How to add a fragment to a programmatically generated layout?
I have the following code working which generates fragments, but only if I am adding them to a linear layout which exists in my XML file.
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag= new ImageFragment();
fragTransaction.add(R.id.foodItemActvity_linearLayout_fragments, myFrag , "fragment" + fragCount);
fragTransaction.commit();
Now what if I want to add that fragment to a linear layout that does not already exist in the XML file such as
LinearLayout rowLayout = new LinearLayout();
Part 2:
Fragment frag1 = generateAppropriateFragment(type1);
Fragment frag2 = generateAppropriateFragment(type2);
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
LinearLayout rowLayout = new LinearLayout(this);
rowLayout.setId(12345); // add counter to end
fragmentsLayout.addView(rowLayout);
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag1, "fragment_grandchild" + fragCount).commit();
fragCount++;
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag2, "fragment_grandchild" + fragCount).commit();
fragCount++;
android android-fragments android-linearlayout
add a comment |
I have the following code working which generates fragments, but only if I am adding them to a linear layout which exists in my XML file.
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag= new ImageFragment();
fragTransaction.add(R.id.foodItemActvity_linearLayout_fragments, myFrag , "fragment" + fragCount);
fragTransaction.commit();
Now what if I want to add that fragment to a linear layout that does not already exist in the XML file such as
LinearLayout rowLayout = new LinearLayout();
Part 2:
Fragment frag1 = generateAppropriateFragment(type1);
Fragment frag2 = generateAppropriateFragment(type2);
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
LinearLayout rowLayout = new LinearLayout(this);
rowLayout.setId(12345); // add counter to end
fragmentsLayout.addView(rowLayout);
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag1, "fragment_grandchild" + fragCount).commit();
fragCount++;
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag2, "fragment_grandchild" + fragCount).commit();
fragCount++;
android android-fragments android-linearlayout
add a comment |
I have the following code working which generates fragments, but only if I am adding them to a linear layout which exists in my XML file.
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag= new ImageFragment();
fragTransaction.add(R.id.foodItemActvity_linearLayout_fragments, myFrag , "fragment" + fragCount);
fragTransaction.commit();
Now what if I want to add that fragment to a linear layout that does not already exist in the XML file such as
LinearLayout rowLayout = new LinearLayout();
Part 2:
Fragment frag1 = generateAppropriateFragment(type1);
Fragment frag2 = generateAppropriateFragment(type2);
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
LinearLayout rowLayout = new LinearLayout(this);
rowLayout.setId(12345); // add counter to end
fragmentsLayout.addView(rowLayout);
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag1, "fragment_grandchild" + fragCount).commit();
fragCount++;
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag2, "fragment_grandchild" + fragCount).commit();
fragCount++;
android android-fragments android-linearlayout
I have the following code working which generates fragments, but only if I am adding them to a linear layout which exists in my XML file.
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag= new ImageFragment();
fragTransaction.add(R.id.foodItemActvity_linearLayout_fragments, myFrag , "fragment" + fragCount);
fragTransaction.commit();
Now what if I want to add that fragment to a linear layout that does not already exist in the XML file such as
LinearLayout rowLayout = new LinearLayout();
Part 2:
Fragment frag1 = generateAppropriateFragment(type1);
Fragment frag2 = generateAppropriateFragment(type2);
LinearLayout fragmentsLayout = (LinearLayout) findViewById(R.id.foodItemActvity_linearLayout_fragments);
LinearLayout rowLayout = new LinearLayout(this);
rowLayout.setId(12345); // add counter to end
fragmentsLayout.addView(rowLayout);
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag1, "fragment_grandchild" + fragCount).commit();
fragCount++;
getFragmentManager().beginTransaction().add(rowLayout.getId(), frag2, "fragment_grandchild" + fragCount).commit();
fragCount++;
android android-fragments android-linearlayout
android android-fragments android-linearlayout
edited Jan 12 '17 at 11:22
jpihl
3,89822337
3,89822337
asked Aug 18 '13 at 7:48
ZapnologicaZapnologica
8,96933101189
8,96933101189
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
At some point, I suppose you will add your programatically created LinearLayout to some root layout that you defined in .xml.
