Need to subtract some hours from given timestamp in hive












0















Input: unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')



Expected output is 4 hours delay from above utc input time i.e 01/15/2018 11:26:37



I know that there is date_sub function in hive but it is only used to subtract days from the given timestamp. But I need to know if there is a way by which I can subtract hours or minutes or seconds.



I have also tried something like below as EDT timezone is 4 hours behind UTC (but getting wrong output):



SELECT to_date(from_UTC_timestamp(unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')*1000, 'EST6EDT')) as earliest_date; -- OUTPUT: 2017-12-31 (wrong) 


So can anyone help me out with this?










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    0















    Input: unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')



    Expected output is 4 hours delay from above utc input time i.e 01/15/2018 11:26:37



    I know that there is date_sub function in hive but it is only used to subtract days from the given timestamp. But I need to know if there is a way by which I can subtract hours or minutes or seconds.



    I have also tried something like below as EDT timezone is 4 hours behind UTC (but getting wrong output):



    SELECT to_date(from_UTC_timestamp(unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')*1000, 'EST6EDT')) as earliest_date; -- OUTPUT: 2017-12-31 (wrong) 


    So can anyone help me out with this?










    share|improve this question

























      0












      0








      0








      Input: unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')



      Expected output is 4 hours delay from above utc input time i.e 01/15/2018 11:26:37



      I know that there is date_sub function in hive but it is only used to subtract days from the given timestamp. But I need to know if there is a way by which I can subtract hours or minutes or seconds.



      I have also tried something like below as EDT timezone is 4 hours behind UTC (but getting wrong output):



      SELECT to_date(from_UTC_timestamp(unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')*1000, 'EST6EDT')) as earliest_date; -- OUTPUT: 2017-12-31 (wrong) 


      So can anyone help me out with this?










      share|improve this question














      Input: unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')



      Expected output is 4 hours delay from above utc input time i.e 01/15/2018 11:26:37



      I know that there is date_sub function in hive but it is only used to subtract days from the given timestamp. But I need to know if there is a way by which I can subtract hours or minutes or seconds.



      I have also tried something like below as EDT timezone is 4 hours behind UTC (but getting wrong output):



      SELECT to_date(from_UTC_timestamp(unix_timestamp('01/15/2018 15:26:37', 'mm/dd/YYYY hh:mm:ss')*1000, 'EST6EDT')) as earliest_date; -- OUTPUT: 2017-12-31 (wrong) 


      So can anyone help me out with this?







      mysql sql hive hiveql sql-date-functions






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      asked Nov 21 '18 at 8:03









      Bhuvi007Bhuvi007

      196




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          It works fine.



          select from_unixtime(unix_timestamp('01/15/2018 15:26:37', 'MM/dd/yyyy HH:mm:ss')-4*3600, 'MM/dd/yyyy HH:mm:ss') 





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          • Great !! This works.

            – Bhuvi007
            Nov 21 '18 at 9:08











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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2














          It works fine.



          select from_unixtime(unix_timestamp('01/15/2018 15:26:37', 'MM/dd/yyyy HH:mm:ss')-4*3600, 'MM/dd/yyyy HH:mm:ss') 





          share|improve this answer
























          • Great !! This works.

            – Bhuvi007
            Nov 21 '18 at 9:08
















          2














          It works fine.



          select from_unixtime(unix_timestamp('01/15/2018 15:26:37', 'MM/dd/yyyy HH:mm:ss')-4*3600, 'MM/dd/yyyy HH:mm:ss') 





          share|improve this answer
























          • Great !! This works.

            – Bhuvi007
            Nov 21 '18 at 9:08














          2












          2








          2







          It works fine.



          select from_unixtime(unix_timestamp('01/15/2018 15:26:37', 'MM/dd/yyyy HH:mm:ss')-4*3600, 'MM/dd/yyyy HH:mm:ss') 





          share|improve this answer













          It works fine.



          select from_unixtime(unix_timestamp('01/15/2018 15:26:37', 'MM/dd/yyyy HH:mm:ss')-4*3600, 'MM/dd/yyyy HH:mm:ss') 






          share|improve this answer












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          answered Nov 21 '18 at 8:51









          StrongYoungStrongYoung

          3571213




          3571213













          • Great !! This works.

            – Bhuvi007
            Nov 21 '18 at 9:08



















          • Great !! This works.

            – Bhuvi007
            Nov 21 '18 at 9:08

















          Great !! This works.

          – Bhuvi007
          Nov 21 '18 at 9:08





          Great !! This works.

          – Bhuvi007
          Nov 21 '18 at 9:08


















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