Rotate a column












27












$begingroup$


Given an integer k and either a block of text, or a 2d array that the inner arrays may have unequal lengths (that resembles a block of text), rotate every character or element in the k-th column up or down to the next position that exists.



Example



Rotate the 20th column of the following text (1-based):



A line with more than k characters.
A longer line with more than k character.
A short line.
Rotate here: ------v--
This is long enough.

This is not enough.
Wrapping around to the first line.


Output:



A line with more thtn k characters.
A longer line with aore than k character.
A short line.
Rotate here: ------m--
This is long enoughv

This is not enough.
Wrapping around to .he first line.


Rotating the k-th column of the same input where 35 < k < 42 would yield the input text unchanged.



Rules




  • You may use raw text, an array of lines, a 2d array of characters, or any reasonable format to represent the data. You may also use data types other than characters.

  • The number of possible values of the data type of the elements must be at least 20 if your code length depends on it, otherwise at least 2. This could be a subset of the characters or other values supported in the native type.

  • Spaces and any kind of null values are just normal values, if you allow them in the input. You may also simply exclude them in the element type.


  • Rule change: You are allowed to pad the shorter arrays with a generic default value (such as spaces), if you prefer using arrays with equal lengths to store the data.


  • k could be 0-based or 1-based. It is guaranteed to be inside the longest line in the input (implying the input has at least one non-empty line).

  • You may choose whether it rotates up or down.

  • Either just rotate one position, or rotate n positions where n is a positive integer given in the input.

  • Shortest code wins.










share|improve this question











$endgroup$

















    27












    $begingroup$


    Given an integer k and either a block of text, or a 2d array that the inner arrays may have unequal lengths (that resembles a block of text), rotate every character or element in the k-th column up or down to the next position that exists.



    Example



    Rotate the 20th column of the following text (1-based):



    A line with more than k characters.
    A longer line with more than k character.
    A short line.
    Rotate here: ------v--
    This is long enough.

    This is not enough.
    Wrapping around to the first line.


    Output:



    A line with more thtn k characters.
    A longer line with aore than k character.
    A short line.
    Rotate here: ------m--
    This is long enoughv

    This is not enough.
    Wrapping around to .he first line.


    Rotating the k-th column of the same input where 35 < k < 42 would yield the input text unchanged.



    Rules




    • You may use raw text, an array of lines, a 2d array of characters, or any reasonable format to represent the data. You may also use data types other than characters.

    • The number of possible values of the data type of the elements must be at least 20 if your code length depends on it, otherwise at least 2. This could be a subset of the characters or other values supported in the native type.

    • Spaces and any kind of null values are just normal values, if you allow them in the input. You may also simply exclude them in the element type.


    • Rule change: You are allowed to pad the shorter arrays with a generic default value (such as spaces), if you prefer using arrays with equal lengths to store the data.


    • k could be 0-based or 1-based. It is guaranteed to be inside the longest line in the input (implying the input has at least one non-empty line).

    • You may choose whether it rotates up or down.

    • Either just rotate one position, or rotate n positions where n is a positive integer given in the input.

    • Shortest code wins.










    share|improve this question











    $endgroup$















      27












      27








      27


      4



      $begingroup$


      Given an integer k and either a block of text, or a 2d array that the inner arrays may have unequal lengths (that resembles a block of text), rotate every character or element in the k-th column up or down to the next position that exists.



      Example



      Rotate the 20th column of the following text (1-based):



      A line with more than k characters.
      A longer line with more than k character.
      A short line.
      Rotate here: ------v--
      This is long enough.

      This is not enough.
      Wrapping around to the first line.


      Output:



      A line with more thtn k characters.
      A longer line with aore than k character.
      A short line.
      Rotate here: ------m--
      This is long enoughv

      This is not enough.
      Wrapping around to .he first line.


      Rotating the k-th column of the same input where 35 < k < 42 would yield the input text unchanged.



      Rules




      • You may use raw text, an array of lines, a 2d array of characters, or any reasonable format to represent the data. You may also use data types other than characters.

      • The number of possible values of the data type of the elements must be at least 20 if your code length depends on it, otherwise at least 2. This could be a subset of the characters or other values supported in the native type.

      • Spaces and any kind of null values are just normal values, if you allow them in the input. You may also simply exclude them in the element type.


      • Rule change: You are allowed to pad the shorter arrays with a generic default value (such as spaces), if you prefer using arrays with equal lengths to store the data.


      • k could be 0-based or 1-based. It is guaranteed to be inside the longest line in the input (implying the input has at least one non-empty line).

      • You may choose whether it rotates up or down.

      • Either just rotate one position, or rotate n positions where n is a positive integer given in the input.

      • Shortest code wins.










      share|improve this question











      $endgroup$




      Given an integer k and either a block of text, or a 2d array that the inner arrays may have unequal lengths (that resembles a block of text), rotate every character or element in the k-th column up or down to the next position that exists.



      Example



      Rotate the 20th column of the following text (1-based):



      A line with more than k characters.
      A longer line with more than k character.
      A short line.
      Rotate here: ------v--
      This is long enough.

      This is not enough.
      Wrapping around to the first line.


      Output:



      A line with more thtn k characters.
      A longer line with aore than k character.
      A short line.
      Rotate here: ------m--
      This is long enoughv

      This is not enough.
      Wrapping around to .he first line.


      Rotating the k-th column of the same input where 35 < k < 42 would yield the input text unchanged.



      Rules




      • You may use raw text, an array of lines, a 2d array of characters, or any reasonable format to represent the data. You may also use data types other than characters.

      • The number of possible values of the data type of the elements must be at least 20 if your code length depends on it, otherwise at least 2. This could be a subset of the characters or other values supported in the native type.

      • Spaces and any kind of null values are just normal values, if you allow them in the input. You may also simply exclude them in the element type.


      • Rule change: You are allowed to pad the shorter arrays with a generic default value (such as spaces), if you prefer using arrays with equal lengths to store the data.


      • k could be 0-based or 1-based. It is guaranteed to be inside the longest line in the input (implying the input has at least one non-empty line).

      • You may choose whether it rotates up or down.

      • Either just rotate one position, or rotate n positions where n is a positive integer given in the input.

      • Shortest code wins.







      code-golf string array-manipulation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 29 at 0:13







      jimmy23013

















      asked Mar 28 at 8:56









      jimmy23013jimmy23013

      29.8k561129




      29.8k561129






















          19 Answers
          19






          active

          oldest

          votes


















          7












          $begingroup$


          APL (Dyalog Extended), 9 bytesSBCS





          Full program. Prompts stdin for 2D block of text, then k (0-based or 1-based, depending on APL's current setting), then n. Positive n rotate up, negative n rotate down.



          The domain consists of either one of the following:




          1. all Unicode characters, except spaces, leaving 1114111 allowed values, which is more than the required 20.


          2. all numbers, except 0, leaving approximately 2129 allowed values, which is more than the required 20.



          Since APL requires 2D blocks to be rectangular, the input must be padded with spaces/zeros. This can be done automatically by entering to the left of a list of strings/numerical lists.



          ⎕⌽@≠@⎕⍢⍉⎕


          Try it online! (the apparent spaces are actually non-breaking spaces)



           prompt for text block



          ⍢⍉ while transposed:



          @⎕ apply the following on the input'th row:



            @≠ at elements different from their prototype (space for characters, zero for numbers):



             ⎕⌽ rotate "input" steps left




          APL (Dyalog Unicode), 22+ bytesSBCS





          This version allows the full character set by using zeros as identifiable fill element.



          0~¨⍨↓⍉⎕⌽@(0≠⊢)@⎕⍉↑0,¨⎕


          Try it online!



          This of course means that zeros are not allowed in numeric arguments. The corresponding program for all numbers would have the three occurrences of 0 replaced by ' ' and thus use space as fill:



          ' '~¨⍨↓⍉⎕⌽@(' '≠⊢)@⎕⍉↑' ',¨⎕


          If we truly want the full ranges of (even a mixture of) both characters and numbers, we could use null as fill:



          n~¨⍨↓⍉⎕⌽@(n≠⊢)@⎕⍉↑⎕,¨⍨n←⎕NULL


          And finally, if we wanted to include nulls and objects in the input domain, we could define a fill class and use instances of this as fills:



          ~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX':Class C' ':EndClass'





          share|improve this answer











          $endgroup$













          • $begingroup$
            Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
            $endgroup$
            – jimmy23013
            Mar 28 at 23:55










          • $begingroup$
            Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
            $endgroup$
            – jimmy23013
            Mar 29 at 0:09










          • $begingroup$
            @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
            $endgroup$
            – Adám
            Mar 29 at 0:43





















          10












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          Python 2, 111 110 109 99 98 96 94 bytes





          lambda a,n:[l[:n]+(l[n:]and[L[n]for L in a[i:]+a if L[n:]][1]+l[n+1:])for i,l in enumerate(a)]


          Try it online!



          Takes input as a list of lines and 0-index column, and returns a list of strings.



          Column is rotated up 1.



          -11 bytes, thanks to Jo King






          share|improve this answer











          $endgroup$





















            7












            $begingroup$

            Java 8, 107 106 135 107 bytes





            k->m->{int s=m.length,i=-1;for(char p=0,t;i<s;t=m[i%s][k],m[i%s][k]=p<1?t:p,p=t)for(;m[++i%s].length<=k;);}


            +29 bytes for a bug-fix..



            0-indexed; rotates down like the example.

            Input as a character-matrix; modifies the char-matrix instead of returning a new one to save bytes.



            Try it online.



            Explanation:



            k->m->{                 // Method with integer and char-matrix parameters and no return-type
            int s=m.length, // Amount of lines in the matrix `s`
            i=-1; // Index-integer `i`, starting at -1
            for(char p=0, // Previous-character, starting at 0
            t; // Temp-char, uninitialized
            i<s // Loop as long as `i` is smaller than `s`:
            ; // After every iteration:
            t=m[i%s][k], // Set the temp to the `k`th character of the `i`'th line
            m[i%s][k]= // Replace the `k`'th character of the `i`'th line with:
            p<1? // If `p` is still 0:
            t // Set it to the temp we just set
            : // Else:
            p, // Set it to the previous-character instead
            p=t) // And then replace `p` with the temp for the next iteration
            for(;m[++i // Increase `i` by 1 before every iteration with `++i`,
            %s].length // And continue this loop until the length of the `i`'th line
            <=k;);} // is smaller than or equal to the input `k`





            share|improve this answer











            $endgroup$









            • 1




              $begingroup$
              One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
              $endgroup$
              – dana
              Mar 28 at 13:31










            • $begingroup$
              @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
              $endgroup$
              – Kevin Cruijssen
              Mar 28 at 13:33








            • 1




              $begingroup$
              @dana Fixed, thanks for noticing.
              $endgroup$
              – Kevin Cruijssen
              Mar 28 at 13:44






            • 2




              $begingroup$
              @dana And back to 107 again. ;)
              $endgroup$
              – Kevin Cruijssen
              Mar 28 at 19:45






            • 1




              $begingroup$
              @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
              $endgroup$
              – Kevin Cruijssen
              Mar 29 at 7:21



















            7












            $begingroup$


            Zsh, 94 87 78 bytes



            -7 bytes by changing to an arithmetic ternary, -9 bytes by changing the character in-place. (TIL)





            i=$1
            shift
            for s;c+=($s[i])
            c=($c[-1] $c)
            for s;s[i]=$c[$[$#s<i?0:++j]]&&<<<$s


            Try it online!
            Try it online!

            Try it online!



            Input is index [ string ... ]





            So, my previous comment about the subshell printing is now outdated, but here it is with the old last line for posterity:



            for s;echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}



            Hey, Gamma, why did you use echo in that last command instead of <<<?
            Wouldn't <<< save you two bytes?




            I'm glad you asked! Go ahead and give it a try. See if you can figure out what's happening.



            (Hint: Run echo $ZSH_SUBSHELL; <<< $ZSH_SUBSHELL.)





            You get 0 for echo, but 1 for <<<.
            Here-strings are run in subshells because they are given as stdin to another program.
            If there is no program given, it is implicitly given to cat.
            You can see this with <<< $_.
            <<< $ZSH_SUBSHELL is similar to echo $ZSH_SUBSHELL | cat.
            Since we need to increment j, we can't be in a subshell.



            Anyway, on to the main event:



            i=$1
            shift
            for s
            c+=($s[i]) # without "", empty strings aren't added
            c=($c[-1] $c) # add the last element onto the start
            for s
            echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}
            $s[0,i-1] ${s:$i} # before and after the replacement point
            $c[ ] # insert from char array
            $[$#s<i?0 ] # Sting is too small: at index 0: empty string
            $[$#s<i :++j] # Increment j and insert from there
            # j is unset, so ++j initially sets j to 1





            share|improve this answer











            $endgroup$





















              6












              $begingroup$


              R, 62 bytes





              function(L,n){L[A,n]<-rep(L[A<-L[,n]!=' ',n],2)[1+1:sum(A)];L}


              Try it online!



              Takes input as a space-padded matrix of characters. Rotates upwards. All thanks to Kirill L.!




              R, 74 bytes





              function(L,n){substr(L[A],n,n)=rep(substr(L[A<-nchar(L)>=n],n,n),2)[-1]
              L}


              Try it online!



              This submission predates the allowance of padded lines.



              Aliasing substr here won't work because we're calling substr and substr<- in the first line.



              I/O as a list of non-padded lines; rotates upwards.






              share|improve this answer











              $endgroup$













              • $begingroup$
                Since consensus allows modifying inputs, we can do this crazy thing
                $endgroup$
                – Kirill L.
                Mar 29 at 9:49










              • $begingroup$
                Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                $endgroup$
                – Kirill L.
                Mar 29 at 9:50










              • $begingroup$
                @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                $endgroup$
                – Giuseppe
                Mar 29 at 14:42










              • $begingroup$
                Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                $endgroup$
                – Kirill L.
                Mar 29 at 15:16



















              5












              $begingroup$


              C# (Visual C# Interactive Compiler), 82 bytes





              k=>a=>{var c='0';a.Where(b=>b.Count>k&&((b[k],c)=(c,b[k])).c>0).ToList()[0][k]=c;}


              Try it online!



              Credit to @ASCIIOnly for suggesting foreach which led to a 12 byte savings!



              -8 bytes thanks to @someone!

              -1 byte thanks to @EmbodimentofIgnorance!






              share|improve this answer











              $endgroup$













              • $begingroup$
                184 bytes
                $endgroup$
                – Expired Data
                Mar 28 at 14:41










              • $begingroup$
                Maybe 183 if using ints instead of chars
                $endgroup$
                – Expired Data
                Mar 28 at 14:46










              • $begingroup$
                @ExpiredData ew int instead of char
                $endgroup$
                – ASCII-only
                Mar 29 at 6:05












              • $begingroup$
                too bad you can't use a foreach since it's the opposite order :(
                $endgroup$
                – ASCII-only
                Mar 29 at 6:08






              • 1




                $begingroup$
                Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                $endgroup$
                – someone
                Mar 30 at 7:25



















              4












              $begingroup$


              Ruby, 57 bytes





              ->a,k{b=a.map{|i|i[k]}-[p];c=-2;a.map{|i|i[k]&&=b[c+=1]}}


              Try it online!



