awk + sum all numbers












4















We want to calculate the first numbers that we get from du



du -b /tmp/*

6       /tmp/216c6f99-6671-4865-b8bc-7205f5388752_resources

668669  /tmp/hadoop7887078727316788325.tmp

6       /tmp/hadoop-hdfs

42456   /tmp/hive

32786   /tmp/hsperfdata_hdfs

6       /tmp/hsperfdata_hive

32786   /tmp/hsperfdata_root

262244  /tmp/hsperfdata_yarn


so final sum will be



sum=6+668669+6+42456+32786+6+32786+262244





echo $sum


How we can do it by awk or perl one liners?






linux shell-script awk perl disk-usage







share|improve this question

























  • du -bs /tmp would get you the answer too

    – roaima
    9 hours ago













  • See How can I quickly sum all numbers in a file?

    – glenn jackman
    9 hours ago











  • See also Is there a way to sum up the size of files listed?

    – Jeff Schaller
    9 hours ago


















4















We want to calculate the first numbers that we get from du



du -b /tmp/*

6       /tmp/216c6f99-6671-4865-b8bc-7205f5388752_resources

668669  /tmp/hadoop7887078727316788325.tmp

6       /tmp/hadoop-hdfs

42456   /tmp/hive

32786   /tmp/hsperfdata_hdfs

6       /tmp/hsperfdata_hive

32786   /tmp/hsperfdata_root

262244  /tmp/hsperfdata_yarn


so final sum will be



sum=6+668669+6+42456+32786+6+32786+262244





echo $sum


How we can do it by awk or perl one liners?






linux shell-script awk perl disk-usage







share|improve this question

























  • du -bs /tmp would get you the answer too

    – roaima
    9 hours ago













  • See How can I quickly sum all numbers in a file?

    – glenn jackman
    9 hours ago











  • See also Is there a way to sum up the size of files listed?

    – Jeff Schaller
    9 hours ago
















4












4








4


1






We want to calculate the first numbers that we get from du



du -b /tmp/*

6       /tmp/216c6f99-6671-4865-b8bc-7205f5388752_resources

668669  /tmp/hadoop7887078727316788325.tmp

6       /tmp/hadoop-hdfs

42456   /tmp/hive

32786   /tmp/hsperfdata_hdfs

6       /tmp/hsperfdata_hive

32786   /tmp/hsperfdata_root

262244  /tmp/hsperfdata_yarn


so final sum will be



sum=6+668669+6+42456+32786+6+32786+262244





echo $sum


How we can do it by awk or perl one liners?






linux shell-script awk perl disk-usage







share|improve this question
















We want to calculate the first numbers that we get from du



du -b /tmp/*

6       /tmp/216c6f99-6671-4865-b8bc-7205f5388752_resources

668669  /tmp/hadoop7887078727316788325.tmp

6       /tmp/hadoop-hdfs

42456   /tmp/hive

32786   /tmp/hsperfdata_hdfs

6       /tmp/hsperfdata_hive

32786   /tmp/hsperfdata_root

262244  /tmp/hsperfdata_yarn


so final sum will be



sum=6+668669+6+42456+32786+6+32786+262244





echo $sum


How we can do it by awk or perl one liners?






linux shell-script awk perl disk-usage




linux shell-script awk perl disk-usage






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 9 hours ago









PRY

2,58831026




2,58831026










asked 9 hours ago









yaelyael

2,66422571




2,66422571













  • du -bs /tmp would get you the answer too

    – roaima
    9 hours ago













  • See How can I quickly sum all numbers in a file?

    – glenn jackman
    9 hours ago











  • See also Is there a way to sum up the size of files listed?

    – Jeff Schaller
    9 hours ago





















  • du -bs /tmp would get you the answer too

    – roaima
    9 hours ago













  • See How can I quickly sum all numbers in a file?

    – glenn jackman
    9 hours ago











  • See also Is there a way to sum up the size of files listed?

    – Jeff Schaller
    9 hours ago



















du -bs /tmp would get you the answer too

– roaima
9 hours ago







du -bs /tmp would get you the answer too

– roaima
9 hours ago















See How can I quickly sum all numbers in a file?

– glenn jackman
9 hours ago





See How can I quickly sum all numbers in a file?

– glenn jackman
9 hours ago













See also Is there a way to sum up the size of files listed?

– Jeff Schaller
9 hours ago







See also Is there a way to sum up the size of files listed?

