Passing a string slice, returning a string slice. But who owns it?





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1















I'm a beginner to Rust and just learning the ownership concept.



I'm using this function to reverse a String



fn reverse(input: &str) -> String {
//we are receiving a borrowed value,
input
//get an iterator of chars from the string slice
.chars()
//Goes between two iterators.
//From the doc: double-ended iterator with the direction inverted.
.rev()
//collect into a String
.collect::<String>()
}

fn process_reverse_case(input: &str, expected: &str) {
assert_eq!(&reverse(input), expected)
}

fn main() {
process_reverse_case("robot", "tobor");
}


I would like to understand who owns robot and tobor.




  • I'm passing a borrowed value. Which is a string slice.

  • I understand this can't be modified. So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!. Am I right?

  • But as the process of reversing + collection happens inside reverse, the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?

  • The above question might have been solved by the compiler at compile time. Am I right?










share|improve this question































    1















    I'm a beginner to Rust and just learning the ownership concept.



    I'm using this function to reverse a String



    fn reverse(input: &str) -> String {
    //we are receiving a borrowed value,
    input
    //get an iterator of chars from the string slice
    .chars()
    //Goes between two iterators.
    //From the doc: double-ended iterator with the direction inverted.
    .rev()
    //collect into a String
    .collect::<String>()
    }

    fn process_reverse_case(input: &str, expected: &str) {
    assert_eq!(&reverse(input), expected)
    }

    fn main() {
    process_reverse_case("robot", "tobor");
    }


    I would like to understand who owns robot and tobor.




    • I'm passing a borrowed value. Which is a string slice.

    • I understand this can't be modified. So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!. Am I right?

    • But as the process of reversing + collection happens inside reverse, the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?

    • The above question might have been solved by the compiler at compile time. Am I right?










    share|improve this question



























      1












      1








      1








      I'm a beginner to Rust and just learning the ownership concept.



      I'm using this function to reverse a String



      fn reverse(input: &str) -> String {
      //we are receiving a borrowed value,
      input
      //get an iterator of chars from the string slice
      .chars()
      //Goes between two iterators.
      //From the doc: double-ended iterator with the direction inverted.
      .rev()
      //collect into a String
      .collect::<String>()
      }

      fn process_reverse_case(input: &str, expected: &str) {
      assert_eq!(&reverse(input), expected)
      }

      fn main() {
      process_reverse_case("robot", "tobor");
      }


      I would like to understand who owns robot and tobor.




      • I'm passing a borrowed value. Which is a string slice.

      • I understand this can't be modified. So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!. Am I right?

      • But as the process of reversing + collection happens inside reverse, the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?

      • The above question might have been solved by the compiler at compile time. Am I right?










      share|improve this question
















      I'm a beginner to Rust and just learning the ownership concept.



      I'm using this function to reverse a String



      fn reverse(input: &str) -> String {
      //we are receiving a borrowed value,
      input
      //get an iterator of chars from the string slice
      .chars()
      //Goes between two iterators.
      //From the doc: double-ended iterator with the direction inverted.
      .rev()
      //collect into a String
      .collect::<String>()
      }

      fn process_reverse_case(input: &str, expected: &str) {
      assert_eq!(&reverse(input), expected)
      }

      fn main() {
      process_reverse_case("robot", "tobor");
      }


      I would like to understand who owns robot and tobor.




      • I'm passing a borrowed value. Which is a string slice.

      • I understand this can't be modified. So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!. Am I right?

      • But as the process of reversing + collection happens inside reverse, the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?

      • The above question might have been solved by the compiler at compile time. Am I right?







      rust






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 23 '18 at 11:11







      clmno

















      asked Nov 23 '18 at 10:42









      clmnoclmno

      734416




      734416
























          1 Answer
          1






          active

          oldest

          votes


















          5














          Your claims are mostly wrong, let me try to correct them.




          Passing a string slice, returning a string slice




          fn reverse(input: &str) -> String you are accepting a string slice, but returning a String. A String "has ownership over the contents of the string".






