logical operator not working in while statement in python [duplicate]











up vote
-1
down vote

favorite













This question already has an answer here:




  • How to test multiple variables against a value?

    18 answers



  • deMorgan rules explained

    8 answers



  • Python 'if' and 'while' conditions not working

    1 answer




my code:



pokemon_choice = input("Choose a pokemon: ")



while pokemon_choice != ("squirtle") or pokemon_choice != ("bulbasaur"):

    pokemon_choice = input("invalid choice, choose a pokemon: ")


I'm new to python so this may be a stupid question but, if the user input for the first pokemon_choice variable were to be bulbasaur or squirtle it would not run the while loop... right? The thing is, when I typed bulbasaur, and only bulbasaur, even though i typed bulbasaur exactly as it should be it still ran the while loop. When I type squirtle however it seems to work just fine, ignoring the while loop. Why is it still running the loop???






python







share|improve this question













marked as duplicate by Jean-François Fabre python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
 Nov 19 at 8:33


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.











  • 3




    while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
    – Jean-François Fabre
    Nov 19 at 8:33






  • 1




    you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
    – rv7
    Nov 19 at 8:35






  • 1




    @Jean-FrançoisFabre that's the wrong dupe, imo.
    – timgeb
    Nov 19 at 8:36






  • 1




    @Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
    – Martijn Pieters♦
    Nov 19 at 8:38








  • 1




    Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
    – Martijn Pieters♦
    Nov 19 at 8:41















up vote
-1
down vote

favorite













This question already has an answer here:




  • How to test multiple variables against a value?

    18 answers



  • deMorgan rules explained

    8 answers



  • Python 'if' and 'while' conditions not working

    1 answer




my code:



pokemon_choice = input("Choose a pokemon: ")



while pokemon_choice != ("squirtle") or pokemon_choice != ("bulbasaur"):

    pokemon_choice = input("invalid choice, choose a pokemon: ")


I'm new to python so this may be a stupid question but, if the user input for the first pokemon_choice variable were to be bulbasaur or squirtle it would not run the while loop... right? The thing is, when I typed bulbasaur, and only bulbasaur, even though i typed bulbasaur exactly as it should be it still ran the while loop. When I type squirtle however it seems to work just fine, ignoring the while loop. Why is it still running the loop???






python







share|improve this question













marked as duplicate by Jean-François Fabre python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
 Nov 19 at 8:33


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.











  • 3




    while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
    – Jean-François Fabre
    Nov 19 at 8:33






  • 1




    you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
    – rv7
    Nov 19 at 8:35






  • 1




    @Jean-FrançoisFabre that's the wrong dupe, imo.
    – timgeb
    Nov 19 at 8:36






  • 1




    @Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
    – Martijn Pieters♦
    Nov 19 at 8:38








  • 1




    Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
    – Martijn Pieters♦
    Nov 19 at 8:41













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite












This question already has an answer here:




  • How to test multiple variables against a value?

    18 answers



  • deMorgan rules explained

    8 answers



  • Python 'if' and 'while' conditions not working

    1 answer




my code:



pokemon_choice = input("Choose a pokemon: ")



while pokemon_choice != ("squirtle") or pokemon_choice != ("bulbasaur"):

    pokemon_choice = input("invalid choice, choose a pokemon: ")


I'm new to python so this may be a stupid question but, if the user input for the first pokemon_choice variable were to be bulbasaur or squirtle it would not run the while loop... right? The thing is, when I typed bulbasaur, and only bulbasaur, even though i typed bulbasaur exactly as it should be it still ran the while loop. When I type squirtle however it seems to work just fine, ignoring the while loop. Why is it still running the loop???






python







share|improve this question














This question already has an answer here:




  • How to test multiple variables against a value?

    18 answers



  • deMorgan rules explained

    8 answers



  • Python 'if' and 'while' conditions not working

    1 answer




my code:



pokemon_choice = input("Choose a pokemon: ")



while pokemon_choice != ("squirtle") or pokemon_choice != ("bulbasaur"):

    pokemon_choice = input("invalid choice, choose a pokemon: ")


I'm new to python so this may be a stupid question but, if the user input for the first pokemon_choice variable were to be bulbasaur or squirtle it would not run the while loop... right? The thing is, when I typed bulbasaur, and only bulbasaur, even though i typed bulbasaur exactly as it should be it still ran the while loop. When I type squirtle however it seems to work just fine, ignoring the while loop. Why is it still running the loop???





This question already has an answer here:




  • How to test multiple variables against a value?

    18 answers



  • deMorgan rules explained

    8 answers



  • Python 'if' and 'while' conditions not working

    1 answer







python




python






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 19 at 8:32









NefariousGent

1




1




marked as duplicate by Jean-François Fabre python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
 Nov 19 at 8:33


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Jean-François Fabre python
Users with the  python badge can single-handedly close python questions as duplicates and reopen them as needed.

StackExchange.ready(function() {
if (StackExchange.options.isMobile) return;

$('.dupe-hammer-message-hover:not(.hover-bound)').each(function() {
var $hover = $(this).addClass('hover-bound'),
$msg = $hover.siblings('.dupe-hammer-message');

$hover.hover(
function() {
$hover.showInfoMessage('', {
messageElement: $msg.clone().show(),
transient: false,
position: { my: 'bottom left', at: 'top center', offsetTop: -7 },
dismissable: false,
relativeToBody: true
});
},
function() {
StackExchange.helpers.removeMessages();
}
);
});
});
 Nov 19 at 8:33


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.










