TypeError: expected string or bytes-like object in Python











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I am currently breaking on the subjected break. What is this TypeError, and how do I resolve it? What are the necessary amendments required in the code?



from urllib.request import urlretrieve

stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')
vstoxx_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/h_vstoxx.txt')

data_folder = 'data/' #Save file to local target destination.
stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
vstoxx_filepath = data_folder + "vstoxx.txt"
urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


This is the output:



File "/home/aryabhatta/anaconda3/lib/python3.6/urllib/parse.py", line 938, in splittype
match = _typeprog.match(url)

TypeError: expected string or bytes-like object









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  • Please include the complete error message.
    – DYZ
    2 days ago















up vote
-1
down vote

favorite












I am currently breaking on the subjected break. What is this TypeError, and how do I resolve it? What are the necessary amendments required in the code?



from urllib.request import urlretrieve

stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')
vstoxx_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/h_vstoxx.txt')

data_folder = 'data/' #Save file to local target destination.
stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
vstoxx_filepath = data_folder + "vstoxx.txt"
urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


This is the output:



File "/home/aryabhatta/anaconda3/lib/python3.6/urllib/parse.py", line 938, in splittype
match = _typeprog.match(url)

TypeError: expected string or bytes-like object









share|improve this question









New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




















  • Please include the complete error message.
    – DYZ
    2 days ago













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I am currently breaking on the subjected break. What is this TypeError, and how do I resolve it? What are the necessary amendments required in the code?



from urllib.request import urlretrieve

stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')
vstoxx_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/h_vstoxx.txt')

data_folder = 'data/' #Save file to local target destination.
stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
vstoxx_filepath = data_folder + "vstoxx.txt"
urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


This is the output:



File "/home/aryabhatta/anaconda3/lib/python3.6/urllib/parse.py", line 938, in splittype
match = _typeprog.match(url)

TypeError: expected string or bytes-like object









share|improve this question









New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I am currently breaking on the subjected break. What is this TypeError, and how do I resolve it? What are the necessary amendments required in the code?



from urllib.request import urlretrieve

stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')
vstoxx_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/h_vstoxx.txt')

data_folder = 'data/' #Save file to local target destination.
stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
vstoxx_filepath = data_folder + "vstoxx.txt"
urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


This is the output:



File "/home/aryabhatta/anaconda3/lib/python3.6/urllib/parse.py", line 938, in splittype
match = _typeprog.match(url)

TypeError: expected string or bytes-like object






python






share|improve this question









New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 2 days ago









public static void main

7231321




7231321






New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 2 days ago









Himanshu Doneria

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New contributor




Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Himanshu Doneria is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












  • Please include the complete error message.
    – DYZ
    2 days ago


















  • Please include the complete error message.
    – DYZ
    2 days ago
















Please include the complete error message.
– DYZ
2 days ago




Please include the complete error message.
– DYZ
2 days ago












2 Answers
2






active

oldest

votes

















up vote
0
down vote













urlretrieve wants a string as its first argument. So stoxxeu600_url should be a string.



from urllib.request import urlretrieve

stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
data_folder = 'data/' #Save file to local target destination.
stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
urlretrieve(stoxxeu600_url, stoxxeu600_filepath)





share|improve this answer




























    up vote
    0
    down vote













    You can see from the documentation of urlretrieve() that the method returns a tuple (filename, headers)



    In your code, you first call urlretrieve() and store it into stoxxeu600_url



    stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')


    stoxxeu600_url now has (filename, headers) returned by urlretrieve()



    You then call urlretrieve() again with stoxxeu600_url which is a tuple, and not the str/byte object, that the method expects. Thereby, causing the TypeError.



    urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


    To fix it, just set stoxxeu600_url to the url and then call the method.



    from urllib.request import urlretrieve

    stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
    stoxxeu600_filepath = "stoxxeu600.txt"
    urlretrieve(stoxxeu600_url, filename=stoxxeu600_filepath)





    share|improve this answer





















    • Thanks for suggestion.
      – Himanshu Doneria
      2 days ago










    • @HimanshuDoneria mark as answered if that was what you were looking for
      – Xnkr
      2 days ago











    Your Answer






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    2 Answers
    2






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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

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    up vote
    0
    down vote













    urlretrieve wants a string as its first argument. So stoxxeu600_url should be a string.



    from urllib.request import urlretrieve

    stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
    data_folder = 'data/' #Save file to local target destination.
    stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
    urlretrieve(stoxxeu600_url, stoxxeu600_filepath)





    share|improve this answer

























      up vote
      0
      down vote













      urlretrieve wants a string as its first argument. So stoxxeu600_url should be a string.



      from urllib.request import urlretrieve

      stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
      data_folder = 'data/' #Save file to local target destination.
      stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
      urlretrieve(stoxxeu600_url, stoxxeu600_filepath)





      share|improve this answer























        up vote
        0
        down vote










        up vote
        0
        down vote









        urlretrieve wants a string as its first argument. So stoxxeu600_url should be a string.