              Takes input as an array of lines a. Rotates the text down at 0-based position k. Returns by modifying the input a.






              share|improve this answer









              $endgroup$





















                3












                $begingroup$


                05AB1E, 21 bytes



                ʒg‹}U¹εXyk©diX®<èIèIǝ


                Can definitely be golfed some more..



                0-indexed; input and output both as a list of strings.

                It rotates down like the example, but < can be replaced with > to rotate up instead.



                Try it online (footer joins the list by newlines, remove it to see the actual list output).



                Explanation:





                ʒ  }             # Filter the (implicit) input-list by:
                g # Where length of the current string
                ‹ # is larger than the (implicit) input-integer
                U # Pop and store this filtered list in variable `X`
                ¹ε # Map over the first input-list again:
                Xyk # Get the index of the current string in variable `X`
                © # Store it in the register (without popping)
                di # If the index is not -1, so the current string is present in variable `X`
                X®<è # Get the (index-1)'th string in variable `X`
                Iè # Get the character at the index of the input-integer
                Iǝ # And insert it at the index of the input-integer in the current string





                share|improve this answer











                $endgroup$





















                  3












                  $begingroup$


                  K4, 41 bytes



                  Solution:



                  {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]}


                  Explanation:



                  Not sure if I'm missing something... 0 index, rotates up (change the 1 to -1 for rotate down)



                  {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]} / the solution
                  { } / lambda taking implicit x and y
                  .[x; ;:; ] / index apply assignment back into x
                  .q.rotate[1; ] / left rotate 1 character
                  ( ; ) / two item list
                  y / index to rotate
                  #:'x / count (#:) each (') input
                  y< / index less than ?
                  & / indexes where true
                  i: / assign to variable w
                  x . / index into x
                  i / indexes we saved as i earlier





                  share|improve this answer









                  $endgroup$





















                    3












                    $begingroup$


                    Japt v2.0a0, 18 bytes



                    0-based with input & output as a multi-line string. Rotates up by 1.



                    There's gotta be a shorter method!



                    yÈrS_Y¦V?Z:°TgXrS


                    Try it



                    yÈrS_Y¦V?Z:°TgXrS     :Implicit input of string U & integer V
                    y :Transpose
                    È :Pass each line X at 0-based index Y through the following function & transpose back
                    r : Replace
                    S : RegEx /S/g
                    _ : Pass each match Z through the following function
                    Y¦V : Test Y for inequality with V
                    ?Z: : If true, return Z, else
                    °T : Increment T (initially 0)
                    g : Index into
                    XrS : X with spaces removed





                    share|improve this answer









                    $endgroup$













                    • $begingroup$
                      I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                      $endgroup$
                      – Kevin Cruijssen
                      Mar 29 at 14:30












                    • $begingroup$
                      @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                      $endgroup$
                      – Shaggy
                      Mar 29 at 15:12










                    • $begingroup$
                      "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                      $endgroup$
                      – Kevin Cruijssen
                      Mar 29 at 17:04





















                    3












                    $begingroup$


                    Jelly, 16 bytes



                    z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦"


                    A dyadic Link accepting a list of lines (lists of characters containing no newline characters) on the left and an integer on the right which returns a list of lines.



                    Try it online! (footer splits on newlines, calls the Link, and joins by newlines again)



                    How?



                    z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦" - Link: lines L; index I        e.g. example in question; 20
                    z⁷ - transpose L with filler 'n' ['AAARTnTW', ' ohnhr', ...]
                    ⁹ị - Ith item 'amnv.nnt'
                    Ỵ - split at newlines ['am', 'v.', '', 't']
                    Ʋ - last four links as a monad - i.e. f(X):
                    F - flatten 'amv.t'
                    - - -1
                    ṙ - rotate left by 'tamv.'
                    ṁ - mould like X ['ta', 'mv', '', '.']
                    Y - join with newlines 'tanmvnn.'
                    - -- call this C
                    ⁸ - chain's left argument, L
                    " - zip with - i.e. [f(L1,C1), f(L2,C2), ...]:
                    ¦ - sparse application...
                    ⁹ - ...to indices: chain's right argument, I
                    ṛ - ...of: right argument, Cn





                    share|improve this answer











                    $endgroup$





















                      2












                      $begingroup$

                      perl 5 (-p), 75 bytes



                      k is 0-indexed, rotate down



                      s/.*//;$r="^.{$&}";s/
                      //;/$r(.)/;$c=$1;s/$rK.(?=(?s:.)*?$r(.)|)/$1||$c/gme


                      TIO






                      share|improve this answer









                      $endgroup$





















                        2












                        $begingroup$


                        Perl 6, 38 33 bytes





                        Modifies the array in place (rules don't disallow)



                        {@^a.grep(*>$^b+1)[*;$b].=rotate}


                        Try it online!






                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                          $endgroup$
                          – guifa
                          Mar 30 at 2:25












                        • $begingroup$
                          ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                          $endgroup$
                          – Jo King
                          Mar 30 at 3:54





















                        2












                        $begingroup$


                        JavaScript (Node.js), 52 bytes





                        k=>a=>a.filter(b=>b[k]&&([b[k],a]=[a,b[k]]))[0][k]=a


                        Try it online!



                        -7 bytes thanks to Shaggy!



                        Didn't see a JavaScript answer yet! Port of my C# answer.






                        share|improve this answer











                        $endgroup$













                        • $begingroup$
                          63 bytes. Can probably be golfed further.
                          $endgroup$
                          – Shaggy
                          Mar 30 at 15:02










                        • $begingroup$
                          @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                          $endgroup$
                          – dana
                          Mar 30 at 15:12






                        • 1




                          $begingroup$
                          Oh, nicely golfed! :)
                          $endgroup$
                          – Shaggy
                          Mar 31 at 2:01



















                        2












                        $begingroup$


                        Charcoal, 34 28 21 bytes



                        θJη⁰≔ΦKDLθ↓℅ιζUMζ§ζ⊖κ


                        Try it online! Link is to verbose version of code. Takes an array of strings as input. 0-indexed. Edit: Now that PeekDirection has been fixed, I can manipulate it directly. Explanation:



                        θ


                        Print the input strings.



                        Jη⁰


                        Jump to the top of the column to be rotated.



                        ≔ΦKDLθ↓℅ιζ


                        Extract the cells that have been printed in.



                        UMζ§ζ⊖κ


                        Replace each printed cell with the value of the previous cell (cyclically). Conveniently the cell values are read at the time of the PeekDirection call so the fact that the MapCommand call writes new values into the cells doesn't matter.






                        share|improve this answer











                        $endgroup$





















                          1












                          $begingroup$


                          Pip -rn, 32 bytes



                          POgY#(g@_)>aFI,#gFiyAE@ySsg@i@ag


                          0-indexed, rotates down. Try it online!



                          Filters to find the indices of all rows that are long enough to participate in the rotation. Then loops over those rows, swapping the appropriate character on each row with a temp variable s. Visiting the first row again at the end swaps the dummy value back out again.






                          share|improve this answer









                          $endgroup$





















                            1












                            $begingroup$


                            Jelly, 19 bytes



                            ZnÄ×$ịḟ¹ṙ-;ɗɗʋ€⁹¦⁶Z


                            Try it online!



                            1-indexed. Rotates down. A monadic link that takes a right-padded list of Jelly strings (a list of lists of characters) as the first argument and k as the second. Spaces are forbidden in the input except as right padding, but all other characters are permitted.



                            As implemented on TIO, the footer splits a single string input into a list of strings and right-pads it, but this is for convenience; as I understand it, the result of that step is permitted input for the main link per the rules.






                            share|improve this answer









                            $endgroup$





















                              0












                              $begingroup$


                              GFortran, 203 bytes



                              -20 or so by reading from stdin rather than a file
                              -14 by using implicit integers for i, k, n



                              Requires user to input k and n on the first line, where k is the column to rotate, and n is the number of rows of text. Subsequent inputs are the lines of text to be rotated. This was a pain to write! Fortran is so pedantic!



                              Original, ungolfed program here, with comments and compilation notes: rotcol.f



                              Try it here: https://rextester.com/RBEE63006



                              character(80),allocatable::A(:)
                              character(1)::r,s
                              read(*,*) k,n
                              allocate(A(n))
                              do i=1,n
                              read(*,'(A)')A(i)
                              r=A(i)(k:k)
                              if(r.ne.''.or.r.ne.' ')then
                              A(i)(k:k)=s
                              s=r
                              endif
                              enddo
                              A(1)(k:k)=s
                              print'(A)',A
                              end





                              share|improve this answer











                              $endgroup$





















                                0












                                $begingroup$

                                T-SQL, 208 bytes



                                WITH C as(SELECT rank()over(order
                                by i)r,sum(1)over()c,*FROM @
                                WHERE len(x)>=@c)SELECT
                                isnull(m,x)FROM @ z
                                LEFT JOIN(SELECT stuff(c.x,@c,1,substring(e.x,@c,1))m,c.i
                                FROM c,c e WHERE e.r%c.c+1=c.r)d
                                ON z.i=d.i


                                Try it online ungolfed version






                                share|improve this answer









                                $endgroup$














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                                  7












                                  $begingroup$


                                  APL (Dyalog Extended), 9 bytesSBCS





                                  Full program. Prompts stdin for 2D block of text, then k (0-based or 1-based, depending on APL's current setting), then n. Positive n rotate up, negative n rotate down.



                                  The domain consists of either one of the following:




                                  1. all Unicode characters, except spaces, leaving 1114111 allowed values, which is more than the required 20.


                                  2. all numbers, except 0, leaving approximately 2129 allowed values, which is more than the required 20.



                                  Since APL requires 2D blocks to be rectangular, the input must be padded with spaces/zeros. This can be done automatically by entering to the left of a list of strings/numerical lists.



                                  ⎕⌽@≠@⎕⍢⍉⎕


                                  Try it online! (the apparent spaces are actually non-breaking spaces)



                                   prompt for text block



                                  ⍢⍉ while transposed:



                                  @⎕ apply the following on the input'th row:



                                    @≠ at elements different from their prototype (space for characters, zero for numbers):



                                     ⎕⌽ rotate "input" steps left




                                  APL (Dyalog Unicode), 22+ bytesSBCS





                                  This version allows the full character set by using zeros as identifiable fill element.



                                  0~¨⍨↓⍉⎕⌽@(0≠⊢)@⎕⍉↑0,¨⎕


                                  Try it online!



                                  This of course means that zeros are not allowed in numeric arguments. The corresponding program for all numbers would have the three occurrences of 0 replaced by ' ' and thus use space as fill:



                                  ' '~¨⍨↓⍉⎕⌽@(' '≠⊢)@⎕⍉↑' ',¨⎕


                                  If we truly want the full ranges of (even a mixture of) both characters and numbers, we could use null as fill:



                                  n~¨⍨↓⍉⎕⌽@(n≠⊢)@⎕⍉↑⎕,¨⍨n←⎕NULL


                                  And finally, if we wanted to include nulls and objects in the input domain, we could define a fill class and use instances of this as fills:



                                  ~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX':Class C' ':EndClass'





                                  share|improve this answer











                                  $endgroup$













                                  • $begingroup$
                                    Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                    $endgroup$
                                    – jimmy23013
                                    Mar 28 at 23:55










                                  • $begingroup$
                                    Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                    $endgroup$
                                    – jimmy23013
                                    Mar 29 at 0:09










                                  • $begingroup$
                                    @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                    $endgroup$
                                    – Adám
                                    Mar 29 at 0:43


















                                  7












                                  $begingroup$


                                  APL (Dyalog Extended), 9 bytesSBCS





                                  Full program. Prompts stdin for 2D block of text, then k (0-based or 1-based, depending on APL's current setting), then n. Positive n rotate up, negative n rotate down.



                                  The domain consists of either one of the following:




                                  1. all Unicode characters, except spaces, leaving 1114111 allowed values, which is more than the required 20.


                                  2. all numbers, except 0, leaving approximately 2129 allowed values, which is more than the required 20.



                                  Since APL requires 2D blocks to be rectangular, the input must be padded with spaces/zeros. This can be done automatically by entering to the left of a list of strings/numerical lists.



                                  ⎕⌽@≠@⎕⍢⍉⎕


                                  Try it online! (the apparent spaces are actually non-breaking spaces)



                                   prompt for text block



                                  ⍢⍉ while transposed:



                                  @⎕ apply the following on the input'th row:



                                    @≠ at elements different from their prototype (space for characters, zero for numbers):



                                     ⎕⌽ rotate "input" steps left




                                  APL (Dyalog Unicode), 22+ bytesSBCS





                                  This version allows the full character set by using zeros as identifiable fill element.



                                  0~¨⍨↓⍉⎕⌽@(0≠⊢)@⎕⍉↑0,¨⎕


                                  Try it online!



                                  This of course means that zeros are not allowed in numeric arguments. The corresponding program for all numbers would have the three occurrences of 0 replaced by ' ' and thus use space as fill:



                                  ' '~¨⍨↓⍉⎕⌽@(' '≠⊢)@⎕⍉↑' ',¨⎕


                                  If we truly want the full ranges of (even a mixture of) both characters and numbers, we could use null as fill:



                                  n~¨⍨↓⍉⎕⌽@(n≠⊢)@⎕⍉↑⎕,¨⍨n←⎕NULL


                                  And finally, if we wanted to include nulls and objects in the input domain, we could define a fill class and use instances of this as fills:



                                  ~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX':Class C' ':EndClass'





                                  share|improve this answer











                                  $endgroup$













                                  • $begingroup$
                                    Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                    $endgroup$
                                    – jimmy23013
                                    Mar 28 at 23:55










                                  • $begingroup$
                                    Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                    $endgroup$
                                    – jimmy23013
                                    Mar 29 at 0:09










                                  • $begingroup$
                                    @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                    $endgroup$
                                    – Adám
                                    Mar 29 at 0:43
















                                  7












                                  7








                                  7





                                  $begingroup$


                                  APL (Dyalog Extended), 9 bytesSBCS





                                  Full program. Prompts stdin for 2D block of text, then k (0-based or 1-based, depending on APL's current setting), then n. Positive n rotate up, negative n rotate down.



                                  The domain consists of either one of the following:




                                  1. all Unicode characters, except spaces, leaving 1114111 allowed values, which is more than the required 20.


                                  2. all numbers, except 0, leaving approximately 2129 allowed values, which is more than the required 20.



                                  Since APL requires 2D blocks to be rectangular, the input must be padded with spaces/zeros. This can be done automatically by entering to the left of a list of strings/numerical lists.



