How to align my equation to left?
8
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
edited Mar 22 at 8:44
JouleV
8,90222155
asked Mar 22 at 8:39
cholechole
411
add a comment |
8
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
edited Mar 22 at 8:44
JouleV
8,90222155
asked Mar 22 at 8:39
cholechole
411
never use$$in latex, use[and then thefleqnoption will left align equations.
– David Carlisle
Mar 22 at 8:45
add a comment |
8
8
8
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
edited Mar 22 at 8:44
JouleV
8,90222155
asked Mar 22 at 8:39
cholechole
411
I want to display four equations which have different length. I want they align left like this.
But my code give this
The following are my code:
$$begin{aligned} p(a) &=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a) \
&={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}
end{aligned}$$
$$begin{aligned} p(b) &=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b) \
&={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}} end{aligned}$$
$$begin{aligned} p(c) &=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}} end{aligned}$$
$$begin{aligned} p(d) &=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d) \
&={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}} end{aligned}$$
Can anyone tell me what I can do?
math-mode align
math-mode align
edited Mar 22 at 8:44
JouleV
8,90222155
asked Mar 22 at 8:39
cholechole
411
edited Mar 22 at 8:44
JouleV
8,90222155
asked Mar 22 at 8:39
cholechole
411
edited Mar 22 at 8:44
JouleV
8,90222155
edited Mar 22 at 8:44
JouleV
8,90222155
edited Mar 22 at 8:44
JouleV
8,90222155
8,90222155
asked Mar 22 at 8:39
cholechole
411
asked Mar 22 at 8:39
cholechole
411
asked Mar 22 at 8:39
cholechole
411
411
never use$$in latex, use[and then thefleqnoption will left align equations.
– David Carlisle
Mar 22 at 8:45
add a comment |
never use$$in latex, use[and then thefleqnoption will left align equations.
– David Carlisle
Mar 22 at 8:45
never use
$$ in latex, use [ and then the fleqn option will left align equations.– David Carlisle
Mar 22 at 8:45
never use
$$ in latex, use [ and then the fleqn option will left align equations.– David Carlisle
Mar 22 at 8:45
add a comment |
2 Answers
2
active
oldest
votes
7
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle? It is very hard to read the fractions! Use tfrac instead!
You should remove ; in the &;={scriptstyle... lines to align the =s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
@chole Then you should usetfracinstead ofscriptstylefrac.
– JouleV
Mar 22 at 8:58
2
+1 for recommendingtfracin place ofscriptstylefrac.
– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$but If I had answered I would also have suggestedalign*rather than[begin{aligned}:-)
– David Carlisle
Mar 22 at 9:08
|
show 1 more comment
6
I propose this layout, using the fleqn environment and, as in my opinion, medium sized fractions will look best, I also use the medmath and mfrac commands, each from nccmath:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
answered Mar 22 at 10:12
BernardBernard
174k776207
add a comment |
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2 Answers
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2 Answers
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7
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle? It is very hard to read the fractions! Use tfrac instead!
You should remove ; in the &;={scriptstyle... lines to align the =s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
@chole Then you should usetfracinstead ofscriptstylefrac.
– JouleV
Mar 22 at 8:58
2
+1 for recommendingtfracin place ofscriptstylefrac.
– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$but If I had answered I would also have suggestedalign*rather than[begin{aligned}:-)
– David Carlisle
Mar 22 at 9:08
|
show 1 more comment
7
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle? It is very hard to read the fractions! Use tfrac instead!
You should remove ; in the &;={scriptstyle... lines to align the =s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
@chole Then you should usetfracinstead ofscriptstylefrac.
– JouleV
Mar 22 at 8:58
2
+1 for recommendingtfracin place ofscriptstylefrac.
– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$but If I had answered I would also have suggestedalign*rather than[begin{aligned}:-)
– David Carlisle
Mar 22 at 9:08
|
show 1 more comment
7
7
7
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle? It is very hard to read the fractions! Use tfrac instead!
You should remove ; in the &;={scriptstyle... lines to align the =s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
Here is a proposal
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&;={scriptstyle frac{1}{2} frac{2}{3}+frac{1}{4} frac{1}{3}+frac{1}{3}+frac{1}{3}=frac{1}{2}}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&;={scriptstylefrac{1}{2} frac{1}{6}+frac{1}{4} frac{1}{2}+frac{1}{3} frac{1}{3}=frac{1}{4}}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{4} frac{1}{6}+frac{1}{8} 0+frac{1}{8}=frac{1}{8}}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&;={scriptstylefrac{1}{2} frac{1}{12}+frac{1}{8} frac{1}{3}+frac{1}{8} frac{1}{3}=frac{1}{3}}
end{align*}
end{document}
Why do you use scriptstyle? It is very hard to read the fractions! Use tfrac instead!
You should remove ; in the &;={scriptstyle... lines to align the =s. I prefer that way.
