how to return different things in function in Julia
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Like the simplified function below, if b<c then how can I get the result "No"?
function o(b,c)
if b>=c
return b,c,b+c
else
return "No"
end
end
b = 3
c = 4
k,h,l = o(b,c)
julia
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
add a comment |
Like the simplified function below, if b<c then how can I get the result "No"?
function o(b,c)
if b>=c
return b,c,b+c
else
return "No"
end
end
b = 3
c = 4
k,h,l = o(b,c)
julia
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
3
just writex = o(b,c)' and you will get a string"No"` or a tuple having three elements.
– Bogumił Kamiński
Nov 23 '18 at 20:29
add a comment |
Like the simplified function below, if b<c then how can I get the result "No"?
function o(b,c)
if b>=c
return b,c,b+c
else
return "No"
end
end
b = 3
c = 4
k,h,l = o(b,c)
julia
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
Like the simplified function below, if b<c then how can I get the result "No"?
function o(b,c)
if b>=c
return b,c,b+c
else
return "No"
end
end
b = 3
c = 4
k,h,l = o(b,c)
julia
julia
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
asked Nov 23 '18 at 19:41
Jiayan YangJiayan Yang
366
366
3
just writex = o(b,c)' and you will get a string"No"` or a tuple having three elements.
– Bogumił Kamiński
Nov 23 '18 at 20:29
add a comment |
3
just writex = o(b,c)' and you will get a string"No"` or a tuple having three elements.
– Bogumił Kamiński
Nov 23 '18 at 20:29
3
3
just write
x = o(b,c)' and you will get a string "No"` or a tuple having three elements.– Bogumił Kamiński
Nov 23 '18 at 20:29
just write
x = o(b,c)' and you will get a string "No"` or a tuple having three elements.– Bogumił Kamiński
Nov 23 '18 at 20:29
add a comment |
1 Answer
1
active
oldest
votes
The real problem is that you are returning two completely different things. In one case 3 different variables assigned to integers, in the other case 1 string.
The function is actually working here. The specific error you get is because you are trying to assign 3 variables to one string. When you assign multiple variables to a string, julia actually splits the string up into characters and assign a character to each variable, but your string is only 2 characters long and you are assigning 3 variables.
You should try and have your function return objects of the same type, or at the least the same number of variables. If you insist on getting this function to work in something resembling it's current form then you could do something like this
function o(b,c)
if b>=c
return [b,c,b+c]
else
return "No"
end
end
b = 5
c = 4
result = o(b,c)
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The real problem is that you are returning two completely different things. In one case 3 different variables assigned to integers, in the other case 1 string.
The function is actually working here. The specific error you get is because you are trying to assign 3 variables to one string. When you assign multiple variables to a string, julia actually splits the string up into characters and assign a character to each variable, but your string is only 2 characters long and you are assigning 3 variables.
You should try and have your function return objects of the same type, or at the least the same number of variables. If you insist on getting this function to work in something resembling it's current form then you could do something like this
function o(b,c)
if b>=c
return [b,c,b+c]
else
return "No"
end
end
b = 5
c = 4
result = o(b,c)
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
add a comment |
The real problem is that you are returning two completely different things. In one case 3 different variables assigned to integers, in the other case 1 string.
The function is actually working here. The specific error you get is because you are trying to assign 3 variables to one string. When you assign multiple variables to a string, julia actually splits the string up into characters and assign a character to each variable, but your string is only 2 characters long and you are assigning 3 variables.
You should try and have your function return objects of the same type, or at the least the same number of variables. If you insist on getting this function to work in something resembling it's current form then you could do something like this
function o(b,c)
if b>=c
return [b,c,b+c]
else
return "No"
end
end
b = 5
c = 4
result = o(b,c)
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
add a comment |
The real problem is that you are returning two completely different things. In one case 3 different variables assigned to integers, in the other case 1 string.
The function is actually working here. The specific error you get is because you are trying to assign 3 variables to one string. When you assign multiple variables to a string, julia actually splits the string up into characters and assign a character to each variable, but your string is only 2 characters long and you are assigning 3 variables.
You should try and have your function return objects of the same type, or at the least the same number of variables. If you insist on getting this function to work in something resembling it's current form then you could do something like this
function o(b,c)
if b>=c
return [b,c,b+c]
else
return "No"
end
end
b = 5
c = 4
result = o(b,c)
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
The real problem is that you are returning two completely different things. In one case 3 different variables assigned to integers, in the other case 1 string.
The function is actually working here. The specific error you get is because you are trying to assign 3 variables to one string. When you assign multiple variables to a string, julia actually splits the string up into characters and assign a character to each variable, but your string is only 2 characters long and you are assigning 3 variables.
You should try and have your function return objects of the same type, or at the least the same number of variables. If you insist on getting this function to work in something resembling it's current form then you could do something like this
function o(b,c)
if b>=c
return [b,c,b+c]
else
return "No"
end
end
b = 5
c = 4
result = o(b,c)
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
answered Nov 25 '18 at 0:30
chasmanichasmani
1,11711020
1,11711020
add a comment |
add a comment |
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3
just write
x = o(b,c)' and you will get a string"No"` or a tuple having three elements.– Bogumił Kamiński
Nov 23 '18 at 20:29