Delete ALL custom cell styles EXCEL











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4
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Is it possible to delete all the custom cell styles in a workbook ?



Without having to delete them all one by time.



enter image description here










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  • Very easy with VBA
    – Gary's Student
    Feb 1 at 16:53















up vote
4
down vote

favorite
3












Is it possible to delete all the custom cell styles in a workbook ?



Without having to delete them all one by time.



enter image description here










share|improve this question
























  • Very easy with VBA
    – Gary's Student
    Feb 1 at 16:53













up vote
4
down vote

favorite
3









up vote
4
down vote

favorite
3






3





Is it possible to delete all the custom cell styles in a workbook ?



Without having to delete them all one by time.



enter image description here










share|improve this question















Is it possible to delete all the custom cell styles in a workbook ?



Without having to delete them all one by time.



enter image description here







microsoft-excel microsoft-excel-2010 vba styles






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edited Nov 23 at 14:47

























asked Feb 1 at 16:46









PeterH

3,14132245




3,14132245












  • Very easy with VBA
    – Gary's Student
    Feb 1 at 16:53


















  • Very easy with VBA
    – Gary's Student
    Feb 1 at 16:53
















Very easy with VBA
– Gary's Student
Feb 1 at 16:53




Very easy with VBA
– Gary's Student
Feb 1 at 16:53










2 Answers
2






active

oldest

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up vote
5
down vote













Try this small VBA macro:



Sub StyleKiller()
Dim N As Long, i As Long

With ActiveWorkbook
N = .Styles.Count
For i = N To 1 Step -1
If Not .Styles(i).BuiltIn Then .Styles(i).Delete
Next i
End With
End Sub


This resolves the Builtin vs Custom issue. Note we run the loop backwards to avoid corrupting the loop index.






share|improve this answer






























    up vote
    2
    down vote













    Ok, this wasn't as hard to do as I first thought.



    Bit messy as I don't often use vba; but this code will roll back to just the default styles:



    Sub DefaultStyles()
    Dim MyBook As Workbook
    Dim tempBook As Workbook
    Dim CurStyle As Style
    Set MyBook = ActiveWorkbook
    On Error Resume Next
    For Each CurStyle In MyBook.Styles
    Select Case CurStyle.Name
    Case "20% - Accent1", "20% - Accent2", _
    "20% - Accent3", "20% - Accent4", "20% - Accent5", "20% - Accent6", _
    "40% - Accent1", "40% - Accent2", "40% - Accent3", "40% - Accent4", _
    "40% - Accent5", "40% - Accent6", "60% - Accent1", "60% - Accent2", _
    "60% - Accent3", "60% - Accent4", "60% - Accent5", "60% - Accent6", _
    "Accent1", "Accent2", "Accent3", "Accent4", "Accent5", "Accent6", _
    "Bad", "Calculation", "Check Cell", "Comma", "Comma [0]", "Currency", _
    "Currency [0]", "Explanatory Text", "Good", "Heading 1", "Heading 2", _
    "Heading 3", "Heading 4", "Input", "Linked Cell", "Neutral", "Normal", _
    "Note", "Output", "Percent", "Title", "Total", "Warning Text"
    Case Else
    CurStyle.Delete
    End Select
    Next CurStyle
    Set tempBook = Workbooks.Add
    Application.DisplayAlerts = False
    MyBook.Styles.Merge Workbook:=tempBook
    Application.DisplayAlerts = True
    tempBook.Close
    End Sub





    share|improve this answer























    • Actually I like the way you loop over Styles rather than my looping over an index.
      – Gary's Student
      Feb 1 at 17:07










    • Will have problems here, deleting a collection forwards.
      – AJD
      Jul 6 at 8:03










    • @AJD Hi, thanks for your comment, what problems could be caused from this ?
      – PeterH
      Jul 6 at 9:16










    • @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
      – AJD
      Jul 6 at 21:25










    • @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
      – PeterH
      Jul 9 at 7:09











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    2 Answers
    2






    active

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    2 Answers
    2






    active

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    active

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    up vote
    5
    down vote