          I understand this [a string slice] can't be modified




          You can modify a &mut str, e.g.



          fn to_lower(s: &mut str) {
          s.make_ascii_lowercase();
          }

          fn main() {
          let mut a = String::from("ABC");
          println!("{}", a);
          to_lower(&mut a);
          println!("{}", a);
          }


          (playground)






          So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!




          No. You collect it into a string, that is what collect::<String>() is for. Also your function reverse returns a String.

          This means, that you are calling the function reverse, which returns a String and you are passing that String as the first "argument" to the assert_eq! macro.






          the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?




          No, how should it? That's all done inside of the reverse function. assert_eq! just takes two parameters. Where they come from is uncertain and not needed to know.






          assert_eq!(&reverse(input), expected)




          What happens in this line is, that you are calling your reverse function with input as parameter. But normally you can't compare &T with T (a reference to something with an actual instance of something), that's where the & (ampersand) in front of reverse comes into play. String implements the Deref trait which means it can be seen as a str as well (see the doc for Deref). But now you are trying to compare a str with &str, which does not work and that's why you put & in front, so you actually end up with &str and &str which you can compare with ==.






          I would like to understand who ownes robot and tobor.




          Nobody. In fact they live inside of the data section in the ELF/Binary itself. They don't have an owner per se, but can be used as &str wherever needed.






          share|improve this answer


























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            Your claims are mostly wrong, let me try to correct them.




            Passing a string slice, returning a string slice




            fn reverse(input: &str) -> String you are accepting a string slice, but returning a String. A String "has ownership over the contents of the string".






            I understand this [a string slice] can't be modified




            You can modify a &mut str, e.g.



            fn to_lower(s: &mut str) {
            s.make_ascii_lowercase();
            }

            fn main() {
            let mut a = String::from("ABC");
            println!("{}", a);
            to_lower(&mut a);
            println!("{}", a);
            }


            (playground)






            So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!




            No. You collect it into a string, that is what collect::<String>() is for. Also your function reverse returns a String.

            This means, that you are calling the function reverse, which returns a String and you are passing that String as the first "argument" to the assert_eq! macro.






            the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?




            No, how should it? That's all done inside of the reverse function. assert_eq! just takes two parameters. Where they come from is uncertain and not needed to know.






            assert_eq!(&reverse(input), expected)




            What happens in this line is, that you are calling your reverse function with input as parameter. But normally you can't compare &T with T (a reference to something with an actual instance of something), that's where the & (ampersand) in front of reverse comes into play. String implements the Deref trait which means it can be seen as a str as well (see the doc for Deref). But now you are trying to compare a str with &str, which does not work and that's why you put & in front, so you actually end up with &str and &str which you can compare with ==.






            I would like to understand who ownes robot and tobor.




            Nobody. In fact they live inside of the data section in the ELF/Binary itself. They don't have an owner per se, but can be used as &str wherever needed.






            share|improve this answer






























              5














              Your claims are mostly wrong, let me try to correct them.




              Passing a string slice, returning a string slice




              fn reverse(input: &str) -> String you are accepting a string slice, but returning a String. A String "has ownership over the contents of the string".






              I understand this [a string slice] can't be modified




              You can modify a &mut str, e.g.



              fn to_lower(s: &mut str) {
              s.make_ascii_lowercase();
              }

              fn main() {
              let mut a = String::from("ABC");
              println!("{}", a);
              to_lower(&mut a);
              println!("{}", a);
              }


              (playground)






              So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!




              No. You collect it into a string, that is what collect::<String>() is for. Also your function reverse returns a String.

              This means, that you are calling the function reverse, which returns a String and you are passing that String as the first "argument" to the assert_eq! macro.






              the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?