                                  ⎕⌽@≠@⎕⍢⍉⎕


                                  Try it online! (the apparent spaces are actually non-breaking spaces)



                                   prompt for text block



                                  ⍢⍉ while transposed:



                                  @⎕ apply the following on the input'th row:



                                    @≠ at elements different from their prototype (space for characters, zero for numbers):



                                     ⎕⌽ rotate "input" steps left




                                  APL (Dyalog Unicode), 22+ bytesSBCS





                                  This version allows the full character set by using zeros as identifiable fill element.



                                  0~¨⍨↓⍉⎕⌽@(0≠⊢)@⎕⍉↑0,¨⎕


                                  Try it online!



                                  This of course means that zeros are not allowed in numeric arguments. The corresponding program for all numbers would have the three occurrences of 0 replaced by ' ' and thus use space as fill:



                                  ' '~¨⍨↓⍉⎕⌽@(' '≠⊢)@⎕⍉↑' ',¨⎕


                                  If we truly want the full ranges of (even a mixture of) both characters and numbers, we could use null as fill:



                                  n~¨⍨↓⍉⎕⌽@(n≠⊢)@⎕⍉↑⎕,¨⍨n←⎕NULL


                                  And finally, if we wanted to include nulls and objects in the input domain, we could define a fill class and use instances of this as fills:



                                  ~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX':Class C' ':EndClass'





                                  share|improve this answer











                                  $endgroup$




                                  APL (Dyalog Extended), 9 bytesSBCS





                                  Full program. Prompts stdin for 2D block of text, then k (0-based or 1-based, depending on APL's current setting), then n. Positive n rotate up, negative n rotate down.



                                  The domain consists of either one of the following:




                                  1. all Unicode characters, except spaces, leaving 1114111 allowed values, which is more than the required 20.


                                  2. all numbers, except 0, leaving approximately 2129 allowed values, which is more than the required 20.



                                  Since APL requires 2D blocks to be rectangular, the input must be padded with spaces/zeros. This can be done automatically by entering to the left of a list of strings/numerical lists.



                                  ⎕⌽@≠@⎕⍢⍉⎕


                                  Try it online! (the apparent spaces are actually non-breaking spaces)



                                   prompt for text block



                                  ⍢⍉ while transposed:



                                  @⎕ apply the following on the input'th row:



                                    @≠ at elements different from their prototype (space for characters, zero for numbers):



                                     ⎕⌽ rotate "input" steps left




                                  APL (Dyalog Unicode), 22+ bytesSBCS





                                  This version allows the full character set by using zeros as identifiable fill element.



                                  0~¨⍨↓⍉⎕⌽@(0≠⊢)@⎕⍉↑0,¨⎕


                                  Try it online!



                                  This of course means that zeros are not allowed in numeric arguments. The corresponding program for all numbers would have the three occurrences of 0 replaced by ' ' and thus use space as fill:



                                  ' '~¨⍨↓⍉⎕⌽@(' '≠⊢)@⎕⍉↑' ',¨⎕


                                  If we truly want the full ranges of (even a mixture of) both characters and numbers, we could use null as fill:



                                  n~¨⍨↓⍉⎕⌽@(n≠⊢)@⎕⍉↑⎕,¨⍨n←⎕NULL


                                  And finally, if we wanted to include nulls and objects in the input domain, we could define a fill class and use instances of this as fills:



                                  ~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX':Class C' ':EndClass'






                                  share|improve this answer














                                  share|improve this answer



                                  share|improve this answer








                                  edited Mar 28 at 17:22

























                                  answered Mar 28 at 11:17









                                  AdámAdám

                                  29k276207




                                  29k276207












                                  • $begingroup$
                                    Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                    $endgroup$
                                    – jimmy23013
                                    Mar 28 at 23:55










                                  • $begingroup$
                                    Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                    $endgroup$
                                    – jimmy23013
                                    Mar 29 at 0:09










                                  • $begingroup$
                                    @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                    $endgroup$
                                    – Adám
                                    Mar 29 at 0:43




















                                  • $begingroup$
                                    Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                    $endgroup$
                                    – jimmy23013
                                    Mar 28 at 23:55










                                  • $begingroup$
                                    Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                    $endgroup$
                                    – jimmy23013
                                    Mar 29 at 0:09










                                  • $begingroup$
                                    @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                    $endgroup$
                                    – Adám
                                    Mar 29 at 0:43


















                                  $begingroup$
                                  Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                  $endgroup$
                                  – jimmy23013
                                  Mar 28 at 23:55




                                  $begingroup$
                                  Now officially declare this (and the new answers like this) as a valid answer. Sorry if this has bothered you too much.
                                  $endgroup$
                                  – jimmy23013
                                  Mar 28 at 23:55












                                  $begingroup$
                                  Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                  $endgroup$
                                  – jimmy23013
                                  Mar 29 at 0:09




                                  $begingroup$
                                  Shorter than your null version: n~¨⍨↓⍉⎕⌽@(≢¨)@⎕⍉↑⎕,¨⍨n←⊂⊂⍬. Maybe you could add modded in your extension to help further golfing (but I'm not exactly sure how useful they are).
                                  $endgroup$
                                  – jimmy23013
                                  Mar 29 at 0:09












                                  $begingroup$
                                  @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                  $endgroup$
                                  – Adám
                                  Mar 29 at 0:43






                                  $begingroup$
                                  @jimmy23013 Yeah, I thought of that, but then it can't take lists of arbitrarily nested stuff. The last one is the ultimate solution, especially if C and I are localised so they don't pollute: {~∘I¨⍨↓⍉⎕⌽@(~⊢∊I←⎕INSTANCES⊢∘C)@⎕⍉↑⎕,¨⍨⎕NEW⎕FIX I←C←':Class C' ':EndClass'}
                                  $endgroup$
                                  – Adám
                                  Mar 29 at 0:43













                                  10












                                  $begingroup$


                                  Python 2, 111 110 109 99 98 96 94 bytes





                                  lambda a,n:[l[:n]+(l[n:]and[L[n]for L in a[i:]+a if L[n:]][1]+l[n+1:])for i,l in enumerate(a)]


                                  Try it online!



                                  Takes input as a list of lines and 0-index column, and returns a list of strings.



                                  Column is rotated up 1.



                                  -11 bytes, thanks to Jo King






                                  share|improve this answer











                                  $endgroup$


















                                    10












                                    $begingroup$


                                    Python 2, 111 110 109 99 98 96 94 bytes





                                    lambda a,n:[l[:n]+(l[n:]and[L[n]for L in a[i:]+a if L[n:]][1]+l[n+1:])for i,l in enumerate(a)]


                                    Try it online!



                                    Takes input as a list of lines and 0-index column, and returns a list of strings.



                                    Column is rotated up 1.



                                    -11 bytes, thanks to Jo King






                                    share|improve this answer











                                    $endgroup$
















                                      10












                                      10








                                      10





                                      $begingroup$


                                      Python 2, 111 110 109 99 98 96 94 bytes





                                      lambda a,n:[l[:n]+(l[n:]and[L[n]for L in a[i:]+a if L[n:]][1]+l[n+1:])for i,l in enumerate(a)]


                                      Try it online!



                                      Takes input as a list of lines and 0-index column, and returns a list of strings.



                                      Column is rotated up 1.



                                      -11 bytes, thanks to Jo King






                                      share|improve this answer











                                      $endgroup$




                                      Python 2, 111 110 109 99 98 96 94 bytes





                                      lambda a,n:[l[:n]+(l[n:]and[L[n]for L in a[i:]+a if L[n:]][1]+l[n+1:])for i,l in enumerate(a)]


                                      Try it online!



                                      Takes input as a list of lines and 0-index column, and returns a list of strings.



                                      Column is rotated up 1.



                                      -11 bytes, thanks to Jo King







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited Mar 28 at 11:42

























                                      answered Mar 28 at 9:26









                                      TFeldTFeld

                                      16.5k21451




                                      16.5k21451























                                          7












                                          $begingroup$

                                          Java 8, 107 106 135 107 bytes





                                          k->m->{int s=m.length,i=-1;for(char p=0,t;i<s;t=m[i%s][k],m[i%s][k]=p<1?t:p,p=t)for(;m[++i%s].length<=k;);}


                                          +29 bytes for a bug-fix..



                                          0-indexed; rotates down like the example.

                                          Input as a character-matrix; modifies the char-matrix instead of returning a new one to save bytes.



                                          Try it online.



                                          Explanation:



                                          k->m->{                 // Method with integer and char-matrix parameters and no return-type
                                          int s=m.length, // Amount of lines in the matrix `s`
                                          i=-1; // Index-integer `i`, starting at -1
                                          for(char p=0, // Previous-character, starting at 0
                                          t; // Temp-char, uninitialized
                                          i<s // Loop as long as `i` is smaller than `s`:
                                          ; // After every iteration:
                                          t=m[i%s][k], // Set the temp to the `k`th character of the `i`'th line
                                          m[i%s][k]= // Replace the `k`'th character of the `i`'th line with:
                                          p<1? // If `p` is still 0:
                                          t // Set it to the temp we just set
                                          : // Else:
                                          p, // Set it to the previous-character instead
                                          p=t) // And then replace `p` with the temp for the next iteration
                                          for(;m[++i // Increase `i` by 1 before every iteration with `++i`,
                                          %s].length // And continue this loop until the length of the `i`'th line
                                          <=k;);} // is smaller than or equal to the input `k`





                                          share|improve this answer











                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                            $endgroup$
                                            – dana
                                            Mar 28 at 13:31










                                          • $begingroup$
                                            @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:33








                                          • 1




                                            $begingroup$
                                            @dana Fixed, thanks for noticing.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:44






                                          • 2




                                            $begingroup$
                                            @dana And back to 107 again. ;)
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 19:45






                                          • 1




                                            $begingroup$
                                            @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 29 at 7:21
















                                          7












                                          $begingroup$

                                          Java 8, 107 106 135 107 bytes





                                          k->m->{int s=m.length,i=-1;for(char p=0,t;i<s;t=m[i%s][k],m[i%s][k]=p<1?t:p,p=t)for(;m[++i%s].length<=k;);}


                                          +29 bytes for a bug-fix..



                                          0-indexed; rotates down like the example.

                                          Input as a character-matrix; modifies the char-matrix instead of returning a new one to save bytes.



                                          Try it online.



                                          Explanation:



                                          k->m->{                 // Method with integer and char-matrix parameters and no return-type
                                          int s=m.length, // Amount of lines in the matrix `s`
                                          i=-1; // Index-integer `i`, starting at -1
                                          for(char p=0, // Previous-character, starting at 0
                                          t; // Temp-char, uninitialized
                                          i<s // Loop as long as `i` is smaller than `s`:
                                          ; // After every iteration:
                                          t=m[i%s][k], // Set the temp to the `k`th character of the `i`'th line
                                          m[i%s][k]= // Replace the `k`'th character of the `i`'th line with:
                                          p<1? // If `p` is still 0:
                                          t // Set it to the temp we just set
                                          : // Else:
                                          p, // Set it to the previous-character instead
                                          p=t) // And then replace `p` with the temp for the next iteration
                                          for(;m[++i // Increase `i` by 1 before every iteration with `++i`,
                                          %s].length // And continue this loop until the length of the `i`'th line
                                          <=k;);} // is smaller than or equal to the input `k`





                                          share|improve this answer











                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                            $endgroup$
                                            – dana
                                            Mar 28 at 13:31










                                          • $begingroup$
                                            @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:33








                                          • 1




                                            $begingroup$
                                            @dana Fixed, thanks for noticing.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:44






                                          • 2




                                            $begingroup$
                                            @dana And back to 107 again. ;)
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 19:45






                                          • 1




                                            $begingroup$
                                            @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 29 at 7:21














                                          7












                                          7








                                          7





                                          $begingroup$

                                          Java 8, 107 106 135 107 bytes





                                          k->m->{int s=m.length,i=-1;for(char p=0,t;i<s;t=m[i%s][k],m[i%s][k]=p<1?t:p,p=t)for(;m[++i%s].length<=k;);}


                                          +29 bytes for a bug-fix..



                                          0-indexed; rotates down like the example.

                                          Input as a character-matrix; modifies the char-matrix instead of returning a new one to save bytes.



                                          Try it online.



                                          Explanation:



                                          k->m->{                 // Method with integer and char-matrix parameters and no return-type
                                          int s=m.length, // Amount of lines in the matrix `s`
                                          i=-1; // Index-integer `i`, starting at -1
                                          for(char p=0, // Previous-character, starting at 0
                                          t; // Temp-char, uninitialized
                                          i<s // Loop as long as `i` is smaller than `s`:
                                          ; // After every iteration:
                                          t=m[i%s][k], // Set the temp to the `k`th character of the `i`'th line
                                          m[i%s][k]= // Replace the `k`'th character of the `i`'th line with:
                                          p<1? // If `p` is still 0:
                                          t // Set it to the temp we just set
                                          : // Else:
                                          p, // Set it to the previous-character instead
                                          p=t) // And then replace `p` with the temp for the next iteration
                                          for(;m[++i // Increase `i` by 1 before every iteration with `++i`,
                                          %s].length // And continue this loop until the length of the `i`'th line
                                          <=k;);} // is smaller than or equal to the input `k`





                                          share|improve this answer











                                          $endgroup$



                                          Java 8, 107 106 135 107 bytes





                                          k->m->{int s=m.length,i=-1;for(char p=0,t;i<s;t=m[i%s][k],m[i%s][k]=p<1?t:p,p=t)for(;m[++i%s].length<=k;);}


                                          +29 bytes for a bug-fix..



                                          0-indexed; rotates down like the example.

                                          Input as a character-matrix; modifies the char-matrix instead of returning a new one to save bytes.



                                          Try it online.



