SWIG struct pointer as output parameter












0














I have a struct:



struct some_struct_s {
int arg1;
int arg2;
};


I have a C function:



int func(some_struct_s *output);


Both are %included into my SWIG file.



I want some_struct_s *output to be treated like an output parameter. Python example:



int_val, some_struct_output = func()


"Output parameters" is covered in the manual for POD-types (sec 10.1.3), but not for non-POD types.



How do I tell SWIG I want some_struct_s *output to be an output parameter?










share|improve this question



























    0














    I have a struct:



    struct some_struct_s {
    int arg1;
    int arg2;
    };


    I have a C function:



    int func(some_struct_s *output);


    Both are %included into my SWIG file.



    I want some_struct_s *output to be treated like an output parameter. Python example:



    int_val, some_struct_output = func()


    "Output parameters" is covered in the manual for POD-types (sec 10.1.3), but not for non-POD types.



    How do I tell SWIG I want some_struct_s *output to be an output parameter?










    share|improve this question

























      0












      0








      0







      I have a struct:



      struct some_struct_s {
      int arg1;
      int arg2;
      };


      I have a C function:



      int func(some_struct_s *output);


      Both are %included into my SWIG file.



      I want some_struct_s *output to be treated like an output parameter. Python example:



      int_val, some_struct_output = func()


      "Output parameters" is covered in the manual for POD-types (sec 10.1.3), but not for non-POD types.



      How do I tell SWIG I want some_struct_s *output to be an output parameter?










      share|improve this question













      I have a struct:



      struct some_struct_s {
      int arg1;
      int arg2;
      };


      I have a C function:



      int func(some_struct_s *output);


      Both are %included into my SWIG file.



      I want some_struct_s *output to be treated like an output parameter. Python example:



      int_val, some_struct_output = func()


      "Output parameters" is covered in the manual for POD-types (sec 10.1.3), but not for non-POD types.



      How do I tell SWIG I want some_struct_s *output to be an output parameter?







      python c swig






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 20 at 6:39









      Michael Labbé

      7,71832131




      7,71832131
























          1 Answer
          1






          active

          oldest

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          1














          From the documentation:




          11.5.7 "argout" typemap



          The "argout" typemap is used to return values from arguments. This is most commonly used to write wrappers for C/C++ functions that need to return multiple values. The "argout" typemap is almost always combined with an "in" typemap---possibly to ignore the input value....




          Here's a complete example for your code (no error checking for brevity):



          %module test

          // Declare an input typemap that suppresses requiring any input and
          // declare a temporary stack variable to hold the return data.
          %typemap(in,numinputs=0) some_struct_s* (some_struct_s tmp) %{
          $1 = &tmp;
          %}

          // Declare an output argument typemap. In this case, we'll use
          // a tuple to hold the structure data (no error checking).
          %typemap(argout) some_struct_s* (PyObject* o) %{
          o = PyTuple_New(2);
          PyTuple_SET_ITEM(o,0,PyLong_FromLong($1->arg1));
          PyTuple_SET_ITEM(o,1,PyLong_FromLong($1->arg2));
          $result = SWIG_Python_AppendOutput($result,o);
          %}

          // Instead of a header file, we'll just declare this code inline.
          // This includes the code in the wrapper, as well as telling SWIG
          // to create wrappers in the target language.
          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo below. Note that the int return value of zero as well as the output parameter as a tuple are returned as a list.



          >>> import test
          >>> test.func()
          [0, (1, 2)]


          If you don't want typemaps, you can also inject code to create the object and return it to hide it from the user:



          %module test

          %rename(_func) func; // Give the wrapper a different name

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}

          // Declare your interface
          %pythoncode %{
          def func():
          s = some_struct_s()
          r = _func(s)
          return r,s
          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001511D70A880> >
          >>> s.arg1
          1
          >>> s.arg2
          2


          You can make the typemap language agnostic if you carefully select SWIG macros:



          %module test

          %typemap(in,numinputs=0) struct some_struct_s *output %{
          $1 = malloc(sizeof(struct some_struct_s));
          %}

          %typemap(argout) struct some_struct_s* output {
          %append_output(SWIG_NewPointerObj($1,$1_descriptor,1));
          }

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001DD0425A700> >
          >>> s.arg1
          1
          >>> s.arg2
          2





          share|improve this answer























          • Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
            – Michael Labbé
            Nov 20 at 18:25












          • @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
            – Mark Tolonen
            Nov 20 at 20:40











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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          1














          From the documentation:




          11.5.7 "argout" typemap



          The "argout" typemap is used to return values from arguments. This is most commonly used to write wrappers for C/C++ functions that need to return multiple values. The "argout" typemap is almost always combined with an "in" typemap---possibly to ignore the input value....