This is just a suggestion of mine and probably one of many solutions, but it works:
Simply set an ID for the programatically created layout, and add it to the root layout that you defined in .xml, and then use the set ID to add the Fragment.
It could look like this:
LinearLayout rowLayout = new LinearLayout();
rowLayout.setId(whateveryouwantasid);
// add rowLayout to the root layout somewhere here
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag = new ImageFragment();
fragTransaction.add(rowLayout.getId(), myFrag , "fragment" + fragCount);
fragTransaction.commit();
Simply choose whatever Integer value you want for the ID:
rowLayout.setId(12345);
If you are using the above line of code not just once, it would probably be smart to figure out a way to create unique-IDs, in order to avoid duplicates.
UPDATE:
Here is the full code of how it should be done:
(this code is tested and works)
I am adding two Fragments to a LinearLayout with horizontal orientation, resulting in the Fragments being aligned next to each other. Please also be aware, that I used a fixed height and width of 200dp, so that one Fragment does not use the full screen as it would with "match_parent".
MainActivity.java:
public class MainActivity extends Activity {
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LinearLayout fragContainer = (LinearLayout) findViewById(R.id.llFragmentContainer);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.HORIZONTAL);
ll.setId(12345);
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 1"), "someTag1").commit();
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 2"), "someTag2").commit();
fragContainer.addView(ll);
}
}
TestFragment.java:
public class TestFragment extends Fragment {
public static TestFragment newInstance(String text) {
TestFragment f = new TestFragment();
Bundle b = new Bundle();
b.putString("text", text);
f.setArguments(b);
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment, container, false);
((TextView) v.findViewById(R.id.tvFragText)).setText(getArguments().getString("text"));
return v;
}
}
activity_main.xml:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rlMain"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="5dp"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<LinearLayout
android:id="@+id/llFragmentContainer"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignLeft="@+id/textView1"
android:layout_below="@+id/textView1"
android:layout_marginTop="19dp"
android:orientation="vertical" >
</LinearLayout>
</RelativeLayout>
fragment.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="200dp"
android:layout_height="200dp" >
<TextView
android:id="@+id/tvFragText"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:text="" />
</RelativeLayout>
And this is the result of the above code: (the two Fragments are aligned next to each other)
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like647589
.
– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
I'd recommend usingView.generateViewId()
to generate a view ID.
– Jeremy Wiebe
Aug 30 '16 at 19:54
|
show 18 more comments
Below is a working code to add a fragment e.g 3 times to a vertical LinearLayout (xNumberLinear).
You can change number 3 with any other number or take a number from a spinner!
for (int i = 0; i < 3; i++) {
LinearLayout linearDummy = new LinearLayout(getActivity());
linearDummy.setOrientation(LinearLayout.VERTICAL);
if (Build.VERSION.SDK_INT < Build.VERSION_CODES.JELLY_BEAN_MR1) {
Toast.makeText(getActivity(), "This function works on newer versions of android", Toast.LENGTH_LONG).show();
} else {
linearDummy.setId(View.generateViewId());
}
fragmentManager.beginTransaction().add(linearDummy.getId(), new SomeFragment(),"someTag1").commit();
xNumberLinear.addView(linearDummy);
}
add a comment |
Add this code in your activity
FragmentTransaction mFragmentTransaction=getSupportFragmentManager().beginTransaction();
mFragmentTransaction.add(R.id.fr_container,new ProductListFragment());
mFragmentTransaction.commit();
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
At some point, I suppose you will add your programatically created LinearLayout to some root layout that you defined in .xml.
This is just a suggestion of mine and probably one of many solutions, but it works:
Simply set an ID for the programatically created layout, and add it to the root layout that you defined in .xml, and then use the set ID to add the Fragment.