                                          Explanation:



                                          k->m->{                 // Method with integer and char-matrix parameters and no return-type
                                          int s=m.length, // Amount of lines in the matrix `s`
                                          i=-1; // Index-integer `i`, starting at -1
                                          for(char p=0, // Previous-character, starting at 0
                                          t; // Temp-char, uninitialized
                                          i<s // Loop as long as `i` is smaller than `s`:
                                          ; // After every iteration:
                                          t=m[i%s][k], // Set the temp to the `k`th character of the `i`'th line
                                          m[i%s][k]= // Replace the `k`'th character of the `i`'th line with:
                                          p<1? // If `p` is still 0:
                                          t // Set it to the temp we just set
                                          : // Else:
                                          p, // Set it to the previous-character instead
                                          p=t) // And then replace `p` with the temp for the next iteration
                                          for(;m[++i // Increase `i` by 1 before every iteration with `++i`,
                                          %s].length // And continue this loop until the length of the `i`'th line
                                          <=k;);} // is smaller than or equal to the input `k`






                                          share|improve this answer














                                          share|improve this answer



                                          share|improve this answer








                                          edited Mar 29 at 7:19

























                                          answered Mar 28 at 12:31









                                          Kevin CruijssenKevin Cruijssen

                                          42.6k571217




                                          42.6k571217








                                          • 1




                                            $begingroup$
                                            One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                            $endgroup$
                                            – dana
                                            Mar 28 at 13:31










                                          • $begingroup$
                                            @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:33








                                          • 1




                                            $begingroup$
                                            @dana Fixed, thanks for noticing.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:44






                                          • 2




                                            $begingroup$
                                            @dana And back to 107 again. ;)
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 19:45






                                          • 1




                                            $begingroup$
                                            @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 29 at 7:21














                                          • 1




                                            $begingroup$
                                            One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                            $endgroup$
                                            – dana
                                            Mar 28 at 13:31










                                          • $begingroup$
                                            @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:33








                                          • 1




                                            $begingroup$
                                            @dana Fixed, thanks for noticing.
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 13:44






                                          • 2




                                            $begingroup$
                                            @dana And back to 107 again. ;)
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 28 at 19:45






                                          • 1




                                            $begingroup$
                                            @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                            $endgroup$
                                            – Kevin Cruijssen
                                            Mar 29 at 7:21








                                          1




                                          1




                                          $begingroup$
                                          One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                          $endgroup$
                                          – dana
                                          Mar 28 at 13:31




                                          $begingroup$
                                          One thing I noticed is that you make an assumption that the first line has enough characters - char p=m[0][k] - if it doesn't, won't this throw an exception? Nice job btw. You are beating my C# attempt by a large margin :)
                                          $endgroup$
                                          – dana
                                          Mar 28 at 13:31












                                          $begingroup$
                                          @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 13:33






                                          $begingroup$
                                          @dana Ah, shit, you're right.. I'm probably beating you by this large of a margin because I accidentally make that assumption.. Will try to fix it.
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 13:33






                                          1




                                          1




                                          $begingroup$
                                          @dana Fixed, thanks for noticing.
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 13:44




                                          $begingroup$
                                          @dana Fixed, thanks for noticing.
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 13:44




                                          2




                                          2




                                          $begingroup$
                                          @dana And back to 107 again. ;)
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 19:45




                                          $begingroup$
                                          @dana And back to 107 again. ;)
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 28 at 19:45




                                          1




                                          1




                                          $begingroup$
                                          @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 29 at 7:21




                                          $begingroup$
                                          @EmbodimentofIgnorance Ah, forgot to change that n to k. I usually use n for integer-inputs, but since the question uses $k$ I later on changed it (but apparently not everywhere). As for int p=0,t; then I will need a cast to char when assigning p to a cell (m[i%s][k]=(char)(p<1?t:p)). And although I could take the input as an integer-matrix, I personally think int-matrix =/= string/string-list/char-matrix..
                                          $endgroup$
                                          – Kevin Cruijssen
                                          Mar 29 at 7:21











                                          7












                                          $begingroup$


                                          Zsh, 94 87 78 bytes



                                          -7 bytes by changing to an arithmetic ternary, -9 bytes by changing the character in-place. (TIL)





                                          i=$1
                                          shift
                                          for s;c+=($s[i])
                                          c=($c[-1] $c)
                                          for s;s[i]=$c[$[$#s<i?0:++j]]&&<<<$s


                                          Try it online!
                                          Try it online!

                                          Try it online!



                                          Input is index [ string ... ]





                                          So, my previous comment about the subshell printing is now outdated, but here it is with the old last line for posterity:



                                          for s;echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}



                                          Hey, Gamma, why did you use echo in that last command instead of <<<?
                                          Wouldn't <<< save you two bytes?




                                          I'm glad you asked! Go ahead and give it a try. See if you can figure out what's happening.



                                          (Hint: Run echo $ZSH_SUBSHELL; <<< $ZSH_SUBSHELL.)





                                          You get 0 for echo, but 1 for <<<.
                                          Here-strings are run in subshells because they are given as stdin to another program.
                                          If there is no program given, it is implicitly given to cat.
                                          You can see this with <<< $_.
                                          <<< $ZSH_SUBSHELL is similar to echo $ZSH_SUBSHELL | cat.
                                          Since we need to increment j, we can't be in a subshell.



                                          Anyway, on to the main event:



                                          i=$1
                                          shift
                                          for s
                                          c+=($s[i]) # without "", empty strings aren't added
                                          c=($c[-1] $c) # add the last element onto the start
                                          for s
                                          echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}
                                          $s[0,i-1] ${s:$i} # before and after the replacement point
                                          $c[ ] # insert from char array
                                          $[$#s<i?0 ] # Sting is too small: at index 0: empty string
                                          $[$#s<i :++j] # Increment j and insert from there
                                          # j is unset, so ++j initially sets j to 1





                                          share|improve this answer











                                          $endgroup$


















                                            7












                                            $begingroup$


                                            Zsh, 94 87 78 bytes



                                            -7 bytes by changing to an arithmetic ternary, -9 bytes by changing the character in-place. (TIL)





                                            i=$1
                                            shift
                                            for s;c+=($s[i])
                                            c=($c[-1] $c)
                                            for s;s[i]=$c[$[$#s<i?0:++j]]&&<<<$s


                                            Try it online!
                                            Try it online!

                                            Try it online!



                                            Input is index [ string ... ]





                                            So, my previous comment about the subshell printing is now outdated, but here it is with the old last line for posterity:



                                            for s;echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}



                                            Hey, Gamma, why did you use echo in that last command instead of <<<?
                                            Wouldn't <<< save you two bytes?




                                            I'm glad you asked! Go ahead and give it a try. See if you can figure out what's happening.



                                            (Hint: Run echo $ZSH_SUBSHELL; <<< $ZSH_SUBSHELL.)





                                            You get 0 for echo, but 1 for <<<.
                                            Here-strings are run in subshells because they are given as stdin to another program.
                                            If there is no program given, it is implicitly given to cat.
                                            You can see this with <<< $_.
                                            <<< $ZSH_SUBSHELL is similar to echo $ZSH_SUBSHELL | cat.
                                            Since we need to increment j, we can't be in a subshell.



                                            Anyway, on to the main event:



                                            i=$1
                                            shift
                                            for s
                                            c+=($s[i]) # without "", empty strings aren't added
                                            c=($c[-1] $c) # add the last element onto the start
                                            for s
                                            echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}
                                            $s[0,i-1] ${s:$i} # before and after the replacement point
                                            $c[ ] # insert from char array
                                            $[$#s<i?0 ] # Sting is too small: at index 0: empty string
                                            $[$#s<i :++j] # Increment j and insert from there
                                            # j is unset, so ++j initially sets j to 1





                                            share|improve this answer











                                            $endgroup$
















                                              7












                                              7








                                              7





                                              $begingroup$


                                              Zsh, 94 87 78 bytes



                                              -7 bytes by changing to an arithmetic ternary, -9 bytes by changing the character in-place. (TIL)





                                              i=$1
                                              shift
                                              for s;c+=($s[i])
                                              c=($c[-1] $c)
                                              for s;s[i]=$c[$[$#s<i?0:++j]]&&<<<$s


                                              Try it online!
                                              Try it online!

                                              Try it online!



                                              Input is index [ string ... ]





                                              So, my previous comment about the subshell printing is now outdated, but here it is with the old last line for posterity:



                                              for s;echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}



                                              Hey, Gamma, why did you use echo in that last command instead of <<<?
                                              Wouldn't <<< save you two bytes?




                                              I'm glad you asked! Go ahead and give it a try. See if you can figure out what's happening.



                                              (Hint: Run echo $ZSH_SUBSHELL; <<< $ZSH_SUBSHELL.)





                                              You get 0 for echo, but 1 for <<<.
                                              Here-strings are run in subshells because they are given as stdin to another program.
                                              If there is no program given, it is implicitly given to cat.
                                              You can see this with <<< $_.
                                              <<< $ZSH_SUBSHELL is similar to echo $ZSH_SUBSHELL | cat.
                                              Since we need to increment j, we can't be in a subshell.



                                              Anyway, on to the main event:



                                              i=$1
                                              shift
                                              for s
                                              c+=($s[i]) # without "", empty strings aren't added
                                              c=($c[-1] $c) # add the last element onto the start
                                              for s
                                              echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}
                                              $s[0,i-1] ${s:$i} # before and after the replacement point
                                              $c[ ] # insert from char array
                                              $[$#s<i?0 ] # Sting is too small: at index 0: empty string
                                              $[$#s<i :++j] # Increment j and insert from there
                                              # j is unset, so ++j initially sets j to 1





                                              share|improve this answer











                                              $endgroup$




                                              Zsh, 94 87 78 bytes



                                              -7 bytes by changing to an arithmetic ternary, -9 bytes by changing the character in-place. (TIL)





                                              i=$1
                                              shift
                                              for s;c+=($s[i])
                                              c=($c[-1] $c)
                                              for s;s[i]=$c[$[$#s<i?0:++j]]&&<<<$s


                                              Try it online!
                                              Try it online!

                                              Try it online!



                                              Input is index [ string ... ]





                                              So, my previous comment about the subshell printing is now outdated, but here it is with the old last line for posterity:



                                              for s;echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}



                                              Hey, Gamma, why did you use echo in that last command instead of <<<?
                                              Wouldn't <<< save you two bytes?




                                              I'm glad you asked! Go ahead and give it a try. See if you can figure out what's happening.



                                              (Hint: Run echo $ZSH_SUBSHELL; <<< $ZSH_SUBSHELL.)





                                              You get 0 for echo, but 1 for <<<.
                                              Here-strings are run in subshells because they are given as stdin to another program.
                                              If there is no program given, it is implicitly given to cat.
                                              You can see this with <<< $_.
                                              <<< $ZSH_SUBSHELL is similar to echo $ZSH_SUBSHELL | cat.
                                              Since we need to increment j, we can't be in a subshell.



                                              Anyway, on to the main event:



                                              i=$1
                                              shift
                                              for s
                                              c+=($s[i]) # without "", empty strings aren't added
                                              c=($c[-1] $c) # add the last element onto the start
                                              for s
                                              echo $s[0,i-1]$c[$[$#s<i?0:++j]]${s:$i}
                                              $s[0,i-1] ${s:$i} # before and after the replacement point
                                              $c[ ] # insert from char array
                                              $[$#s<i?0 ] # Sting is too small: at index 0: empty string
                                              $[$#s<i :++j] # Increment j and insert from there
                                              # j is unset, so ++j initially sets j to 1






                                              share|improve this answer














                                              share|improve this answer



                                              share|improve this answer








                                              edited Mar 30 at 18:15

























                                              answered Mar 28 at 10:56









                                              GammaFunctionGammaFunction

                                              2716




                                              2716























                                                  6












                                                  $begingroup$


                                                  R, 62 bytes





                                                  function(L,n){L[A,n]<-rep(L[A<-L[,n]!=' ',n],2)[1+1:sum(A)];L}


                                                  Try it online!



                                                  Takes input as a space-padded matrix of characters. Rotates upwards. All thanks to Kirill L.!




                                                  R, 74 bytes





                                                  function(L,n){substr(L[A],n,n)=rep(substr(L[A<-nchar(L)>=n],n,n),2)[-1]
                                                  L}


                                                  Try it online!



                                                  This submission predates the allowance of padded lines.



                                                  Aliasing substr here won't work because we're calling substr and substr<- in the first line.



                                                  I/O as a list of non-padded lines; rotates upwards.






                                                  share|improve this answer











                                                  $endgroup$













                                                  • $begingroup$
                                                    Since consensus allows modifying inputs, we can do this crazy thing
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:49










                                                  • $begingroup$
                                                    Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:50










                                                  • $begingroup$
                                                    @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                    $endgroup$
                                                    – Giuseppe
                                                    Mar 29 at 14:42










                                                  • $begingroup$
                                                    Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 15:16
















                                                  6












                                                  $begingroup$


                                                  R, 62 bytes





                                                  function(L,n){L[A,n]<-rep(L[A<-L[,n]!=' ',n],2)[1+1:sum(A)];L}


                                                  Try it online!



                                                  Takes input as a space-padded matrix of characters. Rotates upwards. All thanks to Kirill L.!




                                                  R, 74 bytes





                                                  function(L,n){substr(L[A],n,n)=rep(substr(L[A<-nchar(L)>=n],n,n),2)[-1]
                                                  L}


                                                  Try it online!



                                                  This submission predates the allowance of padded lines.



                                                  Aliasing substr here won't work because we're calling substr and substr<- in the first line.



                                                  I/O as a list of non-padded lines; rotates upwards.






                                                  share|improve this answer











                                                  $endgroup$













                                                  • $begingroup$
                                                    Since consensus allows modifying inputs, we can do this crazy thing
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:49










                                                  • $begingroup$
                                                    Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:50










                                                  • $begingroup$
                                                    @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                    $endgroup$
                                                    – Giuseppe
                                                    Mar 29 at 14:42










                                                  • $begingroup$
                                                    Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 15:16














                                                  6












                                                  6








                                                  6





                                                  $begingroup$


                                                  R, 62 bytes





                                                  function(L,n){L[A,n]<-rep(L[A<-L[,n]!=' ',n],2)[1+1:sum(A)];L}


                                                  Try it online!



                                                  Takes input as a space-padded matrix of characters. Rotates upwards. All thanks to Kirill L.!




                                                  R, 74 bytes





                                                  function(L,n){substr(L[A],n,n)=rep(substr(L[A<-nchar(L)>=n],n,n),2)[-1]
                                                  L}


                                                  Try it online!



                                                  This submission predates the allowance of padded lines.



                                                  Aliasing substr here won't work because we're calling substr and substr<- in the first line.



                                                  I/O as a list of non-padded lines; rotates upwards.






                                                  share|improve this answer











                                                  $endgroup$




                                                  R, 62 bytes





                                                  function(L,n){L[A,n]<-rep(L[A<-L[,n]!=' ',n],2)[1+1:sum(A)];L}


                                                  Try it online!



                                                  Takes input as a space-padded matrix of characters. Rotates upwards. All thanks to Kirill L.!




                                                  R, 74 bytes





                                                  function(L,n){substr(L[A],n,n)=rep(substr(L[A<-nchar(L)>=n],n,n),2)[-1]
                                                  L}


                                                  Try it online!



                                                  This submission predates the allowance of padded lines.



                                                  Aliasing substr here won't work because we're calling substr and substr<- in the first line.



                                                  I/O as a list of non-padded lines; rotates upwards.