          Here's a complete example for your code (no error checking for brevity):



          %module test

          // Declare an input typemap that suppresses requiring any input and
          // declare a temporary stack variable to hold the return data.
          %typemap(in,numinputs=0) some_struct_s* (some_struct_s tmp) %{
          $1 = &tmp;
          %}

          // Declare an output argument typemap. In this case, we'll use
          // a tuple to hold the structure data (no error checking).
          %typemap(argout) some_struct_s* (PyObject* o) %{
          o = PyTuple_New(2);
          PyTuple_SET_ITEM(o,0,PyLong_FromLong($1->arg1));
          PyTuple_SET_ITEM(o,1,PyLong_FromLong($1->arg2));
          $result = SWIG_Python_AppendOutput($result,o);
          %}

          // Instead of a header file, we'll just declare this code inline.
          // This includes the code in the wrapper, as well as telling SWIG
          // to create wrappers in the target language.
          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo below. Note that the int return value of zero as well as the output parameter as a tuple are returned as a list.



          >>> import test
          >>> test.func()
          [0, (1, 2)]


          If you don't want typemaps, you can also inject code to create the object and return it to hide it from the user:



          %module test

          %rename(_func) func; // Give the wrapper a different name

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}

          // Declare your interface
          %pythoncode %{
          def func():
          s = some_struct_s()
          r = _func(s)
          return r,s
          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001511D70A880> >
          >>> s.arg1
          1
          >>> s.arg2
          2


          You can make the typemap language agnostic if you carefully select SWIG macros:



          %module test

          %typemap(in,numinputs=0) struct some_struct_s *output %{
          $1 = malloc(sizeof(struct some_struct_s));
          %}

          %typemap(argout) struct some_struct_s* output {
          %append_output(SWIG_NewPointerObj($1,$1_descriptor,1));
          }

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001DD0425A700> >
          >>> s.arg1
          1
          >>> s.arg2
          2





          share|improve this answer























          • Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
            – Michael Labbé
            Nov 20 at 18:25












          • @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
            – Mark Tolonen
            Nov 20 at 20:40
















          1














          From the documentation:




          11.5.7 "argout" typemap



          The "argout" typemap is used to return values from arguments. This is most commonly used to write wrappers for C/C++ functions that need to return multiple values. The "argout" typemap is almost always combined with an "in" typemap---possibly to ignore the input value....




          Here's a complete example for your code (no error checking for brevity):



          %module test

          // Declare an input typemap that suppresses requiring any input and
          // declare a temporary stack variable to hold the return data.
          %typemap(in,numinputs=0) some_struct_s* (some_struct_s tmp) %{
          $1 = &tmp;
          %}

          // Declare an output argument typemap. In this case, we'll use
          // a tuple to hold the structure data (no error checking).
          %typemap(argout) some_struct_s* (PyObject* o) %{
          o = PyTuple_New(2);
          PyTuple_SET_ITEM(o,0,PyLong_FromLong($1->arg1));
          PyTuple_SET_ITEM(o,1,PyLong_FromLong($1->arg2));
          $result = SWIG_Python_AppendOutput($result,o);
          %}

          // Instead of a header file, we'll just declare this code inline.
          // This includes the code in the wrapper, as well as telling SWIG
          // to create wrappers in the target language.
          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo below. Note that the int return value of zero as well as the output parameter as a tuple are returned as a list.



          >>> import test
          >>> test.func()
          [0, (1, 2)]


          If you don't want typemaps, you can also inject code to create the object and return it to hide it from the user:



          %module test

          %rename(_func) func; // Give the wrapper a different name

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}

          // Declare your interface
          %pythoncode %{
          def func():
          s = some_struct_s()
          r = _func(s)
          return r,s
          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001511D70A880> >
          >>> s.arg1
          1
          >>> s.arg2
          2


          You can make the typemap language agnostic if you carefully select SWIG macros:



          %module test

          %typemap(in,numinputs=0) struct some_struct_s *output %{
          $1 = malloc(sizeof(struct some_struct_s));
          %}

          %typemap(argout) struct some_struct_s* output {
          %append_output(SWIG_NewPointerObj($1,$1_descriptor,1));
          }

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001DD0425A700> >
          >>> s.arg1
          1
          >>> s.arg2
          2





          share|improve this answer























          • Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
            – Michael Labbé
            Nov 20 at 18:25












          • @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
            – Mark Tolonen
            Nov 20 at 20:40














          1












          1








          1






          From the documentation:




          11.5.7 "argout" typemap



          The "argout" typemap is used to return values from arguments. This is most commonly used to write wrappers for C/C++ functions that need to return multiple values. The "argout" typemap is almost always combined with an "in" typemap---possibly to ignore the input value....




          Here's a complete example for your code (no error checking for brevity):



          %module test

          // Declare an input typemap that suppresses requiring any input and
          // declare a temporary stack variable to hold the return data.
          %typemap(in,numinputs=0) some_struct_s* (some_struct_s tmp) %{
          $1 = &tmp;
          %}

          // Declare an output argument typemap. In this case, we'll use
          // a tuple to hold the structure data (no error checking).
          %typemap(argout) some_struct_s* (PyObject* o) %{
          o = PyTuple_New(2);
          PyTuple_SET_ITEM(o,0,PyLong_FromLong($1->arg1));
          PyTuple_SET_ITEM(o,1,PyLong_FromLong($1->arg2));
          $result = SWIG_Python_AppendOutput($result,o);
          %}

          // Instead of a header file, we'll just declare this code inline.
          // This includes the code in the wrapper, as well as telling SWIG
          // to create wrappers in the target language.
          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo below. Note that the int return value of zero as well as the output parameter as a tuple are returned as a list.