It could look like this:
LinearLayout rowLayout = new LinearLayout();
rowLayout.setId(whateveryouwantasid);
// add rowLayout to the root layout somewhere here
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag = new ImageFragment();
fragTransaction.add(rowLayout.getId(), myFrag , "fragment" + fragCount);
fragTransaction.commit();
Simply choose whatever Integer value you want for the ID:
rowLayout.setId(12345);
If you are using the above line of code not just once, it would probably be smart to figure out a way to create unique-IDs, in order to avoid duplicates.
UPDATE:
Here is the full code of how it should be done:
(this code is tested and works)
I am adding two Fragments to a LinearLayout with horizontal orientation, resulting in the Fragments being aligned next to each other. Please also be aware, that I used a fixed height and width of 200dp, so that one Fragment does not use the full screen as it would with "match_parent".
MainActivity.java:
public class MainActivity extends Activity {
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LinearLayout fragContainer = (LinearLayout) findViewById(R.id.llFragmentContainer);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.HORIZONTAL);
ll.setId(12345);
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 1"), "someTag1").commit();
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 2"), "someTag2").commit();
fragContainer.addView(ll);
}
}
TestFragment.java:
public class TestFragment extends Fragment {
public static TestFragment newInstance(String text) {
TestFragment f = new TestFragment();
Bundle b = new Bundle();
b.putString("text", text);
f.setArguments(b);
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment, container, false);
((TextView) v.findViewById(R.id.tvFragText)).setText(getArguments().getString("text"));
return v;
}
}
activity_main.xml:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rlMain"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="5dp"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<LinearLayout
android:id="@+id/llFragmentContainer"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignLeft="@+id/textView1"
android:layout_below="@+id/textView1"
android:layout_marginTop="19dp"
android:orientation="vertical" >
</LinearLayout>
</RelativeLayout>
fragment.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="200dp"
android:layout_height="200dp" >
<TextView
android:id="@+id/tvFragText"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:text="" />
</RelativeLayout>
And this is the result of the above code: (the two Fragments are aligned next to each other)
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like647589
.
– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
I'd recommend usingView.generateViewId()
to generate a view ID.
– Jeremy Wiebe
Aug 30 '16 at 19:54
|
show 18 more comments
At some point, I suppose you will add your programatically created LinearLayout to some root layout that you defined in .xml.
This is just a suggestion of mine and probably one of many solutions, but it works:
Simply set an ID for the programatically created layout, and add it to the root layout that you defined in .xml, and then use the set ID to add the Fragment.
It could look like this:
LinearLayout rowLayout = new LinearLayout();
rowLayout.setId(whateveryouwantasid);
// add rowLayout to the root layout somewhere here
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag = new ImageFragment();
fragTransaction.add(rowLayout.getId(), myFrag , "fragment" + fragCount);
fragTransaction.commit();
Simply choose whatever Integer value you want for the ID:
rowLayout.setId(12345);
If you are using the above line of code not just once, it would probably be smart to figure out a way to create unique-IDs, in order to avoid duplicates.
UPDATE:
Here is the full code of how it should be done:
(this code is tested and works)
I am adding two Fragments to a LinearLayout with horizontal orientation, resulting in the Fragments being aligned next to each other. Please also be aware, that I used a fixed height and width of 200dp, so that one Fragment does not use the full screen as it would with "match_parent".