                                                  share|improve this answer














                                                  share|improve this answer



                                                  share|improve this answer








                                                  edited Mar 29 at 18:23

























                                                  answered Mar 28 at 14:24









                                                  GiuseppeGiuseppe

                                                  17.6k31153




                                                  17.6k31153












                                                  • $begingroup$
                                                    Since consensus allows modifying inputs, we can do this crazy thing
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:49










                                                  • $begingroup$
                                                    Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:50










                                                  • $begingroup$
                                                    @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                    $endgroup$
                                                    – Giuseppe
                                                    Mar 29 at 14:42










                                                  • $begingroup$
                                                    Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 15:16


















                                                  • $begingroup$
                                                    Since consensus allows modifying inputs, we can do this crazy thing
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:49










                                                  • $begingroup$
                                                    Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 9:50










                                                  • $begingroup$
                                                    @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                    $endgroup$
                                                    – Giuseppe
                                                    Mar 29 at 14:42










                                                  • $begingroup$
                                                    Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                    $endgroup$
                                                    – Kirill L.
                                                    Mar 29 at 15:16
















                                                  $begingroup$
                                                  Since consensus allows modifying inputs, we can do this crazy thing
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 9:49




                                                  $begingroup$
                                                  Since consensus allows modifying inputs, we can do this crazy thing
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 9:49












                                                  $begingroup$
                                                  Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 9:50




                                                  $begingroup$
                                                  Also, OP relaxed the rules, so that it is now possible to work with space-padded matrices, something like this
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 9:50












                                                  $begingroup$
                                                  @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                  $endgroup$
                                                  – Giuseppe
                                                  Mar 29 at 14:42




                                                  $begingroup$
                                                  @KirillL. I don't think that R passes by reference so we probably aren't allowed to do that; it strikes me that this only works if the argument is named L in the parent environment. I'll happily update to the space-padding, though!
                                                  $endgroup$
                                                  – Giuseppe
                                                  Mar 29 at 14:42












                                                  $begingroup$
                                                  Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 15:16




                                                  $begingroup$
                                                  Ah, I see, you're right. I came up with this idea looking at my Ruby answer (which saves a whole 1 byte this way :)), but the languages indeed behave differently in this situation.
                                                  $endgroup$
                                                  – Kirill L.
                                                  Mar 29 at 15:16











                                                  5












                                                  $begingroup$


                                                  C# (Visual C# Interactive Compiler), 82 bytes





                                                  k=>a=>{var c='0';a.Where(b=>b.Count>k&&((b[k],c)=(c,b[k])).c>0).ToList()[0][k]=c;}


                                                  Try it online!



                                                  Credit to @ASCIIOnly for suggesting foreach which led to a 12 byte savings!



                                                  -8 bytes thanks to @someone!

                                                  -1 byte thanks to @EmbodimentofIgnorance!






                                                  share|improve this answer











                                                  $endgroup$













                                                  • $begingroup$
                                                    184 bytes
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:41










                                                  • $begingroup$
                                                    Maybe 183 if using ints instead of chars
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:46










                                                  • $begingroup$
                                                    @ExpiredData ew int instead of char
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:05












                                                  • $begingroup$
                                                    too bad you can't use a foreach since it's the opposite order :(
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:08






                                                  • 1




                                                    $begingroup$
                                                    Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                    $endgroup$
                                                    – someone
                                                    Mar 30 at 7:25
















                                                  5












                                                  $begingroup$


                                                  C# (Visual C# Interactive Compiler), 82 bytes





                                                  k=>a=>{var c='0';a.Where(b=>b.Count>k&&((b[k],c)=(c,b[k])).c>0).ToList()[0][k]=c;}


                                                  Try it online!



                                                  Credit to @ASCIIOnly for suggesting foreach which led to a 12 byte savings!



                                                  -8 bytes thanks to @someone!

                                                  -1 byte thanks to @EmbodimentofIgnorance!






                                                  share|improve this answer











                                                  $endgroup$













                                                  • $begingroup$
                                                    184 bytes
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:41










                                                  • $begingroup$
                                                    Maybe 183 if using ints instead of chars
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:46










                                                  • $begingroup$
                                                    @ExpiredData ew int instead of char
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:05












                                                  • $begingroup$
                                                    too bad you can't use a foreach since it's the opposite order :(
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:08






                                                  • 1




                                                    $begingroup$
                                                    Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                    $endgroup$
                                                    – someone
                                                    Mar 30 at 7:25














                                                  5












                                                  5








                                                  5





                                                  $begingroup$


                                                  C# (Visual C# Interactive Compiler), 82 bytes





                                                  k=>a=>{var c='0';a.Where(b=>b.Count>k&&((b[k],c)=(c,b[k])).c>0).ToList()[0][k]=c;}


                                                  Try it online!



                                                  Credit to @ASCIIOnly for suggesting foreach which led to a 12 byte savings!



                                                  -8 bytes thanks to @someone!

                                                  -1 byte thanks to @EmbodimentofIgnorance!






                                                  share|improve this answer











                                                  $endgroup$




                                                  C# (Visual C# Interactive Compiler), 82 bytes





                                                  k=>a=>{var c='0';a.Where(b=>b.Count>k&&((b[k],c)=(c,b[k])).c>0).ToList()[0][k]=c;}


                                                  Try it online!



                                                  Credit to @ASCIIOnly for suggesting foreach which led to a 12 byte savings!



                                                  -8 bytes thanks to @someone!

                                                  -1 byte thanks to @EmbodimentofIgnorance!







                                                  share|improve this answer














                                                  share|improve this answer



                                                  share|improve this answer








                                                  edited Apr 1 at 2:54

























                                                  answered Mar 28 at 13:24









                                                  danadana

                                                  1,921167




                                                  1,921167












                                                  • $begingroup$
                                                    184 bytes
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:41










                                                  • $begingroup$
                                                    Maybe 183 if using ints instead of chars
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:46










                                                  • $begingroup$
                                                    @ExpiredData ew int instead of char
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:05












                                                  • $begingroup$
                                                    too bad you can't use a foreach since it's the opposite order :(
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:08






                                                  • 1




                                                    $begingroup$
                                                    Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                    $endgroup$
                                                    – someone
                                                    Mar 30 at 7:25


















                                                  • $begingroup$
                                                    184 bytes
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:41










                                                  • $begingroup$
                                                    Maybe 183 if using ints instead of chars
                                                    $endgroup$
                                                    – Expired Data
                                                    Mar 28 at 14:46










                                                  • $begingroup$
                                                    @ExpiredData ew int instead of char
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:05












                                                  • $begingroup$
                                                    too bad you can't use a foreach since it's the opposite order :(
                                                    $endgroup$
                                                    – ASCII-only
                                                    Mar 29 at 6:08






                                                  • 1




                                                    $begingroup$
                                                    Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                    $endgroup$
                                                    – someone
                                                    Mar 30 at 7:25
















                                                  $begingroup$
                                                  184 bytes
                                                  $endgroup$
                                                  – Expired Data
                                                  Mar 28 at 14:41




                                                  $begingroup$
                                                  184 bytes
                                                  $endgroup$
                                                  – Expired Data
                                                  Mar 28 at 14:41












                                                  $begingroup$
                                                  Maybe 183 if using ints instead of chars
                                                  $endgroup$
                                                  – Expired Data
                                                  Mar 28 at 14:46




                                                  $begingroup$
                                                  Maybe 183 if using ints instead of chars
                                                  $endgroup$
                                                  – Expired Data
                                                  Mar 28 at 14:46












                                                  $begingroup$
                                                  @ExpiredData ew int instead of char
                                                  $endgroup$
                                                  – ASCII-only
                                                  Mar 29 at 6:05






                                                  $begingroup$
                                                  @ExpiredData ew int instead of char
                                                  $endgroup$
                                                  – ASCII-only
                                                  Mar 29 at 6:05














                                                  $begingroup$
                                                  too bad you can't use a foreach since it's the opposite order :(
                                                  $endgroup$
                                                  – ASCII-only
                                                  Mar 29 at 6:08




                                                  $begingroup$
                                                  too bad you can't use a foreach since it's the opposite order :(
                                                  $endgroup$
                                                  – ASCII-only
                                                  Mar 29 at 6:08




                                                  1




                                                  1




                                                  $begingroup$
                                                  Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                  $endgroup$
                                                  – someone
                                                  Mar 30 at 7:25




                                                  $begingroup$
                                                  Use dynamic to merge declarations and save 2 bytes (I've never seen this before!)Try it online!
                                                  $endgroup$
                                                  – someone
                                                  Mar 30 at 7:25











                                                  4












                                                  $begingroup$


                                                  Ruby, 57 bytes





                                                  ->a,k{b=a.map{|i|i[k]}-[p];c=-2;a.map{|i|i[k]&&=b[c+=1]}}


                                                  Try it online!



                                                  Takes input as an array of lines a. Rotates the text down at 0-based position k. Returns by modifying the input a.






                                                  share|improve this answer









                                                  $endgroup$


















                                                    4












                                                    $begingroup$


                                                    Ruby, 57 bytes





                                                    ->a,k{b=a.map{|i|i[k]}-[p];c=-2;a.map{|i|i[k]&&=b[c+=1]}}


                                                    Try it online!



                                                    Takes input as an array of lines a. Rotates the text down at 0-based position k. Returns by modifying the input a.






                                                    share|improve this answer









                                                    $endgroup$
















                                                      4












                                                      4








                                                      4





                                                      $begingroup$


                                                      Ruby, 57 bytes





                                                      ->a,k{b=a.map{|i|i[k]}-[p];c=-2;a.map{|i|i[k]&&=b[c+=1]}}


                                                      Try it online!



                                                      Takes input as an array of lines a. Rotates the text down at 0-based position k. Returns by modifying the input a.






                                                      share|improve this answer









                                                      $endgroup$




                                                      Ruby, 57 bytes





                                                      ->a,k{b=a.map{|i|i[k]}-[p];c=-2;a.map{|i|i[k]&&=b[c+=1]}}


                                                      Try it online!



                                                      Takes input as an array of lines a. Rotates the text down at 0-based position k. Returns by modifying the input a.







                                                      share|improve this answer












                                                      share|improve this answer



                                                      share|improve this answer










                                                      answered Mar 28 at 11:06









                                                      Kirill L.Kirill L.

                                                      6,0981527




                                                      6,0981527























                                                          3












                                                          $begingroup$


                                                          05AB1E, 21 bytes



                                                          ʒg‹}U¹εXyk©diX®<èIèIǝ


                                                          Can definitely be golfed some more..



                                                          0-indexed; input and output both as a list of strings.

                                                          It rotates down like the example, but < can be replaced with > to rotate up instead.



                                                          Try it online (footer joins the list by newlines, remove it to see the actual list output).



                                                          Explanation:





                                                          ʒ  }             # Filter the (implicit) input-list by:
                                                          g # Where length of the current string
                                                          ‹ # is larger than the (implicit) input-integer
                                                          U # Pop and store this filtered list in variable `X`
                                                          ¹ε # Map over the first input-list again:
                                                          Xyk # Get the index of the current string in variable `X`
                                                          © # Store it in the register (without popping)
                                                          di # If the index is not -1, so the current string is present in variable `X`
                                                          X®<è # Get the (index-1)'th string in variable `X`
                                                          Iè # Get the character at the index of the input-integer
                                                          Iǝ # And insert it at the index of the input-integer in the current string





                                                          share|improve this answer











                                                          $endgroup$


















                                                            3












                                                            $begingroup$


                                                            05AB1E, 21 bytes



                                                            ʒg‹}U¹εXyk©diX®<èIèIǝ


                                                            Can definitely be golfed some more..



                                                            0-indexed; input and output both as a list of strings.

                                                            It rotates down like the example, but < can be replaced with > to rotate up instead.



                                                            Try it online (footer joins the list by newlines, remove it to see the actual list output).



                                                            Explanation:





                                                            ʒ  }             # Filter the (implicit) input-list by:
                                                            g # Where length of the current string
                                                            ‹ # is larger than the (implicit) input-integer
                                                            U # Pop and store this filtered list in variable `X`
                                                            ¹ε # Map over the first input-list again:
                                                            Xyk # Get the index of the current string in variable `X`
                                                            © # Store it in the register (without popping)
                                                            di # If the index is not -1, so the current string is present in variable `X`
                                                            X®<è # Get the (index-1)'th string in variable `X`
                                                            Iè # Get the character at the index of the input-integer
                                                            Iǝ # And insert it at the index of the input-integer in the current string





                                                            share|improve this answer











                                                            $endgroup$
















                                                              3












                                                              3








                                                              3





                                                              $begingroup$


                                                              05AB1E, 21 bytes



                                                              ʒg‹}U¹εXyk©diX®<èIèIǝ


                                                              Can definitely be golfed some more..



                                                              0-indexed; input and output both as a list of strings.

                                                              It rotates down like the example, but < can be replaced with > to rotate up instead.



                                                              Try it online (footer joins the list by newlines, remove it to see the actual list output).



                                                              Explanation:





                                                              ʒ  }             # Filter the (implicit) input-list by:
                                                              g # Where length of the current string
                                                              ‹ # is larger than the (implicit) input-integer
                                                              U # Pop and store this filtered list in variable `X`
                                                              ¹ε # Map over the first input-list again:
                                                              Xyk # Get the index of the current string in variable `X`
                                                              © # Store it in the register (without popping)
                                                              di # If the index is not -1, so the current string is present in variable `X`
                                                              X®<è # Get the (index-1)'th string in variable `X`
                                                              Iè # Get the character at the index of the input-integer
                                                              Iǝ # And insert it at the index of the input-integer in the current string





                                                              share|improve this answer











                                                              $endgroup$




                                                              05AB1E, 21 bytes



                                                              ʒg‹}U¹εXyk©diX®<èIèIǝ


                                                              Can definitely be golfed some more..



                                                              0-indexed; input and output both as a list of strings.

                                                              It rotates down like the example, but < can be replaced with > to rotate up instead.



                                                              Try it online (footer joins the list by newlines, remove it to see the actual list output).