  • 3




    while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
    – Jean-François Fabre
    Nov 19 at 8:33






  • 1




    you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
    – rv7
    Nov 19 at 8:35






  • 1




    @Jean-FrançoisFabre that's the wrong dupe, imo.
    – timgeb
    Nov 19 at 8:36






  • 1




    @Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
    – Martijn Pieters♦
    Nov 19 at 8:38








  • 1




    Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
    – Martijn Pieters♦
    Nov 19 at 8:41














  • 3




    while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
    – Jean-François Fabre
    Nov 19 at 8:33






  • 1




    you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
    – rv7
    Nov 19 at 8:35






  • 1




    @Jean-FrançoisFabre that's the wrong dupe, imo.
    – timgeb
    Nov 19 at 8:36






  • 1




    @Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
    – Martijn Pieters♦
    Nov 19 at 8:38








  • 1




    Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
    – Martijn Pieters♦
    Nov 19 at 8:41








3




3




while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
– Jean-François Fabre
Nov 19 at 8:33




while pokemon_choice != ("squirtle") and pokemon_choice != ("bulbasaur"):
– Jean-François Fabre
Nov 19 at 8:33




1




1




you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
– rv7
Nov 19 at 8:35




you should use and in place of or. So, your loop will run whenever the choice is not bulbasaur and not squirtle!
– rv7
Nov 19 at 8:35




1




1




@Jean-FrançoisFabre that's the wrong dupe, imo.
– timgeb
Nov 19 at 8:36




@Jean-FrançoisFabre that's the wrong dupe, imo.
– timgeb
Nov 19 at 8:36




1




1




@Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
– Martijn Pieters♦
Nov 19 at 8:38






@Jean-FrançoisFabre: that duplicate doesn't explain about De Morgan's boolean laws, which is the real problem here.
– Martijn Pieters♦
Nov 19 at 8:38






1




1




Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
– Martijn Pieters♦
Nov 19 at 8:41




Your boolean test is true for all possible cases. When pokemon_choice is set to "squirtle" then pokemon_choice != ("bulbasaur") is true, and because you used or, that makes the whole test true. When pokemon_choice is set to "bulbasaur", then pokemon_choice != ("squirtle") is true, and because you used or, the whole test is true. Use and to ensure both tests are taken into account.
– Martijn Pieters♦
Nov 19 at 8:41

















active

oldest

votes






















active

oldest

votes













active

oldest

votes









active

oldest

votes






active

oldest

votes

-

Popular posts from this blog

Paul Cézanne

Image
Pour l’article ayant un titre homophone, voir Sézanne. Paul Cézanne.mw-parser-output .entete.artiste{background-image:url("//upload.wikimedia.org/wikipedia/commons/f/f3/Picto_infobox_artiste.png")} Autoportrait vers 1861 Naissance 19 janvier 1839 Aix-en-Provence (France) Décès 22 octobre 1906 (à 67 ans) Aix-en-Provence (France) Nationalité Française Activité Peintre Formation Académie de Charles Suisse Maître Joseph Gilbert, Antoine Guillemet, Camille Pissarro Mouvement Impressionnisme postimpressionnisme Influencé par Eugène Delacroix, Gustave Courbet, Véronèse A influencé Braque, Picasso, Matisse Conjoint Hortense Fiquet (depuis 1886) Enfant Paul Cézanne  ( d ) Œuvres principales La Montagne Sainte-Victoire, Portrait de madame Cézanne signature modifier - modifier le code - modifier Wikidata Paul Cézanne , né le 19 janvier 1839 à Aix-en-Provence et mort le 22 octobre 1906 dans la mê...
Read more

UIScrollView CustomStickyHeader Resize height generates problems when scroll is too fast

Image
0 I have been trying for a while to create a UIViewController that has a CustomStickyHeader and a UITableView. The idea I have been following is use the UITableView scrolling for changing the header view with the value of the contentOffset. The layout for the ViewController (AlbumsViewController) looks like: The UItableView Scrolling functions from the delegate are implemented like that: func scrollViewDidScroll(_ scrollView: UIScrollView) { let endReached = contentTableView.contentOffset.y >= (contentTableView.contentSize.height - contentTableView.frame.size.height) let isUP = lastContentOffset > scrollView.contentOffset.y if scrollView.contentOffset.y < 0 { headerHeightConstraint.constant += abs(scrollView.contentOffset.y) } else{ if !endReached{ ...
Read more

Angular material date-picker (MatDatepicker) auto completes the date on focus out

Image
3 3 I am using angular material/mat-datepicker in my project and whenever the user enters one digit inside of it, and goes out of focus - the date picker is auto completing with a random date. Example Just enter 1 and go out of focus, or enter 5/5/20 The date picker is adding date automatically Update : Also I am using reactive forms and I'm validating the input with that approach Can I disable this ? angular datepicker angular-material angular6 angular-material-datetimepicker share | improve this question edited Nov 20 '18 at 13:21 ...
Read more