              No, how should it? That's all done inside of the reverse function. assert_eq! just takes two parameters. Where they come from is uncertain and not needed to know.






              assert_eq!(&reverse(input), expected)




              What happens in this line is, that you are calling your reverse function with input as parameter. But normally you can't compare &T with T (a reference to something with an actual instance of something), that's where the & (ampersand) in front of reverse comes into play. String implements the Deref trait which means it can be seen as a str as well (see the doc for Deref). But now you are trying to compare a str with &str, which does not work and that's why you put & in front, so you actually end up with &str and &str which you can compare with ==.






              I would like to understand who ownes robot and tobor.




              Nobody. In fact they live inside of the data section in the ELF/Binary itself. They don't have an owner per se, but can be used as &str wherever needed.






              share|improve this answer




























                5












                5








                5







                Your claims are mostly wrong, let me try to correct them.




                Passing a string slice, returning a string slice




                fn reverse(input: &str) -> String you are accepting a string slice, but returning a String. A String "has ownership over the contents of the string".






                I understand this [a string slice] can't be modified




                You can modify a &mut str, e.g.



                fn to_lower(s: &mut str) {
                s.make_ascii_lowercase();
                }

                fn main() {
                let mut a = String::from("ABC");
                println!("{}", a);
                to_lower(&mut a);
                println!("{}", a);
                }


                (playground)






                So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!




                No. You collect it into a string, that is what collect::<String>() is for. Also your function reverse returns a String.

                This means, that you are calling the function reverse, which returns a String and you are passing that String as the first "argument" to the assert_eq! macro.






                the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?




                No, how should it? That's all done inside of the reverse function. assert_eq! just takes two parameters. Where they come from is uncertain and not needed to know.






                assert_eq!(&reverse(input), expected)




                What happens in this line is, that you are calling your reverse function with input as parameter. But normally you can't compare &T with T (a reference to something with an actual instance of something), that's where the & (ampersand) in front of reverse comes into play. String implements the Deref trait which means it can be seen as a str as well (see the doc for Deref). But now you are trying to compare a str with &str, which does not work and that's why you put & in front, so you actually end up with &str and &str which you can compare with ==.






                I would like to understand who ownes robot and tobor.




                Nobody. In fact they live inside of the data section in the ELF/Binary itself. They don't have an owner per se, but can be used as &str wherever needed.






                share|improve this answer















                Your claims are mostly wrong, let me try to correct them.




                Passing a string slice, returning a string slice




                fn reverse(input: &str) -> String you are accepting a string slice, but returning a String. A String "has ownership over the contents of the string".






                I understand this [a string slice] can't be modified




                You can modify a &mut str, e.g.



                fn to_lower(s: &mut str) {
                s.make_ascii_lowercase();
                }

                fn main() {
                let mut a = String::from("ABC");
                println!("{}", a);
                to_lower(&mut a);
                println!("{}", a);
                }


                (playground)






                So when we are collecting the reversed string, I think we are collecting it into a argument 1 of assert_eq!




                No. You collect it into a string, that is what collect::<String>() is for. Also your function reverse returns a String.

                This means, that you are calling the function reverse, which returns a String and you are passing that String as the first "argument" to the assert_eq! macro.






                the memory needed keeps increasing. Does argument 1 of assert_eq! account for that?




                No, how should it? That's all done inside of the reverse function. assert_eq! just takes two parameters. Where they come from is uncertain and not needed to know.






                assert_eq!(&reverse(input), expected)




                What happens in this line is, that you are calling your reverse function with input as parameter. But normally you can't compare &T with T (a reference to something with an actual instance of something), that's where the & (ampersand) in front of reverse comes into play. String implements the Deref trait which means it can be seen as a str as well (see the doc for Deref). But now you are trying to compare a str with &str, which does not work and that's why you put & in front, so you actually end up with &str and &str which you can compare with ==.






                I would like to understand who ownes robot and tobor.




                Nobody. In fact they live inside of the data section in the ELF/Binary itself. They don't have an owner per se, but can be used as &str wherever needed.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 23 '18 at 11:32

























                answered Nov 23 '18 at 11:04









                hellowhellow

                5,44952344




                5,44952344
































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