– Jeff Schaller
9 hours ago












3 Answers
3






active

oldest

votes


















11














In AWK:



{ sum += $1 }

END { print sum }


So



du -b /tmp/* | awk '{ sum += $1 } END { print sum }'


Note that the result won’t be correct if the directories under /tmp have subdirectories themselves, because du produces running totals on directories and their children.



du -s will calculate the sum for you correctly (on all subdirectories and files in /tmp, including hidden ones):



du -sb /tmp


and du -c will calculate the sum of the listed directories, correctly too:



du -cb /tmp/*





share|improve this answer

































    3














    It is simple you can use:



     du -b /tmp/* | awk 'BEGIN{i=0} {i=i+$1} END{print i}'


    If you are not using wildcard, if you are using directory name like /tmp, then you need to avoid the last entry because output of du -b /tmp is like:



    size1 file1
    
size2 file2
    
size_total .


    So now you should avoid this last entry, so use:



    du -b /tmp | awk 'BEGIN{i=0} {if( $2 != "." ){i=i+$1}} END{print i}'


    However you can also use -s option, it will calculate the summary for you then you don't need to add the values, just print the last one, i.e.:



    du -s directory





    share|improve this answer





















    • 1





      variables initialize to zero, if you'd like to golf some bytes off :)

      – Jeff Schaller
      9 hours ago



















    1














    You can also produce a total sum of selected files with du -c. This works even if an argument of du is not a directory, what is not the case of du -s:



    $ du -sb file1 file2
    
17  file1
    
18  file2
    

    
$ du -cb file1 file2
    
17  file1
    
18  file2
    
35  total


    BTW, for interactive use I recommend adding -h option instead of -b or any other multiplier of block-size. This will print the size in human readable unit format.



    $ du -ch file1 file2
    
4.0K    file1
    
4.0K    file2
    
8.0K    total





    share|improve this answer























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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      11














      In AWK:



      { sum += $1 }
      
END { print sum }


      So



      du -b /tmp/* | awk '{ sum += $1 } END { print sum }'


      Note that the result won’t be correct if the directories under /tmp have subdirectories themselves, because du produces running totals on directories and their children.



      du -s will calculate the sum for you correctly (on all subdirectories and files in /tmp, including hidden ones):



      du -sb /tmp


      and du -c will calculate the sum of the listed directories, correctly too:



      du -cb /tmp/*





      share|improve this answer






























        11














        In AWK:



        { sum += $1 }
        
END { print sum }


        So



        du -b /tmp/* | awk '{ sum += $1 } END { print sum }'


        Note that the result won’t be correct if the directories under /tmp have subdirectories themselves, because du produces running totals on directories and their children.



        du -s will calculate the sum for you correctly (on all subdirectories and files in /tmp, including hidden ones):



        du -sb /tmp


        and du -c will calculate the sum of the listed directories, correctly too:



        du -cb /tmp/*





        share|improve this answer




























          11












          11








          11







          In AWK:



          { sum += $1 }
          
END { print sum }


          So



          du -b /tmp/* | awk '{ sum += $1 } END { print sum }'


          Note that the result won’t be correct if the directories under /tmp have subdirectories themselves, because du produces running totals on directories and their children.



          du -s will calculate the sum for you correctly (on all subdirectories and files in /tmp, including hidden ones):



          du -sb /tmp


          and du -c will calculate the sum of the listed directories, correctly too:



          du -cb /tmp/*





          share|improve this answer















          In AWK:



          { sum += $1 }
          
END { print sum }


          So



          du -b /tmp/* | awk '{ sum += $1 } END { print sum }'


          Note that the result won’t be correct if the directories under /tmp have subdirectories themselves, because du produces running totals on directories and their children.



          du -s will calculate the sum for you correctly (on all subdirectories and files in /tmp, including hidden ones):



          du -sb /tmp


          and du -c will calculate the sum of the listed directories, correctly too:



          du -cb /tmp/*






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 7 hours ago

























          answered 9 hours ago









          Stephen KittStephen Kitt

          174k24398473




          174k24398473

























              3














              It is simple you can use:



               du -b /tmp/* | awk 'BEGIN{i=0} {i=i+$1} END{print i}'


              If you are not using wildcard, if you are using directory name like /tmp, then you need to avoid the last entry because output of du -b /tmp is like:



              size1 file1
              
size2 file2
              
size_total .


              So now you should avoid this last entry, so use:



              du -b /tmp | awk 'BEGIN{i=0} {if( $2 != "." ){i=i+$1}} END{print i}'


              However you can also use -s option, it will calculate the summary for you then you don't need to add the values, just print the last one, i.e.:



              du -s directory





              share|improve this answer





















              • 1





                variables initialize to zero, if you'd like to golf some bytes off :)

                – Jeff Schaller
                9 hours ago
















              3














              It is simple you can use:



               du -b /tmp/* | awk 'BEGIN{i=0} {i=i+$1} END{print i}'


              If you are not using wildcard, if you are using directory name like /tmp, then you need to avoid the last entry because output of du -b /tmp is like:



              size1 file1
              
size2 file2
              
size_total .


