Use Sequelize on for loop findAll query and merge result
I'm coding opensource project in the university course
It is a function to search the value of another table by dividing input keyword by comma.
under this example data
Python,CPP,Csharp
var keyword = result[0].keyword;
var keyword_arr = ;
var keyword_split = keyword.split(',');
for (var i in keyword_split)
{
keyword_arr.push(keyword_split[i]);
}
I have succeeded in separating them with commas like above, but I'm looking for a loop in sequelize.
"Error: Can not set headers after they are sent."
An error is returned and is not executed.
I want to output the results merged. What should I do?
my code is
for (i = 0; i < keyword_arr.length; i++) {
query += models.contents.findAll({
where: {keyword: {like: '%' + keyword_arr[i] + '%'}},
raw: true
});
}
Regards.
mysql node.js sequelize.js
edited Nov 22 '18 at 14:37
Mehran
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
add a comment |
I'm coding opensource project in the university course
It is a function to search the value of another table by dividing input keyword by comma.
under this example data
Python,CPP,Csharp
var keyword = result[0].keyword;
var keyword_arr = ;
var keyword_split = keyword.split(',');
for (var i in keyword_split)
{
keyword_arr.push(keyword_split[i]);
}
I have succeeded in separating them with commas like above, but I'm looking for a loop in sequelize.
"Error: Can not set headers after they are sent."
An error is returned and is not executed.
I want to output the results merged. What should I do?
my code is
for (i = 0; i < keyword_arr.length; i++) {
query += models.contents.findAll({
where: {keyword: {like: '%' + keyword_arr[i] + '%'}},
raw: true
});
}
Regards.
mysql node.js sequelize.js
edited Nov 22 '18 at 14:37
Mehran
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
add a comment |
I'm coding opensource project in the university course
It is a function to search the value of another table by dividing input keyword by comma.
under this example data
Python,CPP,Csharp
var keyword = result[0].keyword;
var keyword_arr = ;
var keyword_split = keyword.split(',');
for (var i in keyword_split)
{
keyword_arr.push(keyword_split[i]);
}
I have succeeded in separating them with commas like above, but I'm looking for a loop in sequelize.
"Error: Can not set headers after they are sent."
An error is returned and is not executed.
I want to output the results merged. What should I do?
my code is
for (i = 0; i < keyword_arr.length; i++) {
query += models.contents.findAll({
where: {keyword: {like: '%' + keyword_arr[i] + '%'}},
raw: true
});
}
Regards.
mysql node.js sequelize.js
edited Nov 22 '18 at 14:37
Mehran
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
I'm coding opensource project in the university course
It is a function to search the value of another table by dividing input keyword by comma.
under this example data
Python,CPP,Csharp
var keyword = result[0].keyword;
var keyword_arr = ;
var keyword_split = keyword.split(',');
for (var i in keyword_split)
{
keyword_arr.push(keyword_split[i]);
}
I have succeeded in separating them with commas like above, but I'm looking for a loop in sequelize.
"Error: Can not set headers after they are sent."
An error is returned and is not executed.
I want to output the results merged. What should I do?
my code is
for (i = 0; i < keyword_arr.length; i++) {
query += models.contents.findAll({
where: {keyword: {like: '%' + keyword_arr[i] + '%'}},
raw: true
});
}
Regards.
mysql node.js sequelize.js
mysql node.js sequelize.js
edited Nov 22 '18 at 14:37
Mehran
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
edited Nov 22 '18 at 14:37
Mehran
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
edited Nov 22 '18 at 14:37
Mehran
1831311
edited Nov 22 '18 at 14:37
Mehran
1831311
edited Nov 22 '18 at 14:37
Mehran
1831311
1831311
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
asked Nov 22 '18 at 14:22
Seonggwon YoonSeonggwon Yoon
165112
165112
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You were in the right direction , but here it his how you can do :
queries = ;
for (i = 0; i < keyword_arr.length; i++) {
queries.push({keyword: {like: '%' + keyword_arr[i] + '%'}});
}
models.contents.findAll({
where: {
$or : queries
}
raw: true
}).then(results => {
console.log(results); // <---- Check this
})
NOTES :
models.contents.findAll() //<---- Returns promises
You can't just combine the promises by += as its not string or number
like that
In your case , it will create and run the query for each tag , so
that's not proper way of doing , you should combine the tags and create a single query as I did
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433004%2fuse-sequelize-on-for-loop-findall-query-and-merge-result%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You were in the right direction , but here it his how you can do :
queries = ;
for (i = 0; i < keyword_arr.length; i++) {
queries.push({keyword: {like: '%' + keyword_arr[i] + '%'}});
}
models.contents.findAll({
where: {
$or : queries
}
raw: true
}).then(results => {
console.log(results); // <---- Check this
})
NOTES :
models.contents.findAll() //<---- Returns promises
You can't just combine the promises by += as its not string or number
like that
In your case , it will create and run the query for each tag , so
that's not proper way of doing , you should combine the tags and create a single query as I did
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
add a comment |
You were in the right direction , but here it his how you can do :
queries = ;
for (i = 0; i < keyword_arr.length; i++) {
queries.push({keyword: {like: '%' + keyword_arr[i] + '%'}});
}
models.contents.findAll({
where: {
$or : queries
}
raw: true
}).then(results => {
console.log(results); // <---- Check this
})
NOTES :
models.contents.findAll() //<---- Returns promises
You can't just combine the promises by += as its not string or number
like that
In your case , it will create and run the query for each tag , so
that's not proper way of doing , you should combine the tags and create a single query as I did
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
add a comment |
You were in the right direction , but here it his how you can do :
queries = ;
for (i = 0; i < keyword_arr.length; i++) {
queries.push({keyword: {like: '%' + keyword_arr[i] + '%'}});
}
models.contents.findAll({
where: {
$or : queries
}
raw: true
}).then(results => {
console.log(results); // <---- Check this
})
NOTES :
models.contents.findAll() //<---- Returns promises
You can't just combine the promises by += as its not string or number
like that
In your case , it will create and run the query for each tag , so
that's not proper way of doing , you should combine the tags and create a single query as I did
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
You were in the right direction , but here it his how you can do :
queries = ;
for (i = 0; i < keyword_arr.length; i++) {
queries.push({keyword: {like: '%' + keyword_arr[i] + '%'}});
}
models.contents.findAll({
where: {
$or : queries
}
raw: true
}).then(results => {
console.log(results); // <---- Check this
})
NOTES :
models.contents.findAll() //<---- Returns promises
You can't just combine the promises by += as its not string or number
like that
In your case , it will create and run the query for each tag , so
that's not proper way of doing , you should combine the tags and create a single query as I did
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
edited Nov 22 '18 at 14:39
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
answered Nov 22 '18 at 14:34
Vivek DoshiVivek Doshi
21.7k33451
21.7k33451
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
add a comment |
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Thank you very much!
– Seonggwon Yoon
Nov 22 '18 at 14:39
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
Happy Coding :)
– Vivek Doshi
Nov 22 '18 at 14:43
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53433004%2fuse-sequelize-on-for-loop-findall-query-and-merge-result%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