    Try this small VBA macro:



    Sub StyleKiller()
    Dim N As Long, i As Long

    With ActiveWorkbook
    N = .Styles.Count
    For i = N To 1 Step -1
    If Not .Styles(i).BuiltIn Then .Styles(i).Delete
    Next i
    End With
    End Sub


    This resolves the Builtin vs Custom issue. Note we run the loop backwards to avoid corrupting the loop index.






    share|improve this answer



























      up vote
      5
      down vote













      Try this small VBA macro:



      Sub StyleKiller()
      Dim N As Long, i As Long

      With ActiveWorkbook
      N = .Styles.Count
      For i = N To 1 Step -1
      If Not .Styles(i).BuiltIn Then .Styles(i).Delete
      Next i
      End With
      End Sub


      This resolves the Builtin vs Custom issue. Note we run the loop backwards to avoid corrupting the loop index.






      share|improve this answer

























        up vote
        5
        down vote










        up vote
        5
        down vote









        Try this small VBA macro:



        Sub StyleKiller()
        Dim N As Long, i As Long

        With ActiveWorkbook
        N = .Styles.Count
        For i = N To 1 Step -1
        If Not .Styles(i).BuiltIn Then .Styles(i).Delete
        Next i
        End With
        End Sub


        This resolves the Builtin vs Custom issue. Note we run the loop backwards to avoid corrupting the loop index.






        share|improve this answer














        Try this small VBA macro:



        Sub StyleKiller()
        Dim N As Long, i As Long

        With ActiveWorkbook
        N = .Styles.Count
        For i = N To 1 Step -1
        If Not .Styles(i).BuiltIn Then .Styles(i).Delete
        Next i
        End With
        End Sub


        This resolves the Builtin vs Custom issue. Note we run the loop backwards to avoid corrupting the loop index.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Oct 1 at 12:54









        kurast

        316213




        316213










        answered Feb 1 at 17:00









        Gary's Student

        13.2k31729




        13.2k31729
























            up vote
            2
            down vote













            Ok, this wasn't as hard to do as I first thought.



            Bit messy as I don't often use vba; but this code will roll back to just the default styles:



            Sub DefaultStyles()
            Dim MyBook As Workbook
            Dim tempBook As Workbook
            Dim CurStyle As Style
            Set MyBook = ActiveWorkbook
            On Error Resume Next
            For Each CurStyle In MyBook.Styles
            Select Case CurStyle.Name
            Case "20% - Accent1", "20% - Accent2", _
            "20% - Accent3", "20% - Accent4", "20% - Accent5", "20% - Accent6", _
            "40% - Accent1", "40% - Accent2", "40% - Accent3", "40% - Accent4", _
            "40% - Accent5", "40% - Accent6", "60% - Accent1", "60% - Accent2", _
            "60% - Accent3", "60% - Accent4", "60% - Accent5", "60% - Accent6", _
            "Accent1", "Accent2", "Accent3", "Accent4", "Accent5", "Accent6", _
            "Bad", "Calculation", "Check Cell", "Comma", "Comma [0]", "Currency", _
            "Currency [0]", "Explanatory Text", "Good", "Heading 1", "Heading 2", _
            "Heading 3", "Heading 4", "Input", "Linked Cell", "Neutral", "Normal", _
            "Note", "Output", "Percent", "Title", "Total", "Warning Text"
            Case Else
            CurStyle.Delete
            End Select
            Next CurStyle
            Set tempBook = Workbooks.Add
            Application.DisplayAlerts = False
            MyBook.Styles.Merge Workbook:=tempBook
            Application.DisplayAlerts = True
            tempBook.Close
            End Sub





            share|improve this answer























            • Actually I like the way you loop over Styles rather than my looping over an index.
              – Gary's Student
              Feb 1 at 17:07










            • Will have problems here, deleting a collection forwards.
              – AJD
              Jul 6 at 8:03










            • @AJD Hi, thanks for your comment, what problems could be caused from this ?
              – PeterH
              Jul 6 at 9:16










            • @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
              – AJD
              Jul 6 at 21:25










            • @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
              – PeterH
              Jul 9 at 7:09















            up vote
            2
            down vote













            Ok, this wasn't as hard to do as I first thought.