MainActivity.java:
public class MainActivity extends Activity {
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LinearLayout fragContainer = (LinearLayout) findViewById(R.id.llFragmentContainer);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.HORIZONTAL);
ll.setId(12345);
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 1"), "someTag1").commit();
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 2"), "someTag2").commit();
fragContainer.addView(ll);
}
}
TestFragment.java:
public class TestFragment extends Fragment {
public static TestFragment newInstance(String text) {
TestFragment f = new TestFragment();
Bundle b = new Bundle();
b.putString("text", text);
f.setArguments(b);
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment, container, false);
((TextView) v.findViewById(R.id.tvFragText)).setText(getArguments().getString("text"));
return v;
}
}
activity_main.xml:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rlMain"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="5dp"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<LinearLayout
android:id="@+id/llFragmentContainer"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignLeft="@+id/textView1"
android:layout_below="@+id/textView1"
android:layout_marginTop="19dp"
android:orientation="vertical" >
</LinearLayout>
</RelativeLayout>
fragment.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="200dp"
android:layout_height="200dp" >
<TextView
android:id="@+id/tvFragText"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:text="" />
</RelativeLayout>
And this is the result of the above code: (the two Fragments are aligned next to each other)
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like647589
.
– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
I'd recommend usingView.generateViewId()
to generate a view ID.
– Jeremy Wiebe
Aug 30 '16 at 19:54
|
show 18 more comments
At some point, I suppose you will add your programatically created LinearLayout to some root layout that you defined in .xml.
This is just a suggestion of mine and probably one of many solutions, but it works:
Simply set an ID for the programatically created layout, and add it to the root layout that you defined in .xml, and then use the set ID to add the Fragment.
It could look like this:
LinearLayout rowLayout = new LinearLayout();
rowLayout.setId(whateveryouwantasid);
// add rowLayout to the root layout somewhere here
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag = new ImageFragment();
fragTransaction.add(rowLayout.getId(), myFrag , "fragment" + fragCount);
fragTransaction.commit();
Simply choose whatever Integer value you want for the ID:
rowLayout.setId(12345);
If you are using the above line of code not just once, it would probably be smart to figure out a way to create unique-IDs, in order to avoid duplicates.
UPDATE:
Here is the full code of how it should be done:
(this code is tested and works)
I am adding two Fragments to a LinearLayout with horizontal orientation, resulting in the Fragments being aligned next to each other. Please also be aware, that I used a fixed height and width of 200dp, so that one Fragment does not use the full screen as it would with "match_parent".
MainActivity.java:
public class MainActivity extends Activity {
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LinearLayout fragContainer = (LinearLayout) findViewById(R.id.llFragmentContainer);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.HORIZONTAL);
ll.setId(12345);
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 1"), "someTag1").commit();
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 2"), "someTag2").commit();
fragContainer.addView(ll);
}
}
TestFragment.java:
public class TestFragment extends Fragment {
public static TestFragment newInstance(String text) {
TestFragment f = new TestFragment();
Bundle b = new Bundle();
b.putString("text", text);
f.setArguments(b);
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment, container, false);
((TextView) v.findViewById(R.id.tvFragText)).setText(getArguments().getString("text"));
return v;
}
}
activity_main.xml:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rlMain"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="5dp"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<LinearLayout
android:id="@+id/llFragmentContainer"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignLeft="@+id/textView1"
android:layout_below="@+id/textView1"
android:layout_marginTop="19dp"
android:orientation="vertical" >
</LinearLayout>
</RelativeLayout>
fragment.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="200dp"
android:layout_height="200dp" >
<TextView
android:id="@+id/tvFragText"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:text="" />
</RelativeLayout>
And this is the result of the above code: (the two Fragments are aligned next to each other)
At some point, I suppose you will add your programatically created LinearLayout to some root layout that you defined in .xml.
This is just a suggestion of mine and probably one of many solutions, but it works:
Simply set an ID for the programatically created layout, and add it to the root layout that you defined in .xml, and then use the set ID to add the Fragment.
It could look like this:
LinearLayout rowLayout = new LinearLayout();
rowLayout.setId(whateveryouwantasid);
// add rowLayout to the root layout somewhere here
FragmentManager fragMan = getFragmentManager();
FragmentTransaction fragTransaction = fragMan.beginTransaction();
Fragment myFrag = new ImageFragment();
fragTransaction.add(rowLayout.getId(), myFrag , "fragment" + fragCount);
fragTransaction.commit();
Simply choose whatever Integer value you want for the ID:
rowLayout.setId(12345);
If you are using the above line of code not just once, it would probably be smart to figure out a way to create unique-IDs, in order to avoid duplicates.
