Why can I not use variables as prefix to a command to set environment variables?












9














Normally, it is possible to set an environment variable for a command by prefixing it like so:



hello=hi bash -c 'echo $hello'


I also know that we can use a variable to substitute any part of a command invocation like the following:



$ cmd=bash
$ $cmd -c "echo hi" # equivalent to bash -c "echo hi"


I was very surprised to find out that you cannot use a variable to prefix a command to set an environment variable. Test case:



$ prefix=hello=hi
$ echo $prefix # prints hello=hi
$ $prefix bash -c 'echo $hello'
hello=hi: command not found


Why can I not set the environment variable using a variable? Is the prefix part a special part? I was able to get it working by using eval in front, but I still do not understand why. I am using bash 4.4.










share|improve this question




















  • 1




    You can use env instead of eval, which IIRC is more secure, but slower.
    – wjandrea
    Dec 20 at 18:37
















9














Normally, it is possible to set an environment variable for a command by prefixing it like so:



hello=hi bash -c 'echo $hello'


I also know that we can use a variable to substitute any part of a command invocation like the following:



$ cmd=bash
$ $cmd -c "echo hi" # equivalent to bash -c "echo hi"


I was very surprised to find out that you cannot use a variable to prefix a command to set an environment variable. Test case:



$ prefix=hello=hi
$ echo $prefix # prints hello=hi
$ $prefix bash -c 'echo $hello'
hello=hi: command not found


Why can I not set the environment variable using a variable? Is the prefix part a special part? I was able to get it working by using eval in front, but I still do not understand why. I am using bash 4.4.










share|improve this question




















  • 1




    You can use env instead of eval, which IIRC is more secure, but slower.
    – wjandrea
    Dec 20 at 18:37














9












9








9


2





Normally, it is possible to set an environment variable for a command by prefixing it like so:



hello=hi bash -c 'echo $hello'


I also know that we can use a variable to substitute any part of a command invocation like the following:



$ cmd=bash
$ $cmd -c "echo hi" # equivalent to bash -c "echo hi"


I was very surprised to find out that you cannot use a variable to prefix a command to set an environment variable. Test case:



$ prefix=hello=hi
$ echo $prefix # prints hello=hi
$ $prefix bash -c 'echo $hello'
hello=hi: command not found


Why can I not set the environment variable using a variable? Is the prefix part a special part? I was able to get it working by using eval in front, but I still do not understand why. I am using bash 4.4.










share|improve this question















Normally, it is possible to set an environment variable for a command by prefixing it like so:



hello=hi bash -c 'echo $hello'


I also know that we can use a variable to substitute any part of a command invocation like the following:



$ cmd=bash
$ $cmd -c "echo hi" # equivalent to bash -c "echo hi"


I was very surprised to find out that you cannot use a variable to prefix a command to set an environment variable. Test case:



$ prefix=hello=hi
$ echo $prefix # prints hello=hi
$ $prefix bash -c 'echo $hello'
hello=hi: command not found


Why can I not set the environment variable using a variable? Is the prefix part a special part? I was able to get it working by using eval in front, but I still do not understand why. I am using bash 4.4.







bash environment-variables variable






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 20 at 3:30









Jeff Schaller

38.5k1053125




38.5k1053125










asked Dec 20 at 3:27









wbkang

1483




1483








  • 1




    You can use env instead of eval, which IIRC is more secure, but slower.
    – wjandrea
    Dec 20 at 18:37














  • 1




    You can use env instead of eval, which IIRC is more secure, but slower.
    – wjandrea
    Dec 20 at 18:37








1




1




You can use env instead of eval, which IIRC is more secure, but slower.
– wjandrea
Dec 20 at 18:37




You can use env instead of eval, which IIRC is more secure, but slower.
– wjandrea
Dec 20 at 18:37










2 Answers
2






active

oldest

votes


















13














I suspect this is the part of the sequence that's catching you:




The words that are not variable assignments or redirections are expanded (see Shell Expansions). If any words remain after expansion, the first word is taken to be the name of the command and the remaining words are the arguments




That's from the Bash reference manual in the section on Simple Command Expansion.



In the cmd=bash example, no environment variables are set, and bash processes the command line up through parameter expansion, leaving bash -c "echo hi".



In the prefix=hello=hi example, there are again no variable assignments in the first pass, so processing continues to parameter expansion, resulting in a first word of hello=hi.



Once the variable assignments have been processed, they are not re-processed during command execution.



