Changing the output of a function in R
I have created a function to generate random poisson distributions but want the function to calculate the mean of lambda also.
xpoisson<-function(x,mu){rpois(x, lambda=mu)}
This is what I have written so far and Im not sure where/how to add the mean(mu) to the function. Any help apppreciated.
r poisson
asked Nov 20 '18 at 12:22
Matlab rookie
135
add a comment |
I have created a function to generate random poisson distributions but want the function to calculate the mean of lambda also.
xpoisson<-function(x,mu){rpois(x, lambda=mu)}
This is what I have written so far and Im not sure where/how to add the mean(mu) to the function. Any help apppreciated.
r poisson
asked Nov 20 '18 at 12:22
Matlab rookie
135
add a comment |
I have created a function to generate random poisson distributions but want the function to calculate the mean of lambda also.
xpoisson<-function(x,mu){rpois(x, lambda=mu)}
This is what I have written so far and Im not sure where/how to add the mean(mu) to the function. Any help apppreciated.
r poisson
asked Nov 20 '18 at 12:22
Matlab rookie
135
I have created a function to generate random poisson distributions but want the function to calculate the mean of lambda also.
xpoisson<-function(x,mu){rpois(x, lambda=mu)}
This is what I have written so far and Im not sure where/how to add the mean(mu) to the function. Any help apppreciated.
r poisson
r poisson
asked Nov 20 '18 at 12:22
Matlab rookie
135
asked Nov 20 '18 at 12:22
Matlab rookie
135
asked Nov 20 '18 at 12:22
Matlab rookie
135
asked Nov 20 '18 at 12:22
Matlab rookie
135
asked Nov 20 '18 at 12:22
Matlab rookie
135
135
add a comment |
add a comment |
2 Answers
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I believe what you want is not mean(mu) but mean(rpois(x,lamda=mu)) ?
If so, just add the new line inside the function, assign the distribution and mean to variables and return both values by adding them to a list and returning said list.
answered Nov 20 '18 at 12:29
boski
1258
add a comment |
Functions will only output one variable. In order to output two variables you need, for instance, to output them as a list. Try the following:
xpoisson<-function(x,mu){
list(rpois(x, lambda=mu),mean(mu))
}
answered Nov 20 '18 at 12:30
Hugo Silva
1426
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
I believe what you want is not mean(mu) but mean(rpois(x,lamda=mu)) ?
If so, just add the new line inside the function, assign the distribution and mean to variables and return both values by adding them to a list and returning said list.
answered Nov 20 '18 at 12:29
boski
1258
add a comment |
I believe what you want is not mean(mu) but mean(rpois(x,lamda=mu)) ?
If so, just add the new line inside the function, assign the distribution and mean to variables and return both values by adding them to a list and returning said list.
answered Nov 20 '18 at 12:29
boski
1258
add a comment |
I believe what you want is not mean(mu) but mean(rpois(x,lamda=mu)) ?
If so, just add the new line inside the function, assign the distribution and mean to variables and return both values by adding them to a list and returning said list.
answered Nov 20 '18 at 12:29
boski
1258
I believe what you want is not mean(mu) but mean(rpois(x,lamda=mu)) ?
If so, just add the new line inside the function, assign the distribution and mean to variables and return both values by adding them to a list and returning said list.
answered Nov 20 '18 at 12:29
boski
1258
answered Nov 20 '18 at 12:29
boski
1258
answered Nov 20 '18 at 12:29
boski
1258
answered Nov 20 '18 at 12:29
boski
1258
1258
add a comment |
add a comment |
Functions will only output one variable. In order to output two variables you need, for instance, to output them as a list. Try the following:
xpoisson<-function(x,mu){
list(rpois(x, lambda=mu),mean(mu))
}
answered Nov 20 '18 at 12:30
Hugo Silva
1426
add a comment |
Functions will only output one variable. In order to output two variables you need, for instance, to output them as a list. Try the following:
xpoisson<-function(x,mu){
list(rpois(x, lambda=mu),mean(mu))
}
answered Nov 20 '18 at 12:30
Hugo Silva
1426
add a comment |
Functions will only output one variable. In order to output two variables you need, for instance, to output them as a list. Try the following:
xpoisson<-function(x,mu){
list(rpois(x, lambda=mu),mean(mu))
}
answered Nov 20 '18 at 12:30
Hugo Silva
1426
Functions will only output one variable. In order to output two variables you need, for instance, to output them as a list. Try the following:
xpoisson<-function(x,mu){
list(rpois(x, lambda=mu),mean(mu))
}
answered Nov 20 '18 at 12:30
Hugo Silva
1426
answered Nov 20 '18 at 12:30
Hugo Silva
1426
answered Nov 20 '18 at 12:30
Hugo Silva
1426
answered Nov 20 '18 at 12:30
Hugo Silva
1426
1426
add a comment |
add a comment |
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