Possible to install all missing modules for a node application?
I have a node app that I just started working with and each time I try to run it, it says there is a missing module. I've just been using npm install ... for each module but after doing about 10 of them I'm wondering if there is a way to have npm pull down all needed modules for a node app without me installing each one manually. Can it be done?
node.js npm
add a comment |
I have a node app that I just started working with and each time I try to run it, it says there is a missing module. I've just been using npm install ... for each module but after doing about 10 of them I'm wondering if there is a way to have npm pull down all needed modules for a node app without me installing each one manually. Can it be done?
node.js npm
you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37
add a comment |
I have a node app that I just started working with and each time I try to run it, it says there is a missing module. I've just been using npm install ... for each module but after doing about 10 of them I'm wondering if there is a way to have npm pull down all needed modules for a node app without me installing each one manually. Can it be done?
node.js npm
I have a node app that I just started working with and each time I try to run it, it says there is a missing module. I've just been using npm install ... for each module but after doing about 10 of them I'm wondering if there is a way to have npm pull down all needed modules for a node app without me installing each one manually. Can it be done?
node.js npm
node.js npm
asked Nov 2 '12 at 4:17
Abe Miessler
52.8k68244404
52.8k68244404
you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37
add a comment |
you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37
you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37
you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37
add a comment |
5 Answers
5
active
oldest
votes
Yes, as long as the dependency is listed in package.json.
In the directory that contains package.json, just type:
npm install
add a comment |
I created an npm module to handle installing missing modules automatically.
npm-install-missing
It will install all app dependencies and sub-dependencies automatically. This is useful when submodules aren't installed correctly.
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
add a comment |
You can run npm install yourModule --save in order to install and automatically update package.json with this newly installed module.
So when you run npm install a second time it will install every dependecy previously added and you won't need to reinstall every dependency one by one.
add a comment |
I have written a script for this.
Place it at the start of your script, and any uninstalled modules will be installed when you run it.
(function () {
var r = require
require = function (n) {
try {
return r(n)
} catch (e) {
console.log(`Module "${n}" was not found and will be installed`)
r('child_process').exec(`npm i ${n}`, function (err, body) {
if (err) {
console.log(`Module "${n}" could not be installed. Try again or install manually`)
console.log(body)
exit(1)
} else {
console.log(`Module "${n}" was installed. Will try to require again`)
try{
return r(n)
} catch (e) {
console.log(`Module "${n}" could not be required. Please restart the app`)
console.log(e)
exit(1)
}
}
})
}
}
})()
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
add a comment |
I was inspired by @Aminadav Glickshtein's answer to create a script of my own that would synchronously install the needed modules, because his answer lacks these capabilities.
I needed some help, so I started an SO question here. You can read about how this script works there.
The result is as follows:
const cp = require('child_process')
const req = async module => {
try {
require.resolve(module)
} catch (e) {
console.log(`Could not resolve "${module}"nInstalling`)
cp.execSync(`npm install ${module}`)
await setImmediate(() => {})
console.log(`"${module}" has been installed`)
}
console.log(`Requiring "${module}"`)
try {
return require(module)
} catch (e) {
console.log(`Could not include "${module}". Restart the script`)
process.exit(1)
}
}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
And a one-liner (139 characters!). It doesn't globally define child_modules, has no last try-catch and doesn't log anything in the console:
const req=async m=>{let r=require;try{r.resolve(m)}catch(e){r('child_process').execSync('npm i '+m);await setImmediate(()=>{})}return r(m)}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yes, as long as the dependency is listed in package.json.
In the directory that contains package.json, just type:
npm install
add a comment |
Yes, as long as the dependency is listed in package.json.
In the directory that contains package.json, just type:
npm install
add a comment |
Yes, as long as the dependency is listed in package.json.
In the directory that contains package.json, just type:
npm install
Yes, as long as the dependency is listed in package.json.
In the directory that contains package.json, just type:
npm install
answered Nov 2 '12 at 5:21
JP Richardson
22.1k32110145
22.1k32110145
add a comment |
add a comment |
I created an npm module to handle installing missing modules automatically.
npm-install-missing
It will install all app dependencies and sub-dependencies automatically. This is useful when submodules aren't installed correctly.
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
add a comment |
I created an npm module to handle installing missing modules automatically.
npm-install-missing
It will install all app dependencies and sub-dependencies automatically. This is useful when submodules aren't installed correctly.
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
add a comment |
I created an npm module to handle installing missing modules automatically.
npm-install-missing
It will install all app dependencies and sub-dependencies automatically. This is useful when submodules aren't installed correctly.
