For Loop and Sum












2












$begingroup$


I am requested to do a sum of the first fifty positive even numbers by using For loop.
The For loop that I created is 



For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]


The output of this is a list of numbers from 2 to 50 and they are increasing by 2. Now I need these numbers to be sum so I created 



Sum[For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]]


However, it is not a correct input. I am not sure if I should write the Sum inside the For loop.






homework







share|improve this question











$endgroup$








  • 3




    $begingroup$
    If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
    $endgroup$
    – John Doty
    10 hours ago










  • $begingroup$
    If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
    $endgroup$
    – mjw
    8 hours ago












  • $begingroup$
    Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
    $endgroup$
    – MarcoB
    7 hours ago








  • 5




    $begingroup$
    Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
    $endgroup$
    – Henrik Schumacher
    6 hours ago










  • $begingroup$
    Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
    $endgroup$
    – mjw
    3 hours ago
















2












$begingroup$


I am requested to do a sum of the first fifty positive even numbers by using For loop.
The For loop that I created is 



For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]


The output of this is a list of numbers from 2 to 50 and they are increasing by 2. Now I need these numbers to be sum so I created 



Sum[For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]]


However, it is not a correct input. I am not sure if I should write the Sum inside the For loop.






homework







share|improve this question











$endgroup$








  • 3




    $begingroup$
    If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
    $endgroup$
    – John Doty
    10 hours ago










  • $begingroup$
    If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
    $endgroup$
    – mjw
    8 hours ago












  • $begingroup$
    Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
    $endgroup$
    – MarcoB
    7 hours ago








  • 5




    $begingroup$
    Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
    $endgroup$
    – Henrik Schumacher
    6 hours ago










  • $begingroup$
    Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
    $endgroup$
    – mjw
    3 hours ago














2












2








2





$begingroup$


I am requested to do a sum of the first fifty positive even numbers by using For loop.
The For loop that I created is 



For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]


The output of this is a list of numbers from 2 to 50 and they are increasing by 2. Now I need these numbers to be sum so I created 



Sum[For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]]


However, it is not a correct input. I am not sure if I should write the Sum inside the For loop.






homework







share|improve this question











$endgroup$




I am requested to do a sum of the first fifty positive even numbers by using For loop.
The For loop that I created is 



For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]


The output of this is a list of numbers from 2 to 50 and they are increasing by 2. Now I need these numbers to be sum so I created 



Sum[For[natNum = 2, natNum <= 50, natNum = natNum + 2, Print[natNum]]]


However, it is not a correct input. I am not sure if I should write the Sum inside the For loop.






homework




homework






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 7 hours ago









MarcoB

36.6k556112




36.6k556112










asked 10 hours ago









Laura FigueroaLaura Figueroa

111




111








  • 3




    $begingroup$
    If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
    $endgroup$
    – John Doty
    10 hours ago










  • $begingroup$
    If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
    $endgroup$
    – mjw
    8 hours ago












  • $begingroup$
    Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
    $endgroup$
    – MarcoB
    7 hours ago








  • 5




    $begingroup$
    Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
    $endgroup$
    – Henrik Schumacher
    6 hours ago










  • $begingroup$
    Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
    $endgroup$
    – mjw
    3 hours ago














  • 3




    $begingroup$
    If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
    $endgroup$
    – John Doty
    10 hours ago










  • $begingroup$
    If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
    $endgroup$
    – mjw
    8 hours ago












  • $begingroup$
    Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
    $endgroup$
    – MarcoB
    7 hours ago








  • 5




    $begingroup$
    Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
    $endgroup$
    – Henrik Schumacher
    6 hours ago










  • $begingroup$
    Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
    $endgroup$
    – mjw
    3 hours ago








3




3




$begingroup$
If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
$endgroup$
– John Doty
10 hours ago




$begingroup$
If this is a class assignment, I'd suggest withdrawing from the class. For loops are almost never a good way to do anything in Mathematica.
$endgroup$
– John Doty
10 hours ago












