PHP - Retrieving IPs from host names
up vote
0
down vote
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I am retrieving values from a table field and appending a string to it to get a list of host names. I would then like to loop through all the host names and return the IP for each.
The following code gets my host names:
$sql = "select * from table order by col1 asc";
$q = mysql_query($sql) or die(mysql_error() ." " . $sql);
// Loop through table and append .zzz to each col1.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz" . " ";
//echo $host_name;
}
The above code works as it should, but I am unsure how to retrieve the IPs for each host name. I have been trying gethostbyname but can't get it to work correctly. I know I have to loop through the host name values. Would I use a foreach loop? I have tried that and can't get it working. Can someone give me some pointers please.
I have tried the following but it doesn't return anything:
$host_name_ip = $host_name;
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $ip. '</li>';
}
I have also tried this... again, nothing:
foreach($host_name as $url) {
$ip = gethostbyname(trim($url));
}
echo $ip;
Thanks. :)
php ip host gethostbyname
asked Nov 19 at 20:53
tlmm
13
add a comment |
up vote
0
down vote
favorite
I am retrieving values from a table field and appending a string to it to get a list of host names. I would then like to loop through all the host names and return the IP for each.
The following code gets my host names:
$sql = "select * from table order by col1 asc";
$q = mysql_query($sql) or die(mysql_error() ." " . $sql);
// Loop through table and append .zzz to each col1.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz" . " ";
//echo $host_name;
}
The above code works as it should, but I am unsure how to retrieve the IPs for each host name. I have been trying gethostbyname but can't get it to work correctly. I know I have to loop through the host name values. Would I use a foreach loop? I have tried that and can't get it working. Can someone give me some pointers please.
I have tried the following but it doesn't return anything:
$host_name_ip = $host_name;
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $ip. '</li>';
}
I have also tried this... again, nothing:
foreach($host_name as $url) {
$ip = gethostbyname(trim($url));
}
echo $ip;
Thanks. :)
php ip host gethostbyname
asked Nov 19 at 20:53
tlmm
13
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I am retrieving values from a table field and appending a string to it to get a list of host names. I would then like to loop through all the host names and return the IP for each.
The following code gets my host names:
$sql = "select * from table order by col1 asc";
$q = mysql_query($sql) or die(mysql_error() ." " . $sql);
// Loop through table and append .zzz to each col1.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz" . " ";
//echo $host_name;
}
The above code works as it should, but I am unsure how to retrieve the IPs for each host name. I have been trying gethostbyname but can't get it to work correctly. I know I have to loop through the host name values. Would I use a foreach loop? I have tried that and can't get it working. Can someone give me some pointers please.
I have tried the following but it doesn't return anything:
$host_name_ip = $host_name;
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $ip. '</li>';
}
I have also tried this... again, nothing:
foreach($host_name as $url) {
$ip = gethostbyname(trim($url));
}
echo $ip;
Thanks. :)
php ip host gethostbyname
asked Nov 19 at 20:53
tlmm
13
I am retrieving values from a table field and appending a string to it to get a list of host names. I would then like to loop through all the host names and return the IP for each.
The following code gets my host names:
$sql = "select * from table order by col1 asc";
$q = mysql_query($sql) or die(mysql_error() ." " . $sql);
// Loop through table and append .zzz to each col1.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz" . " ";
//echo $host_name;
}
The above code works as it should, but I am unsure how to retrieve the IPs for each host name. I have been trying gethostbyname but can't get it to work correctly. I know I have to loop through the host name values. Would I use a foreach loop? I have tried that and can't get it working. Can someone give me some pointers please.
I have tried the following but it doesn't return anything:
$host_name_ip = $host_name;
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $ip. '</li>';
}
I have also tried this... again, nothing:
foreach($host_name as $url) {
$ip = gethostbyname(trim($url));
}
echo $ip;
Thanks. :)
php ip host gethostbyname
php ip host gethostbyname
asked Nov 19 at 20:53
tlmm
13
asked Nov 19 at 20:53
tlmm
13
asked Nov 19 at 20:53
tlmm
13
asked Nov 19 at 20:53
tlmm
13
asked Nov 19 at 20:53
tlmm
13
13
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
3
down vote
accepted
You are overwriting the value of $host_name in your initial loop. Change it to be an array and your foreach will work.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz";
}
To print the host name and it's address in your loop use:
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $name . ' is at address ' . $ip. '</li>';
}
You don't even need to store the names in an array. Just do everything you need in your while loop.
while ($r = mysql_fetch_array($q)) {
$ip = gethostbyname($r['col1']. ".zzz");
echo '<li>' . $r['col1']. '.zzz' . ' is at address ' . $ip. '</li>';
}
answered Nov 19 at 20:57
Dave
2,14551525
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in thecol1column in your database? If it is a host name remove everything after the]on the left side of the = in my answer (leaving the;of course).
– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
OK then remove the. " "after the.zzz. you don't need/want it any more.
– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
|
show 4 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
You are overwriting the value of $host_name in your initial loop. Change it to be an array and your foreach will work.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz";
}
To print the host name and it's address in your loop use:
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $name . ' is at address ' . $ip. '</li>';
}
You don't even need to store the names in an array. Just do everything you need in your while loop.
while ($r = mysql_fetch_array($q)) {
$ip = gethostbyname($r['col1']. ".zzz");
echo '<li>' . $r['col1']. '.zzz' . ' is at address ' . $ip. '</li>';
}
answered Nov 19 at 20:57
Dave
2,14551525
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in thecol1column in your database? If it is a host name remove everything after the]on the left side of the = in my answer (leaving the;of course).
– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
OK then remove the. " "after the.zzz. you don't need/want it any more.
– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
|
show 4 more comments
up vote
3
down vote
accepted
You are overwriting the value of $host_name in your initial loop. Change it to be an array and your foreach will work.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz";
}
To print the host name and it's address in your loop use:
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $name . ' is at address ' . $ip. '</li>';
}
You don't even need to store the names in an array. Just do everything you need in your while loop.
while ($r = mysql_fetch_array($q)) {
$ip = gethostbyname($r['col1']. ".zzz");
echo '<li>' . $r['col1']. '.zzz' . ' is at address ' . $ip. '</li>';
}
answered Nov 19 at 20:57
Dave
2,14551525
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in thecol1column in your database? If it is a host name remove everything after the]on the left side of the = in my answer (leaving the;of course).
– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
OK then remove the. " "after the.zzz. you don't need/want it any more.
– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
|
show 4 more comments
up vote
3
down vote
accepted
up vote
3
down vote
accepted
You are overwriting the value of $host_name in your initial loop. Change it to be an array and your foreach will work.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz";
}
To print the host name and it's address in your loop use:
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $name . ' is at address ' . $ip. '</li>';
}
You don't even need to store the names in an array. Just do everything you need in your while loop.
while ($r = mysql_fetch_array($q)) {
$ip = gethostbyname($r['col1']. ".zzz");
echo '<li>' . $r['col1']. '.zzz' . ' is at address ' . $ip. '</li>';
}
answered Nov 19 at 20:57
Dave
2,14551525
You are overwriting the value of $host_name in your initial loop. Change it to be an array and your foreach will work.
while ($r = mysql_fetch_array($q)) {
$host_name = $r['col1']. ".zzz";
}
To print the host name and it's address in your loop use:
foreach ($host_name_ip as $name) {
$ip = gethostbyname($name);
echo '<li>' . $name . ' is at address ' . $ip. '</li>';
}
You don't even need to store the names in an array. Just do everything you need in your while loop.
while ($r = mysql_fetch_array($q)) {
$ip = gethostbyname($r['col1']. ".zzz");
echo '<li>' . $r['col1']. '.zzz' . ' is at address ' . $ip. '</li>';
}
answered Nov 19 at 20:57
Dave
2,14551525
edited Nov 20 at 14:06
answered Nov 19 at 20:57
Dave
2,14551525
answered Nov 19 at 20:57
Dave
2,14551525
answered Nov 19 at 20:57
Dave
2,14551525
2,14551525
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in thecol1column in your database? If it is a host name remove everything after the]on the left side of the = in my answer (leaving the;of course).
– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
OK then remove the. " "after the.zzz. you don't need/want it any more.
– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
|
show 4 more comments
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in thecol1column in your database? If it is a host name remove everything after the]on the left side of the = in my answer (leaving the;of course).
– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
OK then remove the. " "after the.zzz. you don't need/want it any more.
– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
Thank you. It now returns values to the page but returns the host names and not the IPs.
– tlmm
Nov 19 at 21:00
What is in the
col1 column in your database? If it is a host name remove everything after the ] on the left side of the = in my answer (leaving the ; of course).– Dave
Nov 19 at 21:02
What is in the
col1 column in your database? If it is a host name remove everything after the ] on the left side of the = in my answer (leaving the ; of course).– Dave
Nov 19 at 21:02
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
There are 5 letter variables in col1 for each row. Appending 'zzz' gives me my host name. (zzz is just a sample)
– tlmm
Nov 19 at 21:04
1
1
OK then remove the
. " " after the .zzz. you don't need/want it any more.– Dave
Nov 19 at 21:05
OK then remove the
. " " after the .zzz. you don't need/want it any more.– Dave
Nov 19 at 21:05
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
That was the problem! Thanks so much. It works now!!!!
– tlmm
Nov 19 at 21:07
|
show 4 more comments
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