Split string into list contains alphabetical bullet list












5















My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"



I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]



The code which i have used is not providing me the desired result



re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)


Please help me regarding this






python string python-3.x







share|improve this question

























  • Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

    – lxop
    Nov 22 '18 at 12:16











  • You are missing the r at the start of your regex pattern string.

    – usr2564301
    Nov 22 '18 at 12:26






  • 1





    [s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

    – iamklaus
    Nov 22 '18 at 12:30











  • @SarthakNegi that fails for c) A

    – planetmaker
    Nov 22 '18 at 12:46











  • @lxop yes it can also contains c d e so on......

    – Sharjeel Ali Shaukat
    Nov 23 '18 at 5:26
















5















My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"



I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]



The code which i have used is not providing me the desired result



re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)


Please help me regarding this






python string python-3.x







share|improve this question

























  • Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

    – lxop
    Nov 22 '18 at 12:16











  • You are missing the r at the start of your regex pattern string.

    – usr2564301
    Nov 22 '18 at 12:26






  • 1





    [s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

    – iamklaus
    Nov 22 '18 at 12:30











  • @SarthakNegi that fails for c) A

    – planetmaker
    Nov 22 '18 at 12:46











  • @lxop yes it can also contains c d e so on......

    – Sharjeel Ali Shaukat
    Nov 23 '18 at 5:26














5












5








5








My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"



I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]



The code which i have used is not providing me the desired result



re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)


Please help me regarding this






python string python-3.x







share|improve this question
















My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"



I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]



The code which i have used is not providing me the desired result



re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)


Please help me regarding this






python string python-3.x




python string python-3.x






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 22 '18 at 12:24









Patrick Artner

24.8k62443




24.8k62443










asked Nov 22 '18 at 12:12









Sharjeel Ali ShaukatSharjeel Ali Shaukat

395210




395210













  • Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

    – lxop
    Nov 22 '18 at 12:16











  • You are missing the r at the start of your regex pattern string.

    – usr2564301
    Nov 22 '18 at 12:26






  • 1





    [s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

    – iamklaus
    Nov 22 '18 at 12:30











  • @SarthakNegi that fails for c) A

    – planetmaker
    Nov 22 '18 at 12:46











  • @lxop yes it can also contains c d e so on......

    – Sharjeel Ali Shaukat
    Nov 23 '18 at 5:26



















  • Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

    – lxop
    Nov 22 '18 at 12:16











  • You are missing the r at the start of your regex pattern string.

    – usr2564301
    Nov 22 '18 at 12:26






  • 1





    [s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

    – iamklaus
    Nov 22 '18 at 12:30











  • @SarthakNegi that fails for c) A

    – planetmaker
    Nov 22 '18 at 12:46











  • @lxop yes it can also contains c d e so on......

    – Sharjeel Ali Shaukat
    Nov 23 '18 at 5:26

















Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

– lxop
Nov 22 '18 at 12:16





Is it possible to have a string like a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?

– lxop
Nov 22 '18 at 12:16













You are missing the r at the start of your regex pattern string.

– usr2564301
Nov 22 '18 at 12:26





You are missing the r at the start of your regex pattern string.

– usr2564301
Nov 22 '18 at 12:26




1




1





[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

– iamklaus
Nov 22 '18 at 12:30





[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]

– iamklaus
Nov 22 '18 at 12:30













@SarthakNegi that fails for c) A

– planetmaker
Nov 22 '18 at 12:46





@SarthakNegi that fails for c) A

– planetmaker
Nov 22 '18 at 12:46













@lxop yes it can also contains c d e so on......

– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26





@lxop yes it can also contains c d e so on......

– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26












2 Answers
2






active

oldest

votes


















3














You could create the wanted data for your example using a list comp and a second regex:



import re



text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"



# different 1.regex pattern, same result - refining with 2nd pattern

data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*', 

                            text) if x and not re.match(r"s*[a-zA-Z])",x)]

print(data)


Output:



['Baghdad, Iraq', 'United Arab Emirates (possibly)']


See https://regex101.com/r/wxEEQW/1






share|improve this answer































    1














    Instead of re.findall, you can simply use re.split:



    import re
    
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
    
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))


    Output:



    ['Baghdad, Iraq', 'United Arab Emirates (possibly)']





    share|improve this answer























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      2 Answers
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      active

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      You could create the wanted data for your example using a list comp and a second regex:



      import re
      

      
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
      

      
# different 1.regex pattern, same result - refining with 2nd pattern
      
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*', 
      
                            text) if x and not re.match(r"s*[a-zA-Z])",x)]
      
print(data)


      Output:



      ['Baghdad, Iraq', 'United Arab Emirates (possibly)']


      See https://regex101.com/r/wxEEQW/1






      share|improve this answer




























        3














        You could create the wanted data for your example using a list comp and a second regex:



        import re
        

        
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
        

        
# different 1.regex pattern, same result - refining with 2nd pattern
        
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*', 
        
                            text) if x and not re.match(r"s*[a-zA-Z])",x)]
        
print(data)


        Output:



        ['Baghdad, Iraq', 'United Arab Emirates (possibly)']


        See https://regex101.com/r/wxEEQW/1






        share|improve this answer


























          3












          3








          3







          You could create the wanted data for your example using a list comp and a second regex:



          import re
          

          
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
          

          
# different 1.regex pattern, same result - refining with 2nd pattern
          
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*', 
          
                            text) if x and not re.match(r"s*[a-zA-Z])",x)]
          
print(data)


          Output:



          ['Baghdad, Iraq', 'United Arab Emirates (possibly)']


          See https://regex101.com/r/wxEEQW/1






          share|improve this answer













          You could create the wanted data for your example using a list comp and a second regex:



          import re
          

          
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
          

          
# different 1.regex pattern, same result - refining with 2nd pattern
          
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*', 
          
                            text) if x and not re.match(r"s*[a-zA-Z])",x)]
          
print(data)


          Output:



          ['Baghdad, Iraq', 'United Arab Emirates (possibly)']


          See https://regex101.com/r/wxEEQW/1







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 22 '18 at 12:33









          Patrick ArtnerPatrick Artner

          24.8k62443




          24.8k62443

























              1














              Instead of re.findall, you can simply use re.split:



              import re
              
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
              
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))


              Output:



              ['Baghdad, Iraq', 'United Arab Emirates (possibly)']





              share|improve this answer




























                1














                Instead of re.findall, you can simply use re.split:



                import re
                
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
                
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))


                Output:



                ['Baghdad, Iraq', 'United Arab Emirates (possibly)']





                share|improve this answer


























                  1












                  1








                  1







                  Instead of re.findall, you can simply use re.split:



                  import re
                  
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
                  
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))


                  Output:



                  ['Baghdad, Iraq', 'United Arab Emirates (possibly)']





                  share|improve this answer













                  Instead of re.findall, you can simply use re.split:



                  import re
                  
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
                  
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))


                  Output:



                  ['Baghdad, Iraq', 'United Arab Emirates (possibly)']






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 22 '18 at 15:18









                  Ajax1234Ajax1234

                  42k42853




                  42k42853






























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