Recursively generate subset of list in python

I have a json file that looks something like the following:

[

  {

     "category1":"0120391123123"

  },

  [

     {

        "subcategory":"0120391123123"

     },

     [

        {

           "subsubcategory":"019301948109"

        },

        [

           {

              "subsubsubcategory":"013904123908"

           },

           [

              {

                 "subsubsubsubcategory":"019341823908"

              }

           ]

        ]

     ]

  ],

  [

     {

        "subcategory2":"0934810923801"

     },

     [

        {

           "subsubcategory2":"09341829308123"

        }

     ]

  ],

  [

     {

        "category2":"1309183912309"

     },

     [

        {

           "subcategory":"10293182094"

        }

     ]

  ]

]

I also have a list of categories that I would like to find in the original list. If the category exists in categoriesToFind, I would also like to find all subcategories and return those as well.

categoriesToFind = ['019301948109', '1309183912309']



finalCategories = 



def findCategories(currentList, isFirstIteration):

    for x in currentList:

        if type(x) is dict and (next(iter(x.values())) in categoriesToFind or not isFirstIteration):

            finalCategories.append(next(iter(x.values())))

            if len(currentList) < currentList.index(x) + 1:

                findCategories(currentList[currentList.index(x) + 1], False)



findCategories(data, True)

I would want finalCategories to contain the following:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

asked Nov 20 at 3:51

Evan Hessler

779

The original json is not consistently written as category1 is a dict in the root list and category2 is a dict in a nested list. Is that a typo or should be like this?
– b-fg
Nov 20 at 4:00

Yes this was intentional
– Evan Hessler
Nov 20 at 4:14

add a comment |

I have a json file that looks something like the following:

[

  {

     "category1":"0120391123123"

  },

  [

     {

        "subcategory":"0120391123123"

     },

     [

        {

           "subsubcategory":"019301948109"

        },

        [

           {

              "subsubsubcategory":"013904123908"

           },

           [

              {

                 "subsubsubsubcategory":"019341823908"

              }

           ]

        ]

     ]

  ],

  [

     {

        "subcategory2":"0934810923801"

     },

     [

        {

           "subsubcategory2":"09341829308123"

        }

     ]

  ],

  [

     {

        "category2":"1309183912309"

     },

     [

        {

           "subcategory":"10293182094"

        }

     ]

  ]

]

I also have a list of categories that I would like to find in the original list. If the category exists in categoriesToFind, I would also like to find all subcategories and return those as well.

categoriesToFind = ['019301948109', '1309183912309']



finalCategories = 



def findCategories(currentList, isFirstIteration):

    for x in currentList:

        if type(x) is dict and (next(iter(x.values())) in categoriesToFind or not isFirstIteration):

            finalCategories.append(next(iter(x.values())))

            if len(currentList) < currentList.index(x) + 1:

                findCategories(currentList[currentList.index(x) + 1], False)



findCategories(data, True)

I would want finalCategories to contain the following:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

asked Nov 20 at 3:51

Evan Hessler

779

The original json is not consistently written as category1 is a dict in the root list and category2 is a dict in a nested list. Is that a typo or should be like this?
– b-fg
Nov 20 at 4:00

Yes this was intentional
– Evan Hessler
Nov 20 at 4:14

add a comment |

I have a json file that looks something like the following:

[

  {

     "category1":"0120391123123"

  },

  [

     {

        "subcategory":"0120391123123"

     },

     [

        {

           "subsubcategory":"019301948109"

        },

        [

           {

              "subsubsubcategory":"013904123908"

           },

           [

              {

                 "subsubsubsubcategory":"019341823908"

              }

           ]

        ]

     ]

  ],

  [

     {

        "subcategory2":"0934810923801"

     },

     [

        {

           "subsubcategory2":"09341829308123"

        }

     ]

  ],

  [

     {

        "category2":"1309183912309"

     },

     [

        {

           "subcategory":"10293182094"

        }

     ]

  ]

]

I also have a list of categories that I would like to find in the original list. If the category exists in categoriesToFind, I would also like to find all subcategories and return those as well.

categoriesToFind = ['019301948109', '1309183912309']



finalCategories = 



def findCategories(currentList, isFirstIteration):

    for x in currentList:

        if type(x) is dict and (next(iter(x.values())) in categoriesToFind or not isFirstIteration):

            finalCategories.append(next(iter(x.values())))

            if len(currentList) < currentList.index(x) + 1:

                findCategories(currentList[currentList.index(x) + 1], False)



findCategories(data, True)

I would want finalCategories to contain the following:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

asked Nov 20 at 3:51

Evan Hessler

779

I have a json file that looks something like the following:

[

  {

     "category1":"0120391123123"

  },

  [

     {

        "subcategory":"0120391123123"

     },

     [

        {

           "subsubcategory":"019301948109"

        },

        [

           {

              "subsubsubcategory":"013904123908"

           },

           [

              {

                 "subsubsubsubcategory":"019341823908"

              }

           ]

        ]

     ]

  ],

  [

     {

        "subcategory2":"0934810923801"

     },

     [

        {

           "subsubcategory2":"09341829308123"

        }

     ]

  ],

  [

     {

        "category2":"1309183912309"

     },

     [

        {

           "subcategory":"10293182094"

        }

     ]

  ]

]

I also have a list of categories that I would like to find in the original list. If the category exists in categoriesToFind, I would also like to find all subcategories and return those as well.

categoriesToFind = ['019301948109', '1309183912309']



finalCategories = 



def findCategories(currentList, isFirstIteration):

    for x in currentList:

        if type(x) is dict and (next(iter(x.values())) in categoriesToFind or not isFirstIteration):

            finalCategories.append(next(iter(x.values())))

            if len(currentList) < currentList.index(x) + 1:

                findCategories(currentList[currentList.index(x) + 1], False)



findCategories(data, True)

I would want finalCategories to contain the following:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

python recursion

asked Nov 20 at 3:51

Evan Hessler

779

asked Nov 20 at 3:51

Evan Hessler

779

asked Nov 20 at 3:51

Evan Hessler

779

asked Nov 20 at 3:51

Evan Hessler

779

asked Nov 20 at 3:51

Evan Hessler

779

The original json is not consistently written as category1 is a dict in the root list and category2 is a dict in a nested list. Is that a typo or should be like this?
– b-fg
Nov 20 at 4:00

Yes this was intentional
– Evan Hessler
Nov 20 at 4:14

add a comment |

The original json is not consistently written as category1 is a dict in the root list and category2 is a dict in a nested list. Is that a typo or should be like this?
– b-fg
Nov 20 at 4:00

Yes this was intentional
– Evan Hessler
Nov 20 at 4:14

The original json is not consistently written as category1 is a dict in the root list and category2 is a dict in a nested list. Is that a typo or should be like this?
– b-fg
Nov 20 at 4:00

Yes this was intentional
– Evan Hessler
Nov 20 at 4:14

add a comment |

1 Answer
1

active

oldest

votes

You can use recursion with a generator:

categoriesToFind = ['019301948109', '1309183912309']

d = [{'category1': '0120391123123'}, [{'subcategory': '0120391123123'}, [{'subsubcategory': '019301948109'}, [{'subsubsubcategory': '013904123908'}, [{'subsubsubsubcategory': '019341823908'}]]]], [{'subcategory2': '0934810923801'}, [{'subsubcategory2': '09341829308123'}]], [{'category2': '1309183912309'}, [{'subcategory': '10293182094'}]]]

def get_subcategories(_d, _flag):

   flag = None

   for i in _d:

     if isinstance(i, dict):

       _val = list(i.values())[0]

       if _val in categoriesToFind or _flag:

         yield _val

         flag = True

     else:

        yield from get_subcategories(i, _flag or flag)



print(list(get_subcategories(d, False)))