          >>> import test
          >>> test.func()
          [0, (1, 2)]


          If you don't want typemaps, you can also inject code to create the object and return it to hide it from the user:



          %module test

          %rename(_func) func; // Give the wrapper a different name

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}

          // Declare your interface
          %pythoncode %{
          def func():
          s = some_struct_s()
          r = _func(s)
          return r,s
          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001511D70A880> >
          >>> s.arg1
          1
          >>> s.arg2
          2


          You can make the typemap language agnostic if you carefully select SWIG macros:



          %module test

          %typemap(in,numinputs=0) struct some_struct_s *output %{
          $1 = malloc(sizeof(struct some_struct_s));
          %}

          %typemap(argout) struct some_struct_s* output {
          %append_output(SWIG_NewPointerObj($1,$1_descriptor,1));
          }

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001DD0425A700> >
          >>> s.arg1
          1
          >>> s.arg2
          2





          share|improve this answer














          From the documentation:




          11.5.7 "argout" typemap



          The "argout" typemap is used to return values from arguments. This is most commonly used to write wrappers for C/C++ functions that need to return multiple values. The "argout" typemap is almost always combined with an "in" typemap---possibly to ignore the input value....




          Here's a complete example for your code (no error checking for brevity):



          %module test

          // Declare an input typemap that suppresses requiring any input and
          // declare a temporary stack variable to hold the return data.
          %typemap(in,numinputs=0) some_struct_s* (some_struct_s tmp) %{
          $1 = &tmp;
          %}

          // Declare an output argument typemap. In this case, we'll use
          // a tuple to hold the structure data (no error checking).
          %typemap(argout) some_struct_s* (PyObject* o) %{
          o = PyTuple_New(2);
          PyTuple_SET_ITEM(o,0,PyLong_FromLong($1->arg1));
          PyTuple_SET_ITEM(o,1,PyLong_FromLong($1->arg2));
          $result = SWIG_Python_AppendOutput($result,o);
          %}

          // Instead of a header file, we'll just declare this code inline.
          // This includes the code in the wrapper, as well as telling SWIG
          // to create wrappers in the target language.
          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo below. Note that the int return value of zero as well as the output parameter as a tuple are returned as a list.



          >>> import test
          >>> test.func()
          [0, (1, 2)]


          If you don't want typemaps, you can also inject code to create the object and return it to hide it from the user:



          %module test

          %rename(_func) func; // Give the wrapper a different name

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}

          // Declare your interface
          %pythoncode %{
          def func():
          s = some_struct_s()
          r = _func(s)
          return r,s
          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001511D70A880> >
          >>> s.arg1
          1
          >>> s.arg2
          2


          You can make the typemap language agnostic if you carefully select SWIG macros:



          %module test

          %typemap(in,numinputs=0) struct some_struct_s *output %{
          $1 = malloc(sizeof(struct some_struct_s));
          %}

          %typemap(argout) struct some_struct_s* output {
          %append_output(SWIG_NewPointerObj($1,$1_descriptor,1));
          }

          %inline %{

          struct some_struct_s {
          int arg1;
          int arg2;
          };

          int func(struct some_struct_s *output)
          {
          output->arg1 = 1;
          output->arg2 = 2;
          return 0;
          }

          %}


          Demo:



          >>> import test
          >>> r,s=test.func()
          >>> r
          0
          >>> s
          <test.some_struct_s; proxy of <Swig Object of type 'some_struct_s *' at 0x000001DD0425A700> >
          >>> s.arg1
          1
          >>> s.arg2
          2






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 20 at 21:04

























          answered Nov 20 at 7:40









          Mark Tolonen

          90.8k12109175




          90.8k12109175












          • Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
            – Michael Labbé
            Nov 20 at 18:25












          • @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
            – Mark Tolonen
            Nov 20 at 20:40


















          • Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
            – Michael Labbé
            Nov 20 at 18:25












          • @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
            – Mark Tolonen
            Nov 20 at 20:40
















          Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
          – Michael Labbé
          Nov 20 at 18:25






          Thanks for this. Without this, I have noticed that I can instantiate an empty some_struct_s on one line of code and pass it in. When the function returns, the contents are non-opaque. This has the benefit of me not having to write a language-specific typemap. I was hoping there was a way to signify the parameter should be at the end without having to write output language-specific api code for each element in an argout typemap. Should I give up hope?
          – Michael Labbé
          Nov 20 at 18:25














          @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
          – Mark Tolonen
          Nov 20 at 20:40




          @MichaelLabbé haven't found a way without writing a typemap, but you can avoid language specifics by using some SWIG macros. I'll update with an example.
          – Mark Tolonen
          Nov 20 at 20:40


















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