            Bit messy as I don't often use vba; but this code will roll back to just the default styles:



            Sub DefaultStyles()
            Dim MyBook As Workbook
            Dim tempBook As Workbook
            Dim CurStyle As Style
            Set MyBook = ActiveWorkbook
            On Error Resume Next
            For Each CurStyle In MyBook.Styles
            Select Case CurStyle.Name
            Case "20% - Accent1", "20% - Accent2", _
            "20% - Accent3", "20% - Accent4", "20% - Accent5", "20% - Accent6", _
            "40% - Accent1", "40% - Accent2", "40% - Accent3", "40% - Accent4", _
            "40% - Accent5", "40% - Accent6", "60% - Accent1", "60% - Accent2", _
            "60% - Accent3", "60% - Accent4", "60% - Accent5", "60% - Accent6", _
            "Accent1", "Accent2", "Accent3", "Accent4", "Accent5", "Accent6", _
            "Bad", "Calculation", "Check Cell", "Comma", "Comma [0]", "Currency", _
            "Currency [0]", "Explanatory Text", "Good", "Heading 1", "Heading 2", _
            "Heading 3", "Heading 4", "Input", "Linked Cell", "Neutral", "Normal", _
            "Note", "Output", "Percent", "Title", "Total", "Warning Text"
            Case Else
            CurStyle.Delete
            End Select
            Next CurStyle
            Set tempBook = Workbooks.Add
            Application.DisplayAlerts = False
            MyBook.Styles.Merge Workbook:=tempBook
            Application.DisplayAlerts = True
            tempBook.Close
            End Sub





            share|improve this answer























            • Actually I like the way you loop over Styles rather than my looping over an index.
              – Gary's Student
              Feb 1 at 17:07










            • Will have problems here, deleting a collection forwards.
              – AJD
              Jul 6 at 8:03










            • @AJD Hi, thanks for your comment, what problems could be caused from this ?
              – PeterH
              Jul 6 at 9:16










            • @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
              – AJD
              Jul 6 at 21:25










            • @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
              – PeterH
              Jul 9 at 7:09













            up vote
            2
            down vote










            up vote
            2
            down vote









            Ok, this wasn't as hard to do as I first thought.



            Bit messy as I don't often use vba; but this code will roll back to just the default styles:



            Sub DefaultStyles()
            Dim MyBook As Workbook
            Dim tempBook As Workbook
            Dim CurStyle As Style
            Set MyBook = ActiveWorkbook
            On Error Resume Next
            For Each CurStyle In MyBook.Styles
            Select Case CurStyle.Name
            Case "20% - Accent1", "20% - Accent2", _
            "20% - Accent3", "20% - Accent4", "20% - Accent5", "20% - Accent6", _
            "40% - Accent1", "40% - Accent2", "40% - Accent3", "40% - Accent4", _
            "40% - Accent5", "40% - Accent6", "60% - Accent1", "60% - Accent2", _
            "60% - Accent3", "60% - Accent4", "60% - Accent5", "60% - Accent6", _
            "Accent1", "Accent2", "Accent3", "Accent4", "Accent5", "Accent6", _
            "Bad", "Calculation", "Check Cell", "Comma", "Comma [0]", "Currency", _
            "Currency [0]", "Explanatory Text", "Good", "Heading 1", "Heading 2", _
            "Heading 3", "Heading 4", "Input", "Linked Cell", "Neutral", "Normal", _
            "Note", "Output", "Percent", "Title", "Total", "Warning Text"
            Case Else
            CurStyle.Delete
            End Select
            Next CurStyle
            Set tempBook = Workbooks.Add
            Application.DisplayAlerts = False
            MyBook.Styles.Merge Workbook:=tempBook
            Application.DisplayAlerts = True
            tempBook.Close
            End Sub





            share|improve this answer














            Ok, this wasn't as hard to do as I first thought.



