Removing commas from a list and just keeping the elements
$begingroup$
I have the following list. I want to remove all commas and just be left with the elements of the set.
Tuples[{I, l}, 16]
{{I, I, I, I, I, I, I, I, I, I, I, I, I, I, I, I}, {I, I, I, I, I, I,
I, I, I, I, I, I, I, I, I, l}, {I, I, I, I, I, I, I, I, I, I, I, I,
I, I, l, I}, {I, I, I, I, I, I, I, I, I, I, I, I, I, I, l, l}, ....}
I would like something like:
{{IIIIIIIIIIIIIIII}, {IIIIIIIIIIIIIIIl}, {IIIIIIIIIIIIIIlI}, {IIIIIIIIIIIIIIll}, ....}
list-manipulation
$endgroup$
add a comment |
$begingroup$
I have the following list. I want to remove all commas and just be left with the elements of the set.
Tuples[{I, l}, 16]
{{I, I, I, I, I, I, I, I, I, I, I, I, I, I, I, I}, {I, I, I, I, I, I,
I, I, I, I, I, I, I, I, I, l}, {I, I, I, I, I, I, I, I, I, I, I, I,
I, I, l, I}, {I, I, I, I, I, I, I, I, I, I, I, I, I, I, l, l}, ....}
I would like something like:
{{IIIIIIIIIIIIIIII}, {IIIIIIIIIIIIIIIl}, {IIIIIIIIIIIIIIlI}, {IIIIIIIIIIIIIIll}, ....}
list-manipulation
$endgroup$
$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
2
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16I-s
? Maybe knowing the context we could help to solve your initial problem.
$endgroup$
– Kuba♦
yesterday
$begingroup$
doesToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?
$endgroup$
– kglr
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday
add a comment |
$begingroup$
I have the following list. I want to remove all commas and just be left with the elements of the set.
Tuples[{I, l}, 16]
{{I, I, I, I, I, I, I, I, I, I, I, I, I, I, I, I}, {I, I, I, I, I, I,
I, I, I, I, I, I, I, I, I, l}, {I, I, I, I, I, I, I, I, I, I, I, I,
I, I, l, I}, {I, I, I, I, I, I, I, I, I, I, I, I, I, I, l, l}, ....}
I would like something like:
{{IIIIIIIIIIIIIIII}, {IIIIIIIIIIIIIIIl}, {IIIIIIIIIIIIIIlI}, {IIIIIIIIIIIIIIll}, ....}
list-manipulation
$endgroup$
I have the following list. I want to remove all commas and just be left with the elements of the set.
Tuples[{I, l}, 16]
{{I, I, I, I, I, I, I, I, I, I, I, I, I, I, I, I}, {I, I, I, I, I, I,
I, I, I, I, I, I, I, I, I, l}, {I, I, I, I, I, I, I, I, I, I, I, I,
I, I, l, I}, {I, I, I, I, I, I, I, I, I, I, I, I, I, I, l, l}, ....}
I would like something like:
{{IIIIIIIIIIIIIIII}, {IIIIIIIIIIIIIIIl}, {IIIIIIIIIIIIIIlI}, {IIIIIIIIIIIIIIll}, ....}
list-manipulation
list-manipulation
edited yesterday
Peter Mortensen
32827
32827
asked yesterday
A.EA.E
306
306
$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
2
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16I-s
? Maybe knowing the context we could help to solve your initial problem.
$endgroup$
– Kuba♦
yesterday
$begingroup$
doesToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?
$endgroup$
– kglr
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday
add a comment |
$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
2
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16I-s
? Maybe knowing the context we could help to solve your initial problem.
$endgroup$
– Kuba♦
yesterday
$begingroup$
doesToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?
$endgroup$
– kglr
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday
$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
2
2
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16
I-s
? Maybe knowing the context we could help to solve your initial problem.$endgroup$
– Kuba♦
yesterday
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16
I-s
? Maybe knowing the context we could help to solve your initial problem.$endgroup$
– Kuba♦
yesterday
$begingroup$
does
ToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?$endgroup$
– kglr
yesterday
$begingroup$
does
ToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?$endgroup$
– kglr
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Maybe this does what you want?