See the processing and its results under set -x:



$ prefix=hello=hi
+ prefix=hello=hi
$ $prefix bash -c 'echo $hello'
+ hello=hi bash -c 'echo $hello'
-bash: hello=hi: command not found
$ hello=42 bash -c 'echo $hello'
+ hello=42
+ bash -c 'echo $hello'
42


For a safer variation of "variable expansion" -as- "environment variables" than eval, consider wjandrea's suggestion of env:



prefix=hello=hi
env "$prefix" bash -c 'echo "$hello"'
hi


It's not strictly a command-line variable assignment, since we're using the env utility's main function of assigning environment variables to a command, but it accomplishes the same goal. The $prefix variable is expanded during the processing of the command-line, providing the name=value to env, who passes it along to bash.






share|improve this answer



















  • 3




    Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
    – muru
    Dec 20 at 3:45










  • Looks like env is my best bet. Thanks
    – wbkang
    Dec 20 at 21:13



















2














Because $prefix isn't an assignment. @Jeff has the longer explanation.



You could do a similar thing with a function instead:



$ prefix() { hello=hi "$@"; }
$ prefix bash -c 'echo "$hello"'
hi


...and you can even stack those, if you like:



$ foo() { foo=123 "$@"; }
$ bar() { bar=456 "$@"; }
$ foo bar bash -c 'echo "$bar $foo"'
456 123





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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes









    13














    I suspect this is the part of the sequence that's catching you:




    The words that are not variable assignments or redirections are expanded (see Shell Expansions). If any words remain after expansion, the first word is taken to be the name of the command and the remaining words are the arguments




    That's from the Bash reference manual in the section on Simple Command Expansion.



    In the cmd=bash example, no environment variables are set, and bash processes the command line up through parameter expansion, leaving bash -c "echo hi".



    In the prefix=hello=hi example, there are again no variable assignments in the first pass, so processing continues to parameter expansion, resulting in a first word of hello=hi.



    Once the variable assignments have been processed, they are not re-processed during command execution.



    See the processing and its results under set -x:



    $ prefix=hello=hi
    + prefix=hello=hi
    $ $prefix bash -c 'echo $hello'
    + hello=hi bash -c 'echo $hello'
    -bash: hello=hi: command not found
    $ hello=42 bash -c 'echo $hello'
    + hello=42
    + bash -c 'echo $hello'
    42


    For a safer variation of "variable expansion" -as- "environment variables" than eval, consider wjandrea's suggestion of env:



    prefix=hello=hi
    env "$prefix" bash -c 'echo "$hello"'
    hi


    It's not strictly a command-line variable assignment, since we're using the env utility's main function of assigning environment variables to a command, but it accomplishes the same goal. The $prefix variable is expanded during the processing of the command-line, providing the name=value to env, who passes it along to bash.






    share|improve this answer



















    • 3




      Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
      – muru
      Dec 20 at 3:45










    • Looks like env is my best bet. Thanks
      – wbkang
      Dec 20 at 21:13
















    13














    I suspect this is the part of the sequence that's catching you:




    The words that are not variable assignments or redirections are expanded (see Shell Expansions). If any words remain after expansion, the first word is taken to be the name of the command and the remaining words are the arguments




    That's from the Bash reference manual in the section on Simple Command Expansion.



    In the cmd=bash example, no environment variables are set, and bash processes the command line up through parameter expansion, leaving bash -c "echo hi".



    In the prefix=hello=hi example, there are again no variable assignments in the first pass, so processing continues to parameter expansion, resulting in a first word of hello=hi.



    Once the variable assignments have been processed, they are not re-processed during command execution.



    See the processing and its results under set -x:



    $ prefix=hello=hi
    + prefix=hello=hi
    $ $prefix bash -c 'echo $hello'
    + hello=hi bash -c 'echo $hello'
    -bash: hello=hi: command not found
    $ hello=42 bash -c 'echo $hello'
    + hello=42
    + bash -c 'echo $hello'
    42


    For a safer variation of "variable expansion" -as- "environment variables" than eval, consider wjandrea's suggestion of env:



    prefix=hello=hi
    env "$prefix" bash -c 'echo "$hello"'
    hi


    It's not strictly a command-line variable assignment, since we're using the env utility's main function of assigning environment variables to a command, but it accomplishes the same goal. The $prefix variable is expanded during the processing of the command-line, providing the name=value to env, who passes it along to bash.






    share|improve this answer



















    • 3




      Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
      – muru
      Dec 20 at 3:45










    • Looks like env is my best bet. Thanks
      – wbkang
      Dec 20 at 21:13














    13












    13








    13






    I suspect this is the part of the sequence that's catching you:




    The words that are not variable assignments or redirections are expanded (see Shell Expansions). If any words remain after expansion, the first word is taken to be the name of the command and the remaining words are the arguments




    That's from the Bash reference manual in the section on Simple Command Expansion.



    In the cmd=bash example, no environment variables are set, and bash processes the command line up through parameter expansion, leaving bash -c "echo hi".



    In the prefix=hello=hi example, there are again no variable assignments in the first pass, so processing continues to parameter expansion, resulting in a first word of hello=hi.



    Once the variable assignments have been processed, they are not re-processed during command execution.



