Split string into list contains alphabetical bullet list
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
add a comment |
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
5
5
5
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
My string contains
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
I want to split this in list like
["Baghdad, Iraq","United Arab Emirates (possibly)"]
The code which i have used is not providing me the desired result
re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text)
Please help me regarding this
python string python-3.x
python string python-3.x
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
edited Nov 22 '18 at 12:24
Patrick Artner
24.8k62443
24.8k62443
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
asked Nov 22 '18 at 12:12
Sharjeel Ali ShaukatSharjeel Ali Shaukat
395210
395210
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
Is it possible to have a string likea) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?
– lxop
Nov 22 '18 at 12:16
You are missing therat the start of your regex pattern string.
– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails forc) A
– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
You are missing the
r at the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
You are missing the
r at the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
1
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26
add a comment |
2 Answers
2
active
oldest
votes
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
add a comment |
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
add a comment |
3
3
3
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
You could create the wanted data for your example using a list comp and a second regex:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
# different 1.regex pattern, same result - refining with 2nd pattern
data = [x for x in re.split(r'((?:^s*[a-zA-Z0-9]))|(?:s+[a-zA-Z0-9])))s*',
text) if x and not re.match(r"s*[a-zA-Z])",x)]
print(data)
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
See https://regex101.com/r/wxEEQW/1
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
answered Nov 22 '18 at 12:33
Patrick ArtnerPatrick Artner
24.8k62443
24.8k62443
add a comment |
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
add a comment |
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
add a comment |
1
1
1
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
Instead of re.findall, you can simply use re.split:
import re
text = "a) Baghdad, Iraq b) United Arab Emirates (possibly)"
countries = list(filter(None, map(str.rstrip, re.split('w)s', text))))
Output:
['Baghdad, Iraq', 'United Arab Emirates (possibly)']
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
answered Nov 22 '18 at 15:18
Ajax1234Ajax1234
42k42853
42k42853
add a comment |
add a comment |
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Is it possible to have a string like
a) Baghdad, Iraq b) United Arab Emirates (possibly) c) Turkey if UAE is not in (b)?– lxop
Nov 22 '18 at 12:16
You are missing the
rat the start of your regex pattern string.– usr2564301
Nov 22 '18 at 12:26
1
[s for s in re.split('\s*([a-zA-Z\d][).]|•)\s*(?=[A-Z])', text) if len(s) > 4]
– iamklaus
Nov 22 '18 at 12:30
@SarthakNegi that fails for
c) A– planetmaker
Nov 22 '18 at 12:46
@lxop yes it can also contains c d e so on......
– Sharjeel Ali Shaukat
Nov 23 '18 at 5:26