$begingroup$
If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
$endgroup$
– mjw
8 hours ago






$begingroup$
If you want the first 50 positive even numbers, I believe that is {2, 4, ..., 100}. The sum is (2+100) + (4+98) + ... + (50 + 52) = 102 * 25 = 2550.
$endgroup$
– mjw
8 hours ago














$begingroup$
Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
$endgroup$
– MarcoB
7 hours ago






$begingroup$
Total@Range[2, 2*50, 2] would be pretty direct. Note also that Print prints its arguments, but does not return them (in fact, it returns Null).
$endgroup$
– MarcoB
7 hours ago






5




5




$begingroup$
Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
$endgroup$
– Henrik Schumacher
6 hours ago




$begingroup$
Since the days of Carl Friedrich Gauß we know that using a For loop to compute 50 * 51 is a pretty bad idea....
$endgroup$
– Henrik Schumacher
6 hours ago












$begingroup$
Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
$endgroup$
– mjw
3 hours ago




$begingroup$
Is it the first fifty that you want, or is it {2, 4, ..., 50}? The original question had both.
$endgroup$
– mjw
3 hours ago










2 Answers
2






active

oldest

votes


















8












$begingroup$

Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:



rslt = 0;

For[i = 0, i <= 50, i += 2, rslt += i];

rslt


And here's how someone with some familiarity with Mathematica might write it



Plus @@ Range[25]*2


Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?






share|improve this answer









$endgroup$









  • 2




    $begingroup$
    +1 for the first sentence.
    $endgroup$
    – Henrik Schumacher
    7 hours ago



















3












$begingroup$

The first fifty positive integers can be computed with Table:



Q = 0; (* Initialization *)

T = Table[Q + k, {k, 2 Range[50]}]


output of the above code



We can sum up the values of T with Sum:



Sum[T[[k]], {k, Range[50]}]


2550






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
    $endgroup$
    – MarcoB
    7 hours ago










  • $begingroup$
    Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
    $endgroup$
    – mjw
    6 hours ago










  • $begingroup$
    I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
    $endgroup$
    – MarcoB
    5 hours ago












  • $begingroup$
    This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
    $endgroup$
    – mjw
    4 hours ago











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192541%2ffor-loop-and-sum%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









8












$begingroup$

Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:



rslt = 0;

For[i = 0, i <= 50, i += 2, rslt += i];

rslt


And here's how someone with some familiarity with Mathematica might write it



Plus @@ Range[25]*2


Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?






share|improve this answer









$endgroup$









  • 2




    $begingroup$
    +1 for the first sentence.
    $endgroup$
    – Henrik Schumacher
    7 hours ago
















8












$begingroup$

Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:



rslt = 0;

For[i = 0, i <= 50, i += 2, rslt += i];

rslt


And here's how someone with some familiarity with Mathematica might write it



Plus @@ Range[25]*2


Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?






share|improve this answer









$endgroup$









  • 2




    $begingroup$
    +1 for the first sentence.
    $endgroup$
    – Henrik Schumacher
    7 hours ago














8












8








8





$begingroup$

Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:



rslt = 0;

For[i = 0, i <= 50, i += 2, rslt += i];

rslt


And here's how someone with some familiarity with Mathematica might write it



Plus @@ Range[25]*2


Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?






share|improve this answer









$endgroup$



Anyone asking you to write For loops in Mathematica for such a problem is a dolt. Nevertheless, here's how you might do that:



rslt = 0;

For[i = 0, i <= 50, i += 2, rslt += i];

rslt


And here's how someone with some familiarity with Mathematica might write it



Plus @@ Range[25]*2


Now, spend the time you were going to waste writing a For loop by reading the answers to this question Why should I avoid the For loop in Mathematica?







share|improve this answer












share|improve this answer



share|improve this answer










answered 10 hours ago









High Performance MarkHigh Performance Mark

578411




578411








  • 2




    $begingroup$
    +1 for the first sentence.
    $endgroup$
    – Henrik Schumacher
    7 hours ago