        from urllib.request import urlretrieve

        stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
        data_folder = 'data/' #Save file to local target destination.
        stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
        urlretrieve(stoxxeu600_url, stoxxeu600_filepath)





        share|improve this answer












        urlretrieve wants a string as its first argument. So stoxxeu600_url should be a string.



        from urllib.request import urlretrieve

        stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
        data_folder = 'data/' #Save file to local target destination.
        stoxxeu600_filepath = data_folder + "stoxxeu600.txt"
        urlretrieve(stoxxeu600_url, stoxxeu600_filepath)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 2 days ago









        Rob Bricheno

        1,57611




        1,57611
























            up vote
            0
            down vote













            You can see from the documentation of urlretrieve() that the method returns a tuple (filename, headers)



            In your code, you first call urlretrieve() and store it into stoxxeu600_url



            stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')


            stoxxeu600_url now has (filename, headers) returned by urlretrieve()



            You then call urlretrieve() again with stoxxeu600_url which is a tuple, and not the str/byte object, that the method expects. Thereby, causing the TypeError.



            urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


            To fix it, just set stoxxeu600_url to the url and then call the method.



            from urllib.request import urlretrieve

            stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
            stoxxeu600_filepath = "stoxxeu600.txt"
            urlretrieve(stoxxeu600_url, filename=stoxxeu600_filepath)





            share|improve this answer





















            • Thanks for suggestion.
              – Himanshu Doneria
              2 days ago










            • @HimanshuDoneria mark as answered if that was what you were looking for
              – Xnkr
              2 days ago















            up vote
            0
            down vote













            You can see from the documentation of urlretrieve() that the method returns a tuple (filename, headers)



            In your code, you first call urlretrieve() and store it into stoxxeu600_url



            stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')


            stoxxeu600_url now has (filename, headers) returned by urlretrieve()



            You then call urlretrieve() again with stoxxeu600_url which is a tuple, and not the str/byte object, that the method expects. Thereby, causing the TypeError.



            urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


            To fix it, just set stoxxeu600_url to the url and then call the method.



            from urllib.request import urlretrieve

            stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
            stoxxeu600_filepath = "stoxxeu600.txt"
            urlretrieve(stoxxeu600_url, filename=stoxxeu600_filepath)





            share|improve this answer





















            • Thanks for suggestion.
              – Himanshu Doneria
              2 days ago










            • @HimanshuDoneria mark as answered if that was what you were looking for
              – Xnkr
              2 days ago













            up vote
            0
            down vote










            up vote
            0
            down vote









            You can see from the documentation of urlretrieve() that the method returns a tuple (filename, headers)



            In your code, you first call urlretrieve() and store it into stoxxeu600_url



            stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')


            stoxxeu600_url now has (filename, headers) returned by urlretrieve()



            You then call urlretrieve() again with stoxxeu600_url which is a tuple, and not the str/byte object, that the method expects. Thereby, causing the TypeError.



            urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


            To fix it, just set stoxxeu600_url to the url and then call the method.



            from urllib.request import urlretrieve

            stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
            stoxxeu600_filepath = "stoxxeu600.txt"
            urlretrieve(stoxxeu600_url, filename=stoxxeu600_filepath)





            share|improve this answer












            You can see from the documentation of urlretrieve() that the method returns a tuple (filename, headers)



            In your code, you first call urlretrieve() and store it into stoxxeu600_url



            stoxxeu600_url = urllib.request.urlretrieve('https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt')


            stoxxeu600_url now has (filename, headers) returned by urlretrieve()



            You then call urlretrieve() again with stoxxeu600_url which is a tuple, and not the str/byte object, that the method expects. Thereby, causing the TypeError.



            urlretrieve(stoxxeu600_url,stoxxeu600_filepath)


            To fix it, just set stoxxeu600_url to the url and then call the method.



            from urllib.request import urlretrieve

            stoxxeu600_url = 'https://www.stoxx.com/document/Indices/Current/HistoricalData/hbrbcpe.txt'
            stoxxeu600_filepath = "stoxxeu600.txt"
            urlretrieve(stoxxeu600_url, filename=stoxxeu600_filepath)






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 2 days ago









            Xnkr

            400313




            400313












            • Thanks for suggestion.
              – Himanshu Doneria
              2 days ago










            • @HimanshuDoneria mark as answered if that was what you were looking for
              – Xnkr
              2 days ago


















            • Thanks for suggestion.
              – Himanshu Doneria
              2 days ago










            • @HimanshuDoneria mark as answered if that was what you were looking for
              – Xnkr
              2 days ago
















            Thanks for suggestion.
            – Himanshu Doneria
            2 days ago




            Thanks for suggestion.
            – Himanshu Doneria
            2 days ago












            @HimanshuDoneria mark as answered if that was what you were looking for
            – Xnkr
            2 days ago




            @HimanshuDoneria mark as answered if that was what you were looking for
            – Xnkr
            2 days ago










            Himanshu Doneria is a new contributor. Be nice, and check out our Code of Conduct.










             

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            Himanshu Doneria is a new contributor. Be nice, and check out our Code of Conduct.













            Himanshu Doneria is a new contributor. Be nice, and check out our Code of Conduct.












            Himanshu Doneria is a new contributor. Be nice, and check out our Code of Conduct.















             


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