Swift 3 - Can't retrieve the info after downloading this data
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1
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I'm trying to access the data downloaded from a website which looks like this:
{"quizzes":[
{"id":1, "question": "Can't solve this :("},
{"id":2, "question": "Someone help pls"}]}
The data downloaded looks way more complex, with more values, more keys, and some keys being associated to another dictionary of Key:String, but since i can't even access the most simple fields I thought i would start with this.
I'm using JSONSerialization, so my question is:
If I want to create a variable where i can save the downloaded data... Which would be it's type? I would say [String:[String:Any]], but I'm not sure if "quizzes" represents a key on this specific key, since the data starts with '{' and not with '['.
ios json swift
asked Nov 17 at 9:00
V. Garcia
61
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V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
up vote
1
down vote
favorite
I'm trying to access the data downloaded from a website which looks like this:
{"quizzes":[
{"id":1, "question": "Can't solve this :("},
{"id":2, "question": "Someone help pls"}]}
The data downloaded looks way more complex, with more values, more keys, and some keys being associated to another dictionary of Key:String, but since i can't even access the most simple fields I thought i would start with this.
I'm using JSONSerialization, so my question is:
If I want to create a variable where i can save the downloaded data... Which would be it's type? I would say [String:[String:Any]], but I'm not sure if "quizzes" represents a key on this specific key, since the data starts with '{' and not with '['.
ios json swift
asked Nov 17 at 9:00
V. Garcia
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Your data type should be[String:[[String:Any]]]
– Sviatoslav Yakymiv
Nov 17 at 10:56
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I'm trying to access the data downloaded from a website which looks like this:
{"quizzes":[
{"id":1, "question": "Can't solve this :("},
{"id":2, "question": "Someone help pls"}]}
The data downloaded looks way more complex, with more values, more keys, and some keys being associated to another dictionary of Key:String, but since i can't even access the most simple fields I thought i would start with this.
I'm using JSONSerialization, so my question is:
If I want to create a variable where i can save the downloaded data... Which would be it's type? I would say [String:[String:Any]], but I'm not sure if "quizzes" represents a key on this specific key, since the data starts with '{' and not with '['.
ios json swift
asked Nov 17 at 9:00
V. Garcia
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm trying to access the data downloaded from a website which looks like this:
{"quizzes":[
{"id":1, "question": "Can't solve this :("},
{"id":2, "question": "Someone help pls"}]}
The data downloaded looks way more complex, with more values, more keys, and some keys being associated to another dictionary of Key:String, but since i can't even access the most simple fields I thought i would start with this.
I'm using JSONSerialization, so my question is:
If I want to create a variable where i can save the downloaded data... Which would be it's type? I would say [String:[String:Any]], but I'm not sure if "quizzes" represents a key on this specific key, since the data starts with '{' and not with '['.
ios json swift
ios json swift
asked Nov 17 at 9:00
V. Garcia
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 17 at 9:00
V. Garcia
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 17 at 9:00
V. Garcia
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Nov 17 at 9:00
V. Garcia
61
asked Nov 17 at 9:00
V. Garcia
61
61
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
V. Garcia is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Your data type should be[String:[[String:Any]]]
– Sviatoslav Yakymiv
Nov 17 at 10:56
add a comment |
i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Your data type should be[String:[[String:Any]]]
– Sviatoslav Yakymiv
Nov 17 at 10:56
i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Your data type should be
[String:[[String:Any]]]– Sviatoslav Yakymiv
Nov 17 at 10:56
Your data type should be
[String:[[String:Any]]]– Sviatoslav Yakymiv
Nov 17 at 10:56
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
Instead of using JSONSerialization one could use JSONDecoder.
Example
struct Question: Decodable {
let id: Int
let question: String
}
struct Quiz: Decodable {
let quizzes: [Question]
}
Assuming jsonStr is a string with the JSON in your question:
if let jsonData = jsonStr.data(using: .utf8) {
if let quiz = try? JSONDecoder().decode(Quiz.self, from: jsonData) {
for question in quiz.quizzes {
print("(question.id) "(question.question)"")
}
}
}
Output
1 "Can't solve this :("
2 "Someone help pls"
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Instead of using JSONSerialization one could use JSONDecoder.
Example
struct Question: Decodable {
let id: Int
let question: String
}
struct Quiz: Decodable {
let quizzes: [Question]
}
Assuming jsonStr is a string with the JSON in your question:
if let jsonData = jsonStr.data(using: .utf8) {
if let quiz = try? JSONDecoder().decode(Quiz.self, from: jsonData) {
for question in quiz.quizzes {
print("(question.id) "(question.question)"")
}
}
}
Output
1 "Can't solve this :("
2 "Someone help pls"
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
add a comment |
up vote
0
down vote
Instead of using JSONSerialization one could use JSONDecoder.
Example
struct Question: Decodable {
let id: Int
let question: String
}
struct Quiz: Decodable {
let quizzes: [Question]
}
Assuming jsonStr is a string with the JSON in your question:
if let jsonData = jsonStr.data(using: .utf8) {
if let quiz = try? JSONDecoder().decode(Quiz.self, from: jsonData) {
for question in quiz.quizzes {
print("(question.id) "(question.question)"")
}
}
}
Output
1 "Can't solve this :("
2 "Someone help pls"
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
add a comment |
up vote
0
down vote
up vote
0
down vote
Instead of using JSONSerialization one could use JSONDecoder.
Example
struct Question: Decodable {
let id: Int
let question: String
}
struct Quiz: Decodable {
let quizzes: [Question]
}
Assuming jsonStr is a string with the JSON in your question:
if let jsonData = jsonStr.data(using: .utf8) {
if let quiz = try? JSONDecoder().decode(Quiz.self, from: jsonData) {
for question in quiz.quizzes {
print("(question.id) "(question.question)"")
}
}
}
Output
1 "Can't solve this :("
2 "Someone help pls"
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
Instead of using JSONSerialization one could use JSONDecoder.
Example
struct Question: Decodable {
let id: Int
let question: String
}
struct Quiz: Decodable {
let quizzes: [Question]
}
Assuming jsonStr is a string with the JSON in your question:
if let jsonData = jsonStr.data(using: .utf8) {
if let quiz = try? JSONDecoder().decode(Quiz.self, from: jsonData) {
for question in quiz.quizzes {
print("(question.id) "(question.question)"")
}
}
}
Output
1 "Can't solve this :("
2 "Someone help pls"
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
answered Nov 17 at 10:50
Stephan Schlecht
1,622188
1,622188
add a comment |
add a comment |
V. Garcia is a new contributor. Be nice, and check out our Code of Conduct.
V. Garcia is a new contributor. Be nice, and check out our Code of Conduct.
V. Garcia is a new contributor. Be nice, and check out our Code of Conduct.
V. Garcia is a new contributor. Be nice, and check out our Code of Conduct.
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i have no resource to write swift 2 , the answer is in NSCoding
– Sh_Khan
Nov 17 at 9:58
Have you actually tried this? Personally I would go for the more generic format [String:Any] and have runtime check the structure of the data as it is parsed
– Spads
Nov 17 at 10:11
Your data type should be
[String:[[String:Any]]]– Sviatoslav Yakymiv
Nov 17 at 10:56