How can I transform certain values in an object while ignoring some of the keys?
1
I want to loop through Objects in an array with different keys, without using a for-each loop:
[ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ]
I want to check every column mn for a length value then update it with some information, I can just do if else condition, but I think there is a better way of doing this. I tried using Object.entries then for loop, but it won't work because of id and ip columns.
javascript
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
add a comment |
1
I want to loop through Objects in an array with different keys, without using a for-each loop:
[ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ]
I want to check every column mn for a length value then update it with some information, I can just do if else condition, but I think there is a better way of doing this. I tried using Object.entries then for loop, but it won't work because of id and ip columns.
javascript
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
2
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array likemn[1], mn[2], etc.
– Mark Meyer
Nov 20 '18 at 19:26
have you looked atObject.keys?
– Jhecht
Nov 20 '18 at 19:26
You can usefor (var item in obj){ .. }
– Spencer Wieczorek
Nov 20 '18 at 19:29
what information do you want to updatemn*keys with?
– Dacre Denny
Nov 20 '18 at 19:30
add a comment |
1
1
1
I want to loop through Objects in an array with different keys, without using a for-each loop:
[ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ]
I want to check every column mn for a length value then update it with some information, I can just do if else condition, but I think there is a better way of doing this. I tried using Object.entries then for loop, but it won't work because of id and ip columns.
javascript
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
I want to loop through Objects in an array with different keys, without using a for-each loop:
[ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ]
I want to check every column mn for a length value then update it with some information, I can just do if else condition, but I think there is a better way of doing this. I tried using Object.entries then for loop, but it won't work because of id and ip columns.
javascript
javascript
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
edited Nov 20 '18 at 20:47
Roy Scheffers
2,169101826
2,169101826
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
asked Nov 20 '18 at 19:23
The 4th pyramidThe 4th pyramid
55110
55110
2
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array likemn[1], mn[2], etc.
– Mark Meyer
Nov 20 '18 at 19:26
have you looked atObject.keys?
– Jhecht
Nov 20 '18 at 19:26
You can usefor (var item in obj){ .. }
– Spencer Wieczorek
Nov 20 '18 at 19:29
what information do you want to updatemn*keys with?
– Dacre Denny
Nov 20 '18 at 19:30
add a comment |
2
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array likemn[1], mn[2], etc.
– Mark Meyer
Nov 20 '18 at 19:26
have you looked atObject.keys?
– Jhecht
Nov 20 '18 at 19:26
You can usefor (var item in obj){ .. }
– Spencer Wieczorek
Nov 20 '18 at 19:29
what information do you want to updatemn*keys with?
– Dacre Denny
Nov 20 '18 at 19:30
2
2
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array like
mn[1], mn[2], etc.– Mark Meyer
Nov 20 '18 at 19:26
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array like
mn[1], mn[2], etc.– Mark Meyer
Nov 20 '18 at 19:26
have you looked at
Object.keys ?– Jhecht
Nov 20 '18 at 19:26
have you looked at
Object.keys ?– Jhecht
Nov 20 '18 at 19:26
You can use
for (var item in obj){ .. }– Spencer Wieczorek
Nov 20 '18 at 19:29
You can use
for (var item in obj){ .. }– Spencer Wieczorek
Nov 20 '18 at 19:29
what information do you want to update
mn* keys with?– Dacre Denny
Nov 20 '18 at 19:30
what information do you want to update
mn* keys with?– Dacre Denny
Nov 20 '18 at 19:30
add a comment |
3 Answers
3
active
oldest
votes
2
Perhaps something like this would work for you? This solution takes a functional approach to your problem, and avoids explict use of the for-loop construct:
var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
add a comment |
1
You can check the name of the key before you modify it.
Does this help? Try it out by running the code snippet.
const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
add a comment |
1
You can use Object.entries, Array.prototype.filter, and Array.prototype.forEach to your advantage.
const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)This starts to get verbose if you can't use the latest ECMAScript features, though:
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)If you're stuck on a project without Babel, your best bet may be your original suggestion.