  • 2




    $begingroup$
    +1 for the first sentence.
    $endgroup$
    – Henrik Schumacher
    7 hours ago








2




2




$begingroup$
+1 for the first sentence.
$endgroup$
– Henrik Schumacher
7 hours ago




$begingroup$
+1 for the first sentence.
$endgroup$
– Henrik Schumacher
7 hours ago











3












$begingroup$

The first fifty positive integers can be computed with Table:



Q = 0; (* Initialization *)

T = Table[Q + k, {k, 2 Range[50]}]


output of the above code



We can sum up the values of T with Sum:



Sum[T[[k]], {k, Range[50]}]


2550






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
    $endgroup$
    – MarcoB
    7 hours ago










  • $begingroup$
    Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
    $endgroup$
    – mjw
    6 hours ago










  • $begingroup$
    I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
    $endgroup$
    – MarcoB
    5 hours ago












  • $begingroup$
    This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
    $endgroup$
    – mjw
    4 hours ago
















3












$begingroup$

The first fifty positive integers can be computed with Table:



Q = 0; (* Initialization *)

T = Table[Q + k, {k, 2 Range[50]}]


output of the above code



We can sum up the values of T with Sum:



Sum[T[[k]], {k, Range[50]}]


2550






share|improve this answer











$endgroup$









  • 1




    $begingroup$
    Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
    $endgroup$
    – MarcoB
    7 hours ago










  • $begingroup$
    Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
    $endgroup$
    – mjw
    6 hours ago










  • $begingroup$
    I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
    $endgroup$
    – MarcoB
    5 hours ago












  • $begingroup$
    This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
    $endgroup$
    – mjw
    4 hours ago














3












3








3





$begingroup$

The first fifty positive integers can be computed with Table:



Q = 0; (* Initialization *)

T = Table[Q + k, {k, 2 Range[50]}]


output of the above code



We can sum up the values of T with Sum:



Sum[T[[k]], {k, Range[50]}]


2550






share|improve this answer











$endgroup$



The first fifty positive integers can be computed with Table:



Q = 0; (* Initialization *)

T = Table[Q + k, {k, 2 Range[50]}]


output of the above code



We can sum up the values of T with Sum:



Sum[T[[k]], {k, Range[50]}]


2550







share|improve this answer














share|improve this answer



share|improve this answer








edited 3 hours ago









Conor O'Brien

1034




1034










answered 8 hours ago









mjwmjw

3867




3867








  • 1




    $begingroup$
    Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
    $endgroup$
    – MarcoB
    7 hours ago










  • $begingroup$
    Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
    $endgroup$
    – mjw
    6 hours ago










  • $begingroup$
    I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
    $endgroup$
    – MarcoB
    5 hours ago












  • $begingroup$
    This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
    $endgroup$
    – mjw
    4 hours ago














  • 1




    $begingroup$
    Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
    $endgroup$
    – MarcoB
    7 hours ago










  • $begingroup$
    Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
    $endgroup$
    – mjw
    6 hours ago










  • $begingroup$
    I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
    $endgroup$
    – MarcoB
    5 hours ago












  • $begingroup$
    This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
    $endgroup$
    – mjw
    4 hours ago








1




1




$begingroup$
Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
$endgroup$
– MarcoB
7 hours ago




$begingroup$
Perhaps better / more idiomatic than your Sum approach would be using Total[T] or Plus@@T.
$endgroup$
– MarcoB
7 hours ago












$begingroup$
Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
$endgroup$
– mjw
6 hours ago




$begingroup$
Thank you! I was looking for something like Total and I saw the Plus posting above, but haven't yet learned about @@ and such. I would have thought Map might work here (it does not). Anyway, yes Total[T] and Plus@@T are simpler and more elegant!
$endgroup$
– mjw
6 hours ago












$begingroup$
I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
$endgroup$
– MarcoB
5 hours ago