I created an npm module to handle installing missing modules automatically.
npm-install-missing
It will install all app dependencies and sub-dependencies automatically. This is useful when submodules aren't installed correctly.
answered Nov 12 '13 at 16:49
alexcline
34039
34039
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
add a comment |
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
1
1
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
It's even detect dependencies required version!
– msangel
Jan 20 '15 at 20:03
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
When I try this It tells me that I have no missing modules, although when I run npm list It is loaded with missing and unmet dependencies
– Omar Tarek
Jul 22 '17 at 16:45
add a comment |
You can run npm install yourModule --save in order to install and automatically update package.json with this newly installed module.
So when you run npm install a second time it will install every dependecy previously added and you won't need to reinstall every dependency one by one.
add a comment |
You can run npm install yourModule --save in order to install and automatically update package.json with this newly installed module.
So when you run npm install a second time it will install every dependecy previously added and you won't need to reinstall every dependency one by one.
add a comment |
You can run npm install yourModule --save in order to install and automatically update package.json with this newly installed module.
So when you run npm install a second time it will install every dependecy previously added and you won't need to reinstall every dependency one by one.
You can run npm install yourModule --save in order to install and automatically update package.json with this newly installed module.
So when you run npm install a second time it will install every dependecy previously added and you won't need to reinstall every dependency one by one.
answered Nov 3 '12 at 3:27
Renato Gama
10.4k64174
10.4k64174
add a comment |
add a comment |
I have written a script for this.
Place it at the start of your script, and any uninstalled modules will be installed when you run it.
(function () {
var r = require
require = function (n) {
try {
return r(n)
} catch (e) {
console.log(`Module "${n}" was not found and will be installed`)
r('child_process').exec(`npm i ${n}`, function (err, body) {
if (err) {
console.log(`Module "${n}" could not be installed. Try again or install manually`)
console.log(body)
exit(1)
} else {
console.log(`Module "${n}" was installed. Will try to require again`)
try{
return r(n)
} catch (e) {
console.log(`Module "${n}" could not be required. Please restart the app`)
console.log(e)
exit(1)
}
}
})
}
}
})()
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
add a comment |
I have written a script for this.
Place it at the start of your script, and any uninstalled modules will be installed when you run it.
(function () {
var r = require
require = function (n) {
try {
return r(n)
} catch (e) {
console.log(`Module "${n}" was not found and will be installed`)
r('child_process').exec(`npm i ${n}`, function (err, body) {
if (err) {
console.log(`Module "${n}" could not be installed. Try again or install manually`)
console.log(body)
exit(1)
} else {
console.log(`Module "${n}" was installed. Will try to require again`)
try{
return r(n)
} catch (e) {
console.log(`Module "${n}" could not be required. Please restart the app`)
console.log(e)
exit(1)
}
}
})
}
}
})()
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
add a comment |
I have written a script for this.
Place it at the start of your script, and any uninstalled modules will be installed when you run it.
(function () {
var r = require
require = function (n) {
try {
return r(n)
} catch (e) {
console.log(`Module "${n}" was not found and will be installed`)
r('child_process').exec(`npm i ${n}`, function (err, body) {
if (err) {
console.log(`Module "${n}" could not be installed. Try again or install manually`)
console.log(body)
exit(1)
} else {
console.log(`Module "${n}" was installed. Will try to require again`)
try{
return r(n)
} catch (e) {
console.log(`Module "${n}" could not be required. Please restart the app`)
console.log(e)
exit(1)
}
}
})
}
}
})()
I have written a script for this.
Place it at the start of your script, and any uninstalled modules will be installed when you run it.
(function () {
var r = require
require = function (n) {
try {
return r(n)
} catch (e) {
console.log(`Module "${n}" was not found and will be installed`)
r('child_process').exec(`npm i ${n}`, function (err, body) {
if (err) {
console.log(`Module "${n}" could not be installed. Try again or install manually`)
console.log(body)
exit(1)
} else {
console.log(`Module "${n}" was installed. Will try to require again`)
try{
return r(n)
} catch (e) {
console.log(`Module "${n}" could not be required. Please restart the app`)
console.log(e)
exit(1)
}
}
})
}
}
})()
edited Nov 19 at 22:11
Gust van de Wal
3,2821238
3,2821238
answered Feb 3 '14 at 10:37
Aminadav Glickshtein
8,02743079
8,02743079
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
add a comment |
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
this works great, but it fails the first run, because the dependencies are being installed when try to run the rest of the file. how can we wait until your script finishes before begin running the rest of the file?