    See the processing and its results under set -x:



    $ prefix=hello=hi
    + prefix=hello=hi
    $ $prefix bash -c 'echo $hello'
    + hello=hi bash -c 'echo $hello'
    -bash: hello=hi: command not found
    $ hello=42 bash -c 'echo $hello'
    + hello=42
    + bash -c 'echo $hello'
    42


    For a safer variation of "variable expansion" -as- "environment variables" than eval, consider wjandrea's suggestion of env:



    prefix=hello=hi
    env "$prefix" bash -c 'echo "$hello"'
    hi


    It's not strictly a command-line variable assignment, since we're using the env utility's main function of assigning environment variables to a command, but it accomplishes the same goal. The $prefix variable is expanded during the processing of the command-line, providing the name=value to env, who passes it along to bash.






    share|improve this answer














    I suspect this is the part of the sequence that's catching you:




    The words that are not variable assignments or redirections are expanded (see Shell Expansions). If any words remain after expansion, the first word is taken to be the name of the command and the remaining words are the arguments




    That's from the Bash reference manual in the section on Simple Command Expansion.



    In the cmd=bash example, no environment variables are set, and bash processes the command line up through parameter expansion, leaving bash -c "echo hi".



    In the prefix=hello=hi example, there are again no variable assignments in the first pass, so processing continues to parameter expansion, resulting in a first word of hello=hi.



    Once the variable assignments have been processed, they are not re-processed during command execution.



    See the processing and its results under set -x:



    $ prefix=hello=hi
    + prefix=hello=hi
    $ $prefix bash -c 'echo $hello'
    + hello=hi bash -c 'echo $hello'
    -bash: hello=hi: command not found
    $ hello=42 bash -c 'echo $hello'
    + hello=42
    + bash -c 'echo $hello'
    42


    For a safer variation of "variable expansion" -as- "environment variables" than eval, consider wjandrea's suggestion of env:



    prefix=hello=hi
    env "$prefix" bash -c 'echo "$hello"'
    hi


    It's not strictly a command-line variable assignment, since we're using the env utility's main function of assigning environment variables to a command, but it accomplishes the same goal. The $prefix variable is expanded during the processing of the command-line, providing the name=value to env, who passes it along to bash.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Dec 20 at 20:12

























    answered Dec 20 at 3:41









    Jeff Schaller

    38.5k1053125




    38.5k1053125








    • 3




      Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
      – muru
      Dec 20 at 3:45










    • Looks like env is my best bet. Thanks
      – wbkang
      Dec 20 at 21:13














    • 3




      Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
      – muru
      Dec 20 at 3:45










    • Looks like env is my best bet. Thanks
      – wbkang
      Dec 20 at 21:13








    3




    3




    Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
    – muru
    Dec 20 at 3:45




    Similarly, $foo=bar bash -c ... won't work, because $foo=bar isn't a variable assignment (whatever be the value of $foo), because $foo=bar doesn't fit the name=value pattern for variable assignment.
    – muru
    Dec 20 at 3:45












    Looks like env is my best bet. Thanks
    – wbkang
    Dec 20 at 21:13




    Looks like env is my best bet. Thanks
    – wbkang
    Dec 20 at 21:13













    2














    Because $prefix isn't an assignment. @Jeff has the longer explanation.



    You could do a similar thing with a function instead:



    $ prefix() { hello=hi "$@"; }
    $ prefix bash -c 'echo "$hello"'
    hi


    ...and you can even stack those, if you like:



    $ foo() { foo=123 "$@"; }
    $ bar() { bar=456 "$@"; }
    $ foo bar bash -c 'echo "$bar $foo"'
    456 123





    share|improve this answer


























      2














      Because $prefix isn't an assignment. @Jeff has the longer explanation.



      You could do a similar thing with a function instead:



      $ prefix() { hello=hi "$@"; }
      $ prefix bash -c 'echo "$hello"'
      hi


      ...and you can even stack those, if you like:



      $ foo() { foo=123 "$@"; }
      $ bar() { bar=456 "$@"; }
      $ foo bar bash -c 'echo "$bar $foo"'
      456 123





      share|improve this answer
























        2












        2








        2






        Because $prefix isn't an assignment. @Jeff has the longer explanation.



        You could do a similar thing with a function instead:



        $ prefix() { hello=hi "$@"; }
        $ prefix bash -c 'echo "$hello"'
        hi


        ...and you can even stack those, if you like:



        $ foo() { foo=123 "$@"; }
        $ bar() { bar=456 "$@"; }
        $ foo bar bash -c 'echo "$bar $foo"'
        456 123





        share|improve this answer












        Because $prefix isn't an assignment. @Jeff has the longer explanation.



        You could do a similar thing with a function instead:



        $ prefix() { hello=hi "$@"; }
        $ prefix bash -c 'echo "$hello"'
        hi


        ...and you can even stack those, if you like:



        $ foo() { foo=123 "$@"; }
        $ bar() { bar=456 "$@"; }
        $ foo bar bash -c 'echo "$bar $foo"'
        456 123






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Dec 20 at 17:57









        ilkkachu

        55.5k783151




        55.5k783151






























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