Strange plot created based on two numpy arrays and matplotlib
Now I just want to plot a line graph based on two numpy arrays. My x and y are both two (150,1) arrays. After running the following code:
plt.plot(x,y)
What I get is:
Line graph based on two numpy arrays
Hence I am so confused. What do those connected lines represent? I just want one line which goes through all of the points. Any help would be appreciated!
For the dataset, X is just a fixed (150,1) numpy array and y is computed based on the following polynomial function:
def PolyCoefficients(x, coeffs):
""" Returns a polynomial for ``x`` values for the ``coeffs`` provided.
The coefficients must be in ascending order (``x**0`` to ``x**o``).
"""
o = len(coeffs)
y =
for i in range(len(x)):
value = 0
for j in range(o):
value += coeffs[j]*x[i]**j
y.append(value)
return y
The coefficients have been computed and what I want is just a line go through each point of (x,y)
python numpy matplotlib
edited Nov 23 '18 at 7:08
Joe
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
add a comment |
Now I just want to plot a line graph based on two numpy arrays. My x and y are both two (150,1) arrays. After running the following code:
plt.plot(x,y)
What I get is:
Line graph based on two numpy arrays
Hence I am so confused. What do those connected lines represent? I just want one line which goes through all of the points. Any help would be appreciated!
For the dataset, X is just a fixed (150,1) numpy array and y is computed based on the following polynomial function:
def PolyCoefficients(x, coeffs):
""" Returns a polynomial for ``x`` values for the ``coeffs`` provided.
The coefficients must be in ascending order (``x**0`` to ``x**o``).
"""
o = len(coeffs)
y =
for i in range(len(x)):
value = 0
for j in range(o):
value += coeffs[j]*x[i]**j
y.append(value)
return y
The coefficients have been computed and what I want is just a line go through each point of (x,y)
python numpy matplotlib
edited Nov 23 '18 at 7:08
Joe
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
add a comment |
Now I just want to plot a line graph based on two numpy arrays. My x and y are both two (150,1) arrays. After running the following code:
plt.plot(x,y)
What I get is:
Line graph based on two numpy arrays
Hence I am so confused. What do those connected lines represent? I just want one line which goes through all of the points. Any help would be appreciated!
For the dataset, X is just a fixed (150,1) numpy array and y is computed based on the following polynomial function:
def PolyCoefficients(x, coeffs):
""" Returns a polynomial for ``x`` values for the ``coeffs`` provided.
The coefficients must be in ascending order (``x**0`` to ``x**o``).
"""
o = len(coeffs)
y =
for i in range(len(x)):
value = 0
for j in range(o):
value += coeffs[j]*x[i]**j
y.append(value)
return y
The coefficients have been computed and what I want is just a line go through each point of (x,y)
python numpy matplotlib
edited Nov 23 '18 at 7:08
Joe
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
Now I just want to plot a line graph based on two numpy arrays. My x and y are both two (150,1) arrays. After running the following code:
plt.plot(x,y)
What I get is:
Line graph based on two numpy arrays
Hence I am so confused. What do those connected lines represent? I just want one line which goes through all of the points. Any help would be appreciated!
For the dataset, X is just a fixed (150,1) numpy array and y is computed based on the following polynomial function:
def PolyCoefficients(x, coeffs):
""" Returns a polynomial for ``x`` values for the ``coeffs`` provided.
The coefficients must be in ascending order (``x**0`` to ``x**o``).
"""
o = len(coeffs)
y =
for i in range(len(x)):
value = 0
for j in range(o):
value += coeffs[j]*x[i]**j
y.append(value)
return y
The coefficients have been computed and what I want is just a line go through each point of (x,y)
python numpy matplotlib
python numpy matplotlib
edited Nov 23 '18 at 7:08
Joe
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
edited Nov 23 '18 at 7:08
Joe
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
edited Nov 23 '18 at 7:08
Joe
6,11421630
edited Nov 23 '18 at 7:08
Joe
6,11421630
edited Nov 23 '18 at 7:08
Joe
6,11421630
6,11421630
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
asked Nov 23 '18 at 6:50
Bright ChangBright Chang
227
227
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The pairs of x and y represent the points on your graph. With plt.plot() you join the points with a line. If the array x is not in order, what you have is a line that goes back and forward across the graph. To avoid this you should order the x array, and the y accordly. Try with:
new_x, new_y = zip(*sorted(zip(x, y)))
plt.plot(new_x,new_y)
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The pairs of x and y represent the points on your graph. With plt.plot() you join the points with a line. If the array x is not in order, what you have is a line that goes back and forward across the graph. To avoid this you should order the x array, and the y accordly. Try with:
new_x, new_y = zip(*sorted(zip(x, y)))
plt.plot(new_x,new_y)
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
add a comment |
The pairs of x and y represent the points on your graph. With plt.plot() you join the points with a line. If the array x is not in order, what you have is a line that goes back and forward across the graph. To avoid this you should order the x array, and the y accordly. Try with:
new_x, new_y = zip(*sorted(zip(x, y)))
plt.plot(new_x,new_y)
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
add a comment |
The pairs of x and y represent the points on your graph. With plt.plot() you join the points with a line. If the array x is not in order, what you have is a line that goes back and forward across the graph. To avoid this you should order the x array, and the y accordly. Try with:
new_x, new_y = zip(*sorted(zip(x, y)))
plt.plot(new_x,new_y)
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
The pairs of x and y represent the points on your graph. With plt.plot() you join the points with a line. If the array x is not in order, what you have is a line that goes back and forward across the graph. To avoid this you should order the x array, and the y accordly. Try with:
new_x, new_y = zip(*sorted(zip(x, y)))
plt.plot(new_x,new_y)
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
edited Nov 23 '18 at 7:03
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
answered Nov 23 '18 at 6:53
JoeJoe
6,11421630
6,11421630
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
add a comment |
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
Thank you for your answer. But actually my x is fixed and y is just the output from a polynomial function based on x. The coefficients have already been computed... Does the order of these two arrays change during the computation?
– Bright Chang
Nov 23 '18 at 6:58
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
If you have just these 2 lists, order them for the graph. I've added some code to the answer, try it and see if it works
– Joe
Nov 23 '18 at 7:03
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
You are welcome, dont forget to acecpt the answer :) meta.stackexchange.com/questions/5234/…
– Joe
Nov 23 '18 at 7:06
add a comment |
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