Want to remove unnecessary message












2












$begingroup$


Manipulate[

  ParametricPlot[{t, t}, {t, 0, s}],

  {s, 0, 1, 0.1}]


This code is working in Mathematica, but generates messages (ParametricPlot::plld). I tried Quiet, but result was still the same.



I looked at Off, but not understand how to use it.






plotting error







share|improve this question











$endgroup$












  • $begingroup$
    The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
    $endgroup$
    – Carl Lange
    2 days ago






  • 2




    $begingroup$
    The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
    $endgroup$
    – Jason B.
    2 days ago






  • 1




    $begingroup$
    I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
    $endgroup$
    – Chip Hurst
    2 days ago










  • $begingroup$
    Possible duplicate: mathematica.stackexchange.com/questions/120868/…
    $endgroup$
    – Michael E2
    2 days ago










  • $begingroup$
    Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
    $endgroup$
    – Michael E2
    2 days ago
















2












$begingroup$


Manipulate[

  ParametricPlot[{t, t}, {t, 0, s}],

  {s, 0, 1, 0.1}]


This code is working in Mathematica, but generates messages (ParametricPlot::plld). I tried Quiet, but result was still the same.



I looked at Off, but not understand how to use it.






plotting error







share|improve this question











$endgroup$












  • $begingroup$
    The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
    $endgroup$
    – Carl Lange
    2 days ago






  • 2




    $begingroup$
    The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
    $endgroup$
    – Jason B.
    2 days ago






  • 1




    $begingroup$
    I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
    $endgroup$
    – Chip Hurst
    2 days ago










  • $begingroup$
    Possible duplicate: mathematica.stackexchange.com/questions/120868/…
    $endgroup$
    – Michael E2
    2 days ago










  • $begingroup$
    Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
    $endgroup$
    – Michael E2
    2 days ago














2












2








2





$begingroup$


Manipulate[

  ParametricPlot[{t, t}, {t, 0, s}],

  {s, 0, 1, 0.1}]


This code is working in Mathematica, but generates messages (ParametricPlot::plld). I tried Quiet, but result was still the same.



I looked at Off, but not understand how to use it.






plotting error







share|improve this question











$endgroup$




Manipulate[

  ParametricPlot[{t, t}, {t, 0, s}],

  {s, 0, 1, 0.1}]


This code is working in Mathematica, but generates messages (ParametricPlot::plld). I tried Quiet, but result was still the same.



I looked at Off, but not understand how to use it.






plotting error




plotting error






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









Michael E2

146k12197469




146k12197469










asked 2 days ago









GoldyGoldy

1652




1652












  • $begingroup$
    The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
    $endgroup$
    – Carl Lange
    2 days ago






  • 2




    $begingroup$
    The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
    $endgroup$
    – Jason B.
    2 days ago






  • 1




    $begingroup$
    I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
    $endgroup$
    – Chip Hurst
    2 days ago










  • $begingroup$
    Possible duplicate: mathematica.stackexchange.com/questions/120868/…
    $endgroup$
    – Michael E2
    2 days ago










  • $begingroup$
    Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
    $endgroup$
    – Michael E2
    2 days ago


















  • $begingroup$
    The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
    $endgroup$
    – Carl Lange
    2 days ago






  • 2




    $begingroup$
    The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
    $endgroup$
    – Jason B.
    2 days ago






  • 1




    $begingroup$
    I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
    $endgroup$
    – Chip Hurst
    2 days ago










  • $begingroup$
    Possible duplicate: mathematica.stackexchange.com/questions/120868/…
    $endgroup$
    – Michael E2
    2 days ago










  • $begingroup$
    Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
    $endgroup$
    – Michael E2
    2 days ago
















$begingroup$
The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
$endgroup$
– Carl Lange
2 days ago




$begingroup$
The reason for the message is that ParametricPlot[{0,0}] doesn't work. If you do something like Manipulate[ParametricPlot[{t, t}, {t, 0, s}], {s, 0.001, 1, 0.1}] instead (note the s initial value to 0.001) it will stop issuing the message.
$endgroup$
– Carl Lange
2 days ago