            Bit messy as I don't often use vba; but this code will roll back to just the default styles:



            Sub DefaultStyles()
            Dim MyBook As Workbook
            Dim tempBook As Workbook
            Dim CurStyle As Style
            Set MyBook = ActiveWorkbook
            On Error Resume Next
            For Each CurStyle In MyBook.Styles
            Select Case CurStyle.Name
            Case "20% - Accent1", "20% - Accent2", _
            "20% - Accent3", "20% - Accent4", "20% - Accent5", "20% - Accent6", _
            "40% - Accent1", "40% - Accent2", "40% - Accent3", "40% - Accent4", _
            "40% - Accent5", "40% - Accent6", "60% - Accent1", "60% - Accent2", _
            "60% - Accent3", "60% - Accent4", "60% - Accent5", "60% - Accent6", _
            "Accent1", "Accent2", "Accent3", "Accent4", "Accent5", "Accent6", _
            "Bad", "Calculation", "Check Cell", "Comma", "Comma [0]", "Currency", _
            "Currency [0]", "Explanatory Text", "Good", "Heading 1", "Heading 2", _
            "Heading 3", "Heading 4", "Input", "Linked Cell", "Neutral", "Normal", _
            "Note", "Output", "Percent", "Title", "Total", "Warning Text"
            Case Else
            CurStyle.Delete
            End Select
            Next CurStyle
            Set tempBook = Workbooks.Add
            Application.DisplayAlerts = False
            MyBook.Styles.Merge Workbook:=tempBook
            Application.DisplayAlerts = True
            tempBook.Close
            End Sub






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Jul 6 at 7:03

























            answered Feb 1 at 16:57









            PeterH

            3,14132245




            3,14132245












            • Actually I like the way you loop over Styles rather than my looping over an index.
              – Gary's Student
              Feb 1 at 17:07










            • Will have problems here, deleting a collection forwards.
              – AJD
              Jul 6 at 8:03










            • @AJD Hi, thanks for your comment, what problems could be caused from this ?
              – PeterH
              Jul 6 at 9:16










            • @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
              – AJD
              Jul 6 at 21:25










            • @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
              – PeterH
              Jul 9 at 7:09


















            • Actually I like the way you loop over Styles rather than my looping over an index.
              – Gary's Student
              Feb 1 at 17:07










            • Will have problems here, deleting a collection forwards.
              – AJD
              Jul 6 at 8:03










            • @AJD Hi, thanks for your comment, what problems could be caused from this ?
              – PeterH
              Jul 6 at 9:16










            • @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
              – AJD
              Jul 6 at 21:25










            • @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
              – PeterH
              Jul 9 at 7:09
















            Actually I like the way you loop over Styles rather than my looping over an index.
            – Gary's Student
            Feb 1 at 17:07




            Actually I like the way you loop over Styles rather than my looping over an index.
            – Gary's Student
            Feb 1 at 17:07












            Will have problems here, deleting a collection forwards.
            – AJD
            Jul 6 at 8:03




            Will have problems here, deleting a collection forwards.
            – AJD
            Jul 6 at 8:03












            @AJD Hi, thanks for your comment, what problems could be caused from this ?
            – PeterH
            Jul 6 at 9:16




            @AJD Hi, thanks for your comment, what problems could be caused from this ?
            – PeterH
            Jul 6 at 9:16












            @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
            – AJD
            Jul 6 at 21:25




            @PeterH: deleting forwards means that items in the collection are renumbered. For example, in the loop, j is = 1 and then you Delete(1). (2) moves to (1), but j increments to 2, so the next step is Delete(2), which is the old (3). For Each is an enumerating loop, so the same logic is used. There was a good explanation on StackOverflow somewhere - I can't find it, but these also explain: stackoverflow.com/questions/18858718/… , stackoverflow.com/questions/45585393/vba-loop-and-delete-issue
            – AJD
            Jul 6 at 21:25












            @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
            – PeterH
            Jul 9 at 7:09




            @AJD Thanks for the info, the macro itself works as intended, I have used it on several workbooks since I posted it back in Feb
            – PeterH
            Jul 9 at 7:09


















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