Element–wise summation for custom function
$begingroup$
I use a custom function/head Operator[low, high] which encodes a generic polynomial expression split into "low" and "high" summands following considerations which are irrelevant to this question.
Two Operator objects should sum in the following way:
Operator[a,b] + Operator[c,d] -> Operator[a+c,b+d]
which is just standard element–wise summation that List does automatically. How can I tell Mathematica that this kind of automatic simplification or rearrangement is not only allowed, but desirable?
function-construction
$endgroup$
add a comment |
$begingroup$
I use a custom function/head Operator[low, high] which encodes a generic polynomial expression split into "low" and "high" summands following considerations which are irrelevant to this question.
Two Operator objects should sum in the following way:
Operator[a,b] + Operator[c,d] -> Operator[a+c,b+d]
which is just standard element–wise summation that List does automatically. How can I tell Mathematica that this kind of automatic simplification or rearrangement is not only allowed, but desirable?
function-construction
$endgroup$
add a comment |
$begingroup$
I use a custom function/head Operator[low, high] which encodes a generic polynomial expression split into "low" and "high" summands following considerations which are irrelevant to this question.
Two Operator objects should sum in the following way:
Operator[a,b] + Operator[c,d] -> Operator[a+c,b+d]
which is just standard element–wise summation that List does automatically. How can I tell Mathematica that this kind of automatic simplification or rearrangement is not only allowed, but desirable?
function-construction
$endgroup$
I use a custom function/head Operator[low, high] which encodes a generic polynomial expression split into "low" and "high" summands following considerations which are irrelevant to this question.
Two Operator objects should sum in the following way:
Operator[a,b] + Operator[c,d] -> Operator[a+c,b+d]
which is just standard element–wise summation that List does automatically. How can I tell Mathematica that this kind of automatic simplification or rearrangement is not only allowed, but desirable?
function-construction
function-construction
asked Dec 21 '18 at 15:12
Dom MiketaDom Miketa
704
704
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add a comment |
1 Answer
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$begingroup$
One of the standard ways for such things is using TagSetDelayed
Operator /: Operator[a_, b_] + Operator[c_, d_] := Operator[a + c, b + d]
$endgroup$
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
One of the standard ways for such things is using TagSetDelayed
Operator /: Operator[a_, b_] + Operator[c_, d_] := Operator[a + c, b + d]
$endgroup$
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
add a comment |
$begingroup$
One of the standard ways for such things is using TagSetDelayed
Operator /: Operator[a_, b_] + Operator[c_, d_] := Operator[a + c, b + d]
$endgroup$
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
add a comment |
$begingroup$
One of the standard ways for such things is using TagSetDelayed
Operator /: Operator[a_, b_] + Operator[c_, d_] := Operator[a + c, b + d]
$endgroup$
One of the standard ways for such things is using TagSetDelayed
Operator /: Operator[a_, b_] + Operator[c_, d_] := Operator[a + c, b + d]
edited Dec 21 '18 at 15:36
Bob Hanlon
59.2k33595
59.2k33595
answered Dec 21 '18 at 15:27
AndrewAndrew
1,9511115
1,9511115
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
add a comment |
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
$begingroup$
Thanks, that works really well! I'm a bit mystified about semantics behind /: but I'll read up.
$endgroup$
– Dom Miketa
Dec 21 '18 at 15:44
add a comment |
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