QGIS: use geometry from different layer in symbology expression
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 10 hours ago
Matthias Kuhn
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 10 hours ago
Matthias Kuhn
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 10 hours ago
Matthias Kuhn
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
qgis symbology z-value
edited 10 hours ago
Matthias Kuhn
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
edited 10 hours ago
Matthias Kuhn
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
edited 10 hours ago
Matthias Kuhn
18.9k14890
edited 10 hours ago
Matthias Kuhn
18.9k14890
edited 10 hours ago
Matthias Kuhn
18.9k14890
18.9k14890
asked 10 hours ago
CaptainAhabCaptainAhab
657
asked 10 hours ago
CaptainAhabCaptainAhab
657
asked 10 hours ago
CaptainAhabCaptainAhab
657
657
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 9 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 9 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 9 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 9 hours ago
VitruviusVitruvius
439210
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 9 hours ago
VitruviusVitruvius
439210
edited 8 hours ago
answered 9 hours ago
VitruviusVitruvius
439210
answered 9 hours ago
VitruviusVitruvius
439210
answered 9 hours ago
VitruviusVitruvius
439210
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
add a comment |
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
8 hours ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
8 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
Nope it wouldn't.
– Vitruvius
2 hours ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
That's surprising... Did you try?
– Matthias Kuhn
48 mins ago
add a comment |
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