– Dat30
Jan 31 at 16:52
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
@Dat30, see my answer
– Gust van de Wal
Nov 19 at 22:26
add a comment |
I was inspired by @Aminadav Glickshtein's answer to create a script of my own that would synchronously install the needed modules, because his answer lacks these capabilities.
I needed some help, so I started an SO question here. You can read about how this script works there.
The result is as follows:
const cp = require('child_process')
const req = async module => {
try {
require.resolve(module)
} catch (e) {
console.log(`Could not resolve "${module}"nInstalling`)
cp.execSync(`npm install ${module}`)
await setImmediate(() => {})
console.log(`"${module}" has been installed`)
}
console.log(`Requiring "${module}"`)
try {
return require(module)
} catch (e) {
console.log(`Could not include "${module}". Restart the script`)
process.exit(1)
}
}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
And a one-liner (139 characters!). It doesn't globally define child_modules, has no last try-catch and doesn't log anything in the console:
const req=async m=>{let r=require;try{r.resolve(m)}catch(e){r('child_process').execSync('npm i '+m);await setImmediate(()=>{})}return r(m)}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
add a comment |
I was inspired by @Aminadav Glickshtein's answer to create a script of my own that would synchronously install the needed modules, because his answer lacks these capabilities.
I needed some help, so I started an SO question here. You can read about how this script works there.
The result is as follows:
const cp = require('child_process')
const req = async module => {
try {
require.resolve(module)
} catch (e) {
console.log(`Could not resolve "${module}"nInstalling`)
cp.execSync(`npm install ${module}`)
await setImmediate(() => {})
console.log(`"${module}" has been installed`)
}
console.log(`Requiring "${module}"`)
try {
return require(module)
} catch (e) {
console.log(`Could not include "${module}". Restart the script`)
process.exit(1)
}
}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
And a one-liner (139 characters!). It doesn't globally define child_modules, has no last try-catch and doesn't log anything in the console:
const req=async m=>{let r=require;try{r.resolve(m)}catch(e){r('child_process').execSync('npm i '+m);await setImmediate(()=>{})}return r(m)}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
add a comment |
I was inspired by @Aminadav Glickshtein's answer to create a script of my own that would synchronously install the needed modules, because his answer lacks these capabilities.
I needed some help, so I started an SO question here. You can read about how this script works there.
The result is as follows:
const cp = require('child_process')
const req = async module => {
try {
require.resolve(module)
} catch (e) {
console.log(`Could not resolve "${module}"nInstalling`)
cp.execSync(`npm install ${module}`)
await setImmediate(() => {})
console.log(`"${module}" has been installed`)
}
console.log(`Requiring "${module}"`)
try {
return require(module)
} catch (e) {
console.log(`Could not include "${module}". Restart the script`)
process.exit(1)
}
}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
And a one-liner (139 characters!). It doesn't globally define child_modules, has no last try-catch and doesn't log anything in the console:
const req=async m=>{let r=require;try{r.resolve(m)}catch(e){r('child_process').execSync('npm i '+m);await setImmediate(()=>{})}return r(m)}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
I was inspired by @Aminadav Glickshtein's answer to create a script of my own that would synchronously install the needed modules, because his answer lacks these capabilities.
I needed some help, so I started an SO question here. You can read about how this script works there.
The result is as follows:
const cp = require('child_process')
const req = async module => {
try {
require.resolve(module)
} catch (e) {
console.log(`Could not resolve "${module}"nInstalling`)
cp.execSync(`npm install ${module}`)
await setImmediate(() => {})
console.log(`"${module}" has been installed`)
}
console.log(`Requiring "${module}"`)
try {
return require(module)
} catch (e) {
console.log(`Could not include "${module}". Restart the script`)
process.exit(1)
}
}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
And a one-liner (139 characters!). It doesn't globally define child_modules, has no last try-catch and doesn't log anything in the console:
const req=async m=>{let r=require;try{r.resolve(m)}catch(e){r('child_process').execSync('npm i '+m);await setImmediate(()=>{})}return r(m)}
const main = async () => {
const http = await req('http')
const path = await req('path')
const fs = await req('fs')
const express = await req('express')
// The rest of the app's code goes here
}
main()
edited Nov 20 at 8:57
answered Nov 19 at 22:25
Gust van de Wal
3,2821238
3,2821238
add a comment |
add a comment |
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you should use github.com/imkimchi/ni, It automatically install missing dependencies from package.json comparing all js codes in the project
– Phillip YS
Aug 30 at 9:37