UPDATE:
Here is the full code of how it should be done:
(this code is tested and works)
I am adding two Fragments to a LinearLayout with horizontal orientation, resulting in the Fragments being aligned next to each other. Please also be aware, that I used a fixed height and width of 200dp, so that one Fragment does not use the full screen as it would with "match_parent".
MainActivity.java:
public class MainActivity extends Activity {
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
LinearLayout fragContainer = (LinearLayout) findViewById(R.id.llFragmentContainer);
LinearLayout ll = new LinearLayout(this);
ll.setOrientation(LinearLayout.HORIZONTAL);
ll.setId(12345);
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 1"), "someTag1").commit();
getFragmentManager().beginTransaction().add(ll.getId(), TestFragment.newInstance("I am frag 2"), "someTag2").commit();
fragContainer.addView(ll);
}
}
TestFragment.java:
public class TestFragment extends Fragment {
public static TestFragment newInstance(String text) {
TestFragment f = new TestFragment();
Bundle b = new Bundle();
b.putString("text", text);
f.setArguments(b);
return f;
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View v = inflater.inflate(R.layout.fragment, container, false);
((TextView) v.findViewById(R.id.tvFragText)).setText(getArguments().getString("text"));
return v;
}
}
activity_main.xml:
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/rlMain"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="5dp"
tools:context=".MainActivity" >
<TextView
android:id="@+id/textView1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<LinearLayout
android:id="@+id/llFragmentContainer"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_alignLeft="@+id/textView1"
android:layout_below="@+id/textView1"
android:layout_marginTop="19dp"
android:orientation="vertical" >
</LinearLayout>
</RelativeLayout>
fragment.xml:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="200dp"
android:layout_height="200dp" >
<TextView
android:id="@+id/tvFragText"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:text="" />
</RelativeLayout>
And this is the result of the above code: (the two Fragments are aligned next to each other)
edited Feb 11 '17 at 20:44
Willi Mentzel
9,277114470
9,277114470
answered Aug 18 '13 at 7:59
Philipp JahodaPhilipp Jahoda
37k17121145
37k17121145
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like647589
.
– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
I'd recommend usingView.generateViewId()
to generate a view ID.
– Jeremy Wiebe
Aug 30 '16 at 19:54
|
show 18 more comments
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like647589
.
– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
I'd recommend usingView.generateViewId()
to generate a view ID.
– Jeremy Wiebe
Aug 30 '16 at 19:54
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
That is exactly what I am trying to do!! Only thing is what must I set the id as? Cause it wants an INT and normally in the xml files the id is a string ?
– Zapnologica
Aug 18 '13 at 8:13
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like
647589
.– Vikram
Aug 18 '13 at 8:20
This will absolutely work. @Zapnologica Look on SO to find how to generate unique ids. But, it shouldn't be a problem to use something like
647589
.– Vikram
Aug 18 '13 at 8:20
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
Just choose whatever Integer you want as the id :)
– Philipp Jahoda
Aug 18 '13 at 8:24
3
3
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
stackoverflow.com/questions/8460680/… >> Good Link
– Zapnologica
Aug 18 '13 at 8:31
7
7
I'd recommend using
View.generateViewId()
to generate a view ID.– Jeremy Wiebe
Aug 30 '16 at 19:54
I'd recommend using
View.generateViewId()
to generate a view ID.– Jeremy Wiebe
Aug 30 '16 at 19:54
|
show 18 more comments
Below is a working code to add a fragment e.g 3 times to a vertical LinearLayout (xNumberLinear).