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
Perhaps something like this would work for you? This solution takes a functional approach to your problem, and avoids explict use of the for-loop construct:
var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
add a comment |
2
Perhaps something like this would work for you? This solution takes a functional approach to your problem, and avoids explict use of the for-loop construct:
var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
add a comment |
2
2
2
Perhaps something like this would work for you? This solution takes a functional approach to your problem, and avoids explict use of the for-loop construct:
var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
Perhaps something like this would work for you? This solution takes a functional approach to your problem, and avoids explict use of the for-loop construct:
var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);var input = [ { id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' },
{ id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: '' } ];
var output = input.map(object => {
return Object.entries(object).reduce((result, entry) => {
let key = entry[0];
let value = entry[1];
if(key.startsWith('mn')) {
value = `updated value for ${ key }`;
}
result[key] = value;
return result;
}, {});
});
console.log(output);answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
answered Nov 20 '18 at 19:36
Dacre DennyDacre Denny
10.9k4929
10.9k4929
add a comment |
add a comment |
1
You can check the name of the key before you modify it.
Does this help? Try it out by running the code snippet.
const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
add a comment |
1
You can check the name of the key before you modify it.
Does this help? Try it out by running the code snippet.
const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
add a comment |
1
1
1
You can check the name of the key before you modify it.
Does this help? Try it out by running the code snippet.
const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
You can check the name of the key before you modify it.
Does this help? Try it out by running the code snippet.
const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);const arr = [{
id: 1,
ip: 'xx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 2,
ip: 'xxx.xxx.xx.xx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
},
{
id: 4,
ip: 'xxx.xxx.xx.xxx',
mn1: '',
mn2: '',
mn3: '',
mn4: '',
mn5: '',
mn6: '',
mn7: ''
}
];
console.log('BEFORE', JSON.stringify(arr, null, 2));
for (const item of arr) {
for (const key of Object.keys(item)) {
if (!key.startsWith('mn')) continue;
// know if the code gets here then it's an `mn` key
// you can do logic here on the key
// and then manipulate the result
item[key] = 'changed';
}
}
console.log('AFTER', arr);answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
answered Nov 20 '18 at 19:32
Rico KahlerRico Kahler
4,51632033
4,51632033
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
add a comment |
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
I think the goal was to avoid for loops
– Dacre Denny
Nov 20 '18 at 19:32
add a comment |
1
You can use Object.entries, Array.prototype.filter, and Array.prototype.forEach to your advantage.
const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)This starts to get verbose if you can't use the latest ECMAScript features, though:
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)If you're stuck on a project without Babel, your best bet may be your original suggestion.
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
add a comment |
1
You can use Object.entries, Array.prototype.filter, and Array.prototype.forEach to your advantage.
const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)This starts to get verbose if you can't use the latest ECMAScript features, though:
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)If you're stuck on a project without Babel, your best bet may be your original suggestion.
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
add a comment |
1
1
1
You can use Object.entries, Array.prototype.filter, and Array.prototype.forEach to your advantage.
const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)This starts to get verbose if you can't use the latest ECMAScript features, though:
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)If you're stuck on a project without Babel, your best bet may be your original suggestion.
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
You can use Object.entries, Array.prototype.filter, and Array.prototype.forEach to your advantage.
const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)This starts to get verbose if you can't use the latest ECMAScript features, though:
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)If you're stuck on a project without Babel, your best bet may be your original suggestion.
var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)const transform = value => `transformed-${value}`;
const arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(obj => {
Object.entries(obj)
.filter(([key]) => key !== "id" && key !== "ip")
.forEach(([key, value]) => (obj[key] = transform(value)));
});
console.log(arr)var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj)
.filter(function(keyValue) {
var key = keyValue[0];
return key !== "id" && key !== "ip";
})
.forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
obj[key] = transform(value);
});
});
console.log(arr)var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)var transform = function(value) { return "transformed-" + value };
var arr = [{ id: "id", ip: "ip", otherKey: "other" }];
arr.forEach(function(obj) {
Object.entries(obj).forEach(function(keyValue) {
var key = keyValue[0],
value = keyValue[1];
if (key !== "id" && key !== "ip") {
obj[key] = transform(value);
}
});
});
console.log(arr)answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
answered Nov 20 '18 at 19:59
Michael HinesMichael Hines
384
384
add a comment |
add a comment |
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2
When you find yourself using variable/key names ending in numbers its a good indication that you probably want an array like
mn[1], mn[2], etc.– Mark Meyer
Nov 20 '18 at 19:26
have you looked at
Object.keys?– Jhecht
Nov 20 '18 at 19:26
You can use
for (var item in obj){ .. }– Spencer Wieczorek
Nov 20 '18 at 19:29
what information do you want to update
mn*keys with?– Dacre Denny
Nov 20 '18 at 19:30