RxJs6 - Static merge an array of observables
I have a list of objects created dynamically by the user. Each object has a click$ observable, I want to merge all this click$ streams in one stream.
I've tried the merge static operator from rxjs import. With the direct references to the stream:
sub = merge(list[0].click$, list[1].click$)
.subscribe(e => {
console.log('My click event', e);
})
all goes as expected.
But when I use an array of click$ in the subscribe next call I received an Observable object and not my click event.
const streams= ;
list.forEach(o => { streams.push(o.click$); });
sub = merge(streams).subscribe(e => {
console.log(e); // e is an observable ???
});
Why? What am I doing wrong?
Here a similar implementation with the same error: https://stackblitz.com/edit/typescript-ohq6rx?file=index.ts&devtoolsheight=100
javascript reactive-programming rxjs6
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
add a comment |
I have a list of objects created dynamically by the user. Each object has a click$ observable, I want to merge all this click$ streams in one stream.
I've tried the merge static operator from rxjs import. With the direct references to the stream:
sub = merge(list[0].click$, list[1].click$)
.subscribe(e => {
console.log('My click event', e);
})
all goes as expected.
But when I use an array of click$ in the subscribe next call I received an Observable object and not my click event.
const streams= ;
list.forEach(o => { streams.push(o.click$); });
sub = merge(streams).subscribe(e => {
console.log(e); // e is an observable ???
});
Why? What am I doing wrong?
Here a similar implementation with the same error: https://stackblitz.com/edit/typescript-ohq6rx?file=index.ts&devtoolsheight=100
javascript reactive-programming rxjs6
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
add a comment |
I have a list of objects created dynamically by the user. Each object has a click$ observable, I want to merge all this click$ streams in one stream.
I've tried the merge static operator from rxjs import. With the direct references to the stream:
sub = merge(list[0].click$, list[1].click$)
.subscribe(e => {
console.log('My click event', e);
})
all goes as expected.
But when I use an array of click$ in the subscribe next call I received an Observable object and not my click event.
const streams= ;
list.forEach(o => { streams.push(o.click$); });
sub = merge(streams).subscribe(e => {
console.log(e); // e is an observable ???
});
Why? What am I doing wrong?
Here a similar implementation with the same error: https://stackblitz.com/edit/typescript-ohq6rx?file=index.ts&devtoolsheight=100
javascript reactive-programming rxjs6
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
I have a list of objects created dynamically by the user. Each object has a click$ observable, I want to merge all this click$ streams in one stream.
I've tried the merge static operator from rxjs import. With the direct references to the stream:
sub = merge(list[0].click$, list[1].click$)
.subscribe(e => {
console.log('My click event', e);
})
all goes as expected.
But when I use an array of click$ in the subscribe next call I received an Observable object and not my click event.
const streams= ;
list.forEach(o => { streams.push(o.click$); });
sub = merge(streams).subscribe(e => {
console.log(e); // e is an observable ???
});
Why? What am I doing wrong?
Here a similar implementation with the same error: https://stackblitz.com/edit/typescript-ohq6rx?file=index.ts&devtoolsheight=100
javascript reactive-programming rxjs6
javascript reactive-programming rxjs6
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
asked Nov 21 '18 at 15:51
EduBicEduBic
5116
5116
add a comment |
add a comment |
1 Answer
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Since it's an array. You can spread an array with the ... operator in JavaScript. If you do this all should work well.
More information can be found at MDN
I added code so you have an idea what I mean. List is the array of objects that have click$ properties. this array is mapped to just the click$ and then spread with the ... operator.
sub = merge(...list.map(item => item.click$)).subscribe(console.log)
answered Nov 21 '18 at 16:07
MurfMurf
677313
add a comment |
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1 Answer
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oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Since it's an array. You can spread an array with the ... operator in JavaScript. If you do this all should work well.
More information can be found at MDN
I added code so you have an idea what I mean. List is the array of objects that have click$ properties. this array is mapped to just the click$ and then spread with the ... operator.
sub = merge(...list.map(item => item.click$)).subscribe(console.log)
answered Nov 21 '18 at 16:07
MurfMurf
677313
add a comment |
Since it's an array. You can spread an array with the ... operator in JavaScript. If you do this all should work well.
More information can be found at MDN
I added code so you have an idea what I mean. List is the array of objects that have click$ properties. this array is mapped to just the click$ and then spread with the ... operator.
sub = merge(...list.map(item => item.click$)).subscribe(console.log)
answered Nov 21 '18 at 16:07
MurfMurf
677313
add a comment |
Since it's an array. You can spread an array with the ... operator in JavaScript. If you do this all should work well.
More information can be found at MDN
I added code so you have an idea what I mean. List is the array of objects that have click$ properties. this array is mapped to just the click$ and then spread with the ... operator.
sub = merge(...list.map(item => item.click$)).subscribe(console.log)
answered Nov 21 '18 at 16:07
MurfMurf
677313
Since it's an array. You can spread an array with the ... operator in JavaScript. If you do this all should work well.
More information can be found at MDN
I added code so you have an idea what I mean. List is the array of objects that have click$ properties. this array is mapped to just the click$ and then spread with the ... operator.
sub = merge(...list.map(item => item.click$)).subscribe(console.log)
answered Nov 21 '18 at 16:07
MurfMurf
677313
edited Nov 21 '18 at 16:13
answered Nov 21 '18 at 16:07
MurfMurf
677313
answered Nov 21 '18 at 16:07
MurfMurf
677313
answered Nov 21 '18 at 16:07
MurfMurf
677313
677313
add a comment |
add a comment |
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