geom_raster gives “stripy” results
I am trying to create a raster plot with ggplot2
My data looks like this:
freqData <- data.frame(cells = rep(1:27, each = 101),
frequency = rep(1/seq(1, 1001, 10), 27),
power = rnorm(101*27))
Now, when I do
ggplot(freqData, aes(frequency, cells)) +
geom_raster(aes(fill = power), interpolate = T)
I get this
Interestingly, zooming in shows this:
If I try and define frequency as seq(1, 1001, 10) (i.e. without 1/) then everything works as expected.
I am probably missing something really obvious here, can anyone help?
r ggplot2 raster
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
add a comment |
I am trying to create a raster plot with ggplot2
My data looks like this:
freqData <- data.frame(cells = rep(1:27, each = 101),
frequency = rep(1/seq(1, 1001, 10), 27),
power = rnorm(101*27))
Now, when I do
ggplot(freqData, aes(frequency, cells)) +
geom_raster(aes(fill = power), interpolate = T)
I get this
Interestingly, zooming in shows this:
If I try and define frequency as seq(1, 1001, 10) (i.e. without 1/) then everything works as expected.
I am probably missing something really obvious here, can anyone help?
r ggplot2 raster
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27
add a comment |
I am trying to create a raster plot with ggplot2
My data looks like this:
freqData <- data.frame(cells = rep(1:27, each = 101),
frequency = rep(1/seq(1, 1001, 10), 27),
power = rnorm(101*27))
Now, when I do
ggplot(freqData, aes(frequency, cells)) +
geom_raster(aes(fill = power), interpolate = T)
I get this
Interestingly, zooming in shows this:
If I try and define frequency as seq(1, 1001, 10) (i.e. without 1/) then everything works as expected.
I am probably missing something really obvious here, can anyone help?
r ggplot2 raster
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
I am trying to create a raster plot with ggplot2
My data looks like this:
freqData <- data.frame(cells = rep(1:27, each = 101),
frequency = rep(1/seq(1, 1001, 10), 27),
power = rnorm(101*27))
Now, when I do
ggplot(freqData, aes(frequency, cells)) +
geom_raster(aes(fill = power), interpolate = T)
I get this
Interestingly, zooming in shows this:
If I try and define frequency as seq(1, 1001, 10) (i.e. without 1/) then everything works as expected.
I am probably missing something really obvious here, can anyone help?
r ggplot2 raster
r ggplot2 raster
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
asked Nov 22 '18 at 12:52
niconico
39.6k1268101
39.6k1268101
maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27
add a comment |
maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27
maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27
add a comment |
1 Answer
1
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oldest
votes
Looks like the interpolation only works within a local region.
Vertical lines here are the x points we have. I think raster's main use is for equally spaced x & y data points like the example in https://ggplot2.tidyverse.org/reference/geom_tile.html which has the same difference in the x axis. Your's is a really extreme case as 1/(1,10,20)... quickly converges to 0
dt <- expand.grid(x=c(.01,.05,.15,.5,1),
y=seq(0,5,.1))
dt$power <- rnorm(1:nrow(dt))
ggplot(dt, aes(x, y)) +
geom_raster(aes(fill = power), interpolate = T) +
geom_vline(xintercept = unique(dt$x))
Sorry can't provide a solution with this, other than try to use equally spaced data... hopefully someone has a better answer :)
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
add a comment |
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1 Answer
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Looks like the interpolation only works within a local region.
Vertical lines here are the x points we have. I think raster's main use is for equally spaced x & y data points like the example in https://ggplot2.tidyverse.org/reference/geom_tile.html which has the same difference in the x axis. Your's is a really extreme case as 1/(1,10,20)... quickly converges to 0
dt <- expand.grid(x=c(.01,.05,.15,.5,1),
y=seq(0,5,.1))
dt$power <- rnorm(1:nrow(dt))
ggplot(dt, aes(x, y)) +
geom_raster(aes(fill = power), interpolate = T) +
geom_vline(xintercept = unique(dt$x))
Sorry can't provide a solution with this, other than try to use equally spaced data... hopefully someone has a better answer :)
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
add a comment |
Looks like the interpolation only works within a local region.
Vertical lines here are the x points we have. I think raster's main use is for equally spaced x & y data points like the example in https://ggplot2.tidyverse.org/reference/geom_tile.html which has the same difference in the x axis. Your's is a really extreme case as 1/(1,10,20)... quickly converges to 0
dt <- expand.grid(x=c(.01,.05,.15,.5,1),
y=seq(0,5,.1))
dt$power <- rnorm(1:nrow(dt))
ggplot(dt, aes(x, y)) +
geom_raster(aes(fill = power), interpolate = T) +
geom_vline(xintercept = unique(dt$x))
Sorry can't provide a solution with this, other than try to use equally spaced data... hopefully someone has a better answer :)
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
add a comment |
Looks like the interpolation only works within a local region.
Vertical lines here are the x points we have. I think raster's main use is for equally spaced x & y data points like the example in https://ggplot2.tidyverse.org/reference/geom_tile.html which has the same difference in the x axis. Your's is a really extreme case as 1/(1,10,20)... quickly converges to 0
dt <- expand.grid(x=c(.01,.05,.15,.5,1),
y=seq(0,5,.1))
dt$power <- rnorm(1:nrow(dt))
ggplot(dt, aes(x, y)) +
geom_raster(aes(fill = power), interpolate = T) +
geom_vline(xintercept = unique(dt$x))
Sorry can't provide a solution with this, other than try to use equally spaced data... hopefully someone has a better answer :)
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
Looks like the interpolation only works within a local region.
Vertical lines here are the x points we have. I think raster's main use is for equally spaced x & y data points like the example in https://ggplot2.tidyverse.org/reference/geom_tile.html which has the same difference in the x axis. Your's is a really extreme case as 1/(1,10,20)... quickly converges to 0
dt <- expand.grid(x=c(.01,.05,.15,.5,1),
y=seq(0,5,.1))
dt$power <- rnorm(1:nrow(dt))
ggplot(dt, aes(x, y)) +
geom_raster(aes(fill = power), interpolate = T) +
geom_vline(xintercept = unique(dt$x))
Sorry can't provide a solution with this, other than try to use equally spaced data... hopefully someone has a better answer :)
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
answered Nov 22 '18 at 14:32
Jonny PhelpsJonny Phelps
1,04248
1,04248
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
add a comment |
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
Thank you, Jonny. I thought that was the issue, hopefully, someone can point to an alternative...
– nico
Nov 22 '18 at 15:00
add a comment |
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maybe plot against 1/frequency
– Richard Telford
Nov 22 '18 at 15:38
@RichardTelford yes, as mentioned I can easily plot against period... but I wanted to produce a frequency graph! :)
– nico
Nov 22 '18 at 16:27