For loop inside another while not iterating right in c++












0














So basically my problem is for loop inside while loop that's not iterating right.



#include <iostream>
#include <math.h>

using namespace std;

void obl(long long int n){
long long int h = pow(n, n),
ar[n][h],
countH = 1;

//Filling array with 0's
for(int i = 0; i < n; i++){
for(int z = 0; z < h; z++){
ar[i][z] = 0;
}
}


while(countH != h){

for(int u = 0; u < n; u++){
for(int y = 0 ; y < n; y++){
ar[y][countH] = ar[y][countH - 1];
}

if(u == 0) ar[u][countH] = ar[u][countH] + 1;

if(ar[u][countH] > n - 1){
ar[u][countH] = 0;
ar[u + 1][countH] += 1;
}

cout<< ar[u][countH] << " ";
}

cout<<endl;

countH++;
}

}

int main()
{
obl(2);
}


and the output from cmd for input = 2 looks like this:



Give N:
2
1 0
1 0
1 0


When the output for 2 should be



Give N:
2
1 0
0 1
1 1


Or at least that's what I'm trying to do.










share|improve this question




















  • 2




    ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
    – user4581301
    Nov 20 at 0:23












  • Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
    – user4581301
    Nov 20 at 0:26










  • Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
    – Hekmatyar
    Nov 20 at 0:29








  • 3




    The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
    – user4581301
    Nov 20 at 0:30










  • With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
    – Phil1970
    Nov 20 at 1:46
















0














So basically my problem is for loop inside while loop that's not iterating right.



#include <iostream>
#include <math.h>

using namespace std;

void obl(long long int n){
long long int h = pow(n, n),
ar[n][h],
countH = 1;

//Filling array with 0's
for(int i = 0; i < n; i++){
for(int z = 0; z < h; z++){
ar[i][z] = 0;
}
}


while(countH != h){

for(int u = 0; u < n; u++){
for(int y = 0 ; y < n; y++){
ar[y][countH] = ar[y][countH - 1];
}

if(u == 0) ar[u][countH] = ar[u][countH] + 1;

if(ar[u][countH] > n - 1){
ar[u][countH] = 0;
ar[u + 1][countH] += 1;
}

cout<< ar[u][countH] << " ";
}

cout<<endl;

countH++;
}

}

int main()
{
obl(2);
}


and the output from cmd for input = 2 looks like this:



Give N:
2
1 0
1 0
1 0


When the output for 2 should be



Give N:
2
1 0
0 1
1 1


Or at least that's what I'm trying to do.










share|improve this question




















  • 2




    ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
    – user4581301
    Nov 20 at 0:23












  • Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
    – user4581301
    Nov 20 at 0:26










  • Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
    – Hekmatyar
    Nov 20 at 0:29








  • 3




    The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
    – user4581301
    Nov 20 at 0:30










  • With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
    – Phil1970
    Nov 20 at 1:46














0












0








0







So basically my problem is for loop inside while loop that's not iterating right.



#include <iostream>
#include <math.h>

using namespace std;

void obl(long long int n){
long long int h = pow(n, n),
ar[n][h],
countH = 1;

//Filling array with 0's
for(int i = 0; i < n; i++){
for(int z = 0; z < h; z++){
ar[i][z] = 0;
}
}


while(countH != h){

for(int u = 0; u < n; u++){
for(int y = 0 ; y < n; y++){
ar[y][countH] = ar[y][countH - 1];
}

if(u == 0) ar[u][countH] = ar[u][countH] + 1;

if(ar[u][countH] > n - 1){
ar[u][countH] = 0;
ar[u + 1][countH] += 1;
}

cout<< ar[u][countH] << " ";
}

cout<<endl;

countH++;
}

}

int main()
{
obl(2);
}


and the output from cmd for input = 2 looks like this:



Give N:
2
1 0
1 0
1 0


When the output for 2 should be



Give N:
2
1 0
0 1
1 1


Or at least that's what I'm trying to do.










share|improve this question















So basically my problem is for loop inside while loop that's not iterating right.



#include <iostream>
#include <math.h>

using namespace std;

void obl(long long int n){
long long int h = pow(n, n),
ar[n][h],
countH = 1;

//Filling array with 0's
for(int i = 0; i < n; i++){
for(int z = 0; z < h; z++){
ar[i][z] = 0;
}
}


while(countH != h){

for(int u = 0; u < n; u++){
for(int y = 0 ; y < n; y++){
ar[y][countH] = ar[y][countH - 1];
}

if(u == 0) ar[u][countH] = ar[u][countH] + 1;

if(ar[u][countH] > n - 1){
ar[u][countH] = 0;
ar[u + 1][countH] += 1;
}

cout<< ar[u][countH] << " ";
}

cout<<endl;

countH++;
}

}

int main()
{
obl(2);
}


and the output from cmd for input = 2 looks like this:



Give N:
2
1 0
1 0
1 0


When the output for 2 should be



Give N:
2
1 0
0 1
1 1


Or at least that's what I'm trying to do.







c++ loops iteration






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 at 0:32









user4581301

19.5k51831




19.5k51831










asked Nov 20 at 0:18









Hekmatyar

113




113








  • 2




    ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
    – user4581301
    Nov 20 at 0:23












  • Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
    – user4581301
    Nov 20 at 0:26










  • Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
    – Hekmatyar
    Nov 20 at 0:29








  • 3




    The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
    – user4581301
    Nov 20 at 0:30










  • With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
    – Phil1970
    Nov 20 at 1:46














  • 2




    ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
    – user4581301
    Nov 20 at 0:23












  • Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
    – user4581301
    Nov 20 at 0:26










  • Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
    – Hekmatyar
    Nov 20 at 0:29








  • 3




    The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
    – user4581301
    Nov 20 at 0:30










  • With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
    – Phil1970
    Nov 20 at 1:46








2




2




ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
– user4581301
Nov 20 at 0:23






ar[n][h] isn't valid in C++. Some compilers allow Variable Length Array behaviour by extension, but you have to watch out. A user-specified 2D array of long long is just asking for a stack overflow. Especially when one of the parameters is pow(n, n) That's going to get freaking huge freaking fast.
– user4581301
Nov 20 at 0:23














Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
– user4581301
Nov 20 at 0:26




Plus you have to watch out with pow on integers. Internally pow works in floating point and you're going to have all manner of imprecision and truncation issues.
– user4581301
Nov 20 at 0:26












Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
– Hekmatyar
Nov 20 at 0:29






Thanks for info. Will keep that in mind. I think now I have an idea how to remodel whole thing to make it simplier and actually work.
– Hekmatyar
Nov 20 at 0:29






3




3




The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
– user4581301
Nov 20 at 0:30




The best tool to crack this is probably the debugger. With a debugger you can control the execution of the program, stepping it instruction by instruction if you have to. As you advance through the program, keep an eye out for where the program does something you don't expect. The unexpected is either a bug or an error in your expectations. Either needs to be corrected.
– user4581301
Nov 20 at 0:30












With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
– Phil1970
Nov 20 at 1:46




With a small size like 2, it is also a good idea to use a paper with a line per operation and a column per variable or array index. Then it should be obvious how you get what you get.
– Phil1970
Nov 20 at 1:46

















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