ToExpression[StringJoin /@ Map[ToString, Tuples[{I, l}, 16], {2}]]
$endgroup$
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
You can also do:
Symbol @* StringJoin /@ Tuples[{"I", "l"}, 16]
% // Short
{IIIIIIIIIIIIIIII, IIIIIIIIIIIIIIIl, IIIIIIIIIIIIIIlI,
IIIIIIIIIIIIIIll, << 65528 >>, llllllllllllllII, llllllllllllllIl, lllllllllllllllI,
llllllllllllllll}
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Maybe this does what you want?
ToExpression[StringJoin /@ Map[ToString, Tuples[{I, l}, 16], {2}]]
$endgroup$
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
Maybe this does what you want?
ToExpression[StringJoin /@ Map[ToString, Tuples[{I, l}, 16], {2}]]
$endgroup$
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
Maybe this does what you want?
ToExpression[StringJoin /@ Map[ToString, Tuples[{I, l}, 16], {2}]]
$endgroup$
Maybe this does what you want?
ToExpression[StringJoin /@ Map[ToString, Tuples[{I, l}, 16], {2}]]
answered yesterday
Henrik SchumacherHenrik Schumacher
51.6k469146
51.6k469146
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
Thank you, indeed what I wanted.
$endgroup$
– A.E
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
$begingroup$
You're welcome.
$endgroup$
– Henrik Schumacher
yesterday
add a comment |
$begingroup$
You can also do:
Symbol @* StringJoin /@ Tuples[{"I", "l"}, 16]
% // Short
{IIIIIIIIIIIIIIII, IIIIIIIIIIIIIIIl, IIIIIIIIIIIIIIlI,
IIIIIIIIIIIIIIll, << 65528 >>, llllllllllllllII, llllllllllllllIl, lllllllllllllllI,
llllllllllllllll}
$endgroup$
add a comment |
$begingroup$
You can also do:
Symbol @* StringJoin /@ Tuples[{"I", "l"}, 16]
% // Short
{IIIIIIIIIIIIIIII, IIIIIIIIIIIIIIIl, IIIIIIIIIIIIIIlI,
IIIIIIIIIIIIIIll, << 65528 >>, llllllllllllllII, llllllllllllllIl, lllllllllllllllI,
llllllllllllllll}
$endgroup$
add a comment |
$begingroup$
You can also do:
Symbol @* StringJoin /@ Tuples[{"I", "l"}, 16]
% // Short
{IIIIIIIIIIIIIIII, IIIIIIIIIIIIIIIl, IIIIIIIIIIIIIIlI,
IIIIIIIIIIIIIIll, << 65528 >>, llllllllllllllII, llllllllllllllIl, lllllllllllllllI,
llllllllllllllll}
$endgroup$
You can also do:
Symbol @* StringJoin /@ Tuples[{"I", "l"}, 16]
% // Short
{IIIIIIIIIIIIIIII, IIIIIIIIIIIIIIIl, IIIIIIIIIIIIIIlI,
IIIIIIIIIIIIIIll, << 65528 >>, llllllllllllllII, llllllllllllllIl, lllllllllllllllI,
llllllllllllllll}
answered yesterday
kglrkglr
181k10200414
181k10200414
add a comment |
add a comment |
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$begingroup$
Can you show us what kind of final result you expect?
$endgroup$
– rafalc
yesterday
$begingroup$
@rafalc sure, please look at edited question
$endgroup$
– A.E
yesterday
2
$begingroup$
While it can be answered it appears to be a very strange request. Why do you need a symbol composed of 16
I-s
? Maybe knowing the context we could help to solve your initial problem.$endgroup$
– Kuba♦
yesterday
$begingroup$
does
ToExpression /@ (StringRiffle[# , {"{", "", "}"}] & /@ Tuples[ToString /@ {I, l}, 16])
give what you need?$endgroup$
– kglr
yesterday
$begingroup$
@kglr I haven't checked since I got the solution from Henrik, yours probably will work too but he beat you to it :)
$endgroup$
– A.E
yesterday