              So now you should avoid this last entry, so use:



              du -b /tmp | awk 'BEGIN{i=0} {if( $2 != "." ){i=i+$1}} END{print i}'


              However you can also use -s option, it will calculate the summary for you then you don't need to add the values, just print the last one, i.e.:



              du -s directory





              share|improve this answer





















              • 1





                variables initialize to zero, if you'd like to golf some bytes off :)

                – Jeff Schaller
                9 hours ago














              3












              3








              3







              It is simple you can use:



               du -b /tmp/* | awk 'BEGIN{i=0} {i=i+$1} END{print i}'


              If you are not using wildcard, if you are using directory name like /tmp, then you need to avoid the last entry because output of du -b /tmp is like:



              size1 file1
              
size2 file2
              
size_total .


              So now you should avoid this last entry, so use:



              du -b /tmp | awk 'BEGIN{i=0} {if( $2 != "." ){i=i+$1}} END{print i}'


              However you can also use -s option, it will calculate the summary for you then you don't need to add the values, just print the last one, i.e.:



              du -s directory





              share|improve this answer















              It is simple you can use:



               du -b /tmp/* | awk 'BEGIN{i=0} {i=i+$1} END{print i}'


              If you are not using wildcard, if you are using directory name like /tmp, then you need to avoid the last entry because output of du -b /tmp is like:



              size1 file1
              
size2 file2
              
size_total .


              So now you should avoid this last entry, so use:



              du -b /tmp | awk 'BEGIN{i=0} {if( $2 != "." ){i=i+$1}} END{print i}'


              However you can also use -s option, it will calculate the summary for you then you don't need to add the values, just print the last one, i.e.:



              du -s directory






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 9 hours ago

























              answered 9 hours ago









              PRYPRY

              2,58831026




              2,58831026








              • 1





                variables initialize to zero, if you'd like to golf some bytes off :)

                – Jeff Schaller
                9 hours ago














              • 1





                variables initialize to zero, if you'd like to golf some bytes off :)

                – Jeff Schaller
                9 hours ago








              1




              1





              variables initialize to zero, if you'd like to golf some bytes off :)

              – Jeff Schaller
              9 hours ago





              variables initialize to zero, if you'd like to golf some bytes off :)

              – Jeff Schaller
              9 hours ago











              1














              You can also produce a total sum of selected files with du -c. This works even if an argument of du is not a directory, what is not the case of du -s:



              $ du -sb file1 file2
              
17  file1
              
18  file2
              

              
$ du -cb file1 file2
              
17  file1
              
18  file2
              
35  total


              BTW, for interactive use I recommend adding -h option instead of -b or any other multiplier of block-size. This will print the size in human readable unit format.



              $ du -ch file1 file2
              
4.0K    file1
              
4.0K    file2
              
8.0K    total





              share|improve this answer




























                1














                You can also produce a total sum of selected files with du -c. This works even if an argument of du is not a directory, what is not the case of du -s:



                $ du -sb file1 file2
                
17  file1
                
18  file2
                

                
$ du -cb file1 file2
                
17  file1
                
18  file2
                
35  total


                BTW, for interactive use I recommend adding -h option instead of -b or any other multiplier of block-size. This will print the size in human readable unit format.



                $ du -ch file1 file2
                
4.0K    file1
                
4.0K    file2
                
8.0K    total





                share|improve this answer


























                  1












                  1








                  1







                  You can also produce a total sum of selected files with du -c. This works even if an argument of du is not a directory, what is not the case of du -s:



                  $ du -sb file1 file2
                  
17  file1
                  
18  file2
                  

                  
$ du -cb file1 file2
                  
17  file1
                  
18  file2
                  
35  total


                  BTW, for interactive use I recommend adding -h option instead of -b or any other multiplier of block-size. This will print the size in human readable unit format.



                  $ du -ch file1 file2
                  
4.0K    file1
                  
4.0K    file2
                  
8.0K    total





                  share|improve this answer













                  You can also produce a total sum of selected files with du -c. This works even if an argument of du is not a directory, what is not the case of du -s:



                  $ du -sb file1 file2
                  
17  file1
                  
18  file2
                  

                  
$ du -cb file1 file2
                  
17  file1
                  
18  file2
                  
35  total


                  BTW, for interactive use I recommend adding -h option instead of -b or any other multiplier of block-size. This will print the size in human readable unit format.



                  $ du -ch file1 file2
                  
4.0K    file1
                  
4.0K    file2
                  
8.0K    total






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 9 hours ago









                  jimmijjimmij

                  32k874108




                  32k874108






























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