I strongly recommend this one
documentclass{article}
usepackage{amsmath}
begin{document}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&=tfrac{1}{2} tfrac{2}{3}+tfrac{1}{4} tfrac{1}{3}+tfrac{1}{3}+tfrac{1}{3}=tfrac{1}{2}\
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&=tfrac{1}{2} tfrac{1}{6}+tfrac{1}{4} tfrac{1}{2}+tfrac{1}{3} tfrac{1}{3}=tfrac{1}{4}\
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{4} tfrac{1}{6}+tfrac{1}{8} 0+tfrac{1}{8}=tfrac{1}{8}\
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&=tfrac{1}{2} tfrac{1}{12}+tfrac{1}{8} tfrac{1}{3}+tfrac{1}{8} tfrac{1}{3}=tfrac{1}{3}
end{align*}
end{document}
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
edited Mar 22 at 8:59
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
answered Mar 22 at 8:49
JouleVJouleV
8,90222155
8,90222155
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
@chole Then you should usetfracinstead ofscriptstylefrac.
– JouleV
Mar 22 at 8:58
2
+1 for recommendingtfracin place ofscriptstylefrac.
– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$but If I had answered I would also have suggestedalign*rather than[begin{aligned}:-)
– David Carlisle
Mar 22 at 9:08
|
show 1 more comment
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
@chole Then you should usetfracinstead ofscriptstylefrac.
– JouleV
Mar 22 at 8:58
2
+1 for recommendingtfracin place ofscriptstylefrac.
– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using$$but If I had answered I would also have suggestedalign*rather than[begin{aligned}:-)
– David Carlisle
Mar 22 at 9:08
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
Thank you very much. I use 'scriptstyle' because I want the second line of the equation to be small.
– chole
Mar 22 at 8:55
1
1
@chole Then you should use
tfrac instead of scriptstylefrac.– JouleV
Mar 22 at 8:58
@chole Then you should use
tfrac instead of scriptstylefrac.– JouleV
Mar 22 at 8:58
2
2
+1 for recommending
tfrac in place of scriptstylefrac.– Mico
Mar 22 at 9:00
+1 for recommending
tfrac in place of scriptstylefrac.– Mico
Mar 22 at 9:00
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
@chole If my answer helps you, please mark your question as resolved by clicking the checkmark on the left of my answer.
– JouleV
Mar 22 at 9:02
1
1
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using
$$ but If I had answered I would also have suggested align* rather than [begin{aligned} :-)– David Carlisle
Mar 22 at 9:08
+1 yes as I commented under the question the direct answer why there was no left alignment was due to using
$$ but If I had answered I would also have suggested align* rather than [begin{aligned} :-)– David Carlisle
Mar 22 at 9:08
|
show 1 more comment
6
I propose this layout, using the fleqn environment and, as in my opinion, medium sized fractions will look best, I also use the medmath and mfrac commands, each from nccmath:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
answered Mar 22 at 10:12
BernardBernard
174k776207
add a comment |
6
I propose this layout, using the fleqn environment and, as in my opinion, medium sized fractions will look best, I also use the medmath and mfrac commands, each from nccmath:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
answered Mar 22 at 10:12
BernardBernard
174k776207
add a comment |
6
6
6
I propose this layout, using the fleqn environment and, as in my opinion, medium sized fractions will look best, I also use the medmath and mfrac commands, each from nccmath:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
answered Mar 22 at 10:12
BernardBernard
174k776207
I propose this layout, using the fleqn environment and, as in my opinion, medium sized fractions will look best, I also use the medmath and mfrac commands, each from nccmath:
documentclass{article}
usepackage{amsmath, nccmath}
begin{document}
begin{fleqn}
begin{align*}
p(a)&=p(a) p(a rightarrow a)+p(b) p(b rightarrow a)+p(c) p(c rightarrow a)+p(d) p(d rightarrow a)\
&quad= medmath{frac{1}{2}cdot frac{2}{3}+frac{1}{4}cdot frac{1}{3}+frac{1}{3}+frac{1}{3}}=mfrac{1}{2} \[1ex]
p(b)&=p(a) p(a rightarrow b)+p(b) p(b rightarrow b)+p(c) p(c rightarrow b)\
&quad= medmath{frac{1}{2}cdot frac{1}{6}+frac{1}{4}cdot frac{1}{2}+frac{1}{3}cdot frac{1}{3}}=mfrac{1}{4} \[1ex]
p(c)&=p(a) p(a rightarrow c)+p(b) p(b rightarrow c)+p(c) p(c rightarrow c)+p(d) p(d rightarrow c)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{4}cdot frac{1}{6}+frac{1}{8},0 + frac{1}{8}}=mfrac{1}{8} \[1ex]
p(d)&=p(a) p(a rightarrow d)+p(c) p(c rightarrow d)+p(d) p(d rightarrow d)\
&quad= medmath{frac{1}{2}cdot frac{1}{12}+frac{1}{8}cdot frac{1}{3}+frac{1}{8cdot } frac{1}{3}}=mfrac{1}{3}
end{align*}
end{fleqn}
end{document}
answered Mar 22 at 10:12
BernardBernard
174k776207
edited Mar 22 at 10:50
answered Mar 22 at 10:12
BernardBernard
174k776207
answered Mar 22 at 10:12
BernardBernard
174k776207
answered Mar 22 at 10:12
BernardBernard
174k776207
174k776207
add a comment |
add a comment |
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never use
$$in latex, use[and then thefleqnoption will left align equations.– David Carlisle
Mar 22 at 8:45