Output:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

answered Nov 20 at 4:02

Ajax1234

39.9k42652

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

add a comment |

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1 Answer
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active

oldest

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1 Answer
1

active

oldest

votes

You can use recursion with a generator:

categoriesToFind = ['019301948109', '1309183912309']

d = [{'category1': '0120391123123'}, [{'subcategory': '0120391123123'}, [{'subsubcategory': '019301948109'}, [{'subsubsubcategory': '013904123908'}, [{'subsubsubsubcategory': '019341823908'}]]]], [{'subcategory2': '0934810923801'}, [{'subsubcategory2': '09341829308123'}]], [{'category2': '1309183912309'}, [{'subcategory': '10293182094'}]]]

def get_subcategories(_d, _flag):

   flag = None

   for i in _d:

     if isinstance(i, dict):

       _val = list(i.values())[0]

       if _val in categoriesToFind or _flag:

         yield _val

         flag = True

     else:

        yield from get_subcategories(i, _flag or flag)



print(list(get_subcategories(d, False)))

Output:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

answered Nov 20 at 4:02

Ajax1234

39.9k42652

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

add a comment |

You can use recursion with a generator:

categoriesToFind = ['019301948109', '1309183912309']

d = [{'category1': '0120391123123'}, [{'subcategory': '0120391123123'}, [{'subsubcategory': '019301948109'}, [{'subsubsubcategory': '013904123908'}, [{'subsubsubsubcategory': '019341823908'}]]]], [{'subcategory2': '0934810923801'}, [{'subsubcategory2': '09341829308123'}]], [{'category2': '1309183912309'}, [{'subcategory': '10293182094'}]]]

def get_subcategories(_d, _flag):

   flag = None

   for i in _d:

     if isinstance(i, dict):

       _val = list(i.values())[0]

       if _val in categoriesToFind or _flag:

         yield _val

         flag = True

     else:

        yield from get_subcategories(i, _flag or flag)



print(list(get_subcategories(d, False)))

Output:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

answered Nov 20 at 4:02

Ajax1234

39.9k42652

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

add a comment |

You can use recursion with a generator:

categoriesToFind = ['019301948109', '1309183912309']

d = [{'category1': '0120391123123'}, [{'subcategory': '0120391123123'}, [{'subsubcategory': '019301948109'}, [{'subsubsubcategory': '013904123908'}, [{'subsubsubsubcategory': '019341823908'}]]]], [{'subcategory2': '0934810923801'}, [{'subsubcategory2': '09341829308123'}]], [{'category2': '1309183912309'}, [{'subcategory': '10293182094'}]]]

def get_subcategories(_d, _flag):

   flag = None

   for i in _d:

     if isinstance(i, dict):

       _val = list(i.values())[0]

       if _val in categoriesToFind or _flag:

         yield _val

         flag = True

     else:

        yield from get_subcategories(i, _flag or flag)



print(list(get_subcategories(d, False)))

Output:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

answered Nov 20 at 4:02

Ajax1234

39.9k42652

You can use recursion with a generator:

categoriesToFind = ['019301948109', '1309183912309']

d = [{'category1': '0120391123123'}, [{'subcategory': '0120391123123'}, [{'subsubcategory': '019301948109'}, [{'subsubsubcategory': '013904123908'}, [{'subsubsubsubcategory': '019341823908'}]]]], [{'subcategory2': '0934810923801'}, [{'subsubcategory2': '09341829308123'}]], [{'category2': '1309183912309'}, [{'subcategory': '10293182094'}]]]

def get_subcategories(_d, _flag):

   flag = None

   for i in _d:

     if isinstance(i, dict):

       _val = list(i.values())[0]

       if _val in categoriesToFind or _flag:

         yield _val

         flag = True

     else:

        yield from get_subcategories(i, _flag or flag)



print(list(get_subcategories(d, False)))

Output:

['019301948109', '013904123908', '019341823908', '1309183912309', '10293182094']

answered Nov 20 at 4:02

Ajax1234

39.9k42652

answered Nov 20 at 4:02

Ajax1234

39.9k42652

answered Nov 20 at 4:02

Ajax1234

39.9k42652

answered Nov 20 at 4:02

Ajax1234

39.9k42652

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

add a comment |

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

The _flag trick is cool.
– slider
Nov 20 at 4:18

Thanks for the help! If anyone stumbles on this, you can do this in python 2.7.X with this: stackoverflow.com/questions/17581332/…
– Evan Hessler
Nov 20 at 4:22

add a comment |

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