculator that will take some data and return the Z and T scores, now, I need to check this values against the T and Z tables, however, the only idea i get, is to use 2D array, and recreate the same lists that any person would use to calculate them, but that would mean loading a big table into the memory, is there any function i could use?
python-3.x probability
I'm developing a basic calculator that will take some data and return the Z and T scores, now, I need to check this values against the T and Z tables, however, the only idea i get, is to use 2D array, and recreate the same lists that any person would use to calculate them, but that would mean loading a big table into the memory, is there any function i could use?
python-3.x probability
python-3.x probability
asked Nov 22 '18 at 22:19
Fred O.Fred O.
114
114
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I am assuming you want to convert the Z and T scores to p-values of the corresponding distributions, the z-distribution and the t-distribution. To do so you can use the following survival functions from the library 'scipy.stats':
For the Z score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.norm.sf(abs(Z))
For the T score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.t.sf(abs(T))
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53438590%2fz-and-t-score-to-probability-in-python3%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I am assuming you want to convert the Z and T scores to p-values of the corresponding distributions, the z-distribution and the t-distribution. To do so you can use the following survival functions from the library 'scipy.stats':
For the Z score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.norm.sf(abs(Z))
For the T score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.t.sf(abs(T))
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
add a comment |
I am assuming you want to convert the Z and T scores to p-values of the corresponding distributions, the z-distribution and the t-distribution. To do so you can use the following survival functions from the library 'scipy.stats':
For the Z score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.norm.sf(abs(Z))
For the T score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.t.sf(abs(T))
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
add a comment |
I am assuming you want to convert the Z and T scores to p-values of the corresponding distributions, the z-distribution and the t-distribution. To do so you can use the following survival functions from the library 'scipy.stats':
For the Z score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.norm.sf(abs(Z))
For the T score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.t.sf(abs(T))
I am assuming you want to convert the Z and T scores to p-values of the corresponding distributions, the z-distribution and the t-distribution. To do so you can use the following survival functions from the library 'scipy.stats':
For the Z score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.norm.sf(abs(Z))
For the T score:
# one-sided (multiply by 2 if two-sided)
p_value = scipy.stats.t.sf(abs(T))
answered Nov 23 '18 at 0:58
DavidPMDavidPM
33519
33519
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
add a comment |
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
Have a question, shouldnt i need to input the degrees of freedom?
– Fred O.
Nov 27 '18 at 1:14
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
No, these tests do not have degrees of freedom. As for the 'abs()' (the absolute value), I wrote a comment yesterday but I do not see it anymore. For simplicity, yes, keep the absolute value and avoid differentiating between positive and negative values. Such distributions are symmetric.
– DavidPM
Nov 27 '18 at 8:41
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53438590%2fz-and-t-score-to-probability-in-python3%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown