Linear Genetic Programming: Intron removal algorithm











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  1. Let set R_eff always contain all registers that are effective at the current program position. R_eff := { r | r is output register }. Start at the last program instruction and move backwards.

  2. Mark the next preceding operation in program with: destination register r_dest element-of R_eff. If such an instruction is not found then go to 5.

  3. .If the operation directly follows a branch or a sequence of branches then mark these instructions too. Otherwise remove r_dest
    from R_eff .

  4. Insert each source (operand) register r_op of newly marked
    instructions in R_eff if not already contained. Go to 2.

  5. Stop. All unmarked instructions are introns.


This is the algorithm given , I know the question was asked before, but I'm not clear on a few things( and turns out there isn't much online material assisting with this stuff). I mainly need to know what we're comparing. You have a program, and within the program, are instructions with the form of :




r0= r1 + r2




Just as an example. So I understand we start at the last instruction and move backwards for our comparisons. But in step 2 when it says to move backwards are we going back the to the immediately previous instructions, or are we moving backwards to the instruction with a register in common?
For the example I gave, would I keep searching backwards till I found another r0, or would I go backwards until I found a r1 or r2?



I'm pretty confused with this simple thing and would appreciate any help I can get










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    0
    down vote

    favorite













    1. Let set R_eff always contain all registers that are effective at the current program position. R_eff := { r | r is output register }. Start at the last program instruction and move backwards.

    2. Mark the next preceding operation in program with: destination register r_dest element-of R_eff. If such an instruction is not found then go to 5.

    3. .If the operation directly follows a branch or a sequence of branches then mark these instructions too. Otherwise remove r_dest
      from R_eff .

    4. Insert each source (operand) register r_op of newly marked
      instructions in R_eff if not already contained. Go to 2.

    5. Stop. All unmarked instructions are introns.


    This is the algorithm given , I know the question was asked before, but I'm not clear on a few things( and turns out there isn't much online material assisting with this stuff). I mainly need to know what we're comparing. You have a program, and within the program, are instructions with the form of :




    r0= r1 + r2




    Just as an example. So I understand we start at the last instruction and move backwards for our comparisons. But in step 2 when it says to move backwards are we going back the to the immediately previous instructions, or are we moving backwards to the instruction with a register in common?
    For the example I gave, would I keep searching backwards till I found another r0, or would I go backwards until I found a r1 or r2?



    I'm pretty confused with this simple thing and would appreciate any help I can get










    share|improve this question







    New contributor




    Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite












      1. Let set R_eff always contain all registers that are effective at the current program position. R_eff := { r | r is output register }. Start at the last program instruction and move backwards.

      2. Mark the next preceding operation in program with: destination register r_dest element-of R_eff. If such an instruction is not found then go to 5.

      3. .If the operation directly follows a branch or a sequence of branches then mark these instructions too. Otherwise remove r_dest
        from R_eff .

      4. Insert each source (operand) register r_op of newly marked
        instructions in R_eff if not already contained. Go to 2.

      5. Stop. All unmarked instructions are introns.


      This is the algorithm given , I know the question was asked before, but I'm not clear on a few things( and turns out there isn't much online material assisting with this stuff). I mainly need to know what we're comparing. You have a program, and within the program, are instructions with the form of :




      r0= r1 + r2




      Just as an example. So I understand we start at the last instruction and move backwards for our comparisons. But in step 2 when it says to move backwards are we going back the to the immediately previous instructions, or are we moving backwards to the instruction with a register in common?
      For the example I gave, would I keep searching backwards till I found another r0, or would I go backwards until I found a r1 or r2?



      I'm pretty confused with this simple thing and would appreciate any help I can get










      share|improve this question







      New contributor




      Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      1. Let set R_eff always contain all registers that are effective at the current program position. R_eff := { r | r is output register }. Start at the last program instruction and move backwards.

      2. Mark the next preceding operation in program with: destination register r_dest element-of R_eff. If such an instruction is not found then go to 5.

      3. .If the operation directly follows a branch or a sequence of branches then mark these instructions too. Otherwise remove r_dest
        from R_eff .

      4. Insert each source (operand) register r_op of newly marked
        instructions in R_eff if not already contained. Go to 2.

      5. Stop. All unmarked instructions are introns.


      This is the algorithm given , I know the question was asked before, but I'm not clear on a few things( and turns out there isn't much online material assisting with this stuff). I mainly need to know what we're comparing. You have a program, and within the program, are instructions with the form of :




      r0= r1 + r2




      Just as an example. So I understand we start at the last instruction and move backwards for our comparisons. But in step 2 when it says to move backwards are we going back the to the immediately previous instructions, or are we moving backwards to the instruction with a register in common?
      For the example I gave, would I keep searching backwards till I found another r0, or would I go backwards until I found a r1 or r2?



      I'm pretty confused with this simple thing and would appreciate any help I can get







      genetic-programming






      share|improve this question







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      Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







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      Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






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      Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      Robin White is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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      Check out our Code of Conduct.





























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