                                                              Explanation:





                                                              ʒ  }             # Filter the (implicit) input-list by:
                                                              g # Where length of the current string
                                                              ‹ # is larger than the (implicit) input-integer
                                                              U # Pop and store this filtered list in variable `X`
                                                              ¹ε # Map over the first input-list again:
                                                              Xyk # Get the index of the current string in variable `X`
                                                              © # Store it in the register (without popping)
                                                              di # If the index is not -1, so the current string is present in variable `X`
                                                              X®<è # Get the (index-1)'th string in variable `X`
                                                              Iè # Get the character at the index of the input-integer
                                                              Iǝ # And insert it at the index of the input-integer in the current string






                                                              share|improve this answer














                                                              share|improve this answer



                                                              share|improve this answer








                                                              edited Mar 28 at 9:49

























                                                              answered Mar 28 at 9:36









                                                              Kevin CruijssenKevin Cruijssen

                                                              42.6k571217




                                                              42.6k571217























                                                                  3












                                                                  $begingroup$


                                                                  K4, 41 bytes



                                                                  Solution:



                                                                  {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]}


                                                                  Explanation:



                                                                  Not sure if I'm missing something... 0 index, rotates up (change the 1 to -1 for rotate down)



                                                                  {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]} / the solution
                                                                  { } / lambda taking implicit x and y
                                                                  .[x; ;:; ] / index apply assignment back into x
                                                                  .q.rotate[1; ] / left rotate 1 character
                                                                  ( ; ) / two item list
                                                                  y / index to rotate
                                                                  #:'x / count (#:) each (') input
                                                                  y< / index less than ?
                                                                  & / indexes where true
                                                                  i: / assign to variable w
                                                                  x . / index into x
                                                                  i / indexes we saved as i earlier





                                                                  share|improve this answer









                                                                  $endgroup$


















                                                                    3












                                                                    $begingroup$


                                                                    K4, 41 bytes



                                                                    Solution:



                                                                    {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]}


                                                                    Explanation:



                                                                    Not sure if I'm missing something... 0 index, rotates up (change the 1 to -1 for rotate down)



                                                                    {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]} / the solution
                                                                    { } / lambda taking implicit x and y
                                                                    .[x; ;:; ] / index apply assignment back into x
                                                                    .q.rotate[1; ] / left rotate 1 character
                                                                    ( ; ) / two item list
                                                                    y / index to rotate
                                                                    #:'x / count (#:) each (') input
                                                                    y< / index less than ?
                                                                    & / indexes where true
                                                                    i: / assign to variable w
                                                                    x . / index into x
                                                                    i / indexes we saved as i earlier





                                                                    share|improve this answer









                                                                    $endgroup$
















                                                                      3












                                                                      3








                                                                      3





                                                                      $begingroup$


                                                                      K4, 41 bytes



                                                                      Solution:



                                                                      {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]}


                                                                      Explanation:



                                                                      Not sure if I'm missing something... 0 index, rotates up (change the 1 to -1 for rotate down)



                                                                      {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]} / the solution
                                                                      { } / lambda taking implicit x and y
                                                                      .[x; ;:; ] / index apply assignment back into x
                                                                      .q.rotate[1; ] / left rotate 1 character
                                                                      ( ; ) / two item list
                                                                      y / index to rotate
                                                                      #:'x / count (#:) each (') input
                                                                      y< / index less than ?
                                                                      & / indexes where true
                                                                      i: / assign to variable w
                                                                      x . / index into x
                                                                      i / indexes we saved as i earlier





                                                                      share|improve this answer









                                                                      $endgroup$




                                                                      K4, 41 bytes



                                                                      Solution:



                                                                      {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]}


                                                                      Explanation:



                                                                      Not sure if I'm missing something... 0 index, rotates up (change the 1 to -1 for rotate down)



                                                                      {.[x;i;:;.q.rotate[1;x . i:(&y<#:'x;y)]]} / the solution
                                                                      { } / lambda taking implicit x and y
                                                                      .[x; ;:; ] / index apply assignment back into x
                                                                      .q.rotate[1; ] / left rotate 1 character
                                                                      ( ; ) / two item list
                                                                      y / index to rotate
                                                                      #:'x / count (#:) each (') input
                                                                      y< / index less than ?
                                                                      & / indexes where true
                                                                      i: / assign to variable w
                                                                      x . / index into x
                                                                      i / indexes we saved as i earlier






                                                                      share|improve this answer












                                                                      share|improve this answer



                                                                      share|improve this answer










                                                                      answered Mar 28 at 20:55









                                                                      streetsterstreetster

                                                                      2,644515




                                                                      2,644515























                                                                          3












                                                                          $begingroup$


                                                                          Japt v2.0a0, 18 bytes



                                                                          0-based with input & output as a multi-line string. Rotates up by 1.



                                                                          There's gotta be a shorter method!



                                                                          yÈrS_Y¦V?Z:°TgXrS


                                                                          Try it



                                                                          yÈrS_Y¦V?Z:°TgXrS     :Implicit input of string U & integer V
                                                                          y :Transpose
                                                                          È :Pass each line X at 0-based index Y through the following function & transpose back
                                                                          r : Replace
                                                                          S : RegEx /S/g
                                                                          _ : Pass each match Z through the following function
                                                                          Y¦V : Test Y for inequality with V
                                                                          ?Z: : If true, return Z, else
                                                                          °T : Increment T (initially 0)
                                                                          g : Index into
                                                                          XrS : X with spaces removed





                                                                          share|improve this answer









                                                                          $endgroup$













                                                                          • $begingroup$
                                                                            I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 14:30












                                                                          • $begingroup$
                                                                            @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                            $endgroup$
                                                                            – Shaggy
                                                                            Mar 29 at 15:12










                                                                          • $begingroup$
                                                                            "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 17:04


















                                                                          3












                                                                          $begingroup$


                                                                          Japt v2.0a0, 18 bytes



                                                                          0-based with input & output as a multi-line string. Rotates up by 1.



                                                                          There's gotta be a shorter method!



                                                                          yÈrS_Y¦V?Z:°TgXrS


                                                                          Try it



                                                                          yÈrS_Y¦V?Z:°TgXrS     :Implicit input of string U & integer V
                                                                          y :Transpose
                                                                          È :Pass each line X at 0-based index Y through the following function & transpose back
                                                                          r : Replace
                                                                          S : RegEx /S/g
                                                                          _ : Pass each match Z through the following function
                                                                          Y¦V : Test Y for inequality with V
                                                                          ?Z: : If true, return Z, else
                                                                          °T : Increment T (initially 0)
                                                                          g : Index into
                                                                          XrS : X with spaces removed





                                                                          share|improve this answer









                                                                          $endgroup$













                                                                          • $begingroup$
                                                                            I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 14:30












                                                                          • $begingroup$
                                                                            @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                            $endgroup$
                                                                            – Shaggy
                                                                            Mar 29 at 15:12










                                                                          • $begingroup$
                                                                            "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 17:04
















                                                                          3












                                                                          3








                                                                          3





                                                                          $begingroup$


                                                                          Japt v2.0a0, 18 bytes



                                                                          0-based with input & output as a multi-line string. Rotates up by 1.



                                                                          There's gotta be a shorter method!



                                                                          yÈrS_Y¦V?Z:°TgXrS


                                                                          Try it



                                                                          yÈrS_Y¦V?Z:°TgXrS     :Implicit input of string U & integer V
                                                                          y :Transpose
                                                                          È :Pass each line X at 0-based index Y through the following function & transpose back
                                                                          r : Replace
                                                                          S : RegEx /S/g
                                                                          _ : Pass each match Z through the following function
                                                                          Y¦V : Test Y for inequality with V
                                                                          ?Z: : If true, return Z, else
                                                                          °T : Increment T (initially 0)
                                                                          g : Index into
                                                                          XrS : X with spaces removed





                                                                          share|improve this answer









                                                                          $endgroup$




                                                                          Japt v2.0a0, 18 bytes



                                                                          0-based with input & output as a multi-line string. Rotates up by 1.



                                                                          There's gotta be a shorter method!



                                                                          yÈrS_Y¦V?Z:°TgXrS


                                                                          Try it



                                                                          yÈrS_Y¦V?Z:°TgXrS     :Implicit input of string U & integer V
                                                                          y :Transpose
                                                                          È :Pass each line X at 0-based index Y through the following function & transpose back
                                                                          r : Replace
                                                                          S : RegEx /S/g
                                                                          _ : Pass each match Z through the following function
                                                                          Y¦V : Test Y for inequality with V
                                                                          ?Z: : If true, return Z, else
                                                                          °T : Increment T (initially 0)
                                                                          g : Index into
                                                                          XrS : X with spaces removed






                                                                          share|improve this answer












                                                                          share|improve this answer



                                                                          share|improve this answer










                                                                          answered Mar 28 at 21:52









                                                                          ShaggyShaggy

                                                                          18.9k21768




                                                                          18.9k21768












                                                                          • $begingroup$
                                                                            I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 14:30












                                                                          • $begingroup$
                                                                            @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                            $endgroup$
                                                                            – Shaggy
                                                                            Mar 29 at 15:12










                                                                          • $begingroup$
                                                                            "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 17:04




















                                                                          • $begingroup$
                                                                            I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 14:30












                                                                          • $begingroup$
                                                                            @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                            $endgroup$
                                                                            – Shaggy
                                                                            Mar 29 at 15:12










                                                                          • $begingroup$
                                                                            "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                            $endgroup$
                                                                            – Kevin Cruijssen
                                                                            Mar 29 at 17:04


















                                                                          $begingroup$
                                                                          I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                          $endgroup$
                                                                          – Kevin Cruijssen
                                                                          Mar 29 at 14:30






                                                                          $begingroup$
                                                                          I haven't looked closely at the comments and new rules (so perhaps it's somewhere mentioned it's allowed now, while it wasn't before), but is it allowed to skip spaces of the initial input? Let's say you change the input-index to 6, your answer would skip the space at line with in the first line and at Rotate here in the fourth line, whereas most of the other answers would rotate that space as well.
                                                                          $endgroup$
                                                                          – Kevin Cruijssen
                                                                          Mar 29 at 14:30














                                                                          $begingroup$
                                                                          @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                          $endgroup$
                                                                          – Shaggy
                                                                          Mar 29 at 15:12




                                                                          $begingroup$
                                                                          @KevinCruijssen, I'm a bit confused by all the additional rules & allowances but, if it is an issue, it looks like I can get around that by not allowing spaces in the input. I think.
                                                                          $endgroup$
                                                                          – Shaggy
                                                                          Mar 29 at 15:12












                                                                          $begingroup$
                                                                          "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                          $endgroup$
                                                                          – Kevin Cruijssen
                                                                          Mar 29 at 17:04






                                                                          $begingroup$
                                                                          "I think" This part is indeed how I would also respond, haha. I have no idea what is mandatory and optional anymore, but I think you can indeed choose to omit spaces in the in- and output; I think you can choose to count spaces or not; and I think you can use trialing spaces in the output or not; etc. All on all rather confusing. Ah well..
                                                                          $endgroup$
                                                                          – Kevin Cruijssen
                                                                          Mar 29 at 17:04













                                                                          3












                                                                          $begingroup$


                                                                          Jelly, 16 bytes



                                                                          z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦"


                                                                          A dyadic Link accepting a list of lines (lists of characters containing no newline characters) on the left and an integer on the right which returns a list of lines.



                                                                          Try it online! (footer splits on newlines, calls the Link, and joins by newlines again)



                                                                          How?



                                                                          z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦" - Link: lines L; index I        e.g. example in question; 20
                                                                          z⁷ - transpose L with filler 'n' ['AAARTnTW', ' ohnhr', ...]
                                                                          ⁹ị - Ith item 'amnv.nnt'
                                                                          Ỵ - split at newlines ['am', 'v.', '', 't']
                                                                          Ʋ - last four links as a monad - i.e. f(X):
                                                                          F - flatten 'amv.t'
                                                                          - - -1
                                                                          ṙ - rotate left by 'tamv.'
                                                                          ṁ - mould like X ['ta', 'mv', '', '.']
                                                                          Y - join with newlines 'tanmvnn.'
                                                                          - -- call this C
                                                                          ⁸ - chain's left argument, L
                                                                          " - zip with - i.e. [f(L1,C1), f(L2,C2), ...]:
                                                                          ¦ - sparse application...
                                                                          ⁹ - ...to indices: chain's right argument, I
                                                                          ṛ - ...of: right argument, Cn





                                                                          share|improve this answer











                                                                          $endgroup$


















                                                                            3












                                                                            $begingroup$


                                                                            Jelly, 16 bytes



                                                                            z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦"


                                                                            A dyadic Link accepting a list of lines (lists of characters containing no newline characters) on the left and an integer on the right which returns a list of lines.



                                                                            Try it online! (footer splits on newlines, calls the Link, and joins by newlines again)



                                                                            How?



                                                                            z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦" - Link: lines L; index I        e.g. example in question; 20
                                                                            z⁷ - transpose L with filler 'n' ['AAARTnTW', ' ohnhr', ...]
                                                                            ⁹ị - Ith item 'amnv.nnt'
                                                                            Ỵ - split at newlines ['am', 'v.', '', 't']
                                                                            Ʋ - last four links as a monad - i.e. f(X):
                                                                            F - flatten 'amv.t'
                                                                            - - -1
                                                                            ṙ - rotate left by 'tamv.'
                                                                            ṁ - mould like X ['ta', 'mv', '', '.']
                                                                            Y - join with newlines 'tanmvnn.'
                                                                            - -- call this C
                                                                            ⁸ - chain's left argument, L
                                                                            " - zip with - i.e. [f(L1,C1), f(L2,C2), ...]:
                                                                            ¦ - sparse application...
                                                                            ⁹ - ...to indices: chain's right argument, I
                                                                            ṛ - ...of: right argument, Cn





                                                                            share|improve this answer











                                                                            $endgroup$
















                                                                              3












                                                                              3








                                                                              3





                                                                              $begingroup$


                                                                              Jelly, 16 bytes



                                                                              z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦"


                                                                              A dyadic Link accepting a list of lines (lists of characters containing no newline characters) on the left and an integer on the right which returns a list of lines.



                                                                              Try it online! (footer splits on newlines, calls the Link, and joins by newlines again)



                                                                              How?



                                                                              z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦" - Link: lines L; index I        e.g. example in question; 20
                                                                              z⁷ - transpose L with filler 'n' ['AAARTnTW', ' ohnhr', ...]
                                                                              ⁹ị - Ith item 'amnv.nnt'
                                                                              Ỵ - split at newlines ['am', 'v.', '', 't']
                                                                              Ʋ - last four links as a monad - i.e. f(X):
                                                                              F - flatten 'amv.t'
                                                                              - - -1
                                                                              ṙ - rotate left by 'tamv.'
                                                                              ṁ - mould like X ['ta', 'mv', '', '.']
                                                                              Y - join with newlines 'tanmvnn.'
                                                                              - -- call this C
                                                                              ⁸ - chain's left argument, L
                                                                              " - zip with - i.e. [f(L1,C1), f(L2,C2), ...]:
                                                                              ¦ - sparse application...
                                                                              ⁹ - ...to indices: chain's right argument, I
                                                                              ṛ - ...of: right argument, Cn





                                                                              share|improve this answer











                                                                              $endgroup$




                                                                              Jelly, 16 bytes



                                                                              z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦"


                                                                              A dyadic Link accepting a list of lines (lists of characters containing no newline characters) on the left and an integer on the right which returns a list of lines.



                                                                              Try it online! (footer splits on newlines, calls the Link, and joins by newlines again)



                                                                              How?



                                                                              z⁷⁹ịỴFṙ-ṁƲY⁸ṛ⁹¦" - Link: lines L; index I        e.g. example in question; 20
                                                                              z⁷ - transpose L with filler 'n' ['AAARTnTW', ' ohnhr', ...]
                                                                              ⁹ị - Ith item 'amnv.nnt'
                                                                              Ỵ - split at newlines ['am', 'v.', '', 't']
                                                                              Ʋ - last four links as a monad - i.e. f(X):
                                                                              F - flatten 'amv.t'
                                                                              - - -1
                                                                              ṙ - rotate left by 'tamv.'
                                                                              ṁ - mould like X ['ta', 'mv', '', '.']
                                                                              Y - join with newlines 'tanmvnn.'
                                                                              - -- call this C
                                                                              ⁸ - chain's left argument, L
                                                                              " - zip with - i.e. [f(L1,C1), f(L2,C2), ...]:
                                                                              ¦ - sparse application...
                                                                              ⁹ - ...to indices: chain's right argument, I
                                                                              ṛ - ...of: right argument, Cn






                                                                              share|improve this answer














                                                                              share|improve this answer



                                                                              share|improve this answer








                                                                              edited Mar 29 at 22:21

























                                                                              answered Mar 29 at 22:15









                                                                              Jonathan AllanJonathan Allan

                                                                              54k536174




                                                                              54k536174























                                                                                  2












                                                                                  $begingroup$

                                                                                  perl 5 (-p), 75 bytes



                                                                                  k is 0-indexed, rotate down



                                                                                  s/.*//;$r="^.{$&}";s/
                                                                                  //;/$r(.)/;$c=$1;s/$rK.(?=(?s:.)*?$r(.)|)/$1||$c/gme


                                                                                  TIO






                                                                                  share|improve this answer









                                                                                  $endgroup$


















                                                                                    2












                                                                                    $begingroup$

                                                                                    perl 5 (-p), 75 bytes



                                                                                    k is 0-indexed, rotate down



                                                                                    s/.*//;$r="^.{$&}";s/
                                                                                    //;/$r(.)/;$c=$1;s/$rK.(?=(?s:.)*?$r(.)|)/$1||$c/gme


                                                                                    TIO






                                                                                    share|improve this answer









                                                                                    $endgroup$
















                                                                                      2












                                                                                      2








                                                                                      2





                                                                                      $begingroup$

                                                                                      perl 5 (-p), 75 bytes



                                                                                      k is 0-indexed, rotate down



                                                                                      s/.*//;$r="^.{$&}";s/
                                                                                      //;/$r(.)/;$c=$1;s/$rK.(?=(?s:.)*?$r(.)|)/$1||$c/gme


                                                                                      TIO






                                                                                      share|improve this answer









                                                                                      $endgroup$



                                                                                      perl 5 (-p), 75 bytes



                                                                                      k is 0-indexed, rotate down



                                                                                      s/.*//;$r="^.{$&}";s/
                                                                                      //;/$r(.)/;$c=$1;s/$rK.(?=(?s:.)*?$r(.)|)/$1||$c/gme


                                                                                      TIO







                                                                                      share|improve this answer












                                                                                      share|improve this answer



                                                                                      share|improve this answer










                                                                                      answered Mar 29 at 10:44









                                                                                      Nahuel FouilleulNahuel Fouilleul

                                                                                      3,015211




                                                                                      3,015211























                                                                                          2












                                                                                          $begingroup$


                                                                                          Perl 6, 38 33 bytes





                                                                                          Modifies the array in place (rules don't disallow)



                                                                                          {@^a.grep(*>$^b+1)[*;$b].=rotate}


                                                                                          Try it online!






                                                                                          share|improve this answer











                                                                                          $endgroup$













                                                                                          • $begingroup$
                                                                                            @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                            $endgroup$
                                                                                            – guifa
                                                                                            Mar 30 at 2:25












                                                                                          • $begingroup$
                                                                                            ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                            $endgroup$
                                                                                            – Jo King
                                                                                            Mar 30 at 3:54


















                                                                                          2












                                                                                          $begingroup$


                                                                                          Perl 6, 38 33 bytes





                                                                                          Modifies the array in place (rules don't disallow)



                                                                                          {@^a.grep(*>$^b+1)[*;$b].=rotate}


                                                                                          Try it online!






                                                                                          share|improve this answer











                                                                                          $endgroup$













                                                                                          • $begingroup$
                                                                                            @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                            $endgroup$
                                                                                            – guifa
                                                                                            Mar 30 at 2:25












                                                                                          • $begingroup$
                                                                                            ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                            $endgroup$
                                                                                            – Jo King
                                                                                            Mar 30 at 3:54
















                                                                                          2












                                                                                          2








                                                                                          2





                                                                                          $begingroup$


                                                                                          Perl 6, 38 33 bytes





                                                                                          Modifies the array in place (rules don't disallow)



                                                                                          {@^a.grep(*>$^b+1)[*;$b].=rotate}


                                                                                          Try it online!






                                                                                          share|improve this answer











                                                                                          $endgroup$




                                                                                          Perl 6, 38 33 bytes





                                                                                          Modifies the array in place (rules don't disallow)



                                                                                          {@^a.grep(*>$^b+1)[*;$b].=rotate}


                                                                                          Try it online!







                                                                                          share|improve this answer














                                                                                          share|improve this answer



                                                                                          share|improve this answer








                                                                                          edited Mar 30 at 2:25

























                                                                                          answered Mar 30 at 0:09









                                                                                          guifaguifa

                                                                                          28115




                                                                                          28115












                                                                                          • $begingroup$
                                                                                            @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                            $endgroup$
                                                                                            – guifa
                                                                                            Mar 30 at 2:25












                                                                                          • $begingroup$
                                                                                            ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                            $endgroup$
                                                                                            – Jo King
                                                                                            Mar 30 at 3:54




















                                                                                          • $begingroup$
                                                                                            @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                            $endgroup$
                                                                                            – guifa
                                                                                            Mar 30 at 2:25












                                                                                          • $begingroup$
                                                                                            ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                            $endgroup$
                                                                                            – Jo King
                                                                                            Mar 30 at 3:54


















                                                                                          $begingroup$
                                                                                          @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                          $endgroup$
                                                                                          – guifa
                                                                                          Mar 30 at 2:25






                                                                                          $begingroup$
                                                                                          @joking At first I thought storing it rather than outputting it would be a bit cheating, but rereading the rules, there's no actual stipulation to output so … hooray. Doing a (…)(…) to get 31 like you have definitely seems to be cheating though, since it's effectively hoisting a call out of the block, but it can still be done with 33 passing them simultaneously with a single call so I'm going go with that.
                                                                                          $endgroup$
                                                                                          – guifa
                                                                                          Mar 30 at 2:25














                                                                                          $begingroup$
                                                                                          ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                          $endgroup$
                                                                                          – Jo King
                                                                                          Mar 30 at 3:54






                                                                                          $begingroup$
                                                                                          ah oops, i pasted the wrong link. you got what I mean to comment though. Currying input is perfectly fine though (though it doesn't work in this case), and modifying an argument passed by reference is a standard forn of allowed input
                                                                                          $endgroup$
                                                                                          – Jo King
                                                                                          Mar 30 at 3:54













                                                                                          2












                                                                                          $begingroup$


                                                                                          JavaScript (Node.js), 52 bytes





                                                                                          k=>a=>a.filter(b=>b[k]&&([b[k],a]=[a,b[k]]))[0][k]=a


                                                                                          Try it online!



                                                                                          -7 bytes thanks to Shaggy!



                                                                                          Didn't see a JavaScript answer yet! Port of my C# answer.






                                                                                          share|improve this answer











                                                                                          $endgroup$













                                                                                          • $begingroup$
                                                                                            63 bytes. Can probably be golfed further.
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 30 at 15:02










                                                                                          • $begingroup$
                                                                                            @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                            $endgroup$
                                                                                            – dana
                                                                                            Mar 30 at 15:12






                                                                                          • 1




                                                                                            $begingroup$
                                                                                            Oh, nicely golfed! :)
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 31 at 2:01
















                                                                                          2












                                                                                          $begingroup$


                                                                                          JavaScript (Node.js), 52 bytes





                                                                                          k=>a=>a.filter(b=>b[k]&&([b[k],a]=[a,b[k]]))[0][k]=a


                                                                                          Try it online!



                                                                                          -7 bytes thanks to Shaggy!



                                                                                          Didn't see a JavaScript answer yet! Port of my C# answer.






                                                                                          share|improve this answer











                                                                                          $endgroup$













                                                                                          • $begingroup$
                                                                                            63 bytes. Can probably be golfed further.
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 30 at 15:02










                                                                                          • $begingroup$
                                                                                            @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                            $endgroup$
                                                                                            – dana
                                                                                            Mar 30 at 15:12






                                                                                          • 1




                                                                                            $begingroup$
                                                                                            Oh, nicely golfed! :)
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 31 at 2:01














                                                                                          2












                                                                                          2








                                                                                          2





                                                                                          $begingroup$


                                                                                          JavaScript (Node.js), 52 bytes





                                                                                          k=>a=>a.filter(b=>b[k]&&([b[k],a]=[a,b[k]]))[0][k]=a


                                                                                          Try it online!



                                                                                          -7 bytes thanks to Shaggy!



                                                                                          Didn't see a JavaScript answer yet! Port of my C# answer.






                                                                                          share|improve this answer











                                                                                          $endgroup$




                                                                                          JavaScript (Node.js), 52 bytes





                                                                                          k=>a=>a.filter(b=>b[k]&&([b[k],a]=[a,b[k]]))[0][k]=a


                                                                                          Try it online!



                                                                                          -7 bytes thanks to Shaggy!



                                                                                          Didn't see a JavaScript answer yet! Port of my C# answer.







                                                                                          share|improve this answer














                                                                                          share|improve this answer



                                                                                          share|improve this answer








                                                                                          edited Mar 30 at 18:48

























                                                                                          answered Mar 30 at 9:23









                                                                                          danadana

                                                                                          1,921167




                                                                                          1,921167












                                                                                          • $begingroup$
                                                                                            63 bytes. Can probably be golfed further.
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 30 at 15:02










                                                                                          • $begingroup$
                                                                                            @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                            $endgroup$
                                                                                            – dana
                                                                                            Mar 30 at 15:12






                                                                                          • 1




                                                                                            $begingroup$
                                                                                            Oh, nicely golfed! :)
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 31 at 2:01


















                                                                                          • $begingroup$
                                                                                            63 bytes. Can probably be golfed further.
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 30 at 15:02










                                                                                          • $begingroup$
                                                                                            @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                            $endgroup$
                                                                                            – dana
                                                                                            Mar 30 at 15:12






                                                                                          • 1




                                                                                            $begingroup$
                                                                                            Oh, nicely golfed! :)
                                                                                            $endgroup$
                                                                                            – Shaggy
                                                                                            Mar 31 at 2:01
















                                                                                          $begingroup$
                                                                                          63 bytes. Can probably be golfed further.
                                                                                          $endgroup$
                                                                                          – Shaggy
                                                                                          Mar 30 at 15:02




                                                                                          $begingroup$
                                                                                          63 bytes. Can probably be golfed further.
                                                                                          $endgroup$
                                                                                          – Shaggy
                                                                                          Mar 30 at 15:02












                                                                                          $begingroup$
                                                                                          @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                          $endgroup$
                                                                                          – dana
                                                                                          Mar 30 at 15:12




                                                                                          $begingroup$
                                                                                          @Shaggy - nice :) most of the time I see JS answers doing all sorts of crazy things. Figured this time I'd give it a shot since I had a strategy.
                                                                                          $endgroup$
                                                                                          – dana
                                                                                          Mar 30 at 15:12




                                                                                          1




                                                                                          1




                                                                                          $begingroup$
                                                                                          Oh, nicely golfed! :)
                                                                                          $endgroup$
                                                                                          – Shaggy
                                                                                          Mar 31 at 2:01




                                                                                          $begingroup$
                                                                                          Oh, nicely golfed! :)
                                                                                          $endgroup$
                                                                                          – Shaggy
                                                                                          Mar 31 at 2:01











                                                                                          2












                                                                                          $begingroup$


                                                                                          Charcoal, 34 28 21 bytes



                                                                                          θJη⁰≔ΦKDLθ↓℅ιζUMζ§ζ⊖κ


                                                                                          Try it online! Link is to verbose version of code. Takes an array of strings as input. 0-indexed. Edit: Now that PeekDirection has been fixed, I can manipulate it directly. Explanation:



                                                                                          θ


                                                                                          Print the input strings.



                                                                                          Jη⁰


                                                                                          Jump to the top of the column to be rotated.



                                                                                          ≔ΦKDLθ↓℅ιζ


                                                                                          Extract the cells that have been printed in.



                                                                                          UMζ§ζ⊖κ


                                                                                          Replace each printed cell with the value of the previous cell (cyclically). Conveniently the cell values are read at the time of the PeekDirection call so the fact that the MapCommand call writes new values into the cells doesn't matter.






                                                                                          share|improve this answer











                                                                                          $endgroup$


















                                                                                            2












                                                                                            $begingroup$


                                                                                            Charcoal, 34 28 21 bytes



                                                                                            θJη⁰≔ΦKDLθ↓℅ιζUMζ§ζ⊖κ


                                                                                            Try it online! Link is to verbose version of code. Takes an array of strings as input. 0-indexed. Edit: Now that PeekDirection has been fixed, I can manipulate it directly. Explanation:



                                                                                            θ


                                                                                            Print the input strings.



                                                                                            Jη⁰


                                                                                            Jump to the top of the column to be rotated.



                                                                                            ≔ΦKDLθ↓℅ιζ


                                                                                            Extract the cells that have been printed in.



                                                                                            UMζ§ζ⊖κ


                                                                                            Replace each printed cell with the value of the previous cell (cyclically). Conveniently the cell values are read at the time of the PeekDirection call so the fact that the MapCommand call writes new values into the cells doesn't matter.






                                                                                            share|improve this answer











                                                                                            $endgroup$
















                                                                                              2












                                                                                              2








                                                                                              2





                                                                                              $begingroup$


                                                                                              Charcoal, 34 28 21 bytes



                                                                                              θJη⁰≔ΦKDLθ↓℅ιζUMζ§ζ⊖κ


                                                                                              Try it online! Link is to verbose version of code. Takes an array of strings as input. 0-indexed. Edit: Now that PeekDirection has been fixed, I can manipulate it directly. Explanation:



                                                                                              θ


                                                                                              Print the input strings.



                                                                                              Jη⁰


                                                                                              Jump to the top of the column to be rotated.



                                                                                              ≔ΦKDLθ↓℅ιζ


                                                                                              Extract the cells that have been printed in.



                                                                                              UMζ§ζ⊖κ


                                                                                              Replace each printed cell with the value of the previous cell (cyclically). Conveniently the cell values are read at the time of the PeekDirection call so the fact that the MapCommand call writes new values into the cells doesn't matter.






                                                                                              share|improve this answer











                                                                                              $endgroup$




                                                                                              Charcoal, 34 28 21 bytes



                                                                                              θJη⁰≔ΦKDLθ↓℅ιζUMζ§ζ⊖κ


                                                                                              Try it online! Link is to verbose version of code. Takes an array of strings as input. 0-indexed. Edit: Now that PeekDirection has been fixed, I can manipulate it directly. Explanation:



                                                                                              θ


                                                                                              Print the input strings.