2




2




$begingroup$
The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
$endgroup$
– Jason B.
2 days ago




$begingroup$
The bigger question here is why does Quiet[ParametricPlot[{t, t}, {t, 0, s}]]; issue a message?
$endgroup$
– Jason B.
2 days ago




1




1




$begingroup$
I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
$endgroup$
– Chip Hurst
2 days ago




$begingroup$
I think it's because it evaluates inside the Quiet, comes back unevaluated, then reevaluates upon return. Try f /; (Print[1]; 1/0) = Null; Quiet[f].
$endgroup$
– Chip Hurst
2 days ago












$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/120868/…
$endgroup$
– Michael E2
2 days ago




$begingroup$
Possible duplicate: mathematica.stackexchange.com/questions/120868/…
$endgroup$
– Michael E2
2 days ago












$begingroup$
Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
$endgroup$
– Michael E2
2 days ago




$begingroup$
Perhaps this might be a helpful example: Manipulate[ ParametricPlot[{Sin[2 t], Cos[3 t]}, {t, 0, 2 Pi}, Mesh -> {{s}}, MeshStyle -> Red, MeshShading -> {ColorData[97][1], None}, PlotRange -> 1], {s, 0, 2 Pi}]
$endgroup$
– Michael E2
2 days ago










1 Answer
1






active

oldest

votes


















6












$begingroup$

The error message is




ParametricPlot: Endpoints for t [...] must have distinct machine-precision numerical values.




The endpoints for t are 0 and s, so when s is 0, ParametricPlot tries to plot t from 0 to 0 and produces this message.



You can solve the problem by setting the lower bound of s to a value strictly larger than 0:



Manipulate[ParametricPlot[{t,t},{t,0,s}],{s,0.1,1,0.1}]]





share|improve this answer








New contributor




Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

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    active

    oldest

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    active

    oldest

    votes









    6












    $begingroup$

    The error message is




    ParametricPlot: Endpoints for t [...] must have distinct machine-precision numerical values.




    The endpoints for t are 0 and s, so when s is 0, ParametricPlot tries to plot t from 0 to 0 and produces this message.



    You can solve the problem by setting the lower bound of s to a value strictly larger than 0:



    Manipulate[ParametricPlot[{t,t},{t,0,s}],{s,0.1,1,0.1}]]





    share|improve this answer








    New contributor




    Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$


















      6












      $begingroup$

      The error message is




      ParametricPlot: Endpoints for t [...] must have distinct machine-precision numerical values.




      The endpoints for t are 0 and s, so when s is 0, ParametricPlot tries to plot t from 0 to 0 and produces this message.



      You can solve the problem by setting the lower bound of s to a value strictly larger than 0:



      Manipulate[ParametricPlot[{t,t},{t,0,s}],{s,0.1,1,0.1}]]





      share|improve this answer








      New contributor




      Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$
















        6












        6








        6





        $begingroup$

        The error message is




        ParametricPlot: Endpoints for t [...] must have distinct machine-precision numerical values.




        The endpoints for t are 0 and s, so when s is 0, ParametricPlot tries to plot t from 0 to 0 and produces this message.



        You can solve the problem by setting the lower bound of s to a value strictly larger than 0:



        Manipulate[ParametricPlot[{t,t},{t,0,s}],{s,0.1,1,0.1}]]





        share|improve this answer








        New contributor




        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        $endgroup$



        The error message is




        ParametricPlot: Endpoints for t [...] must have distinct machine-precision numerical values.




        The endpoints for t are 0 and s, so when s is 0, ParametricPlot tries to plot t from 0 to 0 and produces this message.



        You can solve the problem by setting the lower bound of s to a value strictly larger than 0:



        Manipulate[ParametricPlot[{t,t},{t,0,s}],{s,0.1,1,0.1}]]






        share|improve this answer








        New contributor




        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        share|improve this answer



        share|improve this answer






        New contributor




        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.









        answered 2 days ago









        ArmavicaArmavica

        762




        762




        New contributor




        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.





        New contributor





        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






        Armavica is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
        Check out our Code of Conduct.






























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