$begingroup$
I was a latecomer to @@ as well. When I was learning about it, it helped me to think about it as a way of "swapping heads" of expressions. So for instance, if you have {1, 2, 3}, its FullForm would be List[1, 2, 3]. If you then Apply Plus to it, i.e. Plus@@, you swap the Listhead for a Plus head, to give Plus[1, 2, 3]. Although it may seem like a niche application at first, once you get used to it, it is tremendously useful!
$endgroup$
– MarcoB
5 hours ago














$begingroup$
This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
$endgroup$
– mjw
4 hours ago




$begingroup$
This is great, thank you! Just as I learned not to use For loops (especially on this Forum), and to Do use Do, I'll look for opportunities to Apply @@.
$endgroup$
– mjw
4 hours ago


















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematica Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid …



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f192541%2ffor-loop-and-sum%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

"Incorrect syntax near the keyword 'ON'. (on update cascade, on delete cascade,)

Image
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box; } 2 total noob sorry any help greatly appreciated. I keep getting this "Incorrect syntax near the keyword 'ON'." heres my codes code one CREATE TABLE supplier ( supplierID INT PRIMARY KEY, ISBN INT FOREIGN KEY REFERENCES book(ISBN), price DECIMAL (5,2), ON UPDATE CASCADE, ON DELETE CASCADE, ); code two CREATE TABLE orders ( orderID INT PRIMARY KEY, customerID INT FOREIGN KEY REFERENCES customer(customerID), ISBN INT FOREIGN KEY REFERENCES book(ISBN), orderDate date, ON UPDATE CASCADE, ON DELETE CASCADE, ); Ive run out of stuff to try other than dumbing it down to uselessness.
Read more

Alcedinidae

Image
Alcedinidae Martin-pêcheur à dos bleu ( Alcedo azurea ) Classification (COI) Règne Animalia Embranchement Chordata Sous-embr. Vertebrata Classe Aves Ordre Coraciiformes Famille Alcedinidae Rafinesque, 1815 Les Alcédinidés ou Alcedinidae forment une famille d'oiseaux plus connus sous les noms de martins-pêcheurs et martins-chasseurs. Sommaire 1 Description 2 Répartition et habitat 3 Systématique 3.1 Liste alphabétique des genres 3.2 Liste des espèces 4 Chez les Anciens : l'alcyon 4.1 Étymologie (Littré) 4.2 Oiseau « fabuleux » ? 5 Notes 6 Articles connexes 7 Liens externes 7.1 Bibliographie Description | Ce sont des oiseaux compacts de taille petite à moyenne (10 à 46 cm), au bec droit et long, en forme de poignard. Leurs pattes sont courtes, et ils portent un plumage aux couleurs vives. Répartition et habitat | Cosmopolites, ils fréquentent surtout
Read more

RAC Tourist Trophy

Image
Pour les articles homonymes, voir Tourist Trophy. Le RAC Tourist Trophy est une course automobile organisée par le Royal Automobile Club d'Angleterre. Créée en 1905, cette course a fait partie des épreuves comptant pour le championnat du monde des voitures de sport entre 1953 et 1955, en 1958 et 1959, et entre 1962 et 1965. Après une interruption de 17 ans (l'épreuve s'arrête après 1988), le RAC Tourist Trophy reprend en 2005 sous l'égide de la FIA GT. Palmarès | John Napier sur Arrol-Johnston, vainqueur du premier RAC Tourist Trophy, en 1905. L'honorable C.S. Rolls, vainqueur du RAC Tourist Trophy 1906. Ernest Curtis, sur Rover 20 hp, vainqueur du RAC Tourist Trophy 1907. William Watson, vainqueur du RAC Tourist Trophy 1908. Kenelm Lee Guinness, vainqueur du RAC Tourist Trophy 1914 sur Sunbeam. Départ du RAC Tourist Trophy 1928. Louis Gérard, vainqueur du RAC Tourist Trophy 1938 sur Delage. Année Circuit Vainqueur
Read more