                                                                                              Jη⁰


                                                                                              Jump to the top of the column to be rotated.



                                                                                              ≔ΦKDLθ↓℅ιζ


                                                                                              Extract the cells that have been printed in.



                                                                                              UMζ§ζ⊖κ


                                                                                              Replace each printed cell with the value of the previous cell (cyclically). Conveniently the cell values are read at the time of the PeekDirection call so the fact that the MapCommand call writes new values into the cells doesn't matter.







                                                                                              share|improve this answer














                                                                                              share|improve this answer



                                                                                              share|improve this answer








                                                                                              edited 2 days ago

























                                                                                              answered Mar 28 at 20:14









                                                                                              NeilNeil

                                                                                              82.7k745179




                                                                                              82.7k745179























                                                                                                  1












                                                                                                  $begingroup$


                                                                                                  Pip -rn, 32 bytes



                                                                                                  POgY#(g@_)>aFI,#gFiyAE@ySsg@i@ag


                                                                                                  0-indexed, rotates down. Try it online!



                                                                                                  Filters to find the indices of all rows that are long enough to participate in the rotation. Then loops over those rows, swapping the appropriate character on each row with a temp variable s. Visiting the first row again at the end swaps the dummy value back out again.






                                                                                                  share|improve this answer









                                                                                                  $endgroup$


















                                                                                                    1












                                                                                                    $begingroup$


                                                                                                    Pip -rn, 32 bytes



                                                                                                    POgY#(g@_)>aFI,#gFiyAE@ySsg@i@ag


                                                                                                    0-indexed, rotates down. Try it online!



                                                                                                    Filters to find the indices of all rows that are long enough to participate in the rotation. Then loops over those rows, swapping the appropriate character on each row with a temp variable s. Visiting the first row again at the end swaps the dummy value back out again.






                                                                                                    share|improve this answer









                                                                                                    $endgroup$
















                                                                                                      1












                                                                                                      1








                                                                                                      1





                                                                                                      $begingroup$


                                                                                                      Pip -rn, 32 bytes



                                                                                                      POgY#(g@_)>aFI,#gFiyAE@ySsg@i@ag


                                                                                                      0-indexed, rotates down. Try it online!



                                                                                                      Filters to find the indices of all rows that are long enough to participate in the rotation. Then loops over those rows, swapping the appropriate character on each row with a temp variable s. Visiting the first row again at the end swaps the dummy value back out again.






                                                                                                      share|improve this answer









                                                                                                      $endgroup$




                                                                                                      Pip -rn, 32 bytes



                                                                                                      POgY#(g@_)>aFI,#gFiyAE@ySsg@i@ag


                                                                                                      0-indexed, rotates down. Try it online!



                                                                                                      Filters to find the indices of all rows that are long enough to participate in the rotation. Then loops over those rows, swapping the appropriate character on each row with a temp variable s. Visiting the first row again at the end swaps the dummy value back out again.







                                                                                                      share|improve this answer












                                                                                                      share|improve this answer



                                                                                                      share|improve this answer










                                                                                                      answered Mar 29 at 7:51









                                                                                                      DLoscDLosc

                                                                                                      19.4k33990




                                                                                                      19.4k33990























                                                                                                          1












                                                                                                          $begingroup$


                                                                                                          Jelly, 19 bytes



                                                                                                          ZnÄ×$ịḟ¹ṙ-;ɗɗʋ€⁹¦⁶Z


                                                                                                          Try it online!



                                                                                                          1-indexed. Rotates down. A monadic link that takes a right-padded list of Jelly strings (a list of lists of characters) as the first argument and k as the second. Spaces are forbidden in the input except as right padding, but all other characters are permitted.



                                                                                                          As implemented on TIO, the footer splits a single string input into a list of strings and right-pads it, but this is for convenience; as I understand it, the result of that step is permitted input for the main link per the rules.






                                                                                                          share|improve this answer









                                                                                                          $endgroup$


















                                                                                                            1












                                                                                                            $begingroup$


                                                                                                            Jelly, 19 bytes



                                                                                                            ZnÄ×$ịḟ¹ṙ-;ɗɗʋ€⁹¦⁶Z


                                                                                                            Try it online!



                                                                                                            1-indexed. Rotates down. A monadic link that takes a right-padded list of Jelly strings (a list of lists of characters) as the first argument and k as the second. Spaces are forbidden in the input except as right padding, but all other characters are permitted.



                                                                                                            As implemented on TIO, the footer splits a single string input into a list of strings and right-pads it, but this is for convenience; as I understand it, the result of that step is permitted input for the main link per the rules.






                                                                                                            share|improve this answer









                                                                                                            $endgroup$
















                                                                                                              1












                                                                                                              1








                                                                                                              1





                                                                                                              $begingroup$


                                                                                                              Jelly, 19 bytes



                                                                                                              ZnÄ×$ịḟ¹ṙ-;ɗɗʋ€⁹¦⁶Z


                                                                                                              Try it online!



                                                                                                              1-indexed. Rotates down. A monadic link that takes a right-padded list of Jelly strings (a list of lists of characters) as the first argument and k as the second. Spaces are forbidden in the input except as right padding, but all other characters are permitted.



                                                                                                              As implemented on TIO, the footer splits a single string input into a list of strings and right-pads it, but this is for convenience; as I understand it, the result of that step is permitted input for the main link per the rules.






                                                                                                              share|improve this answer









                                                                                                              $endgroup$




                                                                                                              Jelly, 19 bytes



                                                                                                              ZnÄ×$ịḟ¹ṙ-;ɗɗʋ€⁹¦⁶Z


                                                                                                              Try it online!



                                                                                                              1-indexed. Rotates down. A monadic link that takes a right-padded list of Jelly strings (a list of lists of characters) as the first argument and k as the second. Spaces are forbidden in the input except as right padding, but all other characters are permitted.



                                                                                                              As implemented on TIO, the footer splits a single string input into a list of strings and right-pads it, but this is for convenience; as I understand it, the result of that step is permitted input for the main link per the rules.







                                                                                                              share|improve this answer












                                                                                                              share|improve this answer



                                                                                                              share|improve this answer










                                                                                                              answered Mar 29 at 19:49









                                                                                                              Nick KennedyNick Kennedy

                                                                                                              1,46649




                                                                                                              1,46649























                                                                                                                  0












                                                                                                                  $begingroup$


                                                                                                                  GFortran, 203 bytes



                                                                                                                  -20 or so by reading from stdin rather than a file
                                                                                                                  -14 by using implicit integers for i, k, n



                                                                                                                  Requires user to input k and n on the first line, where k is the column to rotate, and n is the number of rows of text. Subsequent inputs are the lines of text to be rotated. This was a pain to write! Fortran is so pedantic!



                                                                                                                  Original, ungolfed program here, with comments and compilation notes: rotcol.f



                                                                                                                  Try it here: https://rextester.com/RBEE63006



                                                                                                                  character(80),allocatable::A(:)
                                                                                                                  character(1)::r,s
                                                                                                                  read(*,*) k,n
                                                                                                                  allocate(A(n))
                                                                                                                  do i=1,n
                                                                                                                  read(*,'(A)')A(i)
                                                                                                                  r=A(i)(k:k)
                                                                                                                  if(r.ne.''.or.r.ne.' ')then
                                                                                                                  A(i)(k:k)=s
                                                                                                                  s=r
                                                                                                                  endif
                                                                                                                  enddo
                                                                                                                  A(1)(k:k)=s
                                                                                                                  print'(A)',A
                                                                                                                  end





                                                                                                                  share|improve this answer











                                                                                                                  $endgroup$


















                                                                                                                    0












                                                                                                                    $begingroup$


                                                                                                                    GFortran, 203 bytes



                                                                                                                    -20 or so by reading from stdin rather than a file
                                                                                                                    -14 by using implicit integers for i, k, n



                                                                                                                    Requires user to input k and n on the first line, where k is the column to rotate, and n is the number of rows of text. Subsequent inputs are the lines of text to be rotated. This was a pain to write! Fortran is so pedantic!



                                                                                                                    Original, ungolfed program here, with comments and compilation notes: rotcol.f



                                                                                                                    Try it here: https://rextester.com/RBEE63006



                                                                                                                    character(80),allocatable::A(:)
                                                                                                                    character(1)::r,s
                                                                                                                    read(*,*) k,n
                                                                                                                    allocate(A(n))
                                                                                                                    do i=1,n
                                                                                                                    read(*,'(A)')A(i)
                                                                                                                    r=A(i)(k:k)
                                                                                                                    if(r.ne.''.or.r.ne.' ')then
                                                                                                                    A(i)(k:k)=s
                                                                                                                    s=r
                                                                                                                    endif
                                                                                                                    enddo
                                                                                                                    A(1)(k:k)=s
                                                                                                                    print'(A)',A
                                                                                                                    end





                                                                                                                    share|improve this answer











                                                                                                                    $endgroup$
















                                                                                                                      0












                                                                                                                      0








                                                                                                                      0





                                                                                                                      $begingroup$


                                                                                                                      GFortran, 203 bytes



                                                                                                                      -20 or so by reading from stdin rather than a file
                                                                                                                      -14 by using implicit integers for i, k, n



                                                                                                                      Requires user to input k and n on the first line, where k is the column to rotate, and n is the number of rows of text. Subsequent inputs are the lines of text to be rotated. This was a pain to write! Fortran is so pedantic!



                                                                                                                      Original, ungolfed program here, with comments and compilation notes: rotcol.f



                                                                                                                      Try it here: https://rextester.com/RBEE63006



                                                                                                                      character(80),allocatable::A(:)
                                                                                                                      character(1)::r,s
                                                                                                                      read(*,*) k,n
                                                                                                                      allocate(A(n))
                                                                                                                      do i=1,n
                                                                                                                      read(*,'(A)')A(i)
                                                                                                                      r=A(i)(k:k)
                                                                                                                      if(r.ne.''.or.r.ne.' ')then
                                                                                                                      A(i)(k:k)=s
                                                                                                                      s=r
                                                                                                                      endif
                                                                                                                      enddo
                                                                                                                      A(1)(k:k)=s
                                                                                                                      print'(A)',A
                                                                                                                      end





                                                                                                                      share|improve this answer











                                                                                                                      $endgroup$




                                                                                                                      GFortran, 203 bytes



                                                                                                                      -20 or so by reading from stdin rather than a file
                                                                                                                      -14 by using implicit integers for i, k, n



                                                                                                                      Requires user to input k and n on the first line, where k is the column to rotate, and n is the number of rows of text. Subsequent inputs are the lines of text to be rotated. This was a pain to write! Fortran is so pedantic!



                                                                                                                      Original, ungolfed program here, with comments and compilation notes: rotcol.f



                                                                                                                      Try it here: https://rextester.com/RBEE63006



                                                                                                                      character(80),allocatable::A(:)
                                                                                                                      character(1)::r,s
                                                                                                                      read(*,*) k,n
                                                                                                                      allocate(A(n))
                                                                                                                      do i=1,n
                                                                                                                      read(*,'(A)')A(i)
                                                                                                                      r=A(i)(k:k)
                                                                                                                      if(r.ne.''.or.r.ne.' ')then
                                                                                                                      A(i)(k:k)=s
                                                                                                                      s=r
                                                                                                                      endif
                                                                                                                      enddo
                                                                                                                      A(1)(k:k)=s
                                                                                                                      print'(A)',A
                                                                                                                      end






                                                                                                                      share|improve this answer














                                                                                                                      share|improve this answer



                                                                                                                      share|improve this answer








                                                                                                                      edited Apr 2 at 9:17

























                                                                                                                      answered Apr 1 at 22:21









                                                                                                                      roblogicroblogic

                                                                                                                      1515




                                                                                                                      1515























                                                                                                                          0












                                                                                                                          $begingroup$

                                                                                                                          T-SQL, 208 bytes



                                                                                                                          WITH C as(SELECT rank()over(order
                                                                                                                          by i)r,sum(1)over()c,*FROM @
                                                                                                                          WHERE len(x)>=@c)SELECT
                                                                                                                          isnull(m,x)FROM @ z
                                                                                                                          LEFT JOIN(SELECT stuff(c.x,@c,1,substring(e.x,@c,1))m,c.i
                                                                                                                          FROM c,c e WHERE e.r%c.c+1=c.r)d
                                                                                                                          ON z.i=d.i


                                                                                                                          Try it online ungolfed version






                                                                                                                          share|improve this answer









                                                                                                                          $endgroup$


















                                                                                                                            0












                                                                                                                            $begingroup$

                                                                                                                            T-SQL, 208 bytes



                                                                                                                            WITH C as(SELECT rank()over(order
                                                                                                                            by i)r,sum(1)over()c,*FROM @
                                                                                                                            WHERE len(x)>=@c)SELECT
                                                                                                                            isnull(m,x)FROM @ z
                                                                                                                            LEFT JOIN(SELECT stuff(c.x,@c,1,substring(e.x,@c,1))m,c.i
                                                                                                                            FROM c,c e WHERE e.r%c.c+1=c.r)d
                                                                                                                            ON z.i=d.i


                                                                                                                            Try it online ungolfed version






                                                                                                                            share|improve this answer









                                                                                                                            $endgroup$
















                                                                                                                              0












                                                                                                                              0








                                                                                                                              0





                                                                                                                              $begingroup$

                                                                                                                              T-SQL, 208 bytes



                                                                                                                              WITH C as(SELECT rank()over(order
                                                                                                                              by i)r,sum(1)over()c,*FROM @
                                                                                                                              WHERE len(x)>=@c)SELECT
                                                                                                                              isnull(m,x)FROM @ z
                                                                                                                              LEFT JOIN(SELECT stuff(c.x,@c,1,substring(e.x,@c,1))m,c.i
                                                                                                                              FROM c,c e WHERE e.r%c.c+1=c.r)d
                                                                                                                              ON z.i=d.i


                                                                                                                              Try it online ungolfed version






                                                                                                                              share|improve this answer









                                                                                                                              $endgroup$



                                                                                                                              T-SQL, 208 bytes



                                                                                                                              WITH C as(SELECT rank()over(order
                                                                                                                              by i)r,sum(1)over()c,*FROM @
                                                                                                                              WHERE len(x)>=@c)SELECT
                                                                                                                              isnull(m,x)FROM @ z
                                                                                                                              LEFT JOIN(SELECT stuff(c.x,@c,1,substring(e.x,@c,1))m,c.i
                                                                                                                              FROM c,c e WHERE e.r%c.c+1=c.r)d
                                                                                                                              ON z.i=d.i


                                                                                                                              Try it online ungolfed version







                                                                                                                              share|improve this answer












                                                                                                                              share|improve this answer



                                                                                                                              share|improve this answer










                                                                                                                              answered 2 days ago









                                                                                                                              t-clausen.dkt-clausen.dk

                                                                                                                              2,074314




                                                                                                                              2,074314






























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