You can change number 3 with any other number or take a number from a spinner!
for (int i = 0; i < 3; i++) {
LinearLayout linearDummy = new LinearLayout(getActivity());
linearDummy.setOrientation(LinearLayout.VERTICAL);
if (Build.VERSION.SDK_INT < Build.VERSION_CODES.JELLY_BEAN_MR1) {
Toast.makeText(getActivity(), "This function works on newer versions of android", Toast.LENGTH_LONG).show();
} else {
linearDummy.setId(View.generateViewId());
}
fragmentManager.beginTransaction().add(linearDummy.getId(), new SomeFragment(),"someTag1").commit();
xNumberLinear.addView(linearDummy);
}
add a comment |
Below is a working code to add a fragment e.g 3 times to a vertical LinearLayout (xNumberLinear).
You can change number 3 with any other number or take a number from a spinner!
for (int i = 0; i < 3; i++) {
LinearLayout linearDummy = new LinearLayout(getActivity());
linearDummy.setOrientation(LinearLayout.VERTICAL);
if (Build.VERSION.SDK_INT < Build.VERSION_CODES.JELLY_BEAN_MR1) {
Toast.makeText(getActivity(), "This function works on newer versions of android", Toast.LENGTH_LONG).show();
} else {
linearDummy.setId(View.generateViewId());
}
fragmentManager.beginTransaction().add(linearDummy.getId(), new SomeFragment(),"someTag1").commit();
xNumberLinear.addView(linearDummy);
}
add a comment |
Below is a working code to add a fragment e.g 3 times to a vertical LinearLayout (xNumberLinear).
You can change number 3 with any other number or take a number from a spinner!
for (int i = 0; i < 3; i++) {
LinearLayout linearDummy = new LinearLayout(getActivity());
linearDummy.setOrientation(LinearLayout.VERTICAL);
if (Build.VERSION.SDK_INT < Build.VERSION_CODES.JELLY_BEAN_MR1) {
Toast.makeText(getActivity(), "This function works on newer versions of android", Toast.LENGTH_LONG).show();
} else {
linearDummy.setId(View.generateViewId());
}
fragmentManager.beginTransaction().add(linearDummy.getId(), new SomeFragment(),"someTag1").commit();
xNumberLinear.addView(linearDummy);
}
Below is a working code to add a fragment e.g 3 times to a vertical LinearLayout (xNumberLinear).
You can change number 3 with any other number or take a number from a spinner!
for (int i = 0; i < 3; i++) {
LinearLayout linearDummy = new LinearLayout(getActivity());
linearDummy.setOrientation(LinearLayout.VERTICAL);
if (Build.VERSION.SDK_INT < Build.VERSION_CODES.JELLY_BEAN_MR1) {
Toast.makeText(getActivity(), "This function works on newer versions of android", Toast.LENGTH_LONG).show();
} else {
linearDummy.setId(View.generateViewId());
}
fragmentManager.beginTransaction().add(linearDummy.getId(), new SomeFragment(),"someTag1").commit();
xNumberLinear.addView(linearDummy);
}
answered Sep 21 '18 at 14:57
FarmakerFarmaker
9114
9114
add a comment |
add a comment |
Add this code in your activity
FragmentTransaction mFragmentTransaction=getSupportFragmentManager().beginTransaction();
mFragmentTransaction.add(R.id.fr_container,new ProductListFragment());
mFragmentTransaction.commit();
add a comment |
Add this code in your activity
FragmentTransaction mFragmentTransaction=getSupportFragmentManager().beginTransaction();
mFragmentTransaction.add(R.id.fr_container,new ProductListFragment());
mFragmentTransaction.commit();
add a comment |
Add this code in your activity
FragmentTransaction mFragmentTransaction=getSupportFragmentManager().beginTransaction();
mFragmentTransaction.add(R.id.fr_container,new ProductListFragment());
mFragmentTransaction.commit();
Add this code in your activity
FragmentTransaction mFragmentTransaction=getSupportFragmentManager().beginTransaction();
mFragmentTransaction.add(R.id.fr_container,new ProductListFragment());
mFragmentTransaction.commit();
answered Nov 21 '18 at 7:42
bhoomikabhoomika
42758
42758
add a comment |
add a comment |
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